Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZfaq) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. MoLE ConCepT in 40 mins : CBSE / ICSE : CHEMISTRY : Class 10, Class 11, Class 12 kzfaq.info/get/bejne/mK9drMubnr3LqIU.html MOLE Concept in 6 mins : Class X CBSE / ICSE : kzfaq.info/get/bejne/ja2DeteVzNK-qps.html MOLE CoNcEpT : STOICHIOMETRY : Class X , XI , XII : CBSE /ICSE kzfaq.info/get/bejne/h9FipJR8xry5dnU.html MolecuLar FormuLa and EmperiCal Formula | Percentage CompositioN | Class 10 , 12 ICSE / CBSE kzfaq.info/get/bejne/pL5hlZl4qrCciIk.html Mole ConcepT 01 | How To CalcuLate Number of Moles | Mass Volume Relationship | Revision kzfaq.info/get/bejne/nKd6mpR5xq-chGg.html How to BALANCE any Chemical Equation - ABCD Method | Best Way to Balance Chemical Equation kzfaq.info/get/bejne/bb2oZNKgvNTOgWQ.html Mole Concept || Class 9,10,11 || Stoichiometry || Percentage Composition | Compilation Of OLd Videos kzfaq.info/get/bejne/pdOlm7CUs5_eXYE.html

2024-25 attendance here😅😅

Anyone who is watching this awesome lecture in 2023 🥲🥲

2 saal ka confusion 5 minute me khatam ho gya....................😂😂 Lord for a reason.....💯💯

Anyone in 2024-25 for class 10 attendance here👇

Sir has come as a saviour for people like me who find it difficult to balance equation.

Anyone who is watching is 1 day before exam 😅😅

Sir I am also a chemistry lecturer but seriously I didn't know about this trick but this trick helped me a lot. I used this trick to balance the equation in the classroom and the whole class room applauded me a lot just because of you...🤩

Any one of 2020 boards hit like👊👊👊👍👍👍👍👍👍👍👍

Best teacher award goes to him....if agree hit like....

Sir you made this lecture 6years ago but today it is useful for me...Thanks alot sir

Anyone luckily watching this lecture in 2024? 🥲😅

Alakh sir is best teacher in India Sahi baat hai toh like karo. Plase

The Alakh Pandey method💯

S + 6 HNO3 ----------> H2SO4 + 6 NO2 + 2 H2O Cu + 4 HNO3 ------------> Cu ( NO3 ) 2 + 2 NO2 + 2 H2O Sir, a very big thanks to you 🙏 Watching after almost 4 years and this trick was amazingly perfect like magic 👌👌

2024 attendance..✋

First , I thought what is this method 🙄? But when I tried it .. literally I just love this method So easy and helpful

Legends don't come in a day or night .Legends come by their hard working.Salute you sir💕❤💕.

Excellent method! Out of the box and very accurate. Immensely grateful. Helped me teach my daughter 👍

No words to explain the happiness this person give us through teaching 💖💖💖

1st question's answer: S+6HNO3 ---> H2SO4+6NO2+2H2O 2nd question's answer: Cu+4HNO3 ---> Cu(NO3)2+2NO2+2H2O

I can't even describe how thankful I am to you,,, this was so much necessary for me. I was always confused with hit and trial. Now I have something logical and easy just because of you, thank you so much sir!!! 🥰

2024 attendence please 😂

a = 1 b=6 c=1 d=6 e=2 we know that b = 2× 1 + e putting the value in 3b = 4c+2d +e also b = d there for we get e =2 putting e =2 in solution b =2c+2e we get b =6 and we know that b = d s d =6 and the equation formed is S + 6HNO3 => H2SO4 +6HNO2 + 2H2O this the correct solution for balancing it

Sir ,is video ko dekhne ke baad mughe (infinite) bar like karne ko man kr raha hai.. Agar ho sakta to vo bhi kr deta....

The answers of first 2 equations are : 1. S + HNO3 -> H2SO4 + NO2 + H2O Solution • S + 6HNO3 -> H2SO4 + 6NO2 + 2H2O solved equation -> Sulphur : a = c..(1), Hydrogen : b = 2c + 2e..(2), Nitrogen : b = d..(3), oxygen : 3b = 4c + 2d + e..(4) Let *b = 1 So, *d = 1 Now, from equation (2) and (4), we can write (b = 2c + 2e) and (3b = 4c + 2d + e) [1 = 2c + 2e] and [3(1) = 4c + 2 (1) + e] [1 = 2c + 2e] and [3 -2 = 4c + e] [1 = 2c + 2e] (5) and [1 = 4c + e] (6) ~ {2c + 2e = 4c + e} ~ {2c - 4c = -2e + e} ~ { -2c = -e } ~ { 2c = e } (substitution of e - class 10, chapter 3) Again from equation 6 1 = 4c + e { where e = 2c} 4c + 2c = 1 6c = 1 *C = 1/6 And for e = 2c e = 2 × 1/6 *e = 1/3 *a = c = 1/6 Now, after putting values, we will get -S + 6HNO3 -> H2SO4 + 6NO2 + 2H2O 2. Cu + HNO3 -> Cu (NO3)2 + NO2 + H2O solution • Cu + 4HNO3 -> Cu (NO3)2 + 2NO2 + 2H2O - Copper : a = c..(1), Nitrogen : b = 2c + d..(2), Oxygen : 3b = 6c + 2d + e..(3), Hydrogen: b= 2e..(4) So, let *b= 1 *e = 1/2 (4) From equation (2) b = 2c + d, we get d = 1-2c (substitution of d - chapter 3 class 10) So in equation 3, we can write 3b = 6c + 2d + e (where d = 1-2c, e = 1/2, b= 1) 3(1) = 6c + 2(1-2c) + 1/2 3 = 6c - 4c + 5/2 ( after calculation) So, 2c + 5/2 = 3 *c = 1/4 [ this method is same as finding math's x😂] * a = c = 1/4 Now , d = 1-2c * d = 1/2 (after calculation) Hence, after adding the value of a,b,c,d,e We will get - Cu + 4HNO3 -> Cu (NO3)2 + 2NO2 + 2H2O #substitution is nothing but writing something simmilar which will be equal to 2nd value for solving 2nd value Like - 5 = b + c So we will find smth with variable b and equal to c - C = 2b So we can make this equation - in single variable - 5 = b + 2b, such that we can find the answer

Thanks sir This helped me when I have missed my important school lecture. You are doing great job👍

Any one watching this video 4 days before chemistry board exam😂

Sir ans agaya S + 6HNO3 ---> H2SO4 + 6NO2 + 2H2O Agar sabka sahi aya like kardo for me and sir 😍😍🤗🤗👍👍

You are literally a genius sir, I watched almost 3 videos, and this was the 4th video I watched but none of the 3 were not explained well, I literally got this inside my head so goodly that I can't even forget this

Wow sir ek he Barr me samaj me aa gya ..best teacher ever 👏

Heartfelt Thanks to you!!😇 Very Easy... I will follow it hereafter for sure...

thank you sir just watching before exam very easily learned RESPECT +

Any one of 2020 board exam Like it👍👍👍👍👍👍👍👍👍

Sir ji hats off to you, while solving my class11 1st ch, I was facing problem in balancing but after watching this I solved tough questions too. 🎉❤

9:02 ho rhe h 10 bje tak center pahunchna h aur main yeh dekh rha hunn

This, a great idea thanks a lot sir Who's with me?👇👇👇👇👍

Warning guy's phalae video dekho phir comments dono ak sath nhi ho sakata hai 🙏😂

THANK YOU THANK YOU THANK YOUUU SO MUCH SIR!!! ❤️ U ARE A LIFE SAVIOUR FOR STUDENTS LIKE ME WHO ALWAYS STRUGGLE IN BALANCING EQUATIONS.. I ALWAYS LOST MARKS IN MY EXAMS FOR NOT BALANCING AN EQUATION PROPERLY... THANK YOU SO MUCH SIR❤️... AB HUM SAB "PHOD DENGE"!!!!

Thanks a lot bro I was worried that I couldn't balance equations properly but now I understood

Such an amazing trick!! I was searching for such a trick and got this video 🤩 . Thank you so much Sir for your effort. 🙏🙏🙏

Thanks sir ABCD method is best for balancing..... Thanks...... 😄😄😄😄😄😄

5:7

Awesome lecture sir ☺️ Easily samgh mai aa gya thanks sir ❤️

I came here after 3yrs. I'm really happy to balance equations like a pro. Sir ur are great. I never thought I could balance equations

Thank you sir you made this video,first we had a lot of problems in balancing but after watching this video of yours, all the problems themselves are running away from fear.👌👌👌👌👌☺️☺️☺️☺️☺️

All the best for today's exam 😊

thank you sir i was having difficulty in balancing but now i learned well

Superb explanation sir 👍 First I found it difficult but now it's become very easy for me 😊 Thank you sir 🙇

1st question answer:- S+6HNO3---->H2SO4+6NO2+2H2O 2nd question answer:- Cu+4HNO3----->Cu (NO3)2+2NO2+2H2O

Highly wonderfull ,thank you sir , may you live long.

I LEARNT IT SO EASILYYY THANK YOU SO MUCH

I don't have words about your way of teaching

Sir,This video Might have just made some EXTRA MARKS for my Papers that COULD HAVE BEEN LOST IF I WOULD HAVE NOT KNOWN SOME COMPLEX EQ BALANCING! Great Sir!

Thankyou sooo much sir i was struggling so much with these and now I am enjoying it....

I got a trick to balance any chemical equation with his and trial method and i solved all the equations of this video with that trick. The trick is very simple. You just have to make no. of all elements of products side even by multiplying 2 e.g a+b→ H2O(here no of O is odd) Then a+b→2H2O So that no. Of O and H become even. Now solve the equation of hit and trial method you will get the balanced equation

Sir pahle b=1 lege to d=1ho jayega aur phir hydrogen wale aur oxygen wale me elimination method laga denge isse e=1/3aayega aur c=1/6 and a=1/6 aur phir put karne ke baad multiply by 6 to equation balanced ho jaayegi

Bhai saab..u solved my biggest fear..god bless

This man picked up the camera and choose to change the world

Who Is watching this video 2hours before exam

Thankuuu so much sir. U re d best teacher I have ever seen.I'm in 10th class nd my boards exams r in 2021 nd now I m much confident to balance the equations.May u live long nd continue teaching us.

Best Teacher in the world!! His is an inspirable character of Handwork.

Anyone watching 8 hours before exam😅

Thank you sir. This is very helpful video

Sir I just cannot express how happy I am after watching this video every other teacher have use the ABCD method but had not explained anything properly. You explain very well keep it up you earned a subscriber!

You are the best sir 🙏 this method helped me a lot 👍

The best best best way explained🥺🥺

Thank you sir, this helped me a lot

Extraordinary teacher ,with great methods and amazing concepts, now every thing is possible with him

Who is the best teacher of PHYSICS & CHEMISTRY IN THE WORLD?? Ans) All answer ♥️ *ALAKH SIR* 🇮🇳🇮🇳

S+6HNO3=H2SO4+6NO2+2H2O first question's answer / CU+4HNO3=CU(NO3)2+2NO2+2H2O second question's answer

S+6HNO3=H2SO4+6NO2+2H2O Thanks a lot sir 👍👍👍👍

Any one of 2021 board . We are first the boards with online classes in history. Hit like 👍👍👍👍👍👊👊👊

This is the first video that I am watching from physics wallah channel and now I understand why students appreciate this channel You are great sir 👌 I am so confused in this method but you solve my problem in just 15 min 😀 Thank you for this video 😊

S+6HNO³-H²SO⁴+6NO²+2H²O

Best ever teacher to ever exist

My teachers never taught me this method. I think this method is a very fast and easy way to balance any equation. Thank you for showing us!!

Really Amazing trick to solve any equations in easiest way. Best teacher in the world. Do you agree ? 👇👇 👇👇 👇👇 👇👇

Found it very helpful thank you so much sir

All the best for my junior and I wish all get 95%

After watching this students say -- "ab majaa aaye ga na biidu" 😂😂 Thankyou alakh sir ❤ 🙏

Thank you sir !!! Your method helped me a lot ❤️

Sir mai ne apni bahan ko padhaane ke liye aapki video yah dekhiae to mujhe dekh kar bahut aasani se samajh mein a Gaya .you are great sir 😅😅

Really amazing explanation sir . Thank you sir .

Hw wale questions 1. S + 6HNO3 ===> H2SO4 + 6NO2 + 2H2O 2. Cu + 4HNO3 ===> Cu(NO3)2 + 2NO2 + 2H2O

Sir you don't know how much grateful I am to you. Salute for you

Excellent teaching iam very happy tq so much sir 😊😊😊😊😊

Thank you sir it helped a lot!!!❤❤

Yes sir , it's really work! 1 equation:- Let:- b=1 ; After doing calculation:- d=1, c=1/6 , a= 1/6 , e= 1/3 comes. The answer:- S+6HNO3---->H2SO4+6NO2+2H2O A'm correct or not?

I just started class 11th and chose pcm...my cousin who is 3 years elder to me just gave her hs examination and she's a very bright student...i always seek help in anything I face problem in especially in my studies. The first'thing she said me when I told her that I'm a little tensed about physics and chemistry, was that "Don't worry, just trust me and start learning from Physics Wallah, a yt channel". I started chemistry today and this is my first time on this channel and trust me guys, it's amazing!!!!!

Date...10/3/2024 Tommorow is my chemistry exam.... 👍😭

Thank you sir now I am confident in this topic ❤

Thank you so much sir❤ I had always used to lose my marks in balancing in my examinations. You literally solved it completely

Hw Ist equation answers question S + HNO3 TO give H2SO4 + NO2 + H2O Answer S + 6HNO3 ------H2SO4 + 6NO2 + 2H2O Message: Thx for the homework it is easy i got b=d so i let c=1 and there is a equation in which 3 three variable are there b,d,e ,i also got b=d ,a=cand in the other equation there I got 2 variable after putting c=1 then in the equation where 3 variable exist I put b=d in RHS side where equation in which is put b=d is 3b=4+2d+e after putting b=d on rhs I got 3b=4+2b+e now just subract 2b from 3b then we have two equation Ist b=2+2end b=4+e multiply 2nd by 2 then eliminate e now you have your all the values

Love u sir ji 5 year old method still as gold .

Thank you sir this is very helpful for me

S + HNO3 ----> H2SO4 + NO2 + H2O Here now take a,b,c,d as shown in video Now make equation 1) a= c 2) b = 2c + 2e 3} b = d 4) 3b = 4c + 2d + e Then Let a = 1 then c also 1 Then b = 2 + 2e and also 3b = 4 + 2d + e and also b = d then 2 + 2e = d then 1 + e = d by 2 Noe in this equation 3b = 4 + 2d + e substitute 1 + e = d by 2 and b = d We get then 3d = 3 + 2d + d by 2 Now solve this and get d Then get e by putting values Hope you understand

sir you and your teaching method is mind blowing. It is truely amazing method. hats off to you sir for your unique teaching tricks in this platform

We can see the struggle alakh sir did 5yrs ago really great salute 🙏🏻

Zabardast sir g itna behtareen Hamari balancing ka to masla hi hal ho gya Allah apko khush rakhi☺️☺️