I loved your way of explaining. Always recheck anything before you publish because you included a mistake in the final calculation. Well done.

Hi all, I made this video 8 years ago when I was in 11th grade. I had to make this for school and had no ambition to make chemistry videos. As people have pointed out, there's a mistake in the calculations. Sorry that happened, please note what people have commented about the end. Keep in mind this was made by 16-year-old me. I never went on to study chemistry past first year university, I study philosophy now. I'm never remaking this, but some people found it helpful so that's why I never deleted it. Much love.

Although a few errors were made, I thought the presentation was excellent. I see she has no other videos. I hope she wasn't discouraged. I would like to see more from her.

-log(1x10^-7) is 7 not 1.9 this could be very confusing for some people, please fix the error and re post

The question contradicts from your answer in ex.3 In Q the value is 1.2x10^-7 whereas in the answer it is 1.0x10^-7 Also the calculation is a total error as -log10^-7 does not equals 1.920... rather its just 7. So I'd suggest you to fix it ..ma'am

pls continue thanks to you this topic has been easy for me but for the last part you made a mistake pls continue

Thanks mam I am from India

I love this, thank you. You're awesome.

Well ....i understand here ...a big thank you #mam

Hi Alena, your last problem is calculated incorrectly - the pH is about 6.62, and the pOH 7.38 for 1.2x10^-7 sulfuric acid. Since the sulfuric acid concentration is of the order or 10^(-7), the pH can't be very different from 7.0

Thanks a ton, ma'am!!!

THANK YOUU

For Ex. 3 at 5:50, you changed the [H+] concentration from 1.2x10^-7 to 1.0x10^-7 when you simplified the problem. Kinda confusing

Thanks for the help but omg so confusing when you made the few mistakes.

How many times stronger is the hydrogen ion concentration of pH 4 solution as compared with a pH 9 solution

this is very informative but i have a problem.... i cant use my calculator properly; so can u do a repost or something to add how to use your calculator to get the answer for the H3O+ ph at the video time 4.38 mins

can you explain how did you come up with 6.3 X10^2 M please

Hey please help me i can't get the correct answer for Ph in ex 3 my answer is 7 ?

thank you

In the 3rd problem you could've used the following formula, which is MUCH shorter: Kw = [H₃O+][OH-] (Kw = 1 * 10^(-14))

At 5:00 You need 3 significant digits because leading zeros don't count!

When you were 1.9 what you do

Kya bata rahi hain kuch samj nhi a raha.....?

When tommorow is ur exam

You are doing good but in INDIA we should not use calculator we should use our brain..

damn, so confusing.. I thought I got it wrong but I went over the solutions and tried it over and over again then I realized..the tutorial is wrong.-log 1.0x10^-7.1 is actually 7. hahaha.

useless. no one can teach this topic correctly. I applaud you for trying.

In her 3rd problem its 1.2x10 now its 1.0. Then the answer is different. You have to delete this video. And make a new one because its confusing.

the last part is confusing as hell 😭😭

You didn't calculate it. Please some error is there fixed it.

Speak in hindi ok English girl ph what speepking phich h

Hi medam,u write directly answer

PLEASE DONT DRINK AND TEACH

thank you