Thanks so much! A lot of teachers/professors fail to go over these more complicated questions and the line of reasoning behind answering them. I really do appreciate the time you spent making this video!

I am teaching myself A levels chemistry at home, I don't go to any college, and your videos are the base of my learning, thank you.

I wonder who pressed The dislike button up there😠 really!!!. Fuckn love how you teach👌

Kaacidoversalt, fucking love that.

I don't know what I would do without this channel so much immense respect and gratitude for you sir!

I'm in Gen Chem 2 as a Bio major and chemistry is so intimidating for me because of the calculations, but you helped a lot. My text book uses the pH=pKa + log(base)/(acid) equation but your version helped a lot better. It was easier for me to grasp - I practiced several problems and got the right answer every time. Exam tomorrow & I'm more confident. THANKS!

Just wanted to say thank you soo much for taking time out of your day to make these awesome videos! Theyve been super helpful over the last 2 years! Thank you!

Really liked your lessons, thank you very much! A few things that I would like to notice is that cm^3 is used mostly for solids (metals, soil etc); for liquids ml is mostly used - which is the same size. Another thing is that the 45ml volume is not certain that it will be the final volume of the two mixed solutions but certainly the final volume is the final volume so this could not be stated by using the moles for a constant not known exactly volume. I am trying to learn about buffer solutions and your videos are very useful! Thank you again!

Thanks very much!!! My own teacher didn’t explain anything about buffers, not even a single thing! I really appreciate that 🙏🏻

Thankyou! Such a great vid, will be able to answer buffer q's now! :)

I love you man, thanks for these videos they really do help us!

THANK YOU SO MUCH. THIS IS GREAT!! KEEP UP THE GOOD WORK

Thank youuuu!!!!! You probably just saved my chemistry grade

MaChemGuy for Oscar! you are a legend thank you :)

Amazing video and great explanation! Thanks

Im going on holiday....Kaacid over salt!!!!!!!!! Whooop loool i got that question right... Cant thank you enough sir! ☺️

these videos actually make me like chemistry!

Thankyou so so so much!!! So helpful

And I finally understand what I have to learn by watching your video.☺️☺️☺️.Short and full of informative video as well as simple explanation.I am glad that I had came across your channel yesterday and it saves my life.Can't say how much I appreciate for your video.

this help my exam are in week.thanks

Explained 10000x better than my chemistry teacher, many thanks

@MaChemGuy Do you source your examples from the CGP textbook, and if so, would you recommend them for revision notes etc.

Thank you so much for your awesome videos. You have an amazing way of teaching. You don't only cover the basic content but you also go over exam style questions. Things I thought I couldn't do has been made easy with your videos so thank you SO much. :)

very helpful, thanks :)

thank you sir,very helpful

Very helpful TY

Thank you, thank you, thank you,

sir, is the mol remaining which was 0.0165 the mols at equilibrium for the acid?

Thanks for this video, it Really helped

Very nice, simplfied how to do a hard buffer calc

I like the Holiday to KaCidoverSalt bit - very good, can I say though that you are harbouring a misconception regarding [H+] and [A-] on your introductory 'slide'? They are in EQUAL concentration until EXTRA "A-" is ADDED. It's not possible for them to be in different concentrations just as a result of dissolving an acid regardless of how strong or weak it is because in order to form H+, there must have also been A- formed!!!

helps a lot

ever heard of the Henderson-hasselbalch equation? It works a lot faster than this trick you're doing. Still great video, thank you!

Do you not have to subtract A- from HA to find new moles of HA as there this is partial neutralisation?

Thanks.

thank you sooo much for all your useful videos, you explain everything so clearly! forever grateful :))

i love you man

Is there a video for a question similar to 2015 F325 where it asked the PH of the new buffer on addition of Magnesium? I fail to understand why 0.25 moles of Mg added would mean the conc. of acid to decrease by 0.5. Thanks, loved your videos.

shoulnt it be salt=h+/ka multiplied by acid. This is according to rearranging equations. And if u wanna find out n in pv=nrt, it is n=pv/rt. What the hell grh pls respond

Why is the optimum pH for the H2CO3/HCO3- buffer 6.36 when the pH of blood is 7.4?

i calculated the amounts of salt and acid and put them into the h+ equation without subtracting salt from the acid, yet i still got the right pH in the end? any idea why? :/

it was really good but one req please put your camera at some height the ques were not visible properly.

Hi you said the moles of sodium ethanoate is 0.0015. How did you come to this ?

At 8:50 why do you divide by 0.045? I would have thought you divided the moles of ch3ch2cooh by 0.030 as that is what it's volume is. Thanks a lot for all your videos they're so helpful

so why is the acid dissociation constant for the weak acid 1.6 x10 -4, where do you get that from?

In the second question, there was no need to convert number of moles of acid and salt to concentrations since both exist in same solution.

For Q3 are you not supposed to do 0.1mol/0.5dm^3 to get the concentration as you have just used the moles but the square brackets means concentration. Hope that made sense!!!

In my Chemistry class, it's taught to do the ICE Table before finding the acid for weak acids. But I see you didn't do this, is the ICE table required?

I love you man

Isnt the acid concentration on the last question suppose to be 0.2 not 0.1, since 0.1 is just the mol of the acid and not the concentration.

It gets always talked about the addition of a strong acid or strong base to a buffer... my question would be how to calculate the ph with the addition of a weak acid? Lets say the addition of acetic acid to a phosphate buffer

Why can't we calculate [H+] using the square root Ka x [HA] method? If its in equilibrium, isn't it a weak acid?

For Q2, why is [CH3CH2COOH]=0.37 and not 0.6?

why not use henderson hasslebach?

rubbish science Teachers need to take a leaf out of your book on how to teach effectively

what do you mean kaacidoversalt is not a place. #liar

Surely the [A-] is not a salt, it's just the negative ion from the dissociation of salts or original acid? The salt would surely be the combination of some kind of metal ion and the conjugate base of the dissociated acid? Confused me a bit. Hate to sound like a nerdy twat criticising.