LINEAR APPROXIMATION AND DIFFERENTIALS TO APPROXIMATE SQRT(0.9) - how to use linearization (Part 2)

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Jake's Math Lessons

Jake's Math Lessons

4 жыл бұрын

Linearization or the linear approximation of a function can be used to estimate the output of a function when finding its exact value is difficult. This has a handful of different useful applications. In this video I'll show you how to find the linearization of a function at a point and how to apply it to estimate more challenging values near that point.
In order to find the linearization of a given function at a given point, it will be very similar to finding the equation of a tangent line. With linearization, we can use the formula for the linearization of a function, denoted L(x).
In this video I'll show you how to find the linearization of f(x)=sqrt(x+1) at the point a=0. This means that we will be coming up with a linear function that goes through the point that lies on the function at a=0 and has the same slope as the function f(x)=sqrt(x+1) at that point. Then we will use this linear approximation to approximate the value of sqrt(0.9).
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Пікірлер: 11
@emreozturk305
@emreozturk305 3 жыл бұрын
Thanks man
@JakesMathLessons
@JakesMathLessons 3 жыл бұрын
You’re welcome!
@Salted11
@Salted11 Жыл бұрын
Thanks man!
@JakesMathLessons
@JakesMathLessons Жыл бұрын
Of course!
@davidmaheshe4297
@davidmaheshe4297 2 жыл бұрын
please illurate what you are doing by graphing functions
@goth6638
@goth6638 3 жыл бұрын
Sir , isn't the square route of a negative number invalid ? Then how are we evaluating -0.1
@JakesMathLessons
@JakesMathLessons 3 жыл бұрын
Keep in mind, we’re taking the square root of (x+1). So when we have x=-0.1 you’re actually taking the square root of (-0.1+1) which is 0.9, a positive number!
@goth6638
@goth6638 3 жыл бұрын
@@JakesMathLessons thank you !
@JakesMathLessons
@JakesMathLessons 3 жыл бұрын
@@goth6638 you’re welcome!
@shaunaugeri8200
@shaunaugeri8200 Жыл бұрын
I can do all of this but I don't understand WHERE -.1 is even coming from. How did we arrive at -.1?
@shaunaugeri8200
@shaunaugeri8200 Жыл бұрын
I know we’re doing .9-1 to get -.1 but why would we do that? The formula specifically states (x-a) for the last part and that holds true for every “a” EXCEPT when a=0. Seems like we shouldn’t have to do .99=1-x and solve. But we do and it’s incredibly frustrating because every problem you find with a=0 it’s just an assumed step and it’s totally not intuitive
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