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Math Olympiad | A Nice Exponential Problem | VIJAY Maths

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VIJAY Maths

VIJAY Maths

Ай бұрын

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Пікірлер: 11
@zzjdkjx1520
@zzjdkjx1520 Ай бұрын
again:a=18,b=1 or a=1,b=-16
@mayankkatekhaye9220
@mayankkatekhaye9220 Ай бұрын
B can't be as negative as this question says that a,b belongs to +ve integer
@ezzatabdo5027
@ezzatabdo5027 Ай бұрын
After thanking professor, we can return the powers of the original equation b= b2/2 and a= a2/2 and complete by your solution state, thanks.
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Thanks a lot 🎈
@jans1616
@jans1616 Ай бұрын
Another solution : a=18 , b=1 18^1 - 1^ 18 = 18-1 = 17
@vurank
@vurank Ай бұрын
You made mistake on (x-y)(x+y) = 17. You made assumption that x and y are whole numbers while they do not have to be as you created them as sqrt(a^b).
@petertai2893
@petertai2893 Ай бұрын
a=1 b=-16 a=3 b=4 a=18 b=1
@petertai2893
@petertai2893 Ай бұрын
用 Python 寫個程式 for a in range(-20,20): for b in range(-20,20): if a==0 or b==0: continue elif a**b-b**a==17: print(f"a={a} b={b}")
@pendulumandraven9338
@pendulumandraven9338 Ай бұрын
First one isn't right as it says a,b belongs to Z+
@petertai2893
@petertai2893 Ай бұрын
己重新寫過,這個不會找到負數 for a in range(20): for b in range(20): if a**b-b**a==17: print(f"a={a} b={b}")
@RealQinnMalloryu4
@RealQinnMalloryu4 Ай бұрын
17/8=2.1➖ 17/8=2.1 {2.1+2..1}=4.2 2^2.2 1^1.2 1.2 (B ➖ 2+A)
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