Motion in a Straight Line Class 11

Рет қаралды 19,821

3 ай бұрын

Motion in a Straight Line Class 11 Kinematics Equations
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Motion in a straight line refers to the movement of an object along a path that can be represented by a straight line. It's a fundamental concept in physics and is often studied in the context of kinematics, which deals with the description of motion without considering its causes (forces).
Kinematic equations of accelerated motion are equations that describe the motion of an object experiencing acceleration. These equations are derived from the basic principles of kinematics and are useful for predicting various parameters of motion such as displacement, velocity, and acceleration over time.
The four main kinematic equations for motion in a straight line under constant acceleration are:
1. v = u + at: This equation relates the final velocity (v) of the object to its initial velocity (u), acceleration (a), and time (t). Here, u is the initial velocity, a is the constant acceleration, t is the time taken, and v is the final velocity.
2. s = ut + 1/2at^2: This equation relates the displacement (s) of the object to its initial velocity (u), acceleration (a), and time (t). Here, u is the initial velocity, a is the constant acceleration, t is the time taken, and s is the displacement.
3. v^2 = u^2 + 2as: This equation relates the final velocity (v) of the object to its initial velocity (u), acceleration (a), and displacement (s). Here, u is the initial velocity, a is the constant acceleration, s is the displacement, and v is the final velocity.
4. s = 1/(u + v)t: This equation relates the displacement (s) of the object to its initial velocity (u), final velocity (v), and time (t). Here, u is the initial velocity, v is the final velocity, t is the time taken, and s is the displacement.
These equations are applicable when the acceleration is constant. If acceleration is not constant, calculus-based methods are required to analyze the motion.
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Пікірлер: 61

@roshankrishna1254 2 ай бұрын

Hello! I found your video quite understandable and enjoyable as well. However, @ 32:52 I felt the need to point out something here as thus: Here, when we integrate, it was actually definite since they said, "if initially the body is at rest". This implies that t=0s (since initial velocity is 0) and since they asked us to find velocity at t=4s, therefore, we can assume the time interval for acceleration to be between t=0 and t=4 which means we can safely assume that the lower limit of the integration is 0 whereas the upper limit is 4. So, we can use definite integration to get the desired solution (which is 64 m/s). Other than that, everything in the video was great. Thanks a lot!

@rangeshkrishna7804 3 ай бұрын

Sir please make a video on the introduction to Differential and Integral calculus.

@MakoligoScienceHQ 3 ай бұрын

Thanks Sir. Now I’m teching chemistry in Tanzania, in my own way, but you inspire me a lot. 🙏🏻🙏🏻🙏🏻

@ashwinplays5935 3 ай бұрын

Thank you sir! Learned a lot

@user-fj3vt3ub4g 3 ай бұрын

sir i thought cars have nothing to do with my studies(I'm a car guy) but this video intro and the examples you told was really informative for me thankyou so much dear sir.

@bindhu82 3 ай бұрын

Kindly make a video on the 4 quantum numbers, spdf, klmn and the electronic configuration in detail. I beg you, plss🙏

@shreyasharma6263 3 ай бұрын

Sir I wish you had started class 11th , 12 th earlier , I had learned Chem and Phy from u in class 10 th and got 95% , in class 11th my score dropped miserably and now I am just done with my class 12 th boards and Phy was really tough . When I saw this lecture I had tears in my eyes I wished u were there during my class 11 th and 12 th. Loads of love 🥰

@Smart_Soham 3 ай бұрын

Displacement= 6t + t³ So, V(velocity)= ds/dt = d(6t + t³)/dt=6+3t² Acceleration = dv/dt= d(6 + 3t²)/dt= 0+6t=6t Putting t = 5s We get Acceleration = (6*5)units=30 units If correct, then please reply 😅

@priyalnarang8344 Ай бұрын

yes

@TGIies 23 күн бұрын

@@priyalnarang8344 yes same ans

@Educationaldesign-ev1zq 9 күн бұрын

Yes same ans

@Vetri444 3 ай бұрын

Thank you so much sir 😊

@neethuciju 3 ай бұрын

Brilliantly executed and explained sir.

@ManochaAcademy 3 ай бұрын

Thank you!!

@tabithanadimpalli7541 3 ай бұрын

thank you sir.

@Youyou0927 3 ай бұрын

Thanks you sir love from south Sudan🇸🇸🇸🇸

@chinmaykowshik5161 3 ай бұрын

I think the answer to the question at the end 30 units. This is the method I used: Displacement = t^3 + 6t By differentiation, we get: Instantaneous velocity = 3 * t^2 + 6 Differentiating again, we get: Instantaneous acceleration = 6t At t=5, this would be 6 * 5 = 30 units Let me know if this is right

@tamannasantamoni8229 2 ай бұрын

I found the answer same to your answer.

@sujaphilip3632 3 ай бұрын

Sir, any other lessons started already? Chemistry started?

@soundsoulplayz 2 ай бұрын

Hello sir! Could you do a "Motion in a Place" for Class 11? It would be very helpful for me in my on-going Class-11 Year.

@SarbjitKaur-gp3ze Ай бұрын

Sir please cover all the chapters of physics asap.. Please..

@vemagiriradhamani3341 3 ай бұрын

He deserve to get so many likes , comments more than he expecte

@raghamadhuridarla7241 3 ай бұрын

Tq for teaching this topic sir it is a difficult topic for me and you made it too easy now😊😊😊

@ManochaAcademy 3 ай бұрын

Glad to hear that

@bindhu82 3 ай бұрын

@@ManochaAcademyKindly make a video on the 4 quantum numbers, spdf, klmn and the electronic configuration in detail. I beg you, plss🙏

@bindhu82 3 ай бұрын

@@ManochaAcademy Kindly make a video on the 4 quantum numbers, spdf, klmn and the electronic configuration in detail. I beg you, plss🙏

@tamannasantamoni8229 2 ай бұрын

Sir, the determined acceleration is 30 unit.

@24.msrikaran60 2 ай бұрын

Sir please make video on calculus

@MelloAnimations 3 ай бұрын

posted at the perfect time

@ManochaAcademy 3 ай бұрын

Ha ha ... thanks!

@alusarichandana3333 12 күн бұрын

Sir plz tell about motion in a plane

@tesfahungetahunargachew4328 3 ай бұрын

Tnx a lot sir for all your support I have physics question can I send you

@BihaanRoy 2 ай бұрын

1. 10 m/s 2.-20m/s**2 3. Maximum Distance = 10 m Time = 2 seconds

@Revant875 3 ай бұрын

Explain data handing

@Revant875 3 ай бұрын

Explain faraday law

@abdulmojeedakinwande2320 3 ай бұрын

Well done sir.

@ManochaAcademy 3 ай бұрын

Thank you!

@user-bw4wl2fl3h 3 ай бұрын

👍🏻♥️

@allroundercelebrity4194 3 ай бұрын

Sri there is no class 12th course

@djbrothersfun9602 3 ай бұрын

Thank you for saying class it is very helpful for tomorrow exam

@ManochaAcademy 3 ай бұрын

All the best

@bloodgaming2844 3 ай бұрын

please post videos of all class 11 physics chapters

@ManochaAcademy 3 ай бұрын

Will do

@tamannasantamoni8229 3 ай бұрын

Shubho Noboborsho.

@harbajansinghbhukya872 3 ай бұрын

Hi sir

@pavanmanikanta7237 3 ай бұрын

My name is manikanta You are my visibleing god sir tomorrow exam sir very very very thanks sir

@educationaccount8946 19 күн бұрын

30m/s²

@user-zb1bd7db1i 3 ай бұрын

sir I'm very confused , are you mr bean you're matching with the actor, name is babuji❤ are you babuji ? Sir! I'm very confused about you i swear

@Dr.VishalShah23 3 ай бұрын

is the answer 12.4

@anaren9396 3 ай бұрын

Answer is 30 units

@bikiranbarman8049 3 ай бұрын

Very informative sir ❤

@ManochaAcademy 3 ай бұрын

Thanks!

@bineetbiswas5824 3 ай бұрын

Sir used to teach us better before 2-3 years. I miss those days when sir used to teach complex topics in easy, interesting and unique ways. Sir, I think the decrease in viewers of your recent videos is due to your change in teaching techniques. Sorry to say, but your videos are not interesting like your previous videos... Please teach us through your old unique ways. everybody will like it, your old viewers will return and your channel will grow as before . I have commented this in your previous recent videos in order to send this message to you. Do reply if you received this message...

@ashwinplays5935 3 ай бұрын

@a.pal_yt2018 3 ай бұрын

He used to teach my whole class in lockdown both 9th and 10th. We used to skip online lect in 2021😂. We were able to get good percentage in 10th only bcoz of him. My skool wasn't having legible average %age. But just in 2022, it grew to 100%pass .