Sister, for Q2. common in two Array, the output is not correct if elements are not distinct in array1. so I think need to add: distinct() as well. Now output correct: public class Intersection { public static void main(String[] args) { int[] arr1 = {1,2,3,4,4,5}; int[] arr2 = {4, 4,5,6, 7}; findIntersection(arr1, arr2); } public static void findIntersection(int[] arr1, int[] arr2){ List intersection = Arrays.stream(arr1).distinct().filter(i-> Arrays.stream(arr2).anyMatch(j-> j == i)).boxed().toList(); System.out.println(intersection); } }

I feel like for the 1st questions we can approach as below if you are a beginner like me: I personally feel the below approach is more logic oriented as it can be understood by anyone and isn't as confusing as shown in video as the video uses so many inbuilt methods. I just learned array yesterday and felt happy for being able to solve it completely by myself haha. Please do suggest me if there's more simpler methods and logical than this one. In the below program, I simply found the smallest array and then again run a loop which neglects the smallest array and goes on to look for another small number. public class Ques { public static void main(String[] args) { // Finding second smallest array int []a= {-100,-20,80,60}; int min1=Integer.MAX_VALUE; int min2=Integer.MAX_VALUE; for(int i=0;i

Hey mam... started learning Java 8 6 months ago from ur given playlist as a beginner and now cracking multiple coding rounds in MNCs. Thanx a lot for that, I have one query if u can pls include in next video - the approach that u have used in reverse array via forEach(Consumer Interface) ,how can we done same for checking integerPalindrome via filter( Predicate).

Yes we need more such questions covered

wow the first one, I would only sort the array and do a "arr[1]" as an answer, but using stream gives a nice touch to it!!

Thanks for creating such videos, would you please create a video continuation of this? This will be very helpful.

Answer for Last Question: int[] numbers = {2, 4, 6, 8}; int except = 4; int res = Arrays.stream(numbers).filter(n -> n != except).reduce(1, (n1, n2) -> n1 * n2); System.out.println(res);

Very nice explaination, I finished the whole playlist in 2 days, meanwhile I was wondering whether I can get the notes and code shown in the videos, it would be really helpful, I have some interviews, will need that for revision. Thanks

thank you mam, the way of explaining is very superb

Thanks mam for provides us such a important content..We will waiting for next part of that video 🤗🎉

I love ur explanation....thank u very much mam... U r helping people like me to rock the interview also To understand the concepts... Clear explanation... Nice voice... Too good.... first time viewing ur Vedios also subscribed 😊😊

reverse a list--- List arr=Arrays.asList(1,2,3,4,5); arr.stream().collect(Collectors.toCollection(LinkedList::new)).descendingIterator().forEachRemaining(System.out::println);

It is nice topic are covered on java 8 features 😊

firts time viewing your vedio best helpfull vedio mam ....i subscribed and like .....and heartly thanku mam

Instead of using available functions explain with logic because HRs only asks for logic

Love you for this video 👌👌👌 what a video 👌👌 waiting for next part

Really so useful ...ur videos r awesome..pls make some professional java courses olayilisy

Thanks alot Mam, could you plz create it's next part covering more such questions?

Nice questions and its solution. Keep up creating videos !

Thank you for making such good video on java8. Can you please write java program on java 8? Find the length of the longest substring with all distinct characters

Good content

Always a big fan. Thanks.

Thanks a lot

Love to watch ur content. It will be more helpful if u provide ur source code for same

Very useful thanks

Thanks

good explanation.

Awesome, waiting for next vh ideo

Your explanation is always awesome mam.. keep rock

great job maam

Absolutely magnificent

Informative Java 8 Interview Series, thanku, mam I think this one is the last video of this Series, not able to find the videos of last 2 questions of this current video.. 1) Remove duplicates preserving order. 2) Product of all elements except current element. Please make video on this if not made because ur logic & explanations really open ups the mind to think in different approach. thanku mam

Tq

Great🎉

Thank u so much for sharing such videos..

Great video

well explained

It's better if you solve them without inbuilt methods As beginning cannot understand the methods directly

Please upload more videos on stream

We need many more questions

Bring more videos for this

Nome of the interviewer will ask you to use pre defined Classes and methods, you need to write the logic specially for freshers

hi, can u please do a video on HashMap custom key ?

Indori Rocks !!!

We can using distinct to remove duplicates.

1 Question ] Answer package z_pracxtice; public class xyzz { public static void main(String[] args) { int arr1[]= {10, 20, 30, 40, 50,50}; int big =0; int sm=0; for(int i=0;i

We can solve this problem using Max heap

When will the next video be posted arrays programming?

Hi, Do you have any video how to debug the program in Java streams? Example: I do operation on stream then filter and then collect to a list.. if there are 1000 records and seems my 40th record is not filtering properly. How can i debug in eclipse with out using peek and in normal debug mode.. because usually we work with objects like employee and want to check either name or id or some other details of it. Can you please create a video for this or if you have any explanation, can you please let know.. looking forward for your response

🙏👍💯

Hi please provide remaining array questions

The approach to Q1 is not the best. Sorting is expensive than searching so a linear search is much better to use.

liked commets

When can we expect the next video ???

👍☺️

Last question Answere: int[] arr = {2, 3, 4, 5}; int[] ints = Arrays.stream(arr). map(i -> Arrays.stream(arr).filter(j -> j != i).reduce(1, (a, b) -> a * b)).toArray();

String[] strings = {"Banana","Apricot","Apple","Strawberry","Mango","Pineapple"}; int maxLength = Arrays.stream(strings).mapToInt(string -> strings.length).max().orElse(0); System.out.println("Length of longest string:" +maxLength); Can you check this one, I'm getting wrong output of 6 instead of 10

Audio not clear

Questions with timing :- Q1 - Given an array of integers, write a java8 program to find the second smallest element - 0:33 Q2 - Given two arrays of integers, write a java8 program to find the common elements between them - 6:31 Q3 - Write a java8 program to reverse an array of integers in-place - 14:02 Q4 - Given an array of strings, write a java8 program to find the length of the longest string - 18:59

This is not for beginners 😅😅 and we can use more simple ways to solve these problems.

Promo'SM ✅

String[] str = new String[]{"Apple","Banana","Apple","Grapes","Banana"}; List stringList = Arrays.stream(str) .collect(Collectors.groupingBy(s -> s, Collectors.counting())) .entrySet().stream() .filter(entry -> entry.getValue() < 2) .map(Map.Entry::getKey) .collect(Collectors.toList()); System.out.println(stringList);//removing duplicates while preserving original order