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Math Olympiad | A Beautiful Exponential Problem | VIJAY Maths

  Рет қаралды 1,513

VIJAY Maths

VIJAY Maths

Ай бұрын

#exponentialproblems #matholympiad
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Пікірлер: 15
@crazyindianvines1472
@crazyindianvines1472 Ай бұрын
Nicely explained
@superiorlyrics8326
@superiorlyrics8326 Ай бұрын
👏👏👏
@sumit-mn6ys
@sumit-mn6ys Ай бұрын
Amazing sir👍
@Brijpal-lt2qv
@Brijpal-lt2qv Ай бұрын
nice solution Sir ji
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Thank you
@Rocio62154
@Rocio62154 Ай бұрын
SENSATIONAL!
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Thank you
@walterwen2975
@walterwen2975 Ай бұрын
3^m - 2^m = 65 = (5)(13) = (9 - 4)(9 + 4) = 9^2 - 4^2 = 3^4 - 2^4; m = 4
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Excellent 👌
@Govardhan-o4o
@Govardhan-o4o Ай бұрын
I just assumed that m=4
@ezzatabdo5027
@ezzatabdo5027 Ай бұрын
Also by state try and error, 3 powered m = 2 powered m +65 to attain the equaled by L. H. S = R. H. S value 81must be m=4 ,thanks sir
@Harshal378
@Harshal378 Ай бұрын
I simply brute forced, by thinking what 3 powered exponent is closer to the 65. that came to be 3^4=81 and 2^4=16. 81-16=65. so, m=4. That's my mediocre way to solve it. Great content, keep making!!
@jodha2381
@jodha2381 Ай бұрын
Is there a proper solution to this as this takes longer than just directly to power and solve, specifically for very complex problem
@RealQinnMalloryu4
@RealQinnMalloryu4 Ай бұрын
65/3=21.2 65/2=31.3 {21.2+31.3}= 52.5 21^31.3^2 3^7^31^1.3^2 1^11^1.3^2 3^2 (m ➖ 3 m+2)
@tylerd5924
@tylerd5924 Ай бұрын
🤣🤣🤣🤣
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