Japanese | Math Olympiad | A Nice Algebra Problem

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Math Hunter

Math Hunter

Ай бұрын

Hello My Dear KZfaq Family 😍😍😍
Hope you all are doing well 🥰🥰🥰
If you are enjoying my video about how to solve this math olympiad algebra problem then please Like and Subscribe my channel as it helps me a lot 🙂🙂🙂

Пікірлер: 111
@KipIngram
@KipIngram 25 күн бұрын
It takes about eight seconds to see that that's 2^18.
@jamesharmon4994
@jamesharmon4994 23 күн бұрын
Definitely not an Olympiad level problem.
@jesusthroughmary
@jesusthroughmary 13 күн бұрын
Yeah, pretty obvious that the one and everything past the one goes away immediately
@DavyCDiamondback
@DavyCDiamondback 9 күн бұрын
Now solve that in your head. I got 262144 from 512^2
@KipIngram
@KipIngram 9 күн бұрын
I know the powers of two instantly from direct memory up through 2^16, but I usually then have to calculate a bit. I've just never bothered to learn the higher powers. I spent my career working in the digital hardware area, but by the time powers higher than 65536 started to become "more relevant" I had moved on to other facets of the work, so those beyond 16 just never got "burned in" like the lower ones did. I can give them all to you in hexadecimal, though. 🙂 0x40000. There's a reason we made so much use of hex.
@jamesharmon4994
@jamesharmon4994 9 күн бұрын
@@KipIngram I'd bet you know 2^20 (one MB)
@user-cg5xv4zz2b
@user-cg5xv4zz2b 21 күн бұрын
for computer person - after you get to 2^18 = 2^10 ( 1K ) * 256 - multiply that - easier than all that stuff after 2^18 in this video. Or 2^18 =- 2^20 (1M ) /4. both give the correct answer and easier.
@Psykolord1989
@Psykolord1989 Күн бұрын
Before watching: Alright, if you have like a^b^c^d^e^f^g, you'll typically calculate f^g first, then e^(f^g), then d^(e^(f^g)), and so on,. With that in mind, we can ignore the outermost 3 exponents we see. Why? Because those last 3 are 1^(5^9)), and 5^9 is a real number, and 1^X = 1 for real X. So what this actually meansi s that we're looking at √ 2^(6^2). But square root is simply an exponent of 1/2. Thus, √(2^(6^2)) = (2^((1/2)6^2)) = 2^(36/2) = 2^18. Solution is 2^18. Because we're not solving for X, but simply evaluating a square root, we do not include the negative root in this case. Most math classes will allow you to leave the term 2^18 as-is. However, if your class is currently doing a unit on *evaluating* exponents, you may have to multiply it out. Quickest way without knowing the higher powers of 2 (suppose you only know as far as...2^12 = 4096) would be to do (2^9)(2^9) = 512*512 = 1024 + 5120 +256000 = 262144 Honestly 4096*64 is probably going to go faster, but I went with what popped into my head.
@jodybennett3753
@jodybennett3753 8 күн бұрын
I think this problem is more interesting if instead of solving for the square root of 2^6^2^1^5^9 you solve for the square root of 2^6^2^1^4^4 which has an answer with same digits as the problem
@marifulislam2
@marifulislam2 5 күн бұрын
Good
@shouryakeshkar5309
@shouryakeshkar5309 27 күн бұрын
oml bruh you can straight up cancel out the 1^5^9 and get sqrt(2^6^2) = 2^18 its that simple dont overcomplicate things take it easy
@terracottapie
@terracottapie 11 күн бұрын
They're just going step by step for novices who might not see it as quickly. There's other channels for more advanced math stuff.
@dumitrudraghia5289
@dumitrudraghia5289 5 күн бұрын
YES!
@anilkumarsharma8901
@anilkumarsharma8901 8 күн бұрын
Zebras and 🦒 giraffe are having some positive corelation 😃😄😁😄😃😃😃
@Ayanokoji-k-x2b
@Ayanokoji-k-x2b 28 күн бұрын
❤❤❤❤❤❤❤
@noobmota8126
@noobmota8126 14 күн бұрын
U COMPLICATED IT MORE...
@aryanbhaiyt295
@aryanbhaiyt295 10 күн бұрын
The actual video is to find the value of 2^18
@jayengineering1102
@jayengineering1102 4 күн бұрын
Why is everyone thinking of 2^18 , I think its 2^36 , since there is whole underroot therefore it will be 9^(1/2).
@ToanPham-wr7xe
@ToanPham-wr7xe 25 күн бұрын
😮
@ashishjha1039
@ashishjha1039 11 күн бұрын
Just put 2 in place of 1 and see the magic of infinity.
@abhijeetparasar5977
@abhijeetparasar5977 16 күн бұрын
U can solve without assuming 5^9=x one sight easy question
@tomjones6777
@tomjones6777 20 күн бұрын
👍😊🇺🇸✌️
@tylosenpai6920
@tylosenpai6920 13 күн бұрын
2^18 The key is you need to recognize that 1
@andredcavalcante
@andredcavalcante 6 күн бұрын
Forget powers of 1: result is always 1. 2 power 1 is 2. 6 power 2 = 36. But you are in a square root, and a square root of any number power 2 is this number. Then, square number of 2 power 36 is 2 power 18. Then, the result is 2 power 18 = 512 x 512 Piece cake!
@kextrz
@kextrz 10 күн бұрын
Forget about the top three numbers. One to the power of anything equals one.
@syedmdabid7191
@syedmdabid7191 25 күн бұрын
Hic est 2^18 responsum.
@user-mh4df9vb5m
@user-mh4df9vb5m 2 күн бұрын
1
@jaggisaram4914
@jaggisaram4914 5 күн бұрын
2^18
@sergioabdalla8698
@sergioabdalla8698 20 күн бұрын
this music is from electrolab channel
@AK2117official
@AK2117official 11 күн бұрын
2^(18)
@rampassi1577
@rampassi1577 19 күн бұрын
CM Maan is right.Needs reelection for Parliament.
@rjs7906
@rjs7906 11 күн бұрын
I solved and found 2^18 in 5 seconds
@SuperAnangs
@SuperAnangs 22 күн бұрын
In 5 sec, i get the answet 2^18 The key is number 1
@Kkunai.21
@Kkunai.21 14 күн бұрын
2¹⁸
@bozotheclown935
@bozotheclown935 4 күн бұрын
I get this to be 64 ie 2^6
@tamarshahverdyan2723
@tamarshahverdyan2723 23 күн бұрын
19
@enesgunesli6574
@enesgunesli6574 4 күн бұрын
Song name plz ? ❤
@Damanalovca
@Damanalovca 7 күн бұрын
Square root from 262144 is 512. The final answer 512.
@AloneStroller
@AloneStroller 24 күн бұрын
512*512 using quadratic equation is funny. Maybe you know ANOTHER way to multiply numbers? 😂😂😂
@noobmota8126
@noobmota8126 14 күн бұрын
MY calculs does 513... And not so longtime and complicated...
@tamarshahverdyan2723
@tamarshahverdyan2723 23 күн бұрын
29
@ChingatuMadre-dl8hu
@ChingatuMadre-dl8hu 22 күн бұрын
Es correcto
@alexniklas8777
@alexniklas8777 4 күн бұрын
2^18😅
@LakshmiNarayana-zm9ey
@LakshmiNarayana-zm9ey 22 күн бұрын
2 power x
@confrontations5578
@confrontations5578 15 күн бұрын
262 144
@job341kg
@job341kg 13 күн бұрын
64
@LakshmiNarayana-zm9ey
@LakshmiNarayana-zm9ey 22 күн бұрын
What about 29=x
@nenemtiaof5016
@nenemtiaof5016 24 күн бұрын
E o 5^9 ?
@seba8115
@seba8115 19 күн бұрын
Nice trick
@galvao6182
@galvao6182 9 күн бұрын
Parabéns! Complicado NÃO, extenso! Longo! Tem como fazer menos Longo?
@LeWoWGuides
@LeWoWGuides 6 күн бұрын
xdd it takes like 1 second to see the answer sqrt(2^36) = 2^18
@CaptainDangeax
@CaptainDangeax 5 күн бұрын
10 seconds to 2^18=262144. Yes I know my powers of 2 by heart
@CaptainDangeax
@CaptainDangeax 5 күн бұрын
@@johnnyragadoo2414 1 ^ 2 ^ 9 = 1. 2^9 is even, 9^2 is odd. You just fooled your maths completely
@CaptainDangeax
@CaptainDangeax 5 күн бұрын
@@johnnyragadoo2414 ln(1+2+3)=ln(1)+ln(2)+ln(3) is a singularity, not a démonstration ln is associative. 2^4=4^2 is also a singularity, not a proof power is commutative
@CaptainDangeax
@CaptainDangeax 5 күн бұрын
@@johnnyragadoo2414 10^4^2=10^16=10000000000000000 Did you write ANYTHING correct?
@CaptainDangeax
@CaptainDangeax 5 күн бұрын
@@johnnyragadoo2414 back to the question, you have a 1 in the ladder of powers, therefore you must ignore what comes after. 2^6^2^1= 2^6^2=2^36. Apply square root, 2^(36/2)=2^18=262144
@CaptainDangeax
@CaptainDangeax 5 күн бұрын
@@johnnyragadoo2414 You must read power from right to left 1 ^ 5 ^ 9 = 1 ^ (5 ^ 9) = 1. Result 262144. Period. And if you want to change the rules of math, try with prime numbers and figure out (2^3)^5 and 2^(3^5) are not the same. Result 262144
@Missmijyu
@Missmijyu 14 күн бұрын
2の270乗じゃないの?分からん
@bmkdz
@bmkdz 28 күн бұрын
I got a result 2^18
@bmkdz
@bmkdz 28 күн бұрын
Before i watch the result
@KipIngram
@KipIngram 25 күн бұрын
@@bmkdz Same here. Took about eight seconds looking at the opening screen. The 1^5^9 just goes away.
@Fire_Axus
@Fire_Axus 6 күн бұрын
it is 2^18
@johnnyragadoo2414
@johnnyragadoo2414 5 күн бұрын
No, it's not. It's 2^270. Exponents are not associative. They can be rearranged, but not regrouped.
@mdlelim4234
@mdlelim4234 26 күн бұрын
2 power 270
@KipIngram
@KipIngram 25 күн бұрын
Not the right answer.
@KipIngram
@KipIngram 5 күн бұрын
Did you do it right? You work from the top down. You'd calculate x = 5^9, and then 1^x. But that will just be 1, because 1^ is 1. Then we have 2^1, which is 2. Then 6^2, which is 36. Then 2^36. Then we take the square root of the whole thing, which is 2^18. You do not start at the bottom 2 and work your way up. The answer is 2^18.
@jerrypaquette5470
@jerrypaquette5470 28 күн бұрын
It is really not that difficult to just multiply 512 x 512.
@KipIngram
@KipIngram 25 күн бұрын
Yes - takes a few seconds to do in your head.
@constantinfedorov2307
@constantinfedorov2307 24 күн бұрын
Ну там же есть 1 среди степеней, начиная с неё можно просто все стереть. Остается √2³⁶ = .....
@user-ee7nw2rx9s
@user-ee7nw2rx9s 11 күн бұрын
Если 1^а=1, то 5^9, вообще не играет роли и не зачем уделять внимание ей
@shankarlalsaraswat6283
@shankarlalsaraswat6283 10 күн бұрын
How 2 power 6 power 2 can be 2 power 36. Power get multiplied so it should be 2 power 12 rather than 2 power 36. Sq root of it will be 2 power 6.
@ThreePointOneFou
@ThreePointOneFou 8 күн бұрын
Wrong-you perform successive exponentiations from the top down. 2^6^2 should be interpreted as 2^(6^2), or 2^36. The square root of that is then 2^(36/2) = 2^18.
@johnnyragadoo2414
@johnnyragadoo2414 5 күн бұрын
@@ThreePointOneFou Are you saying that 2^6^2 is not the same as 2^12? Even in this video a^b^c is represented as the same as a^(b*c). Evaluate exponentiation from the bottom up. Otherwise 2^6^2 is 2^36 and not equal to 2^(6*2).
@ThreePointOneFou
@ThreePointOneFou 5 күн бұрын
@@johnnyragadoo2414 Successive exponentiations are supposed to be evaluated from _right_ to _left_ when written horizontally, to reflect the top-down rule that applies to exponentiation. (Ideally, exponentiation wouldn't be written like that, but those are the limits we're stuck with in commentbforums without mathML or similar support.) The problem shown should be evaluated as though it were written 2^(6^(2^(1^(5^9)))).
@johnnyragadoo2414
@johnnyragadoo2414 5 күн бұрын
@@ThreePointOneFou Then 2^6^2^1^5^9 wouldn't equal 2^(6*2*1*5*9). As it shows in the video, a^b^c = a^(b*c). So, which is it? Should a^b^c = a^(b*c)? I think it should.
@ThreePointOneFou
@ThreePointOneFou 5 күн бұрын
Correct, 2^6^2^1^5^9 is not equal to 2^(6*2*1*5*9). And no, a^b^c should be evaluated as a^(b^c). The video does everything correctly, apart from a bit of slightly sloppy writing when showing the rule that (a^b)^c = a^(b*c). When evaluating exponents, the exponent must be fully determined before raising the base to that power-in other words, 6^2^1^5^9 must be calculated _before_ raising 2 to that power. Thus, 2^1^5^9 must be calculated before raising 6 to _that_ power, meaning 1^5^9 must be evaluated before raising 2 to _that_ power, etc. In other words, exponents must be calculated from the top down, or from right to left in horizontal notation.
@eduardpujade5854
@eduardpujade5854 14 күн бұрын
No !!!!!!! Quan fas (1⁵)⁹, dius que és igual a 1 i no és cert !!!!! Tractes l'1 com si fos Base i no ho és -----> és un exponent!!! No és correcta El correcta és V(((((6)²)¹)⁵)⁹)= V6⁹⁰= 6⁴⁵
@thecitchannel2856
@thecitchannel2856 6 күн бұрын
Meh ... took me less than 5 seconds.
@64Rosso
@64Rosso 6 күн бұрын
First learn the basis of math, THEN try and post this video again... correct, please!
@alimetlak
@alimetlak 5 күн бұрын
Wrong solution..the powers should be multiplied an not rooted...andswer is 2^270
@bcl4815
@bcl4815 15 күн бұрын
太吓人了,简单的很:32.
@ashotdjrbashian9606
@ashotdjrbashian9606 16 күн бұрын
Was this olympiad for 4th graders? It is ridiculous to spend 6.5 minutes on this stupid problem
@vollmonm
@vollmonm 16 күн бұрын
2^(0,5*6*2*1*5*9) =2^(270) - i guess - i was wrong and rely bad at math and al those u-tube commies r foking geniuses///
@VitaliyRos
@VitaliyRos 17 күн бұрын
Full error, answer incorrect! This lie
@Howiefaam31459
@Howiefaam31459 6 күн бұрын
Annoying music
@DanDart
@DanDart 23 күн бұрын
Please speak rather than adding useless music, try to verify the source and having something challenging will help people.
@Chessziscrazyifyouareso
@Chessziscrazyifyouareso 15 күн бұрын
Trur❤
@qelmnl
@qelmnl 5 күн бұрын
No, on the contrari, Music is better than talk
@VincentLauria6
@VincentLauria6 6 күн бұрын
Can we PLEASE stop with the common core bullshit? These competitions don’t give time to do all of that extra bullshit
@g.k.6451
@g.k.6451 12 күн бұрын
Its boring. Could have been shortened.
@dhy5342
@dhy5342 23 күн бұрын
It would have been nicer if it came out to 262159
@dimitrijbender7285
@dimitrijbender7285 15 күн бұрын
2^ 18
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