Lecture - 4 Heat Conduction

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Lecture - 4 Heat Conduction - 1

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Lecture Series on Heat and Mass Transfer by Prof. S.P.Sukhatme and Prof. U.N.Gaitonde, Department of Mechanical Engineering, IIT Bombay. For more details on NPTEL visit nptel.iitm.ac.in

Пікірлер: 105

@HoldemPro09 11 жыл бұрын

This guy is so much easier to listen to than my heat transfer professor

@sohamkulkarni7207 3 жыл бұрын

There was a time when you used to get admission to MIT with just a recommendation letter from this guy

@prateekshivhare7245 3 жыл бұрын

kya baat kr rhe ho bhai

@swagotosurjodutta7341 3 жыл бұрын

@@prateekshivhare7245 doctorate overseas krne ke liye, college ke experienced professors ka recommendation letter lagta h.

@tequilajoe518 3 жыл бұрын

He did his PhD from MIT in the year 1964.

@aryanraval110 Жыл бұрын

@@tequilajoe518 does he still teach?

@sayvishhvlogs186 Жыл бұрын

@@aryanraval110 he is just God Level

@RITESHKUMAR-ou5wu 5 жыл бұрын

Watch at 1.25x speed...it's perfect

@nishant9478nl 3 жыл бұрын

I did at 2x

@periyasamym1896 4 жыл бұрын

i feel fulfilled in all categary of your lecture sir. My mind experienced that your lecture is a benchmark for HMT. thank you sir

@divyarao9020 4 жыл бұрын

Thankyou very much sir! The way the subject is taught here clears concept from basic like no other!

@Modernman10000 11 жыл бұрын

thank you , you make it so easy.from algeria

@Skeptik75102 2 жыл бұрын

In thermal Resistance of an infinite Composite Slab we used t1-tw1 for first case while applying Newton law of cooling but according to the law it's Tw-tf so why we used t1-tw1 here ??

@vishalroadways7700 8 жыл бұрын

please give us content covered in the video into discription (i.e. name of the topics)

@SauravParle 8 жыл бұрын

watch at 1.5x speed

@GENIUSAMI100 5 жыл бұрын

already watching at 2x :D

@Pandit.Kamshi 8 жыл бұрын

We want better resolution like 480p and above for more picture clarity

@chaosui3169 8 жыл бұрын

that would be great

@TheSharmaFilms 7 жыл бұрын

Bajoy kamshi donate a nice camera to the IITB

@harshtiwari491 2 жыл бұрын

Sir I understood cylindrical heat conduction very well.. But the area is missing here in overall heat transfer coefficient.Anyone who can solve my doubt is welcome here

@23youwatch 12 жыл бұрын

amazing! Dr. S! U the man!

@7oota2007 15 жыл бұрын

THANK YOU SO MUCH . that helped alot. ill be watching all of ur lecturs

@jeet1402 11 жыл бұрын

thank you sir for making conduction derivations so easy

@naikganesh5677 Жыл бұрын

k = 0.58 W/mK here thermal conductivity is in K and T is taken in degree celsius?

@maxlav742 6 жыл бұрын

!thank you NPTEL and prof. S.P.Sukhatme I own your lactures at least 2 university courses keep up the good work!

@RizwanAbdul29 5 жыл бұрын

How did you put 1/Uri for overall heat transfer coefficient for hollow cylinder, it must be simply Uri isn't? Please tell me sir.. at 50:30

@SunilYadav-ks7ww 6 жыл бұрын

Great talent to express knowledge

@shreejishah7256 8 жыл бұрын

thank you very much sir for simply undesting of conduction as easy as possible and plzz yarr improve quality of video 420p or more plzz..

@aaminahrabaab635 4 жыл бұрын

Sir I would like to know how we arrived at the thermal resistance (1/hA) for heat flow from surface to fluid? From Newton's law of cooling.

@doinggood3564 4 жыл бұрын

Generally , by MOLECULAR TRANSPORT EQUATION RATE = DRIVING FORCE / RESISTANCE for our case of heat flow from wall to fluid...(newton's law of cooling) is q = h A ( T of wall - T of fluid ) 《1》 Here, DRIVING FORCE = temperature difference RATE = q We want RESISTANCE to heat flow.... Then RESISTANCE = DRIVING FORCE / RATE.... by 《1》 1/ hA = temp diff / q Therefore, we get R = 1 /hA...

@SPravinth 2 жыл бұрын

Sir i think you have missed the unit conversion from cm to meter and celsius to kelvin while substituting the values of temperature and radial distances @21:56... Since the thermal conductivity is in w/mK....

@anandpanchal5717 7 жыл бұрын

Better if available in good quality 480 or 720p

@dynamo-gaming4339 6 жыл бұрын

sir anyone please help,,,if q is same every where then how we get two temperatures at two ends i.e, T1 and T2

@hafed404 13 жыл бұрын

THANKYOU VERY VERY VERY SO MUCH . to helped me alot ,and the great explanation . I will be watching all of your lecturs

@Manish_saroha 3 жыл бұрын

watching in 2021, better than online classes of any institution

@asadali-ht4gr 7 жыл бұрын

Pure concepts... Thank you Sir.

@manoj22232 9 жыл бұрын

thank u sir.. this video was very helpful

@tanvirahamed9432 9 жыл бұрын

thanks sir.. this video was very helpful my amie engineering

@AniketKumar-wo5te 5 жыл бұрын

Professor, I think you forget to convert the given temperature unit into Kelvin. Because, K (thermal conductivity ) is in Kelvin as per the question.

@shubhamkumarsingh7371 5 жыл бұрын

It's temperature difference, so not a problem

@ThabangSelota 12 жыл бұрын

wow this is awesome, i may not attend lectures anymore...lol.

@purushothamtheegala 13 жыл бұрын

THANKYOU VERY VERY VERY SO MUCH but i want some value that is what is lenth of the hollow sphere 2 PI L K --------L?

@-Shabareeshku 2 жыл бұрын

How can I find that q in problem Is there any length value

@strugglingshorts6760 3 жыл бұрын

Sir my question is why heat flows normal to the surface....

@adityaanand5031 3 жыл бұрын

Because we are talking about temperature gradient in only one direction. Otherwise heat can flow in any direction.

@NUPUR-t3e 2 жыл бұрын

Good question, Because as soon as heat is conducted there is net transport of molecular kinetic energy along normal direction in a material from surface....So it is always normal to the isothermal planes so that temperature gradient forms to propagate it. It may be 2 or 3 dimensional depends upon the combined effect of thermal conductivity & temperature gradients. Though you apply the heat flux from any direction but at or from interface boundary it flows normally..... The fundamental law of transfer under potential gradient is always transport normally though the flux may or may not aligned with normal but as soon as it crosses the interface of the domain under study there is the flux normal to the interface...... Then be it - Darcy's law of - Fluid flow under pressure difference, Ohm's law of current flow under voltage difference, Fourier's law of this heat transfer under temperature gradient & Fick's law of mass flux transport under concentration gradient..... When there is transport flux across the interface, it always normally in or out of it.......

@Rohit104-s7b 3 ай бұрын

Thank you sir 🙏

@gagan...2846 5 жыл бұрын

Thanks sir ,lecture is very good

@surendraalapati5769 4 жыл бұрын

for sphere problem, Iam getting 437.3 w instead of 4.37 w .. can you help me anyone?

@g.nirmalkumar5773 4 жыл бұрын

Convert Cm to Meters

@murali21968 11 жыл бұрын

nice lecture

@manvendrapratap7062 11 жыл бұрын

thanks a lot

@jatinkaul5488 6 жыл бұрын

wow.. u are great

@jaypatelpatel7373 5 жыл бұрын

THANKU SIR FOR YOUR LECTURES

@sebamtorres 14 жыл бұрын

great explanation. thank you very much

@shyamsunder8133 8 жыл бұрын

for hallow sphere whats the formula.and wher the l gone in dat formula give me the answer sir

@DevKartikSharma 8 жыл бұрын

+Shyam Sunder formula you get is q= -k(T2-T1) x ((4* pi * r1r2)/(r2-r1)) you get this from the expression of fourier's heat flow of conduction q x integrating from r1 to r2(1/(4 pi r^2))= -k x integrating from T1 to T2(dT)

@shyamsunder8133 8 жыл бұрын

thanx buddy...

@DevKartikSharma 8 жыл бұрын

No problem. All the best for hmt

@jaydeepn7260 10 жыл бұрын

very nice... thank you sir ...!!!

@suryakanthjadhav2733 8 жыл бұрын

no audio what to do ?? please help me...

@TheSharmaFilms 7 жыл бұрын

Suryakanth jadhav turn on your speaker

@excitedinspired9939 7 жыл бұрын

some lectures are not audible in my computer speaker but its ok on the smartphones.

@murali21968 11 жыл бұрын

very nice lecture

@1Bored3 12 жыл бұрын

Is this in a playlist? I can't seem to find it :<

@mro2038 5 жыл бұрын

I was about to give you the link for the playlist, but then i checked the date of the comment its 7yrs old XD.

@SUPERMAN-ef8gh 4 жыл бұрын

@@mro2038 😂😂😂😂😂ab tak to iski shadi bhi ho gyi hogi

@Rajnishkumar-fq4pg 4 жыл бұрын

@@SUPERMAN-ef8gh 2 3 bache bhi ho gye honge

@abhijeetdewangan6933 4 жыл бұрын

now it's 8 years old comment.

@pythongaming1775 3 жыл бұрын

@@SUPERMAN-ef8gh 😂

@adarshgupta9272 9 жыл бұрын

gr8 video sir

@SunilYadav-ks7ww 6 жыл бұрын

Great

@dynamo-gaming4339 6 жыл бұрын

can anyone tell the expression of Ur3

@ItsEshan392 6 жыл бұрын

i want to know that too

@AchiragChiragg 5 жыл бұрын

@@ItsEshan392 just multiply the Right hand side by r3/r1. And you'll get it in terms of Ur3

@pratap4net 5 жыл бұрын

thank you sir

@gagan...2846 5 жыл бұрын

I watch it on 2x speed cool

@shanmukh111 11 жыл бұрын

i'm getting 8.75 instead of 4.35 @24:54

@ameya2310 6 жыл бұрын

dia to radii

@shreyastaware 5 жыл бұрын

@@ameya2310 Thanks

@alanoropeza4761 5 жыл бұрын

@@shreyastaware jajajaja thanks XD

@vloggie4u 5 жыл бұрын

Thnx sir

@anandmaurya3545 6 жыл бұрын

Is conduction is possible in fluids.

@moalotaibi6002 6 жыл бұрын

Yes, Conduction is possible in Fluids in case that fluids are stationary such as hot water in a cup.

@NUPUR-t3e 2 жыл бұрын

Yes. But following conditions - 1. Fluids are completely at rest & no relative motion exists either relative to any solid interface or within its own layers. 2. Convective heat transfer coefficient is very low & also radiation effects are such that they themselves are acting like non participating & solid to solid interface gap is very small. 3. They should have at least sufficient thermal conductivity for heat to pass or conduct through them. Their area of exposure should also be small. All these parameter should give overall trivial effect of some finite but very low thermal resistance. Otherwise, instead radiation will dominate.