Momentum - GCSE & A-level Physics (full version)

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scienceshorts.net Please don't forget to leave a like if you found this helpful!
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00:00 Conservation of momentum
03:23 Elastic & inelastic collisions
04:30 Coupling
07:39 Recoil
10:50 Rebound
12:20 Momentum & force
15:02 Impulse & F-t graphs
17:08 Force exerted by flowing fluid -
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Пікірлер: 209

@ileggaless8715 9 ай бұрын

Sir you have single handedly saved my A level physics grade

@kquote03 4 жыл бұрын

I swear to god yall are sadistic I was watching khan academy projectile motion and he used a person jumping off a cliff as an example Now I'm both getting shot at and being hit by a train, thanks shorts !

@bijyetamaharjan9644 3 жыл бұрын

lolol nice

@abdulrehmannagi352 3 жыл бұрын

what too much physics does to a person

@hashimalsadah6250 3 жыл бұрын

@@abdulrehmannagi352 facts

@richasocool 3 жыл бұрын

@@khaliljasiah4631 bot

@richasocool 3 жыл бұрын

@Joe Bradley bot

@Diamond-zd1cl 9 ай бұрын

Thank you, to this day your video still holds up. This has made it so simple to understand my A level physics

@wannabe_Hacker 4 жыл бұрын

his voice brings me happiness

@danishhraza 4 жыл бұрын

I think its time to drop physics

@fardinahmedtameem5332 Жыл бұрын

Which uni does ya read in

@fernandoalonso27 Жыл бұрын

@@fardinahmedtameem5332 MIT

@Sushimindest24 Жыл бұрын

Its too late for me the as level exam is after 1 month

@danishhraza Жыл бұрын

You can do it, I scored A

@mannytalwar3095 Жыл бұрын

@scienceshorts bros violating

@fatimakhalid470 5 жыл бұрын

Sir, You are really doing a great job.

@spacetimeduality Жыл бұрын

really wanna give you hug for this, i have my exams in 8 days and i am hardly prepared... im a pretty avg scoring person. this video really helped me internalize the concepts. thank you so much!

@PersonallyOptimistic Жыл бұрын

How'd it go?

@Nazo0622 4 жыл бұрын

my new physics teacher for a-level since my other one is terrible x

@aayonpadhy8676 6 ай бұрын

Hello sir, I just wanted to show my gratitude towards you for the videos, they are extremely concise and well explained. My grades in physics have taken a boost ever since and I always revise these videos before my exams.

@bubushhh 5 жыл бұрын

8:56 if u do physics and drillings u know

@shinamay8815 3 жыл бұрын

life saver i wouldve failed my a levels without you!

@zannino7889 2 жыл бұрын

How did you do in them

@haroonqadir3474 2 жыл бұрын

@@zannino7889 good q

@zannino7889 2 жыл бұрын

@@haroonqadir3474 Nice, good too

@neversayangel 5 жыл бұрын

The best explainatory video i've found about this. Very well done!

@h4lplays932 3 жыл бұрын

10:30 sad thing is this would probably be a 1 marker in the exam

@aleccowan2774 4 жыл бұрын

You should become an ASMRtist. Such a soothing voice.

@SadiyaAndSarah 5 жыл бұрын

Anyone else are giving As level exams? Good luck!💕

@Lazer-bp9lf 4 жыл бұрын

Sadiya And Sarah me and physics MCQ's are really hard. But gotta keep trying to achieve good grades.

@jasonngwa9151 4 жыл бұрын

Thanks ❤

@amywinter9453 3 жыл бұрын

Meeee😭😭😭😭😭😭

@rapfarsibaza 3 жыл бұрын

Cheers

@rapfarsibaza 3 жыл бұрын

@@amywinter9453 😥

@janebeckett4927 4 жыл бұрын

Brilliant channel. Clear. Concise. Unlike the textbook XD

@abschy648 4 жыл бұрын

yh the textbook thinks were already physicist!

@puddleduck1405 2 жыл бұрын

yeah I can literally never learn from textbooks

@maryamsheikh6919 5 жыл бұрын

Thanks, my mind feels a little cleared.

@camclark4522 6 жыл бұрын

THANKYOU SO MUCH YOUR VIDEOS ARE INCREDIBLE

@beyondconfuzzled 3 жыл бұрын

Thanks for the help! really love your videos

@priyajsingh2308 4 жыл бұрын

thank you sir, this has really helped me out.

@magn8195 7 жыл бұрын

Thank you for this amazing video!

@Hunn003 4 ай бұрын

I genuinely love you, thank u smm youre saving lives😣

@user-yb3gq3hf8u 3 жыл бұрын

This is so useful, thank you very much

@fiziksfriend2497 7 жыл бұрын

Excellent channel nice one!

@ScienceShorts 7 жыл бұрын

+Fiziks Friend Tar muchly!

@btoombstertriesyt6532 5 жыл бұрын

Good luck for Monday pepes

@Nohandle95 5 жыл бұрын

Good luck

@chinmayvashishtha 5 жыл бұрын

good luck!

@guangaotian6044 5 жыл бұрын

Good luck lol

@ayeshaa44 5 жыл бұрын

which unit do you guys think will come up the most?

@btoombstertriesyt6532 5 жыл бұрын

@@ayeshaa44 unit 3 and 5 on Monday 4+6 Friday...?

@davidkuuya5021 4 жыл бұрын

you're doing a great job

@suryannair4490 3 жыл бұрын

this is amazing no other words

@dylanstipke3170 2 жыл бұрын

love your videos, theyre amazing

@allitorres2026 5 жыл бұрын

thx sir. it‘s clear than what i know now

@adilmubashirchaudhry4115 5 жыл бұрын

I'm just gonna call it v I can't be bothered to write v12 lmao I love this guy xD

@gailchirebvu716 6 жыл бұрын

this is helpful thank you sir

@sufanaamir8926 5 жыл бұрын

GREAT HELP! THANKS!!

@zannino7889 2 жыл бұрын

Watching this before my a levels, great videos

@tillytiger5041 2 жыл бұрын

Good luckkk. In the same boat

@zannino7889 2 жыл бұрын

@@tillytiger5041 Ty u too buddy

@tanvirahmed1010 2 жыл бұрын

AQA ?

@zannino7889 2 жыл бұрын

@@tanvirahmed1010 yes

@tanvirahmed1010 2 жыл бұрын

Are you revising only the advance information topic given by AQA ?

@ruthannfacey7586 5 жыл бұрын

Really good video .Thanks

@serena1330 6 жыл бұрын

This was extremely helpful. Thank you for making this

@rin_morts 2 жыл бұрын

its been 4 years, how did you do? what are you doing now

@serena1330 2 жыл бұрын

@@rin_morts got an A in physics and about to graduate uni!

@rin_morts 2 жыл бұрын

@@serena1330 i’m so proud that you got an A, i’m sitting mine in less than a months time 😭 wish me luck

@puddleduck1405 2 жыл бұрын

@@rin_morts good luckkk!!

@zndh 2 жыл бұрын

@@rin_morts how was it?

@jeremy1115 2 жыл бұрын

why is it -2 pls reply i have test in ten minutes

@duanaeem8359 4 жыл бұрын

Sir what is the effect of different masses of objects on momentum and kinetic energy?

@lordfarquaad9887 5 жыл бұрын

Thank you!

@kaivanshah4304 4 жыл бұрын

a great work done really a good work done.

@sarahmalik2143 3 жыл бұрын

Got Unit 4 on monday, 0 prep but these videos are definitely gonna make me pass!

@jaketaylor5272 3 жыл бұрын

great video thanks

@Jamie_kemp 2 жыл бұрын

16:10 might be easier just to use 1/2 base x height on that one triangle you already have 😄

@ScienceShorts Жыл бұрын

...🥲

@ASRtuness Жыл бұрын

its not a right angled triangle, is it sherlock?

@Jamie_kemp Жыл бұрын

@@ASRtuness it doesn’t have to be, watson

@sirsnow371 6 жыл бұрын

I dont rlly like collision questions :/ for example, people ice skating that collide then bounce off. Dont understand those questions.

@vsmoonchildmahir283 5 жыл бұрын

If they collide and bounce off, m1u1 + m2u2 = m1v1 + m2v2 U=initial velocity V=final velocity And if they collide and 'don't' bounce off, final velocity v is the same for both as they are stuck together: m1u1 + m2u2 = (m1 + m2) v

@DrPeppicalPlayzMC 3 жыл бұрын

@@vsmoonchildmahir283 legend

@emmacole2296 4 жыл бұрын

14:24 why does change in momentum = -2mu? Thank you!

@DrPeppicalPlayzMC 3 жыл бұрын

@Ariana Saly thanks !

@fahadmansoorvlogs2041 3 жыл бұрын

How will we get to know if the colision is elastic or inelastic

@samiyeelalim 4 жыл бұрын

Great video

@amaniiqra659 5 жыл бұрын

Thank You so muchhhhh

@mukasafatima4327 2 жыл бұрын

how do yo find momentum when they expect you to use vertical and horizontal component

@Axashx 4 жыл бұрын

I really hope you still reply to questions T_T Can we just plug in values for the equation in the last sum or do we have to show how we derived our answer?

@chenath9582 3 жыл бұрын

probably have to derive since data can be different, instead of density the question might give some other data and u might have to derive an equation specifically for that

@99txgh 6 жыл бұрын

Thanks, the last part was especially useful because those water pipes and density questions comes up quite a bit in AQA

@hlomphoprincess3573 5 жыл бұрын

alevel right? not GC right?

@Jontheawsome92 5 жыл бұрын

@@hlomphoprincess3573 yeah not gcse

@rapfarsibaza 3 жыл бұрын

Thanks

@khizarhassan4152 2 жыл бұрын

Thank you so much for this lit video you definitely will get to heaven with this much love

@areebahayat1308 3 жыл бұрын

U cut out the part in video where u explain rebound....y sir 😢😢😢 I really needed that information

@muhammadhamza4494 5 жыл бұрын

In the example of a boy and bullet (which you discussed) can we say that "total momentum of boy and bullet after collision is 0." OR is it that total momentum of bullet and gun is zero? please reply. thankyou

@danieldavies7708 5 жыл бұрын

You would say: the total momentum of everything in the system is zero". In other words, the total momentum of the gun, boy and bullet is zero.

@muhammadhamza4494 5 жыл бұрын

Ok thanks a lot

@danieldavies7708 5 жыл бұрын

No problem

@kriiistenchao8451 5 жыл бұрын

the video is helpful thx

@samstorm6219 4 жыл бұрын

how can impulse AND momentum both be the area under the graph f=i/t thank you

@yaamir7201 4 жыл бұрын

Because in essence impulse IS momentum. Same units too. Impulse is only the CHANGE in momentum

@jadesolaadelekan4907 2 жыл бұрын

At 17:02 , if momentum is zero at the start, how is momentum mv at the end if momentum is meant to be conserved?

@MH-wh9ek 2 жыл бұрын

it's TOTAL momentum before the collision equals TOTAL momentum after the collision, he only shows the graph for the stationary object, there would be another moving object that would hit the stationary object before the collision that would balance it out.

@alexellis856 5 жыл бұрын

life saver

@disuqihijazi1524 5 жыл бұрын

At the start you say that momentum is always conserved but then when you talk about the car accident you say that after the accident momentum goes down to zero. Im confused. Can someone please explain

@CAMPer2610 5 жыл бұрын

Cuz momentum is mass x velocity, a moving object would stop after hitting something applying force to the opposite direction of the moving object , that cancels out the velocity , therefore the the momentum which is mass x velocity would be zero since velocity will be = to zero.Hope it help.

@NoorFatima_06 Жыл бұрын

18:07 velocity cant be constant cuz in that case acceleration will be equal to zero and change in momentum and F will all be zero

@saadyasir6708 2 жыл бұрын

this probably wont get answered but why did you put v^2 in end while deriving the formula through density at 20:33

@MH-wh9ek 2 жыл бұрын

so what he got initially was change in mass divided by time which can be written as kgs^-1 which is what he managed to make an equation for at 20:06 but if you look at the initial equation for force for the fluid which he wrote at 17:57 , it is VELOCITY x change in mass over time.

@dreamz8355 Жыл бұрын

thanks :)

@petermohrasri9584 2 жыл бұрын

mass of the gun, mg - proceeds to chuckle xD

@nofalyu4524 6 жыл бұрын

1. coupling 2.?? I can't see pls what is the name for 2?

@steevoo 6 жыл бұрын

recoil

@berryxeditss Жыл бұрын

14:33 shouldnt it just be 2mu because v--v adds up to 2u

@ArikCool Ай бұрын

14:29 Why is it -2mu Please help

@marwanmohammed6259 5 жыл бұрын

8:50 how can you get negative velocity?

@hp3262 5 жыл бұрын

Velocity is a vector so needs direction . As it is going the opposite direction it is negative.

@rachiekimberly6800 5 жыл бұрын

Is this process only required for questions related to water?

@ScienceShorts 5 жыл бұрын

Nope, it can be air (say from helicopter rotors, seen that before).

@munishmusic 5 жыл бұрын

no could be anything really

@angieho8837 6 жыл бұрын

What about if particle hits a wall at an angle? would I have to find the horizontal component of that particle? Great video btw

@ScienceShorts 6 жыл бұрын

Yep! Vertical momentum doesn't change, only horizontal component.

@jlaughnskeete4855 4 жыл бұрын

Watching in 2019👍

@FPLogistic 3 жыл бұрын

Watching in 2021 xD

@-_saudyahya1269 Жыл бұрын

Watching in the end of 2022

@hoogajobie 5 жыл бұрын

How did you get 3.29 from 140? 7:16

@danieldavies7708 5 жыл бұрын

Because you add the two momenta (300+160=460) and divide by 140. 460/140=3.285...=3.29m/s (2dp)

@iamsazzz354 2 жыл бұрын

it would be great if you demonstrate us practically, which would send us further the bullet or train... hehe

@nsr6489 Жыл бұрын

Hi Sir, when you were answering the water equation, you used rho as density however I thought rho was resistivity? Is rho used for both or have I made a mistake? Thanks a lot for these great videos!

@bombi1591 Жыл бұрын

it is used for both

@tinprimo17 3 ай бұрын

17:11

@imaanwahaib5095 4 жыл бұрын

what was he talking about at 7:47 couldnt red it

@ggt4437 4 жыл бұрын

He was talking about recoil m8

@fireboy5950 6 жыл бұрын

Thumbs up :-)

@alinasargsyan3893 Жыл бұрын

bro helping us: menaces with this

@steevoo 6 жыл бұрын

14:33 why is it -2mu

@randerson5172 6 жыл бұрын

Change from 'u' to '- u' : You have to subtract one 'u' to get from 'u' to zero, then another 'u' to get from zero to '-u'. So in total it's -2u. Then multiply by the mass to get -2mu.

@laiissac9734 5 жыл бұрын

On the wall by the ball.... the direction if force is to the right?

@Umer-rg8ik 4 жыл бұрын

Or change in velocity is , v - u , so v is final velocity and u is initial velocity, in this case v = -u and u =u , so -u - u = -2u . Thus its -2mu / t. Hope this helps.

@vatsaljagdish6978 4 жыл бұрын

@@Umer-rg8ik thanks bro

@Arslan09 4 жыл бұрын

Sir it helped a lot but i didnt get that u didnt explaind inelastic colliaion

@sanjidafairozislam1747 5 ай бұрын

Is this edexcel phy?

@shifatshelby9859 5 ай бұрын

I was thinking why it gives vintage vibes... Its 7 years old!

@lebronpandey5632 6 жыл бұрын

Some times the question asks about average force that makes me confussed..

@Linwei01 4 жыл бұрын

Just change in momentum divide by time taken by N2L

@reyesmartina Жыл бұрын

Thank you a lot！

@geezer1024 5 ай бұрын

wouldn't it be MgVg = -MbVb at 10:31 ?

@ScienceShorts 5 ай бұрын

Technically yes, but in the recoil situation, we can be cheeky and just concern ourselves with the magnitudes, seeing as we know they have to be travelling in opposite directions.

@geezer1024 5 ай бұрын

@@ScienceShorts still need to fully wrap my head around separating out magnitude and direction from equations, sounds stupid but something I trip up on regularly. Thank you for the swift explanation.