Math Olympiad Algebra Problem || a=? & b=?

Рет қаралды 3,389

Ай бұрын

Math Olympiad Algebra Problem || a=? & b=?
Welcome to our channel! In this video, we will be tackling a challenging Math Olympiad question involving exponential and algebraic equations. We will walk through the problem step by step, providing clear explanations and helpful tips to help you solve similar problems in the future. Whether you're preparing for a competition or just looking to improve your math skills, this video is perfect for you. Let's dive in and solve some equations together!
#mathematics
#olympiadmaths
#algebra
#matholympiad
#matholympiadproblem
#exponentialproblem

Пікірлер: 22

@immischannel1747 Ай бұрын

Tried solving it in my head, then realised the solution must be a complex number. So I gave up calculating it in my head.

@Abhishek4EV3 Ай бұрын

Yep an inaginary number.

@84com83 Ай бұрын

How to invent or imagine something that only exist if you "believe in it" [yes I was taught something like that in school ( in the 1960-ties) but didn´t see why it was necessary to invent something that only existed in the mind of my teacher (at that time)] well, well things happen!

@benjitsu8461 Ай бұрын

tried this in my head, I got (-6 +/- 6I√(3) )/-2, which is at least similar to the answer they got 😅

@kakugan Ай бұрын

basic 10th grade high school math

@iamhere2382 Ай бұрын

Good Olympiad....🎉

@E.h.a.b Ай бұрын

It may be easier if you use the following approach: a + b = 6 ----> [1] a b = 36 ----> [2] (a - b)^2 = (a + b)^2 - 4 ab (a - b)^2 = 6^2 - 4 * 36 Froma [1] and [2] (a - b)^2 = 36 ( 1-4) (a - b) = +/- 6 √(-3) a - b = +/- 6 i √3 ----> [3] 2a = 6 +/- 6 i √3 From [1]+[3] a = 3 +/- 3 i √3 2b = 6 -/+ 6 i √3 From [1]-[3] b = 3 -/+ 3 i √3 (a, b) = { (3 +3 i √3, 3 - 3 i √3) , (3 -3 i √3, 3 + 3 i √3) }

@Abhishek4EV3 Ай бұрын

Agreed. This video is totally stupid for explaining absolutely nothing. Those who don't know about i, won't understand anything from it.

@eliashilger7067 Ай бұрын

The third part of step 2 should be negative b squared plus 6b minus 36 shouldn't it?

@jonb4020 Ай бұрын

If that wasn't a complete waste of time and effort, what was it? And what does the weird upside down "?" mean? 😵‍💫

@Abhishek4EV3 Ай бұрын

Literally my thoughts after watching the thumbnail😂 before even starting the video.

@Abhishek4EV3 Ай бұрын

That's iota. It is used for imaginary numbers.

@jonb4020 Ай бұрын

@@Abhishek4EV3 Thank you. Would you maybe help me some more here please, if you can. Is there actually an answer to this equation? Or is that imaginary too?

@Abhishek4EV3 Ай бұрын

@@jonb4020 There is an answer. It's just not a good video for the explanation of the answer. Also it's not clear what are we supposed to find? a-b? a and b? a²-b²? So it should be put in the video to make it clear for everybody to understand.

@jonb4020 Ай бұрын

@@Abhishek4EV3 Well I'm prepared to believe you, though I can't see it. But then, I'm just a simple interpreter! It seems from the video that we are supposed to find the values of a and b. But the issue for me is that if a + b = 6, then neither a nor b can exceed 6, individually. By elimination of the possibilities, the maximum number that a x b can be is 9 (3x3) and that therefore one or other of the two statements is false. Therefore trying to work it out as if they are both true is, as I mentioned in my first comment, a waste of time.

@Dalroc Ай бұрын

Since both have to be positive, considering both the sum and the product are positive, if we're looking at real value'd solution we get a = 6-b => b(6-b) = 6b - b^2 which is strictly smaller than 36 for a,b