If angle θ is divided into two parts such that the tangent of one part is k
times the tangent of other, and φ is their difference, then show that
sin θ =
(k+1)/(k-1) sinφ
θ is divided into two parts such that tanθ = ktan φ, φ is their difference
sin θ =
(k+1)/(k-1) sinφ
If angle theta is divided into two two parts and phi is difference then show sin θ = (k+1)/(k-1)sinφ