Visit ilectureonline.com for more math and science lectures! In this video I will find the capacitance of a capacitor with 2 dielectrics with various thicknesses. Next video can be seen at: • Physics 39 Capacitor...
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@thomasnell84374 жыл бұрын
You have literally taught me more about electromagnetics than my acutal electromagnetics lecturer
@AntoAparicio5 жыл бұрын
Thank you very much for your work Michel, I wish I had a professor like you. It was clear, simple and short, as it should be.
@stephaniestampher69815 жыл бұрын
There is a tiny violin in the lower right corner lol
@MichelvanBiezen5 жыл бұрын
Good observation.
@stephaniestampher69815 жыл бұрын
Thank you for the video, it helped me so much on my quiz today :)
@nlo1144 жыл бұрын
How do I resolve this to obtain a total value of K, for 2 different K values? I'm trying to work out the propagation velocity of a coaxial cable where the inner core is insulated with PVC, (K=3.2), and surrounded by air (K=1.0). From this I can design a 1/4 wave sleeve-Balun for suppressing dipole current imbalance.
@azzamlabib47854 жыл бұрын
thank you very much! This helps me a lot
@funandlearn75135 жыл бұрын
Thanks.... Helps me a lot
@karameyer94994 жыл бұрын
Very well explained. Thank you so much from South Africa !
@MichelvanBiezen4 жыл бұрын
Welcome to the channel!
@goodlucklyimo62873 жыл бұрын
my lecturer needs a lecture from u
@louishenderson45168 жыл бұрын
great video
@zainerikat47043 жыл бұрын
for me it was easy in high school but the professor i got now thinks we're gonna use it in daily life situations. and great video and thanks for explaining everything i needed in the first two minutes.
@MichelvanBiezen3 жыл бұрын
Glad you liked it!
@sSkullCollector8 жыл бұрын
Many thanks!
@arunbrvce3 жыл бұрын
Very intuitive explanation. Easy to understand. Thank you so much. I had a question as well. If we insert a metal plate at the interface of K1 and K2, the expression will be exactly the same correct?
@MichelvanBiezen3 жыл бұрын
That is an interesting concept. And yes, essentially you would have 2 capacitors in series and you would solve it exactly the same way.
@watertruth Жыл бұрын
This made my day! 1:03 Respect for all the work he puts into his content loved it!
@MichelvanBiezen Жыл бұрын
Thank you. Glad you find our videos helpful. 🙂
@darthvaderisawesome25732 жыл бұрын
Amazing explanation sir! Thank you very muchhh
@MichelvanBiezen2 жыл бұрын
Most welcome! Glad you found our videos! 🙂
@solomongebreyesus31894 ай бұрын
Big respect for you professor.I understand vary well now.
@MichelvanBiezen4 ай бұрын
Thank you. Gald you found it helpful.
@tolulopeadekoya45314 жыл бұрын
Thank you so much
@imonsanyal3 жыл бұрын
What happens if the dielectrics are arranged horizontally with respect to the capacitor plates?
@slowsniper1254 Жыл бұрын
This is why I'm here
@javierlopez20222 жыл бұрын
What is the maximum voltage that can be applied if we know the dielectric strangth of both substrates?. It is useful to use two layers of a layer-1 of 10kV/mm dielectric strength and dielectric constant 10 with another of 1kv/mm and dielectric constant=100? I should like to know if using 2 layers we could store more energy (energy=1/2*C*Vmax^2)
@MichelvanBiezen2 жыл бұрын
You will need to know at which voltage the dielectric will break down (this is different from the dielectric strength). At some point the dielectric will not prevent the current from tunneling through the dielectric. When that happens the capacitor is destroyed.
@luisstar55946 жыл бұрын
Anyone else notice the sound @3:04
@SaveTheFuture5 жыл бұрын
Doesn't the formula you came to suggest that with a capacitor with two dielectrics, having even a tiny layer of one of the dielectrics will massively increase the capacitance? Like if you take e and A as constants, as well as d2, k2 and k1, won't making d1 as tiny as possible make the capacitance as large as possible, even if the dielectric of the super thin layer has a huge dielectric constant?
@MichelvanBiezen5 жыл бұрын
In theory, the capacitance increase with decreasing distance between the plates. However, if the distance becomes too small, the capacitor is subject to dielectric breakdown as charges will jump across the gap.
@valeriereid23379 ай бұрын
Well explained thank you so very much for this example.
@MichelvanBiezen9 ай бұрын
Glad it was helpful! 🙂
@logio76635 жыл бұрын
Great video, but there is, it think, easier way to do that, without knowing that V = Ed, these dielectric, you can say "form 2 capacitor in parraller", so their total capacitanc is 1/C = 1/C1 + 1/C2, you can plug in for C1 and C2 their respective capacitance and you will get the same answer .
@ruiguerra73905 жыл бұрын
No, actually, they are in series (which association law has the same form of resistors in parallel)
@chadbrown49944 жыл бұрын
That only works if both dielectrics have equal distances
@anuragmittal98166 жыл бұрын
Please Clarify : In parallel capacitor having two dielectrics with relaive permitivity X1 and X2 and distance "D" between plates . Now voltage "V" between the plates of both capacitors is same , but electric field in both dielectrics will be different due to different dielectrics ....than how come DE1 =DE2 = V ?? ( E1 AND E2 are feild in different dielectrics) what is wrong here???
@MichelvanBiezen6 жыл бұрын
By definition, the potential difference between the plates (V) = d x E (distance x electric field strength).
@anuragmittal98166 жыл бұрын
you mean to say its not the other way around?
@satishgana35995 жыл бұрын
How to get the value of 'Q' for the materials?
@JohanBesterphotos5 жыл бұрын
Google "coulomb meter" or have a look at www.dicks-website.eu/coulombmeter/enindex.htm
@QScientist2 жыл бұрын
Thank you for your amazing explanation. But I've the question on physical process, not math inference: why do we have a right to devide one capacitor into two ones, serially connected? I see this in the picture, but WHICH RULES AND STRICT LAWS do we use when we say this? Why can't I say that capacitors aren't parallel connected or by other more tricky way? Does it use that lines of vector E are strictly horizontal?
@MichelvanBiezen2 жыл бұрын
Electric field lines will always emanate from the plate perpendicular to the plate. (there are some edge effects, but note that the plates are VERY close together and the distance between them is very small compared to the dimensions of the plates).
@QScientist2 жыл бұрын
@@MichelvanBiezen Thank you for reply. So, may I explain splitting into 2 vertical capacitors like this: When figuring out U we calculate work of electric field to move the charge from one plate to another, so U=A/q (A is work of Electric field E). So, if the "charge flows" through two dielectrics perpendicular to plates, so A = F1*d1+F2*d2=E1*q*d1+E2*q*d2; U=A/q=E1*d1+E2*d2 - only because we move charges perpendicular (BUT potentiality of an electric field ? we don't care about way, only start and end point) to plates and that is why we split capacitor to 2 capacitors in sequence. If we consider, two capacitors with horizontally located dielectrics we use 2 parallel capacitors because charge can use one of two ways to getting contact 2. Is it correct reasoning? Thank you.
@MichelvanBiezen2 жыл бұрын
Have you seen the videos that very carefully explain how capacitors work? PLAYLIST: PHYSICS 39.2 CAPACITORS UNDERSTOOD
@sshannon19485 жыл бұрын
My text says that the E field of a flat sheet of charge is sigma/(2epsilon naught) rather than sigma/(epsilon naught)....is that just a mistake in the video or am I missing something? I am thinking that this should be the E field of a parallel plate cap?
@MichelvanBiezen5 жыл бұрын
It depends on the charge distribution and the object the charge resides on. If there is a single sheet of charge (a physical impossibility) then yes you need a 2 in the denominator. But if you have a conducting flat plate, (a realistic scenario ) there will be charge on the top and charge at the bottom with zero electric field in between. In that case the electric field is: E = sigma /epsilon In the case of a capacitor plate all the charge will be on one side and none on the other side and E = sigma / epsilon
@sshannon19485 жыл бұрын
@@MichelvanBiezen Do you know of an online resource that explains the differences and uses Gauss's Law to derive the result in all three cases...I am in particular not sure about the conducting flat plate. I am not sure how one derives the result.
@YodoJakamodoАй бұрын
@@MichelvanBiezen I do not think that view is correct, since it ignores the superposition principle for electric fields and the fact that the opposite plate exists with an equal number of negative charges and the opposite dA sign pointing into the space between the plates (for the purposes of Gauss' Law). Due to this, If each plate would actually individually produce a field of E = sigma / epsilon, then the field in-between the two oppositely charged plates would amount to E = 2 * sigma / epsilon since they superimpose -- which is NOT the case.
@jaenpryschepa80102 жыл бұрын
Muchas gracias 💜
@MichelvanBiezen2 жыл бұрын
Glad you liked it.
@flaviomonastirscy66696 жыл бұрын
Michel My question is about Breakdown voltage when we have a capacitor with several dieletric layers.
@MichelvanBiezen6 жыл бұрын
What is your question?
@flaviomonastirscy66696 жыл бұрын
How to calculate the breakdown voltage in case of several layers dieletrics in capacitor.
@MichelvanBiezen6 жыл бұрын
Calculate the breakdown voltage for each layer and then add the voltages.
@flaviomonastirscy66696 жыл бұрын
My other question: If Is it possible to have breakdown in one layer and not on the other?
@ymax80683 жыл бұрын
Perfect
@deathrider48973 жыл бұрын
Thank you now i am able to solve a question based on it.
@MichelvanBiezen3 жыл бұрын
Great 👍
@alankuo27272 жыл бұрын
so they basically are in series
@MichelvanBiezen2 жыл бұрын
That is correct
@sudhanvab5 жыл бұрын
What if the area of dielectric is not same as capacitors area
@MichelvanBiezen5 жыл бұрын
Typically the edge effect (the region beyond the capacitor plates) play an insignificant role in the determination of the capacitance and is thus ignored.
@sudhanvab5 жыл бұрын
I meant if dielectric slab has smaller length than the capacitor’s plate then how do I go about solving
@francescovultaggio7815 жыл бұрын
from my understanding: layers of different dielectrics can be treated as different capacitors in serie. On the other hand if the top half has a dielectric and the bottom half doesn't, then you treat the situation as different capacitor in parallel.
@ezanadaniel91493 жыл бұрын
thank you !
@MichelvanBiezen3 жыл бұрын
You're welcome!
@sarveshrinu Жыл бұрын
Thanks
@MichelvanBiezen Жыл бұрын
You are welcome.
@user-bn4js2hk7t3 жыл бұрын
شكرن استاذ💞💞
@MichelvanBiezen3 жыл бұрын
You are welcome.
@raefon72 Жыл бұрын
Im building a variable capacitor generator i have 2 dielectric materials plus an air gap. Is there any difference or just keep adding dielectric with one the k value 1. kzfaq.info/get/bejne/j72Sn5dz0KfFqZs.html The insulator distance being considerably less then the air gap.
@MichelvanBiezen Жыл бұрын
Not sure what you are trying to do or what the application is.