Calc

I suppose you could use Leibnitz's theorem of nth product derivative if u=1 and v=f(x); but I haven't done the calculation.

Wait!! I remember seeing you in some other comment section! What are the odds?!

@@nalingoel6971 Idk, lol. Probably 1 in a several million. Considering there are around 30 billion videos on KZfaq and most of my comments don't gain enough likes to get exposed to more than a few people, even if I comment a lot, the chances are very very low.

@@THEMATT222 You may not remember but we actually talked about Reddit lol.

@@nalingoel6971 Hmmmm, in which video did we talk in? Should we add each other on Reddit or something?

@@THEMATT222 I don't remember which video; I am not on Reddit anymore

l'hopital's rule would have to be used so u take d/dx of the top and bottom to get 0/1 = 0

Since h isn’t actually 0, just approaching 0, you can evaluate 0/h before applying the limit. You do not have to apply L’Hopital.

Imagine that h is just slightly above zero, then the answer will be zero, therefore you can imagine as to why the limit is 0.

The whole purpose of the limit is that h is never equal to 0, just very close to 0