Math Olympiad | A Beautiful Exponential Problem | VIJAY Maths

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VIJAY Maths

VIJAY Maths

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Пікірлер: 7
@shehzadsingh3411
@shehzadsingh3411 Ай бұрын
just eyeballing it we can see that 2016 can be written as 2048 - 32 => 2^11 - 2^5. Therefore we can say that a = 11 and b = 5
@Danieswors
@Danieswors Ай бұрын
(a,b) = 11,5
@user-mq2cj2ff4z
@user-mq2cj2ff4z Ай бұрын
(2の11乗)=2048,(2の5乗)=32……よって,a=11,b=5となる! This question is very very easy !
@ajayyagnamurthy5796
@ajayyagnamurthy5796 Ай бұрын
2016 ÷ 32 is 63. 32 is 2^5 63 = 64-1 = 2^6 - 1 2^a - 2^b assuming a > b 2^b (2^(a-b) -1) 2^5(2^6-1)=2016 Hence b = 5 and a=11
@murdock5537
@murdock5537 Ай бұрын
a = 11, b = 5 - a bit complicated, Sir.
@RealQinnMalloryu4
@RealQinnMalloryu4 Ай бұрын
2016/2=108 2016/2= 108 {108 ➖ 108}=0
@lolsamet9225
@lolsamet9225 Ай бұрын
2016/2 = 1008 2016/2 = 1008 {1008 - 1008} = 0 correction
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