you are right

As a chemical engineering major, idk why we have to know this 🤷🏻‍♂️🤷🏻‍♂️🤷🏻‍♂️

I'm glad you find the video helpful. Best wishes in all your studies.

True.

@@lampa298 True.

+Datguy obi thanks for positive feedback. Can you please edit your comment and delete name of University. I hope one day you will be a successful alumni of that University. We have all had a few difficult professors, as well as some excellent ones.

There is a distributed force acting on the wall. You can represent this as a single force acting (1/3)h from the bottom.

STRAIGHT LEGENNNNNDDDDDDDDDDDDDD

at 40:00 horizontal force Fs is shown. the gate is assumed to "hang" from hinge at A. So don't need vertical force acting on bottom of gate. Could the gate rest on the ground? Yes. If it did rest on the ground, would there be vertical force at bottom? Yes.

+Dimitri Dobroskok yes, I see no reason it wouldn't work.

Thank You!

+john zimmerman pressure of water at bottom of container is not the same as "pressure" or "Force/Area" between container and scale. Force between container and scale must equal weight of container and weight of fluid in container. Sorry if this doesn't help. But that is all the time I have to try and answer your question.

+Randall Manteufel Thank you for responding. However, you misunderstand because I was not real clear. I try again. It will be simpler to reword my question using containers. Consider a container in the shape of a cylinder 10 feet depth of water, 1 square foot horizontal area. A weigh scale is placed inside the container at the bottom. One would think it would register the weight of the liquid, 624 pounds,. because that is the weight of water. But actually what the scale registers is not a function of the weight of water but the force from the water which is a function of pressure not weight, though in this example the resultant force is the same. Now take a container, 1 square foot at the bottom but that narrows and it holds 10 feet of water. Lets say it holds only 5 pounds of water. What would a scale inside the container resting on the bottom, supporting the entire liquid register 5 pounds (the weight of the water) or 624 pounds according to the formula F = 62.4lb/cu ft x 10ft x 1 sq ft? (answer is 624 pounds - right?)

He calls it equilateral, but labels it as if the "height" (measured at right angles to the vertical side) is equal to the length of the vertical side. If that's the case, then the triangle is not equilateral. His area formula is wrong for equilateral, but correct for the way he labeled the triangle.

discussion is confusing at this point, sorry. An equilateral triangle is drawn and incorrectly I say it is isosceles (or at least imply it is isosceles). If length of each side of equilateral is "b" then distance from middle of edge to opposite corner is "b*sin(60)" (not b as I think I say). Centroid is at (1/3) of this distance, measured from each side toward the opposite corner. To help see this, draw equilateral triangle, then 3 lines from middle of each edge to opposite corner. All 3 lines will intersect at centroid. With ruler you can verify this is (1/3) from middle of "base" to "peak"

Sir irrespective of isosceles or equilateral triangle the centre of pressure must lie on the centre of pressure prism and in this case it will be exactly at ( b /2 ) because we have a horizontal surface.

And it shouldnt be at centroid of cross section as you have mentioned..please correct me if i am wrong sir

+SageAdam length of cylinder in third dimension (not shown) is 5 ft. Hope that helps with second question as well..

+Randall Manteufel isn't it eg(h^2/2)

jffoz1 you are correct. thanks

Hibbeler

Thanks me too I was looking for the same book

And now?

Keske degil mi? Sanirim ders kaydi bu..