No video

Math Olympiad | A Nice Algebra Problem | How to solve for 'X' and 'Y' in this problem?

  Рет қаралды 77,446

Learncommunolizer

Learncommunolizer

Күн бұрын

Hello My Dear Family😍😍😍
I hope you all are well 🤗🤗🤗
If you like this video about
How to solve this math problem
please Like & Subscribe my channel as it helps me alot ,🙏🙏🙏🙏

Пікірлер: 43
@johnmccullagh2705
@johnmccullagh2705 4 ай бұрын
Good solid algebra. Yes a bit slow, but for someone like myself who has not done much serious math since student days (half a century ago now), better to include all the steps rather than skip some. And yes, the obvious real solutions from simple inspection are x=2, y=1 and x=1, y=2, however that's not the point of the exercise. Whether it's a good Math Olympiad problem or not, I'm afraid I can't judge.
@TWJRPGGamming
@TWJRPGGamming 7 ай бұрын
x=2.y=1 x=1,y=2
@neel333neel
@neel333neel 3 ай бұрын
thanks
@learncommunolizer
@learncommunolizer 3 ай бұрын
You're welcome!
@KipIngram
@KipIngram 4 ай бұрын
By "looking at it and thinking for a second," x=2, y=1 and x=1, y=2 are solutions.
@catiaman208
@catiaman208 6 ай бұрын
this has sipleset way since the numbers of X AND Ymyst be integer X+Y=3 RESULT X=1 and Y=2 X5+y5=1+2^5=1+32=33
@ryanchiang9587
@ryanchiang9587 6 ай бұрын
x = 2, y = 1 or vice cersa
@user-nd7th3hy4l
@user-nd7th3hy4l 2 ай бұрын
(1;2) (2;1)
@rafielmesaias
@rafielmesaias 5 ай бұрын
We have an equation of grade 5. But you have just four roots or solutions por x and y
@GFlCh
@GFlCh 4 ай бұрын
While it might be nice to see how to work out another solution, it's possible any additional solution would be extraneous, or a duplicate of an existing solution. But most importantly, any valid solution for the problem as a whole, has to work in both equations, and another solution to the "x⁵ + y⁵=33" equation, if it exists, might not work in the "x + y = 3" equation.
@user-dq3uh6ee5w
@user-dq3uh6ee5w 3 ай бұрын
Such system has 5 solutions or less.
@sudarshandutta2498
@sudarshandutta2498 2 ай бұрын
X= 2/1, Y=2/1.
@user-dq3uh6ee5w
@user-dq3uh6ee5w 3 ай бұрын
(1, 2), (2, 1). They €R².
@prayitsmg7086
@prayitsmg7086 6 ай бұрын
X = 1 , Y = 2 or X = 2 , Y = 1
@arturmadatyan4892
@arturmadatyan4892 6 ай бұрын
Очень простое уровнение, почему так мучается?
@user-ye6go4ft7q
@user-ye6go4ft7q 5 ай бұрын
Надо немножко подумать,потом мучатся,точно !!!
@heniwatisetiono6995
@heniwatisetiono6995 7 ай бұрын
x=1, y=2 or x=2, y=1
@ArashHormozi-xx3mu
@ArashHormozi-xx3mu 6 ай бұрын
X:2 y:1 or x:1 y:2
@guyhoghton399
@guyhoghton399 7 ай бұрын
You can use the identity _uₘ₊ₙ = uₘuₙ - uₘ₋ₙ(xy)ⁿ_ where _uₙ = xⁿ + yⁿ_ Thus: _u₀ = 2, u₁ = 3, u₅ = 33_ _u₂ = u₁² - u₀(xy)¹ = 9 - 2xy_ _u₃ = u₂u₁ - u₁(xy)¹ = 3(9 - 2xy) - 3xy = 27 - 9xy_ _u₅ = 33 = u₃u₂ - u₁(xy)² = (9 - 2xy)(27 - 9xy) - 3(xy)²_ ∴ _243 - 135xy + 15(xy)² = 33_ ⇒ _(xy)² - 9xy + 14 = 0_ ⇒ _(xy - 2)(xy - 7) = 0_ ∴ _xy = 2_ or _7_ Note that _x_ and _y_ are the roots of _t² - (x + y)t + xy = 0_ Case (i): _xy = 2_ _t² - 3t + 2 = 0_ ⇒ _(t - 1)(t - 2) = 0_ ∴ _x, y = 1, 2_ in either order. Case (ii): _xy = 7_ _t² - 3t + 7 = 0_ ⇒ _t = ½[3 ± √(9 - 28)]_ ∴ _x, y = ½(3 + √19), ½(3 - √19)_ in either order.
@Verdiw
@Verdiw 7 ай бұрын
I graph it in demos , only 2 real sol Edit : Sadly at the last part you messed up 9-28 is -19 not 19 so 2 complex roots
@wongkienloon
@wongkienloon 5 ай бұрын
33+3+33+3=72 66+6=72 (66/72) + (6/72)=1=100%
@user-nd7th3hy4l
@user-nd7th3hy4l 7 ай бұрын
X=2 et Y=1
@neilmccafferty5886
@neilmccafferty5886 7 ай бұрын
you can see it must be 2 and 1 immediately.
@user-lf1bm8fm2g
@user-lf1bm8fm2g 7 ай бұрын
Комплексные корни не интересны.
@neilmccafferty5886
@neilmccafferty5886 7 ай бұрын
@@user-lf1bm8fm2g has to be integers, both greater than 1. simple.
@Verdiw
@Verdiw 7 ай бұрын
@@neilmccafferty5886Doesn’t need to be integer
@user-cp5wu5pg1o
@user-cp5wu5pg1o 3 ай бұрын
Это же устно решается, сразу в глаза бросается, что х=1, у=2 или х=2, у=1.
@user-dq3uh6ee5w
@user-dq3uh6ee5w 3 ай бұрын
Hо система может иметь др. решения.
@is7728
@is7728 7 ай бұрын
Can anyone explain why there are only 4 roots, not 5?
@Verdiw
@Verdiw 7 ай бұрын
An degree n equation doesn’t need to have n distinct root , some can be the same so the amount of root is not more than n
@is7728
@is7728 7 ай бұрын
@@Verdiw I know that so which one is the double root?🌲
@nemesiochupaca5024
@nemesiochupaca5024 6 ай бұрын
Porque si sustituyes y=3-x Te va a quedar x^5+(3-x)^5-33=0 y el término quíntico se irá, quedando un polinomio de grado 4
@markterribile6948
@markterribile6948 6 ай бұрын
Who is your audience? Your audience is people who can appreciate and learn what you are showing them. Such people must have mastered high school algebra, and have presumably mastered grade school arithmetic, preparing them to learn the more advanced techniques and principles you are showing them. They--we--don't need to see basic numerical division belabored. They--we--don't need the detailed steps of factoring a quadratic. With the factors given, we need about three seconds to verify them, then we can move on. The value in these solutions is the overall scheme, recognizing the larger patterns that we can use to pry the problem apart. But you bury those steps in the minutia that we have already mastered, making it hard to find the precious grains of gold mixed with the dross of first year algebra and fourth grade arithmetic. These are brilliant solutions. The presentations would be so much better if you demonstrated the brilliance and moved routinely through the routine mechanics.
@calcnoon
@calcnoon 6 ай бұрын
・・これを日本の大学入試は 5分以内で全てやらにゃあかん。 このスピードでは既に不合格。
@user-wu6jj5no7k
@user-wu6jj5no7k 5 ай бұрын
Supposed to be 5 roots
@CrYou575
@CrYou575 4 ай бұрын
If you set x = 3-y using equation 2 then the highest term of x^5 is - y^5, which cancels out with y^5 in equation 1. This reduces the problem to solving a quartic and results in four roots.
@user-dq3uh6ee5w
@user-dq3uh6ee5w 3 ай бұрын
5 or less.
@supermanusa4828
@supermanusa4828 5 ай бұрын
X^5 + Y^5 # (X + Y)^5
@user-jp2ow1cj1l
@user-jp2ow1cj1l 7 ай бұрын
Х=1, У=2 ; У=2, Х=1.🙉🙉🙉🙉🙉
@williammarshal4043
@williammarshal4043 6 ай бұрын
Evaluate before doing all of your shit. If x+y = integers. and x⁵+y⁵= integer then x and y is integer then evaluate b²-4ac, if it's negative, stop. No point of continuing, i^odd integers. Will always has I as result.
@edwardwang7929
@edwardwang7929 7 ай бұрын
kzfaq.info/get/bejne/bd6kp7Wappy-hpc.html
@MarcelCox1
@MarcelCox1 6 ай бұрын
Sorry, but I find your video disappointing for 3 reasons: 1. You did not specify in which domain you are solving, integers? real numbers? complex numbers?. You solved for complex, but you did not specify in advance. In math alympiads, problems are always specified more precisely. You omitted important information. This is an error often commited by a number of people doing this kind of videos, and I find it hugly annoying. 2. Your solution is correct but the problem can be solved more easily. In this kind of problems, there are often more efficient approaches than the brute force method. The colculations get easier when you realise that that x5+x5=(x+y)(x4-x3y+x2y2-xy3+y4) and continue from that. You then only need 4th and second powers of (x+y) which makes the fomulas a little bit simpler and thus less error prone. 3. This comment is mino: state your sources. Like xxx math olympiad problem from yyyy where xxx is the orangisation/country or whatever and dddd is the year. For poitn 3, I have the impression that many youtubers just copy the problems from other youtube videos as while there are so many interessing math olympiad problems, you oftend find the same problems over and over again.
A Nice Algebra Problem. | X=?
15:38
Learncommunolizer
Рет қаралды 16 М.
China | Can you solve this ? | A Nice Math Olympiad Algebra Problem | X=?
15:35
这是王子儿子吗
00:27
落魄的王子
Рет қаралды 20 МЛН
Smart Sigma Kid #funny #sigma #comedy
00:40
CRAZY GREAPA
Рет қаралды 33 МЛН
Russia | Math Olympiad Question | You should know this trick!!
8:01
Russia math Olympiad | Math Olympiad International For Russians
12:02
A Nice Algebra Equation | Math Olympiad Problem
16:42
Learncommunolizer
Рет қаралды 114 М.
China | Can you solve this ? | Math Olympiad | X=?
12:26
Learncommunolizer
Рет қаралды 19 М.
Japanese | Can you solve this ? | A Nice Olympiad Algebra Problem
18:43
Learncommunolizer
Рет қаралды 23 М.
Nice Olympiad Math | x^2-x^3=12  | Nice Math Olympiad Solution
15:05
OnlineMaths TV
Рет қаралды 1,3 МЛН
A Nice Math Problem | How to solve for X in this Olympiad Problem ?
16:31
Learncommunolizer
Рет қаралды 29 М.
这是王子儿子吗
00:27
落魄的王子
Рет қаралды 20 МЛН