Math Olympiad | A Nice Algebra Problem

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Күн бұрын

Math Olympiad | A Nice Algebra Problem
Welcome to our latest math challenge video! In this episode, we tackle a fascinating algebra problem from the Math Olympiad. This problem is test for algebraic skills and problem-solving abilities. Whether you're preparing for a math competition or simply love solving math problems, this video is for you!
Join us as we break down the problem step by step and explore different strategies to find the solution. Don't forget to pause the video and try solving it on your own before watching the solution.
If you enjoy this video, please like, comment, and subscribe for more math challenges and Olympiad preparation content!
Topics covered:
Math Olympiad
Math Olympiad Preparation
Simplification
Exponents
Expressions
An Algebra Challenge
Olympiad
Algebraic identities
Algebraic manipulations
Properties of exponents
Substitutions
Radicals
Math Tutorial
Problem solving
Timestamps:
0:00 Introduction
0:20 Substitution
3:25 Algebraic identities
6:50 Simplifying expression
9:10 Answer
Time-stamps:
00:00 Introduction
01:50 Exponent laws
04:40 Algebraic identities
07:42 Evaluating expressions
13:24 Answer
Additional Resources:
• Thailand Math Olympiad...
• A Nice Algebra Simplif...
• Chinese | Math Olympia...
• A Nice Simplification ...
#matholympiad #algebrachallenge #mathskills #problemsolving #simplification #algebra #learnmaths #mathtutorial #math
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Пікірлер: 6

@user-kp2rd5qv8g 27 күн бұрын

Let a = sort(5/24) and b= 1/2(1/sqrt(2) - 1/sqrt(3)). The the expression to be evaluated is N=(a+b)^4 + (a-b)^4 = 2[(a^2+b^2)^2 +4a^2 b^2. (a^2+b^2)^2 = 31/144 -(5 sqrt(6))/72 and 4a^2b^2=25/144- (5sqrt(6))/72. Thus, N = 1/18[14 -5 sqrt(6)].

@RajeshKumar-wu7ox 27 күн бұрын

(199-80√6)/288

@kassuskassus6263 27 күн бұрын

(56 - 11sqrt(6)) / 72

@user-ny6jf9is3t 27 күн бұрын

(14-5×ριζα6)/18

@RealQinnMalloryu4 27 күн бұрын

(20/96+{(1)^2/*8)^2 ➖ (1)^2/(12)^4 }= {1/64 ➖ 1/244} ={0+0 ➖}/180.=1/180 {20/96+1/180}=21/276 =10.66 2^5.6^11 2^1.6^11^1 2^1.61^1 2^1.3^2^1^1 1^1.3^2 3^2 (x ➖ 3x+2). (1)^2/(24)^4 = 1/1152{ 1+1 ➖/8+8 ➖ +1+1 ➖/12+12 ➖} =4/40 {1/1152 ➖ 4/40} =3/1112 =37.2 37^1.2^1 1^1 .2^1 2^1(x ➖ 2x+1)

@RajeshKumar-wu7ox 27 күн бұрын

0.0105584