Math Olympiad | A Nice Exponential Problem | EasyMaths

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EasyMaths

EasyMaths

7 күн бұрын

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Пікірлер: 3
@Ipernova9
@Ipernova9 3 күн бұрын
we can also break the exponent into 3/2×3/2...and then do 2 successive breakdowns?
@Ipernova9
@Ipernova9 3 күн бұрын
so what I mean is:- (9/4)^9/4 => {(9/4)^3/2}^3/2 => {(3/2)^3}^3/2 => {27/8}^3/2 => {3√3/2√2}^3 => {81√3/16√2}
@Zen_Phantom
@Zen_Phantom 3 күн бұрын
(9/4)^9/4 (3/2)^9/2 (3/2)^9 × (3/2)^1/2 (19683/512) ×(√3/2) (19683/512) × (√3/2) (6561 ×3 /512) ×(√3/2) (81^2 ×3 /512)×(√3/2) (81^2×3/256×2)×(√3/2) (81^2×3/16^2×2)×(√3/2) (5.0625^2 ×3/2)×(√3/2) im tired ill complete this later
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