Question: Molar mass of the hydrocarbon (X) which on ozonolysis consumes one mole of O3 per mole of (X) and gives one mole each of ethanal and propanone is ______ g/mol (Molar mass of C : 12 g/mol, H : 1 g/mol)
Calling all JEE & NEET aspirants! Struggling with Ozonolysis problems in JEE Main 2023 (Paper-1, Q89)? ShreyashChemistry is here to the rescue!
In this video, we'll MASTER this question:
👉Ozonolysis Adventure: We'll explore how a hydrocarbon (X) undergoes ozonolysis, consuming ozone (O3) and breaking down into specific products.
👉Molar Mass Mission: We'll calculate the molar mass of the unknown hydrocarbon (X) based on the given information about its ozonolysis products (ethanal and propanone).
👉Crack the Code: We'll walk you through a step-by-step solution to find the EXACT molar mass (in g/mol) - the answer you need for JEE Main!
ShreyashChemistry - Your one-stop platform for JEE & NEET success! Watch Now!
Download a detailed PDF with extra notes and explanations for this topic in the video description!
Join our Telegram channel, ShreyashChemistry, for more JEE prep & NEET prep resources and discussions:
telegram.openinapp.co/1ppue
JEE | JEE Main | JEE Advanced | NEET | CUET | Chemistry | Organic Chemistry | Hydrocarbons | Alkenes | Ozonolysis | Reductive Ozonolysis | Aldehydes | Ketones | Shreyash Chemistry | Shreyash Sir
#JEEMain #Chemistry #ShreyashChemistry #Ozonolysis #Hydrocarbon #MolarMass #pyq