How to update data using onchange event selected value | JavaScript with PHP and MySQL

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How to update data using onchange event selected value | JavaScript with PHP and MySQL | E-CODEC

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How to update data using onchange event selected value | JavaScript with PHP and MySQL | E-CODEC
In this tutorial you will learn How to update data using onchange event selected value | JavaScript with PHP and MySQL coding, subscribe E-CODEC channel to watch more videos on website designing tutorials for beginners.
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Пікірлер: 18

@jsmithtraveller 11 ай бұрын

A great tutorial and pleasant background music

@akindelesamuelkehinde6817 7 ай бұрын

thanks it really help a lot

@anupamadilshan9322 2 жыл бұрын

It is working really well thank you so much.but i used ajax to pass data in to function page...anyway thank tou again i got new knowledge from this..🎉❣

@e-codec7359 2 жыл бұрын

Thank you !

@zhellene1236 11 ай бұрын

Thank you so much for this hehehe it's working fine

@chlorine4290 Жыл бұрын

Eres un genio, Gracias!!!!!

@kararqasim177 Жыл бұрын

welcome everybody In such a table, I want to modify all the data at once by pressing the Submit button. please can you make a video how to make that

@gfranciscoyap Жыл бұрын

Can you share the source code for creating the "login" table for this tutorial? I would really appreciate it. Thank you very much!

@farisazwar5224 Жыл бұрын

how to do this process using JSP. Please help me

@hridoyahmed6939 9 ай бұрын

will it work in live server??

@e-codec7359 9 ай бұрын

yes

@emittyarts Жыл бұрын

please sir make a video to display every 3 days from date. Like my village market days is always every 3 days. i wanted to create an input filed that a user can enter his date and the system will tell the user the next market days or if the date given is previous,the system should be able to tell the market days back at then. Please help. // The given date $given_date=$_POST['given_date']; if(isset($_POST['submit'])){ // Loop for 7 times for($i=0; $i this my code but it's having draw backs.

@e-codec7359 Жыл бұрын

$day_name = array(); $date = array(); $given_date = "2023-01-21"; $count = 3; for($i = 1; $i

@emittyarts Жыл бұрын

@@e-codec7359 thanks sir,lemme try it and see

@emittyarts Жыл бұрын

@@e-codec7359 it worked also sir. The " array " and indexes [0] ,[1],how can i hide them to only display the array data?