Poles and Zeros of z-Transforms

Рет қаралды 179,252

Barry Van Veen

Күн бұрын

Definition of poles and zeros for z-transforms that are a ratio of polynomials in z. Examples.

Пікірлер: 26

@skirkley268 5 жыл бұрын

Thank you for explaining the z-transform in all these videos, it's helping me out!

@jeevanraju8834 2 ай бұрын

your the best sir . thanks it really helpedfor my exam :)

@Ankit_Kumar_Sasaram 8 жыл бұрын

Hello sir, i just wanted to ask , what is more efficient application of z transform ?

@allsignalprocessing 11 жыл бұрын

Sorry for the slow response - alpha is a complex number in general, so the pole can be anywhere in the z-plane.

@sehyunpark6829 3 жыл бұрын

You are my hero... Thanks you a lot! :) Thanks to the development of technology, I can watch this awesome lecture in my room.

@morgansampi5336 8 жыл бұрын

Hello sir, i just wanted to ask is this a WHOLE chapter about Z-transform? Is that all we need to know? Or is there more to it?

@shuffleplaypause 8 жыл бұрын

Thank you so much, sir.

@mertcomert7893 6 жыл бұрын

I need to ask one question.x[ n] = 7 ( 1/3)^n u[ n] - 6 ( 1/2)^n u[ n] .For the Z transform I found only one zero which is 3/2 but the answer says there are two zeros suc as 3/2 and 0.How is that possible?

@VideoKonstantin 5 жыл бұрын

thank you very much for this perfect explanation! :-)

@KamalJ5 3 жыл бұрын

Thank you so much.

@ajsamart2445 11 жыл бұрын

Hi Barry, Once again thanks a lot for these lectures. They've really helped me and others in our Dsp module. I might be mistaken but you know at 1.55, while marking the poles and zeros in the z plane. Should alpha be marked on the x axis instead of on the circle? Because z = alpha (so there's no imaginary component for it to be marked on the circle).

@yazminaldama4781 2 жыл бұрын

, , ,:-O*\0/*

@anuraglaumas2966 10 жыл бұрын

hey man i really want to know how to check the stability of this.. please can u explain...

@palnikola347 8 жыл бұрын

+Anurag laumas Okay so checking the stability goes like this 1) if all the poles lye on the left half of the y-axis u say a system is stable 2)if any one of the pole is in right half of the y-axis u say a system is unstable 3)if pole(s) lye on y-axis then u say it is marginally stable i.e for some condition it will be stable and for some it is unstable hope this helps

@mdsharif84 3 жыл бұрын

Thank u, I liked it

@metroidandroid 11 ай бұрын

1:26 what does that mean? where does it come from??

@adarsh.niranjanadarsh.nira7866 3 жыл бұрын

H(z)=1-z^(-1) Does it have pole at z=0 as we can write is as H(z)=(z-1)/z ? If it has pole then y(n)=x(n)-x(n-1) Can not be FIR filter .

@shaubilhaq3998 4 жыл бұрын

How to implementation to diagrams

@arafathdhroba8897 Жыл бұрын

thank you

@souravdas8629 6 жыл бұрын

example 4 inverse z transform is worng

@krangw6755 9 жыл бұрын

At 01:24 you say there is a pole at z=0. But you haven't simplified the expression. The expression can be simplified to 1/(1-a*z^(-1)) and in this case there is no zero! So I think you are wrong. You must look at the most simplified expression when looking for zeros and poles.