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POTD- 01/11/2023 | Frequencies of Limited Range Array Elements | Problem of the Day GeeksforGeeks

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GeeksforGeeks Practice

GeeksforGeeks Practice

Күн бұрын

Welcome to the daily solving of our PROBLEM OF THE DAY with Karan Mashru. We will discuss the entire problem step-by-step and work towards developing an optimized solution. This will not only help you brush up on your concepts of Data Structures and Algorithms but will also help you build up problem-solving skills.
So come along and solve the GFG POTD of 01st November 2023 with us!
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Пікірлер: 9
@kumarqwerty4452
@kumarqwerty4452 7 ай бұрын
Karan Mashru is the best teacher GfG has ever produced.Thanks man for wonderful explanation.
@miracleguy1330
@miracleguy1330 Сағат бұрын
Easiest Solution -> int[] freq = new int[N + 1]; // Counting the frequency of each element for (int i = 0; i < N; i++) { if (arr[i]
@prateekbhaisora
@prateekbhaisora 9 ай бұрын
A cleaner code using modular arithematic: void frequencyCount(vector& arr,int n, int p) { p++; for(int i=0; i= n) continue; int cnt = arr[ind] / p; int ele = arr[ind] % p; cnt ++; arr[ind] = cnt * p + ele; } for (int i=0; i
@piyushphaske3271
@piyushphaske3271 7 ай бұрын
Thanks
@chandruram7553
@chandruram7553 5 күн бұрын
Tq💖
@srinijabhogoju9033
@srinijabhogoju9033 3 ай бұрын
Thank you. Very well explained.
@jyoti3427
@jyoti3427 28 күн бұрын
great explanation
@himansuiii
@himansuiii 2 ай бұрын
for(int i=0;iN) arr[i]=0; int i=0; while(i
@daaamn6414
@daaamn6414 3 ай бұрын
Solution giving Run time error.
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