Physics 52 Refraction and Snell's Law (10 of 11) Ex. 5: Prism & Mirror

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10 жыл бұрын

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In this video I will find angle=? exiting light beam traveling through glass and reflecting off a mirror.

Пікірлер: 12

@kaursingh637 2 ай бұрын

sir -- best on internet --please explain contour in complex analysis -- thank u sir

@kaursingh637 2 ай бұрын

sir please explain contour in complex analysis

@abdirahmangumu7028 8 жыл бұрын

yes that angel must be Divide into 2

@joshuabloodymierpolicarpio568 Жыл бұрын

5:01 much better to directly compute for the interior angles.

@MichelvanBiezen Жыл бұрын

Glad you liked it.

@devinlawnfield6035 2 жыл бұрын

sir im really struggling with geometrical optics questions can you inform me about the prerequisites in need for this chapter?

@MichelvanBiezen 2 жыл бұрын

Reviewing the basic geometry principles will help. There are also some general tricks and procedures that help, (such as always referencing the angles to the vertical and/or horizontal axis often helps).

@Klapeful 6 жыл бұрын

I have a question I can't get an answer to, maybe you can help me. It goes like that : what's the angle of incidence knowing N1 (1) and N2 (1.5) , only with the information that I2 is deviated of 5°? We don't know the refracted angle, we just know that it's deviated BY 5° It's an exercise we did in class but I didn't understand the correction which is : I2 = I1 -5° Sin (i1) = 1.5 sin (i1 - 5) Sin (i1) = 1.5[sin (i1) Cos (5) - Tan (5) Cos (i1)] Sin (i1) = 1.5 x 0.99 x sin (i1) - 1.5 X 0.087 cos (I1) Sin (i1) = 1,4 sin (i1) - 0,13 cos (i1) Sin (i1) - 1,4 sin (i1) = -0,13 cos (i1) -0,4 sin (i1) = -0,13 cos (i1) Sin (i1)/Cos (i1) = -0.13/-0.4 Tan (i1) = 0.325 I1 = 18° I'm lost with this equation, can you help me ? thank you very much Sir

@MichelvanBiezen 6 жыл бұрын

That is an interesting problem. Using Snell's law we have: n1 x sin (i1) = n2 x sin(i2) which in your case becomes 1 * sin(i1) = 1.5 x sin(i2) you are not told what the angle of incidence or angle of refraction is, but you are told that there is a difference of 5 degrees, which means that i2 must be 5 degrees less than i1 since the light bends towards the normal. Thus i1 = i1 - 5 and then Snell's law becomes: sin(i1) = 1.5 x sin(i1 - 5) Then use the trig identity: sin(A-B) = sinA x cosB - cosA x sinB then Snell's law becomes sin(i1) = 1.5 [sin(i1) x cos(5) - cos(i1) x sin(5) Then you solve for i1