Morera's Theorem and Liouville's Theorem
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10 жыл бұрын
@CatherineBerrouet 8 жыл бұрын
YOU SERIOUSLY HAVE SIMPLIFIED MY LIFE WITH THIS VIDEO IN PARTICULAR :) thank you.
@uhavebeen 7 жыл бұрын
I'd prefer to pay you for teaching than my so-called professor(s). You break down complicated things into digestible information so well!
@sumchief 2 жыл бұрын
great attention to detail , thank you
@henrywang6931 6 жыл бұрын
Very well explained!
@balikakamble1433 7 жыл бұрын
thank you so much ritvik sir. could you please maker a collection of realanalysis? please 😊
@jaimeafarah7445 5 жыл бұрын
Nice demonstration.
@ukvaishnav 7 жыл бұрын
Awesome
@FugieGamers 5 жыл бұрын
You say that morera's theorem statement is for a triangle but it is for any jordan curve? That aside you're a great teacher and good proof.
@akrishna1729 11 ай бұрын
It holds for every simple, closed, piecewise-C^1 curve in an open set. With these stronger hypotheses the converse need not be true, but the triangle formulation is actually equivalent to holomorphy in a region.
@Holm22 8 жыл бұрын
Could you elaborate the reasoning behind F(z) being well-defined?
@user-sq7tx2rf2o 4 жыл бұрын
I agree with your opinion. I think omega need to be convex in this argument, for the line segment parpametrization to be defined.
What the Meowk!
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