newton raphson method of numerical methods || Statical method || SNME

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Dev prit

Dev prit

9 ай бұрын

newton raphson method of numerical methods || Statical method || SNME
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newton raphson method of numerical methods || Statical method || SNME
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Пікірлер: 15
@raviroy7941
@raviroy7941 29 күн бұрын
Bahut aacha se aap samajye sir. 👍👍
@chhotu_J.E
@chhotu_J.E 5 ай бұрын
Nice sir
@sharikanayak8974
@sharikanayak8974 2 ай бұрын
Thank you sir
@iamrohini
@iamrohini 7 ай бұрын
@rukhsarkhatoon-yf9wg
@rukhsarkhatoon-yf9wg 6 ай бұрын
sir mera x1 ki value 1.964 aa raha h mujhe lagta h aapki x1 ki value galat h
@radhikamohan2191
@radhikamohan2191 7 ай бұрын
Hlo sir mera exam ha 28 ko toh mene yeh qution solve Kiya ha ..... Mene 2.5 ki jgga 3 choose Kiya ha or mera answer 0.607 aya ha
@rishisingh5841
@rishisingh5841 7 ай бұрын
Kyy kre
@Ashoka_bhat
@Ashoka_bhat 26 күн бұрын
Or else you can take the value Which is nearer to 0 as x0. Like in this question f(2)=-1 which is nearest to zero compared to f (3)=16 . Hence we can take x0=2
@mamooransari526
@mamooransari526 6 ай бұрын
Ek question h agar equation positive m hoto, f(x) negative m aa hi nhi paayega toh kaise solve hoga ?
@saurabhkumar-rl2we
@saurabhkumar-rl2we 6 ай бұрын
X ko negative value mein lo like -1,-2,
@mamooransari526
@mamooransari526 6 ай бұрын
@@saurabhkumar-rl2we thanks 👍
@radhikamohan2191
@radhikamohan2191 7 ай бұрын
Kya yeh sahi ha answer ha
@proadvices8592
@proadvices8592 7 ай бұрын
Nahi inki x1 ki value he galat hai
@rukhsarkhatoon-yf9wg
@rukhsarkhatoon-yf9wg 6 ай бұрын
@@proadvices8592 kya aapka x1 ki value 1.964 aa raha h
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