Join the Smartie Party now to get EXCLUSIVE reward puzzle packs, ad free content, discord access, and so much more www.buymeacoffee.com/timberlakeB/membership

Thanks for solving my puzzle and for giving me the opportunity to make the June smarty party pack!

Wow ! This one was beyond me. Great demo.

After a long day out in the smoke & humidity, it was a pleasant surprise to find a new ??? waiting. I didn't have much in the way of problems with this one (rated unfair vs extreme). I'll watch the video tomorrow when there's no distractions.

Feeling so satisfied after doing it on my own . Actually ,when i was unable to proceed further after filling the pencil marks and just finding x wing on 1' s , i then thought of watching ur video , as soon as i heard u talking abt the technique SDC, I stopped watching urs and clicked on sudoku swami's tutorial related to Sue de Coq. And then i tried on my own .If i remember correctly , i applied SDC in three boxes 7, 9 and 5. Then i guess i found 79 pair in col 5 Wow! Great puzzle. Now let me watch ur video.

6:30 don’t need SDC here. You know that the only place for the 89 from row 8 column 1 within box 1 is in row 1 column 3 so you can use this knowledge to remove 67 from row 1 column 3. Not sure what that method is called but much easier than SDC. However this is a good way to illustrate SDC though!

5:32 Basically what you are looking at is: 8@VII4 => 8@I3, 9@VII4 => 9@I3, therefore I3 can only be an 8 or a 9. This is one of those things that would take me ages to spot with the toolset that I use.

Wow, I managed to crack that using the 89. I've got to say I have learned quite a lot from you with these series of puzzles, even though I don't always comment.

I'm trying it before watching the video. I hope I detect the logic, even though I don't remember the Sue De Coq pattern. Okay, it's done. I began by filling in the six-digit rows and columns. I got 789 triples in the rows. (I knew I was supposed to do something with them, but couldn't figure out what. An 89 cell in block 2 later on didn't help.) Then I went to cornermarking. I got an immediate X-wing in 1s that clipped a few. In 5s, an empty rectangle clipped a couple 5s. 7s gave me a finned swordfish that clipped a digit. (The 789 triples formed two of the rows.) My first digit was a naked 6 in block 5, thanks to the empty rectangle, and then a 5 in block 4. A 237 XYZ-Wing (Is that what it's called?) clipped a 2 in block 6. Stuck as I was, I continued to fill out the grid. I finally bifurcated on a 18 in R7C6. 1 led quickly to a collision, and I placed 8. That finally cracked the puzzle. 0:20 Yes, I did place the 1 very early, long before the 6. I just didn't notice the blue 1 when I was backtracking to tell my story. I think that the 1, 6, and 5 were the only digits I placed before bifurcating. 2:10 I didn't see the 56 pair. It was later. The empty rectangle left a pointing pair in 5s that removed the 5 from R4C5, leaving the naked 6. Then I placed the 5 in R4C2. 2:40 The finned swordfish in 7s is visible in the grid. I don't know how useful it was. 3:00 Ah, the advantage of a clutterless grid. I never saw the skyscraper. However, 5 in row 7 was limited to columns 1 and 9. Consequently, the empty rectangle did the same thing. Since I hadn't spotted the 56 pair, the result was a pointing pair that removed the 5 from R4C5. 4:20 Yes, my second and third digits. 5:50 A jumble of cells plus a 36 pair. I couldn't do anything with the latter, though. 10:00 I spent a little time studying my grid, having paused the video. Originally, I thought of using letters (H and I) for 8 and 9. I might have hit upon the logic if not the name. Defining H to be the digit in R8C1 (89) and I to be the other of 8 and 9, that would lead to a 367I quad in block 1, placing H in R1C3. With 7 and I restricted in that block to column 1, I could remove 7, 8, and 9 from the rest of column 1. Thanks for the video.