Jordan Form

Рет қаралды 63,831

Jeffrey Adams

9 жыл бұрын

Пікірлер: 28

@leylaalkan6630 8 жыл бұрын

The only well-explained & sufficient video about Jordan form on youtube. Please, keep making more videos

@NotLegato 5 жыл бұрын

i don't understand why you didn't explain exactly how those 1s are determined.

@michaelj.podlovics2246 6 жыл бұрын

This was a perfect lin. alg. refresher for my controls systems course!

@dmitchell999 8 жыл бұрын

At the moment, this is my favourite video on youtube.

@youtuber_nr3504 3 жыл бұрын

Perfectly explained, thanks a lot!

@andrec.2935 11 ай бұрын

Excellent!

@TheTomas503 5 жыл бұрын

This is my last hope how to pass my linear alg. exams. Thanks !

@thomasrad3880 7 жыл бұрын

Master class teaching right here.

@rohanvb6589 8 жыл бұрын

pretty good; but shouldnt you have mentioned the correlation of selecting jordan blocks based on its dependancy on minimal polynomials?

@MichaelGoodrum 6 жыл бұрын

Thank you for a well explained video where the audio is clear

@furkana.1359 8 жыл бұрын

nice one.Enjoyed and useful

@samario_torres 6 жыл бұрын

why didnt you work an entire example...

@enabeanabanana 5 жыл бұрын

perfectly explained!

@xiaoruizhou694 6 жыл бұрын

Very good explanation！ Thanks

@ebrimakuyateh394 5 жыл бұрын

well explained thank u

@ernestmupenzi4474 5 жыл бұрын

very good

@user-ed9sc5zs1b 5 жыл бұрын

super nice video

@satashreeroy1652 5 жыл бұрын

Could you please explain what you wrote at 17:09 ? How'd you get all zeroes in the diagonal of the matrices? That can only happen when A has only 2s in its diagonal (and in that case it's already diagonizable), but we don't know that, do we

@waseemfrancis1376 5 жыл бұрын

A has 2s in the diagonal for sure because its characteristic polynomial (with out knowing if A is recognizable or not)

@psawyer871 7 жыл бұрын

At 5:02, i don't understand why the dimension of the kernel is 1. can you explain to me more, please?

@Dimitri4416 7 жыл бұрын

He used the rank-nullity theorem - the dimension of the image plus the dimension of the kernel is the size of the matrix (it should be clear dim(Im) (i.e. the rank of A) is 1)

@matthewfairfield9354 5 жыл бұрын

Thanks so much

@bandar1606 3 жыл бұрын

10:17 It seems S matrix is incorrect. Performing S^-1 * A * S doesn't yield the result you've shown.

@neckudart272 6 жыл бұрын

All the examples are incomplete , just what's the point from that .

@TheDelcin 5 жыл бұрын

Not for beginners obviously. Read Gilbert Strang

@ink2467 5 жыл бұрын

@@TheDelcin actually it's too much for beginners: he doesn't explain the theorem itself, WHY can we just have ones on the superdiagonal and zeroes everywhere else. He just quickly described what Jordan form looks like