first solution: T=2*n*tpd where n=5 Hence T=10*tpd Since tpd=100 pico second T=10*100 pico sec.=1000pico second Now 1sec=10^12 ps(relation of second and picosecond) Hence 1ps=10^-12s 1000ps=10^-9s From this T becomes as T=10^-9 sec f=1/T =1/(10^-9) =1*10^9 hertz Again from relation of hertz and gegahertz 1 hertz = 10^-9 gegahertz. Hence ans is 1 Ghz
@emresagr85934 жыл бұрын
nice exp. thx
@ritikshrivastava94423 жыл бұрын
Shandaar londe
@alfredhercules3 жыл бұрын
Thank you!
@plutonium45742 жыл бұрын
And the second solution??
@nithishnagendra Жыл бұрын
thnx bro you shld start a youtube channel 😂
@thereeltoreal5 жыл бұрын
Sir, your flow of English is really impressive! :)
@user-dv6ei9kk5l4 жыл бұрын
The 2nd problem was really impressing. I was kind of wandering what actually feedback does, and this gave me the answer. Anyway, the answer is 14 ns time period at first ouput and 12 ns after that. The key point is that after the 3rd NOT Gate the feedback sends the input signal. So when the first input goes from 3rd to 4th NOT Gate, simultaneously 2nd input goes to 1st. So it takes the second output to come out taking time of 1st to 4th NOT Gate, not the 0th to 4th. For who doesn't understand due to my short english, 1st 0(8 ns) 1st 1(6 ns) 2nd 0 (6 ns) 2nd 1 (6 ns) 3rd 0 (6ns) 3rd 1 (6ns) 1st output(14 ns) 2nd output (12 ns) 3rd output(12 ns) Thanks to the comments I also got wrong at first!
@suhriddas87694 жыл бұрын
Absolutely correct bro! As far as I have analyzed the 1st and the fourth, not gate perform at the same instant after the feedback is in action, so clearly for the first time value=0 prevails for 7 delays=14ns and thereafter the interchange of values is after 3 delays = 6 ns , hence time period comes out to be twice of the former = 6 delays =12ns ! Good question!
@gyanig85014 жыл бұрын
I still dont understand. Can you help?
@amankapoor57534 жыл бұрын
@@suhriddas8769 right bro?
@AnoNymous-po5sx3 жыл бұрын
@@suhriddas8769 it cannot be 14 ns. Because the last not gate and the first not gate are performing at same time. So you can't take extra 2ns. It's always 12ns from beginning.
@amitanand9483 жыл бұрын
It's 12 nanosecond. We will start observing only after first output is produced because initially Y can be in any state 0 or 1.
@knvssandeepbolisetti50083 жыл бұрын
thank you so much to neso academy because i didn't even attended a single class in my college but you helped me a lot!!!!!!
@214F7Iic0ybZraC6 жыл бұрын
Just suggestion, but you would be better off always starting with the previous H.W.'s answers.
@durjoydas96172 жыл бұрын
He wants to sleep if he is allowed to sit
@anshumanagrawal48847 жыл бұрын
12 ns imo... because from the feedback point to Y it will take 2ns but in that time the feedback will provide signal back to the first NOT gate... so what im saying is that by the time signal reaches Y...it has already passed the first NOT gate . So effectively there are 3 NOT gates namely 2,3 and 4 ...thus 12ns
@studentcommenter58586 жыл бұрын
This is exactly what I have done. I think this answer is correct.
@pbanikk5 жыл бұрын
How come the first answer?
@amayatre35585 жыл бұрын
Absolutely right Sir
@sumitsouravamohanty89354 жыл бұрын
16 nsec!!
@sumitsouravamohanty89354 жыл бұрын
O/p of feedback loop is applied to the I/p to the NOT gate!! Now NOT gate output will be complement of O/p of feedback loop ... and delay will be added where the O/p of feedback changes from 0-1 and 1-0 ... addind extra 2td ... so period is 8td.
@jrbucky Жыл бұрын
well, my college is useless now.
@sag7611Ай бұрын
Everyone's is
@myonlynick6 жыл бұрын
question 2: 12ns. The question asks what is the TIME period of the square wave, it does not ask to say what you see at Y output. The first 3 gates create and determine the frequency and time period of the square wave. The last gate comes AFTER the feedback loop,it adds a small delay of 2ns.
@myonlynick6 жыл бұрын
the first 3 NOT gates will create and sustain the square wave. You plug one extra NOT gate which will let you see the waveform after an additional 2ns delay :) Build the circuit, do not just read books/videos.
@im.meer-asif6 жыл бұрын
yaa we found it after 2 ns ..but it will not add time period or f of wave ..it will just delay it.......but the T will be same as previous...champ....
@myonlynick6 жыл бұрын
yes. :)
@Shubham-ln2lq6 жыл бұрын
myonlynick ca u tell me the wave form in detail🙏🏼
@ayushmansingh56206 жыл бұрын
Please add logic family videos as soon as possible before 15 dec. I understand now more clearly and free than my college facilities. Very very very very very very very nice 👍. Thank you for helping each of us
@bimalkumar41375 жыл бұрын
Q1-1GHZ,Q2-12ns .as only first three not gate is responsible for creating square wave so 12 ns is right answer.
@varshagupta41257 жыл бұрын
Kind Attention Sir, Thank You so much for such a helpful videos. but sir i want the solution for the HW problems but cant access your website. kindly provide the solution for it.
@divyanshsharma8133 жыл бұрын
remember 1 thing when signal passes from 3rd gate to 4th gate , at the same time it reaches as a input to 1st gate..... and when it passes from 4th gate to the output , at the same time it passes from 1st gate to 2nd gate........ in this way we have time period equal to 14ns for 1st cycle and 12ns for rest of the cycles..... hope u understood...:-)
@musicdebliss97672 жыл бұрын
How 14ns for 1st cycle ..Can u please explain bro
@muzammalhussain48873 жыл бұрын
Q1. 1GHz Q2. 12nsec. fourth gate is used to invert the square waveform generated by first three gates.
@ankurrastogi30807 жыл бұрын
I suppose its 16ns because when Y is assumed to be zero then output of gate no 3 should be 1.Now after passing gate one it will be zero not affecting the output Y ,same for gate 2 but when signal passes through the gate 3 , 1 now becomes zero but this change will only affect the output Y only after passing through Gate 4.So in order to produce any change in Y.so it sjould be after passing a net of 8 gates. I am not too sure about it otherwise what difference will remain in this and the above question!
@Sachin-bz9ix7 жыл бұрын
exaxtly, same question arised bro...
@pratikshachavan67026 жыл бұрын
My answer is 16nsec
@tanyasharma92095 жыл бұрын
16 ns
@deepakprasad67535 жыл бұрын
Exactly bro
@bhaskara90202 жыл бұрын
my ans too 16nsec.
@findingbloopers12854 жыл бұрын
for 1. it is 1 GHz and for 2. in it's first input it takes 14 n sec for complete cycle and afterwards it takes 12 n sec. always and since time period means time taken for period motion to take place thus, 12 n sec. is the correct answer.
@beautygupta2135 Жыл бұрын
Plzz explain me...solve the 2nd number problem
@ritwikshribhate91685 жыл бұрын
1:- 1ghz 2:- 1st o/p will take14ns and after that it will give time period of 12ns
@Geethapgasst5 жыл бұрын
This is correct
@toystories215 жыл бұрын
thx
@vinayakpatil5315 жыл бұрын
I also got the same thing
@nawnwa5 жыл бұрын
Shouldn't the first operation take 8ns, after that it becomes cyclic. I hope the channel posts an answer to this question.
@flayy57505 жыл бұрын
you mean 8 ns right?
@utkarshshukla2315 жыл бұрын
2) c) 14ns , because if we start with 0 then after 6ns o/p to 3rd not gate will be 1 then by feedback after 6ns we will get 0 then this will go to 4th NOT gate producing 1within 2ns and hence a square wave and hence total T = 14ns
@deepakhutthy26635 жыл бұрын
bro u have calculated T/2 but T=14 x 2 = 28 if u find any mistake u can reply
@utkarshshukla2315 жыл бұрын
@@deepakhutthy2663 I think you are Right as Time periop will be calculated for full pulse , Thanks
@xiaoshen1942 жыл бұрын
@@utkarshshukla231 Abe Kya right?😂 Options bhi to dekh bhai
@amankumarrai90967 жыл бұрын
In order to access the answers to your homework problems, the website is showing 404 error. Kindly fix it ASAP ! Else your video work is awesome. Big thumbs UP!!!
@binilrajadhikari26436 жыл бұрын
Sir why is not the first ckt acting as square wave generator.
@madhavirathi60043 жыл бұрын
Same problem
@kingcm1273 жыл бұрын
3 years gone, still the same problem
@ariyansardar90292 жыл бұрын
Can I believe blindly this playlist as best ?
@AdityaPratapsingh91258 жыл бұрын
Amazing tutorial.Thanks a lot sir.
@shruthipeddinti39443 жыл бұрын
Sir the way you explain the subject is amazing sir thank you ,thank you very much sir .😊😊😊
@gatjuatwicteatriek4590 Жыл бұрын
I always feel at home whenever am here
@malkurthisreekar30585 жыл бұрын
Please provide answers for the home work problems also sir. Thank you
@beaconoflight64112 жыл бұрын
Thank you very much for providing us with all these well-made educational videos. They really helped me get through my last semester. I'll definitely recommend your channel to others!
@hondahonda15392 жыл бұрын
Which clg and 2nd sem??
@parmarkalpesh3164 Жыл бұрын
@@hondahonda1539 bro svnit me hu fir bhi ye dekh raha hu
@amitanand9483 жыл бұрын
12 nano second. At any instant we start applying input 0. We don't know what will be the output at Y, it can be anything 0 or 1. After 3nsec the output will be 0 and we can start drawing the square waveform.
@Abhi-qi6wm3 жыл бұрын
In q2: Shouldn't the first cycle be 20ns at first and then 12ns? Explanation: We start with 0. Then after the first 4 time periods, Y is still 0. Then during the next 3 time periods, Y remains 0 and after the 7th time period, Y=1 and then Y falls back down to 0 after the next 3 time periods. So it should actually be (7+3)tpd * 2 = 20ns for the first cycle and then 12ns for the next cycles.
@gag_pod52425 жыл бұрын
answer to the 2nd que is 14nsec .there are 3 not gates in the feedback loop so applying 2nTpd= 2*3*2ns = 12ns and there is a delay given by the 4th gate of 2ns . adding them we get : 14 nsec
@ms.nishajakhar86383 жыл бұрын
HW Question 2 Answer:- 12 n sec T= 2n tpd n= no of NOT gates involved in feedback Circuit , ( which are 3) tpd = 2 n sec Already given Hence T = 2*3*2 n sec T = 12 nsec
@beautygupta2135 Жыл бұрын
And what is the use of not gate at the end of feedback circuit
@vlog12867 Жыл бұрын
Great work have a nice day for you.
@mitrasen22954 жыл бұрын
Sir why it is not buffer if it have feedback then what reason behind that could u explain feedback plz sir
@eutopiarhythms87433 жыл бұрын
I Love Neso Academy ❤️
@im.meer-asif6 жыл бұрын
in q 2 .. we get square wave a both after three and four buffer ..the T will be defined by first three buffers only =12ns the fourth one will only give us the delayed square wave having same frequency... so ans is 12ns..
@yogenderyadav5235 жыл бұрын
3 buffer khai hai .
@gopikrishnamoodu61524 жыл бұрын
1. 1Hz 2. 16 ns Because ,when may be the feedback is provided the input have to paas through all four gates to get output. And each gate will take 2 ns. It is simply like above problem. And it requires to pass through 8 NOT gates to complete on cycle. T=8 *2 ns T=16 ns I think it is mostly correct.
@20DoseOver6 жыл бұрын
a general approach: square wave generator will work as the same period calculation, but the last not gate provides a time shift to positive direction. anyone agrees?
@byronwakhisi58802 жыл бұрын
Magnificent knowledge
@tigabumitiku64215 жыл бұрын
I am happy for this service
@Harekrishna.sathsang3 жыл бұрын
Why it is not buffer sir ? I didn't understand
@snehashishbanerjee25753 жыл бұрын
It is not a Buffer due to the presence of Feedback
@allcompetativeexams29874 жыл бұрын
Sir, are these all videos in order? I find some topics are not in sequence!...
@shubhambhavsar79584 жыл бұрын
No it's scattered
@chenymittal21548 жыл бұрын
Answer of the 1st question is b and the answer of 2nd is b as well try to go through each gate and mention the time passed each time u pass the gate. and u will get 12ns as the answer
@gurjotsingh7528 жыл бұрын
its sound silly, but can u please tell me how to convert pico into ghz. and pico to sec?
@minhvu88938 жыл бұрын
psec=10^(-12) sec and ghz=10^9 hz (hz=1/sec)
@jaihosabkijhs82364 жыл бұрын
@@minhvu8893 for this google is there
@AbhijeetKumar-pk8tg3 жыл бұрын
why the first one is not a sq wave generator while 2nd is sq wave generator
@worldwibeweb7133 Жыл бұрын
I feel like this course is not for a complete beginner who haven't even heard the term Logic gate in their life hahaha.
@harshavardhanreddy79985 жыл бұрын
Here feedback is only for generating square wave(in this situation only), we only consider total output delay, so for each state we get 8nec delay and so total time period is equal to 16nsec. So q2 ans:: 16nsec, think about it.
@granthiksen35776 жыл бұрын
for the 2nd one the answer will be 14tpd or 28 ns say you have 0 as input so after 4tpd Y is still at 0 but after 3 tpd the feedback comes into play and feeds 1 back to 1st NOT gate so after 4 tpd that 1 has come out of the 1st NOT gate as 0..this passes another 3tpd to become 1 at Y so you have 4+3 = 7 tpd for the signal to change from 0 to 1 so a cycle will be of 7+7 = 14 tpd = 28 ns
@kingcm1273 жыл бұрын
14 tpd for only 1st cycle After 1st cycle it's 12 tpd
@__Azmah2 жыл бұрын
According to me the answer of question 2 is 12ns cuz the question is saying to find the time period of generated square wave .. So first three NOT gates are making square wave ... So we have to calculate with respect to these 3 gates... So answer will be 12 ns... Plzz tell me if i m wrng @nesoacademy
@refreshment5676 жыл бұрын
i think second one will be 12ns because consider y=0 then the input for that gate is 1 if we analyse this then from 0 to 6ns waveform is high 6ns to 12ns it will be low so time period is 12ns .now this square pulse is passed through not gate which will just convert 1 to 0 and 0 to 1 this will not ofcourse change time period or frequency so 12ns is correct
@suvarnasunkari21598 жыл бұрын
Hi Sir.Your explanation is very good.Thank you.I got option 'B'' for first prob and option 'C' for second prblm.Could u plz solve the second prblm and upload it.
@bhanuprakashreddy6 жыл бұрын
For second one answer is 12ns. Why because after the third not gate we can generate a square wave and also there is no feed back for the 4th not gate. But the delay is 2ns already We know that if any signal may be transmitted to the delayed device that will produce that output after that delay only. Hence in the given problem they are asking calculate the time period of the generated signal. Hence after passing the generated signal through the NOT gate we will get an output in the form inverse after 2ns time delay but time period is same. Hence don't consider the 4th NOT gate of while calculating the time period of generated square wave. Hence ans:12ns I hope it is useful to everyone
@akshaynarwade21046 жыл бұрын
ques 2 ans is 12ns square wave generator is not gate in series and last is gate is just to delay the o/p. hence 2*3*2=12 ns
@basantadhamala37156 жыл бұрын
In q1. Even without the feedback isn't the circuit going 2 give the same results? Why is not a buffer, if it has feedback.?
@krmanish0435 жыл бұрын
dear ne so ....plz provide the sol of h/w problem as well
@ultratechnicalideas33563 ай бұрын
Sir plzz combine all videos in one shot of 2-2.5 hr according to the topic
@stargirl10743 ай бұрын
I didnt understand in first example why the circuit was not buffer ... someone pls explain ... and why feedback was the reason to not being a buffer.
@RajuKumar-jl3bq5 жыл бұрын
why is example 1 not squar wave generator?
@ramamurthy79375 жыл бұрын
Hi sir, Why xor and xnor are called arithmetic gates even though they don't perform any arithmetic operations
@r.dineshkumar39844 жыл бұрын
used in half adder and half subtractor
@EEEAREA3 жыл бұрын
There are 2 not gates connected in series. For first not gate logic 0 is the input. Second not gate output is Ored to input of second gate only. What is the optput sir
@sudhanshusharma45946 жыл бұрын
2nd ans is 6ns that is a option.because the square wave is generated by the feedback circuit which has only 3 diode and 4th diode will take its delay time and just reverse the input signal nothing more than that
@geetikagogoi80457 жыл бұрын
Problem 1: 1 GHz for problem 2 is it 12 nsec?
@PradeepYadav-fg2yg3 жыл бұрын
no
@piyughosh45423 жыл бұрын
first problem- 1GHZ.. second problem for simplification take the point after 3 NOT gates as X. now make a graph of X. After that to get the output Y take the graph of X, each time X changes add a delay and invert the value and there you have Y. you'll see X and Y have the same time period only Y is 2nsec lagging. Ans is 12nsec
@WesleyFrt2 жыл бұрын
nice explanation
@sytk36945 жыл бұрын
What is the 2nd answer? Last gate propagation delay has to be counted?
@mdnoorullah5634 жыл бұрын
Thx sir but kindly discuss h.w problem in next lecture
@jayeshshukla23136 жыл бұрын
in the last hw problem the output would be same as input as there are 4 not gates so when we give 0 at the input after 8ns 0 will be obtained at the output while at 6ns the feedback will provide the signal 1 to input and during the time of 2ns in which the first 0 input will cross the last not gate this 1 will cross the first not gate and after crossing the rest of 3 not gates i.e after 6ns more the signal 1 will be recieved at the output and will last for 6ns till the next signal is recieved at output so conclusion is the time period is 12ns but initially there was a time lag during the start of generation of the square wave. correct me if i am wrong.
@umamaheswari85636 жыл бұрын
Need answer for the second question
@snehashishbanerjee25753 жыл бұрын
🔴H/W problem 1: Solution: frequency f = 1/T Given~ n= 5, tₚₔ= 100ps = 100 × 10^(-12) s So, f = 1/(2 × n × tₚₔ) = 1/(2 × 5 × 100 × 10^(-12)) = 1/(10^(-9)) = 1 GHz ✔️ans: Option (b) 1 GHz ................................................................. 🔴H/W problem 2: Solution: Time period T = 2 × n × tₚₔ Given~ n = no. of NOT gates in feedback loop = 3, tₚₔ= 2 ns So, T = 2 × n × tₚₔ = 2 × 3 × 2 = 12 ✔️ans: 12 ns
@deepannandy72882 жыл бұрын
And what about the last NOT gate in problem 2?
@snehashishbanerjee25752 жыл бұрын
@@deepannandy7288 Consider only those NOT gates which are there in the feedback loop.
@nithishnagendra Жыл бұрын
@@snehashishbanerjee2575 the last one is also there in the loop
@mayasmahmed84712 жыл бұрын
great explation for problem , I have question how i can draw tpd Idont really catch the idea could you help me?
@HelloWorld40408 Жыл бұрын
Thank You Sir
@nikhilteja14806 жыл бұрын
sir what if we took 1st input as 0,in that case after 5th Tpd aslo we get output 0 then signal would be low.
@somtouraih449010 ай бұрын
The first tpd question. How come the first 1 wasn't represented in the time diagram?
@rakshitagupta2936 жыл бұрын
In example 2 being explained, please tell Why it is astable multivibrator?
@markanthonyoccena73453 жыл бұрын
thank you, really helpful.
@umairfarooq31608 жыл бұрын
sir plzz upload the solution of 2nd problem
@akhileshyadav98624 жыл бұрын
Odd priority me kuchh change hogq???
@prakasharja5695 жыл бұрын
can you explain about cmos using all logic gates in one video it is very useful
@nitishkumarprajapati60962 жыл бұрын
Thanks Sir😃😃
@BTSArmy-xn9fz5 ай бұрын
Tpd = 2nd 2*ntpd= 2*3tpds= 6tpd Each tpd = 2ns Finally 6*2= 12 Ghz I understood like this
@curesnow64933 жыл бұрын
Do you have the bubble pushing example video?
@025-anuragruhal84 жыл бұрын
how many transistors are in NOT , AND ,OR gate?
@hafsamahmood55654 жыл бұрын
Do you have any playlist for computer architecture and logic design?
@osamaelzubair12039 ай бұрын
Can someone expalin how to get the answer to question number 2 ?
@chandrashekharchandu92846 жыл бұрын
i don't think the second circuit generates a square wave at all....or if it does can someone please explain?
@yeezy_on_sterr24426 жыл бұрын
Great video ! One question though. Why do we multiply by two when we have 5 NOT gates if the function repeats itself after 5tpd and not 2*5tpd ? Thank you
@r.dineshkumar39844 жыл бұрын
on and off period 2 know
@nakulasahadevudulatchi50783 жыл бұрын
what is the answer for second home work problem. please send answer sir.
@anilmacharla69397 жыл бұрын
Thanks a lot...I owe to u sir.
@kabandajamir98442 жыл бұрын
So nice
@developerNik Жыл бұрын
In this video : logic gates are the physical device that perform logical operation on logical input and produce single logical output. three types basic: AND , NAND , universal: NAND,NOR , arithmetic : XOR,XNOR NOT -->O
@balaramsharma496628 күн бұрын
yes q1 ans is 1Ghz and q2 ans is 12 ns
@vysaghthambi16243 жыл бұрын
Is there any possibility to adding of noise to the parity bits??
@rohitsutrave86093 жыл бұрын
Good question S it is
@sandipdas56842 жыл бұрын
What is the case if noise occurred in parity bit?
@dadiindrasenareddy58022 жыл бұрын
2nd question Answer is 12nsec. T=2*n*tpd //n=3,tpd=2nsec T=2*3*2nsec T=12nsec
@zynthos98 жыл бұрын
I get choice b for both
@yogeshagarwal92993 жыл бұрын
at 12:44 how they made diagram , they said time after first tpd y is zero , how
@KonduruMounikashetty6 жыл бұрын
Sir,can you tell me the how to convert the last answer psec to Ghz ??????
@avinashsingh9065 жыл бұрын
not gate me more input kiss type se de sakte h
@learnwithmanu56558 жыл бұрын
Sir can you please upload the videos on 8085 microprocessor
@gyanig85014 жыл бұрын
@nesoacademy The website is not functional in many ways. I can help
@madhavirathi60043 жыл бұрын
Please tell the answer to second que
@sahil13072 жыл бұрын
Please explain 2nd question
@arjitgiri22713 жыл бұрын
Where do we get the answers to HW problems? Ur website is showing a 404 error at that page.
@rashmipatel41243 жыл бұрын
Please post your solution of 2 question
@jubinkashyap5027 Жыл бұрын
In a logical system consisting of a feed backloop ,,,,,,, the processing time will be....... 2 x Numbers of NOT operators inside the feedbackloop System x timeDelay.
@CalebDiT7 жыл бұрын
1. None of the above. Y changes every 100 ps because the fifth inverter changes every 100 ps. It does not wait 500 ps to change. That gives it a period of 200 ps, and a frequency of 5 GHz. 2. None of the above. Y, again, will change every 2 ns because that's the t_pd of the final inverter. In other words, the final inverter receives a new value every 2 ns. That gives Y a period of 4 ns. Or am I missing something? Also, your website is giving 404 errors when I try to access the homework solutions.