Visit ilectureonline.com for more math and science lectures! In this video I will give a summery of isobaric, isovolumetric, isothermic, and adiabatic process.
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@byhariee5 ай бұрын
Thankyou so much. This video was published 10 years ago when i was i like 4th grade and u still replying to all the doubts in the comments. Absolute Lengend.
@MichelvanBiezen5 ай бұрын
Thank you. It is great to interact with our viewers.
@gift22999 жыл бұрын
people like you are the true heroes of the world.
@collinthomas79013 жыл бұрын
I’ve been stressing about my physics final all day, thank you for this
@MichelvanBiezen3 жыл бұрын
You’re welcome 😊
@spoon49744 ай бұрын
Seriously, you're a real life hero for this video. College students everywhere are grateful.
@MichelvanBiezen4 ай бұрын
Not a hero. Just glad my wife and I can give back a little to the world.
@emanueleg.41063 ай бұрын
COLLAGE???? it’s 10th grade here in Italy. 🙃
@winner13384 жыл бұрын
I've watched a lot of vdo's about interference of light, including yours vdo's: Physics - Interference of Light The Thin Film. And i passed for physics. Thank you so much. Now i'm back for Thermodynamics.
@billymushoke63704 жыл бұрын
You Tube is really helpful to us because it makes us understand things even lectures and anything you would like to research about .
@nigelvanlaethem3860 Жыл бұрын
This is probably the most important video in this chapter. Thnx!
@MichelvanBiezen Жыл бұрын
Definitely a good summary. 🙂
@mostafaabdelrauof31858 жыл бұрын
God bless you man , "your follower from Egypt"
@sandisomatu1131 Жыл бұрын
I've been stressing over my computer skills exam all day thank you for this
@MichelvanBiezen Жыл бұрын
Glad you found our videos. 🙂
@MichelvanBiezen9 жыл бұрын
Samual, The equation for delta U (change in internal energy) is always: delta U = n * Cv * delta T
@haelrapal7335 жыл бұрын
sir, shall we use n or m?
@winner13384 жыл бұрын
this is the most asking question i will remember this, no matter what happens, sun explode, my cat dying, end of the world, my bike got stolen, no more pepsi, 1/0 is defined, etc. delta U will always be n * Cv * delta T
@anilsharma-ev2my4 жыл бұрын
What is Aneroid barometer efficiency ? Please found for shake of universe ?
@mohamedmagdy2993 жыл бұрын
∆
@MBhoodai7 жыл бұрын
Great summary! Very helpful to recap information a few days before my thermo I exam. Thank you.
@tamashamas61933 жыл бұрын
Cleared up a few confusions I’ve been having thank you so much
@MichelvanBiezen3 жыл бұрын
Glad it helped!
@AlmostCow10 жыл бұрын
Thank you for these amazing classes..
@zainkhan-xz6mc5 жыл бұрын
A really amazing and helpful video to build up the concept. Sir can you make a video on the polytropic process.
@abrahamabraham25835 жыл бұрын
very simple and easy to understand thank you
@Worldmemes42 жыл бұрын
Another semester...and we are starting with thermodynamics...good work my eistein
@MichelvanBiezen2 жыл бұрын
We have a lot of videos on thermodynamics. Enjoy!
@Worldmemes42 жыл бұрын
@@MichelvanBiezen Nice i will check out ✍️✍️✍️💪
@capcan239 жыл бұрын
Mr Biezen, I just started thermodynamics, and your videos are really great help.I wonder if you can explain about Polytropic Process, I been taught that there are 5 processes, and polytropic process is one of them. Would be great help if you can. Thanks
@MichelvanBiezen9 жыл бұрын
Mubashir The general equation is: PV^n = C where C is a constant note that the ideal gas equation is: PV = nRT Draw the PV^n = C equation for different values of n and you'll see an interesting pattern. start with n = 0, then n = 1, n = 2, etc.
@Thelydiariley6 ай бұрын
Love this explanation, easy to follow
@MichelvanBiezen6 ай бұрын
Glad you liked it.
@ValiBee876 жыл бұрын
This was extremely helpful , thank you so much
@isabellambert10115 жыл бұрын
Love this summary, I just copied it down, now I’m gong to go take my quiz. Thanks.
@physicsloverjoinmychannel29373 жыл бұрын
Thanks! From Ethiopia
@MichelvanBiezen3 жыл бұрын
Welcome to the channel!
@gauravkotkar3731 Жыл бұрын
Excellent summary!
@MichelvanBiezen Жыл бұрын
Thank you. Glad you liked it! 🙂
@physicsloverjoinmychannel29372 жыл бұрын
In Isothermal Process Change In temperature Is ZerO B/c Of Constant as We Know Q=MC Change In Temperature So We Say temperature Is Constant For Isothermal Process Why Heat Become Zero? pls Teacher Answer It It Confused Me A Lot
@MichelvanBiezen2 жыл бұрын
In an isothermal process, the temperature remains constant, which means that the internal energy of the gas remains the same, which means that if the gas does work, (by expanding), then this energy needed to do work must come from somewhere else (head added to the gas). Therefore W = Q (the work done by the gas is equal to the heat added to the gas).
@pipertripp8 жыл бұрын
that tie is excellent!
@yogeshmandrekar1777 Жыл бұрын
Very well explained…thank you
@MichelvanBiezen Жыл бұрын
You are welcome! Glad it was helpful.
@likestomeasurestuff35544 жыл бұрын
I appriciate this channel
@YeshanewTeamru Жыл бұрын
NICE TO SEE YOU
@MichelvanBiezen Жыл бұрын
Hope you like the videos. 🙂
@miracle3.1887 ай бұрын
Do we use different sign conventions in physics thermodynamics? In my chemistry textbook, the equation is dU=dQ+dW In my physics textbook, the equation is dQ=dU+dW
@miracle99xD7 ай бұрын
Earlier negative sign was assigned by the work is done on the system and positive sign when the work is done by the system . this is still followed in physics books , although IUPAC has recommended the use of new sign convention..
@MichelvanBiezen7 ай бұрын
dU = dQ + dW: The change in internal energy of the gas is equal to the heat added to gas + the work done ON the gas. dU = dQ - dW: The change in internal energy of the gas is equal to the heat added to the gas - the work done BY the gas
@felino5334 Жыл бұрын
The man literally saved my physics final
@MichelvanBiezen Жыл бұрын
Glad to hear it. Good luck on your final! 🙂
@Eric-sq4hd4 жыл бұрын
this guy is a true baller
@latifurrahmanzihad7 жыл бұрын
love you,the great teacher............
@farooquiphysics4583 жыл бұрын
Love from India 🇮🇳🙏 thanks sir
@MichelvanBiezen3 жыл бұрын
Welcome to the channel!
@bhavyaramakrishnan8012 жыл бұрын
In an isochoric process how do you know the change in pressure is constant and not exponential?
@MichelvanBiezen2 жыл бұрын
That is so by definition. An isochoric process is defined as the volume changing while the pressure remains constant. W = P x delta V
@parisashahabi50672 жыл бұрын
Thanks for the clarification!!
@MichelvanBiezen2 жыл бұрын
Glad it helped.
@wesleyblack8302 Жыл бұрын
why for p,v,t we associate the names with the change of the variables ex.(change in pressure/temp/vol = 0), but we just say heat = 0 instead of saying 0 change in entropy in the adiabatic case. is it to avoid students asking what entropy is?
@MichelvanBiezen Жыл бұрын
No, that topic is covered at a later time. Typically we don't mention entropy yet, during the introduction to the adiabatic process.
@ganeshgs22412 жыл бұрын
Superb sir!
@MichelvanBiezen2 жыл бұрын
Thank you
@Blessings-rw3qt4 ай бұрын
Does anyone know why ∆U is sometimes written as equal to mC∆T and sometimes equal to nC∆T , which one is correct? Or when should either be used?
@MichelvanBiezen4 ай бұрын
When we are dealing witn gases it should be delta U = n c delta T n = number of moles For solids and liquids we typically use m for mass (in kg)
@Blessings-rw3qt4 ай бұрын
@@MichelvanBiezen alright, I think I get it now. Thank you.
@johannwegmann43655 жыл бұрын
Thanks to Professor van Biezen, Please clarify in Isovolumetric Process,V=cte, what is de Heat Rejection in pulsejets,Lenoir cycle, Q, expression, regarding Thrust Force on 50 Hertz or cyles /sec.? Kind Considerations,Thankfully,Johann Wegmann.
@fitrijaafar70915 жыл бұрын
Thank you so much sir
@maxtabmann6701 Жыл бұрын
Are you able to tell me how you practically change the volume without changing the pressure? My professor always avoided this detail. And later I found no book that looks at this question. My thoughts to this are all useless. I thought one could punch a hole in the back side so that the exess air can escape, but then this would mean that the pressure outside must be the same as inside, otherwise the volume would adapt to the outside pressure. But if the pressure outside is the same as inside, whats the point of defining a volume here?
@MichelvanBiezen Жыл бұрын
Take a container and place a sliding lid at the top (like the piston of a car cylinder). Place a mass on top of the lid, such that the force remains constant and hence the pressure remains constant. If you heat the gas, it will expand under constant pressure.
@maxtabmann6701 Жыл бұрын
@@MichelvanBiezen I see! Thus you do not change the volume yourself, but allow it to change when it gets heated or cooled, using a piston that excerts a constant force. Thanks, this makes it all understandable. The temperature does not change due to a change of volume but it gets changed by adding thermal energy. Thus cause and effect are reversed. Cause is the heating and effect is the volume change. Thanks!
@MichelvanBiezen Жыл бұрын
That is correct.
@stephanihab7 жыл бұрын
Thank you sir for your huge effort
@SEAndies5 жыл бұрын
Thank you!
@carlosnunez-eddy25332 жыл бұрын
what is the significance of the red lines on eitherb sides of the isthermic and adiabatic P x V graphs?
@MichelvanBiezen2 жыл бұрын
The red line are isotherms (along which the temperature is constant). That way you can compare the isothermic and adiabatic process.
@mattbiss64147 жыл бұрын
Great summary, thanks!!
@sanft60702 жыл бұрын
Great video, i love your bow tie!
@MichelvanBiezen2 жыл бұрын
Thank you! 😊
@AndreaNBAYER8 жыл бұрын
just excellent !. thanks for all the videos
@miracle99xD7 ай бұрын
Isovolumetric process and isochoric process , both are same thing ???
@MichelvanBiezen7 ай бұрын
That is correct. Older text books use the term "isochoric", but newer textbooks use the term "isovolumetric"
@huzaifamehmood29662 жыл бұрын
Hi could you tell me the relationship between the pressure and temperature in an adiabatic process please?
@MichelvanBiezen2 жыл бұрын
TV^(gamma - 1) = constant
@JohnVKaravitis3 жыл бұрын
5:24 Delta U = n*Cv*delta T is ALWAYS true!
@carultch2 жыл бұрын
That is an approximation that Cv is independent of temperature, which is approximately true, but not completely true. The complete formula is delta U = n*integral Cv dT, from T=Ti to T=Tf. Or: dU/dT = n*Cv
@favvee2 жыл бұрын
If work is done on the system, is it going to be negative sir
@MichelvanBiezen2 жыл бұрын
It depends on how "it" is defined. First we need to know what the "it" is. Let's define the first law of thermodynamics: The change in the internal enegy of the gas is equal to the heat added to the gas minus the work done by the gas. Using that definition, when the gas does work it is positive work and when work is done on the gas (by compressing it) it is negative work.
@AkshayVasant6 жыл бұрын
Hi Sir, since you are teaching thermodynamics from the pov of Physics, I think it will be better if you describe work as "work done by the system" instead of 'by gas', because I got confused for a moment, if this was chemistry or physics. I hope I made sense and sorry if I didn't.
@MichelvanBiezen6 жыл бұрын
It is done both ways, and varies by text and author.
@cristinamarquez33483 жыл бұрын
Thank you sir.
@MichelvanBiezen3 жыл бұрын
Most welcome
@nellvincervantes32234 жыл бұрын
On isothermic sir, Q = W, will it violate 2nd law of thermodynamics? Where all heat cannot be converted into work? Sorry im just confused.
@MichelvanBiezen4 жыл бұрын
No it doesn't violate the 2nd law of thermodynamics. Only the heat added is converted to work.
@shinkizoku9705 жыл бұрын
Sir, how about polytropic process?
@MichelvanBiezen5 жыл бұрын
What is the question?
@vivekkumargupta12217 жыл бұрын
Splendid ....
@qiqiz42903 жыл бұрын
thank u so much! ur videos are very useful!!!
@MichelvanBiezen3 жыл бұрын
Glad you like them!
@sandisomatu1131 Жыл бұрын
Where be the thermodynamics playlist
@MichelvanBiezen Жыл бұрын
There are about 10-15 thermodynamics playlists on this channel. They can all be found easily from the home page. Let us know if you have trouble finding them.
@chriskoperniak7849 жыл бұрын
At the 4:30 mark where you calculate the work done during an adiabatic process: how are you justified in stating that the volume remains constant (and hence the selection of your constant volume equation) ? I thought all 3 variables (volume, pressure, temp) are permitted to change during this process.
@MichelvanBiezen9 жыл бұрын
Chris I did not state that the volume stays the same. I used the equation for change in internal energy.(which uses Cv) (notice that V2 - V1 is not zero)
@larryzdanis53773 жыл бұрын
This is a fantastic comparison of these processes. Please verify where an "isentropic" falls amongst these.. I know that isentropic is both adiabatic and reversible, so would it be the same as the adiabatic -does the adiabatic equation for work presume reversibility ??
@MichelvanBiezen3 жыл бұрын
An isentropic process is just a special case of the adiabatic process. Therefore it would not represent a "fifth" process.
@carultch2 жыл бұрын
Yes, the adiabatic equation for work assumes reversibility. Adiabatic and reversible, collectively form the term isentropic. If there were irreversibility, it would mean there are inefficiencies in the change of internal energy and work done. The extreme case of an irreversible adiabatic processes, is called an isenthalpic process. The Joule-Thompson effect is an example of this.
@iraqson6665 жыл бұрын
Thanks so much sir.. big greeting from iraq
@almacyrenable Жыл бұрын
Is the isovolumtric same as isochoric process
@MichelvanBiezen Жыл бұрын
Yes it is. The current editions of physics textbooks now use "isovolumetric".
@sebastiandierks79193 жыл бұрын
There is a typo in the thumbnail, should be a c_p (instead of c_v) for Q at the isobaric process.
@MichelvanBiezen3 жыл бұрын
Good catch. Thank you.
@danmcginn90027 жыл бұрын
Do you call the process of converting a solid to a liquid through a change of pressure 'melting', or is there a more precise term?
@MichelvanBiezen7 жыл бұрын
It is technically a change of phase due to the change in pressure.
@adarshvlogyzfr15v365 жыл бұрын
well explain sir .. thank u
@binyamin37477 жыл бұрын
very good sir van
@fatmajjjxx25095 жыл бұрын
So nice
@elamaneceroscuro3 ай бұрын
Bro but PV^5/3 is constant in adiabatic
@MichelvanBiezen2 ай бұрын
That statement was referring to the state variable. None of the state variables are constant in an adiabatic process.
@brave3856 жыл бұрын
where is polytropic process?
@carultch2 жыл бұрын
Polytropic processes are the general case where P*V^n = constant. n has nothing to do with the number of moles, but is called the polytropic index. It can be any number from 0 to +infinity. All of these processes are special cases of the polytropic process. Isobaric, n=0 Isothermal, n=1 Adiabatic/isentropic, n = k, where k is a substance-specific constant. For air and 2-atom elemental gasses, k=1.4. Isochoric, n=infinity
@sarujanrupan4831 Жыл бұрын
At @5:04 how come it's Csub(v) and not Csub(p) as pressure is constant?
@MichelvanBiezen Жыл бұрын
Yes, that is a common source of confusion. Cp only applies to the heat exchanged (Q = n Cp delta T) But regardles of the thermodymic process we always use Cv for delta U Delta U = n Cv delta T for all processes.
@sarujanrupan4831 Жыл бұрын
@@MichelvanBiezen Mm ok thank you.
@lini48654 жыл бұрын
This is great!
@youssefrefaat15946 жыл бұрын
Sir, please read this question. What are these red lines that you draw on the graph?
@MichelvanBiezen6 жыл бұрын
The red lines are called: "ISOTHERMS" They represent lines on the PV diagram along which the temperature remains constant. An isothermic process is drawn parallel to isotherms.
@ashw7304 жыл бұрын
Hi TY for this well explained video. Just a question Isnt delta U= W+Q My lecturer taught like that. 🤔
@MichelvanBiezen4 жыл бұрын
It is Q + W when it is work done ON the gas and Q - W when it is work done BY the gas. The first law of thermodynamics is expressed both ways. I prefer the second way.
@historyisthebest58314 жыл бұрын
Yes so when work is done by the gas, the W is positive and the equation is delta U = Q - W. The minus sign is not representing the sign of W so W is still positive here. But if work is done ON the gas, then W becomes -W. delta U = Q - (-W) equals delta U = Q + W.
@linakasi4034 жыл бұрын
Thanks a lot
@briandiscala5 жыл бұрын
I'm curious, for an Isobaric process, wouldn't Q = nCv delta T and delta U = nCp delta T, as Cp is really Cv + R
@MichelvanBiezen5 жыл бұрын
By definition, delta U is always equal to: delta U = n Cv delta T regardless of the process
@pranaysai7713 Жыл бұрын
Sir, for isothermal process isn't delta Q 0 becoz delta t is 0???
@MichelvanBiezen Жыл бұрын
In an isothermal process the internal energy remains the same (delta U = 0) since the temperature is constant. But when the gas expands, it is doing work. Since the energy cannot come from the internal energy, it must come from the heat added to the gas. Therefore work done = Q received.
@pranaysai7713 Жыл бұрын
@@MichelvanBiezen sir that's ok but what about the formula?Q = nCdt?? Dt is 0... pls clarify
@MichelvanBiezen Жыл бұрын
That equation is ONLY valid for an isobaric process or an isovolumetric process, but not for an isothermic process.
@user-yp6js1uh6d4 жыл бұрын
Thanks.. ❤️🇸🇾
@peterv6i10 жыл бұрын
thank you
@user-my8ll6lw4q8 ай бұрын
my professor didnt need to everything sooo complicated
@MichelvanBiezen8 ай бұрын
Once you see that commonality and the reference to PV = nRT and the first law of thermodynamics it will make sense.
@Andalfulfulde9 ай бұрын
You're cool, What about ISOCHORIC processes😢
@MichelvanBiezen9 ай бұрын
Isochoric and isovolumetric is one and the same. = constant volume The term isochoric is not used anymore in most newer textbooks.
@Andalfulfulde9 ай бұрын
@@MichelvanBiezen okay Engineer, I appreciate you. Please what about "betta and kappa" coefficients for university thermodynamics, am searching for it on your playlist but seeing nothing
@MichelvanBiezen9 ай бұрын
Are you referring to the coefficients of expansion? You need to specify what the coefficients are for..
@Andalfulfulde8 ай бұрын
@@MichelvanBiezen yes sir
@bodotimesmusic46975 жыл бұрын
Thanks a
@ashleym936910 жыл бұрын
for an isobaric process why can C_v be used for internal energy? I thought that was for constant volume only?
@MichelvanBiezen10 жыл бұрын
Ashley, Yes, this is often confusing to students. The internal energy of a gas is only dependent on the temperature and Cv. The internal energy of a gas should not depend on how the gas got into that state. But the heat added or taken out of a gas does the depend how the gas changes (via constant volume or constant pressure). So remember, delta U = n Cv delta T.
@Peter_19869 жыл бұрын
Michel van Biezen I have always thought of it like this - constant volume means that no work is done, therefore dW = 0, and dU = dQ. And since in this case dQ = n*Cv*dT, this also means that dU = n*Cv*dT, and thus dU = n*Cv*dT would then be true for all other processes as well. Something like that.
@MichelvanBiezen9 жыл бұрын
Laurelindo That is a good way of defining it.
@iliekmathphysics4 жыл бұрын
why do we use cv even when volume is changing?
@iliekmathphysics4 жыл бұрын
okay here’s what I’m thinking: (I’m not taking thermodynamics at the moment). I think it is that “delta U = Cv delta T” is simply the definition of Cv and therefore it can be applied to any process since U is a state function. Also the ‘constant volume’ aspect of the specific heat capacity only depends on the fact that we’re dealing with gases. Assuming that these are ideal gas conditions, Cv would be the same for monatomic gases, and same for diatomic gases (though different for each category) since the only type of energy contained in it is kinetic energy, which is directly related to temperature and internal energy
@MichelvanBiezen4 жыл бұрын
The change in internal ALWAYS uses Cv.
@historyisthebest58314 жыл бұрын
Hi sir sorry just a question. In my textbook, there's also a statement says that in every cyclical process, heat transfer must occur from the system in order to get a net work output. But why is that? Been digging Thermodynamics lately and sometimes my brain is just slow.
@MichelvanBiezen4 жыл бұрын
Since the internal energy of the gas is the same when you end up at the state you started from, the energy needed to get the work done must come from somewhere else. (therefore the heat gained) First law of thermodynamics: change in internal energy (which = 0 for a cyclic process) = heat added - work done No heat added means no work done.
@historyisthebest58314 жыл бұрын
@@MichelvanBiezen Oh I get it! Thank you I understand now! Thank you!
@historyisthebest58314 жыл бұрын
@@MichelvanBiezen Yes but the question is saying that heat must transfer out in order to get a net work output?
@MichelvanBiezen4 жыл бұрын
In order to perform work, heat must travel into and out of the process. But more heat goes in than comes out. The difference is the work done. I suggest you watch the rest of the videos and this playlist: PHYSICS 27 FIRST LAW OF THERMODYNAMICS and PHYSICS 28 CYCLIC PROCESSES and PHYSICS 29 EFFICIENCY OF HEAT ENGINES for a good understanding of this topic
@historyisthebest58314 жыл бұрын
@@MichelvanBiezen Okay thank you!! Actually I already watched almost all of the videos in your suggested playlists but I will watch them again. Thank you though!
@abdelrahmanahmedfouad20842 жыл бұрын
5 days left to my final physics exam
@MichelvanBiezen2 жыл бұрын
All the best on your final!
@abdelrahmanahmedfouad20842 жыл бұрын
@@MichelvanBiezen thank you ❤️❤️
@KashifKhan-xo7ym4 жыл бұрын
What is n sir
@MichelvanBiezen4 жыл бұрын
n represents the numbers of mols of the gas
@PauloJAdams3 ай бұрын
you are a g.
@MichelvanBiezen3 ай бұрын
Not in the least. Just a simple man with lots of faults.
@kartikey02086 жыл бұрын
Reversible or irreversible process ? The most important point is missed lol😂
@theprofessor21293 жыл бұрын
Hehehe ideal gas is used in thermodynamics not reactive gases lol