PV diagrams - part 1: Work and isobaric processes | Chemical Processes | MCAT

No video

PV diagrams - part 1: Work and isobaric processes | Chemical Processes | MCAT | Khan Academy

Рет қаралды 222,668

Күн бұрын

Visit us (www.khanacademy...) for health and medicine content or (www.khanacademy...) for MCAT related content. These videos do not provide medical advice and are for informational purposes only. The videos are not intended to be a substitute for professional medical advice, diagnosis or treatment. Always seek the advice of a qualified health provider with any questions you may have regarding a medical condition. Never disregard professional medical advice or delay in seeking it because of something you have read or seen in any Khan Academy video. Created by David SantoPietro.
Watch the next lesson: www.khanacadem...
Missed the previous lesson? www.khanacadem...
MCAT on Khan Academy: Go ahead and practice some passage-based questions!
About Khan Academy: Khan Academy offers practice exercises, instructional videos, and a personalized learning dashboard that empower learners to study at their own pace in and outside of the classroom. We tackle math, science, computer programming, history, art history, economics, and more. Our math missions guide learners from kindergarten to calculus using state-of-the-art, adaptive technology that identifies strengths and learning gaps. We've also partnered with institutions like NASA, The Museum of Modern Art, The California Academy of Sciences, and MIT to offer specialized content.
For free. For everyone. Forever. #YouCanLearnAnything
Subscribe to Khan Academy’s MCAT channel: / @khanacademymcatprep
Subscribe to Khan Academy: www.youtube.co...

Пікірлер: 57

@saratomorszki3904 4 жыл бұрын

You clearly taught me everything in 10 minutes that my teacher couldn't in 45 mins

@1polyron1 Жыл бұрын

Oh, I love these comments. They have me dying laughing because if I wasn't laughing I'd be crying at how hard it hits that what you said is facts

@Pr0x1mo 7 жыл бұрын

Dude, you're up there with Khan in terms of how clear you are.

@hashirkhattak9180 4 жыл бұрын

Your voice is clear, your concept is clear ,,, you are perfection

@1polyron1 Жыл бұрын

no you

@dominicesteban3174 Ай бұрын

As usual, David points out the pitfalls and traps like the Zen Jedi master teacher he is. Amazing!

@hrperformance 4 жыл бұрын

This guy is actually way better than Sal and Sal is a very good teacher

@ariancruzat3519 9 жыл бұрын

What a cool way of teaching. I am actually learning thermodynamics even though Im not taking it for now on my course. Haha. Thank you dude!

@gingernut5057 7 жыл бұрын

When I am older and work as a hobo I will thank you for this video

@lalabEsjen 8 жыл бұрын

You are really good!

@amaderjonnomathematics4288 3 жыл бұрын

Sir i am not understanding anything what to do

@amonahud3250 5 жыл бұрын

Very clear explanation. Thanks a lot

@ECOMMUSK 9 жыл бұрын

Thanks.

@Incrue 8 жыл бұрын

Anyway thanks dude, i tough i understand this thing for the first time in my life

@FeynmanAcademics 4 жыл бұрын

Lolz. Me too

@khozikahmed2168 7 жыл бұрын

amazing . fisrt time understanding those 4 processes

@jaehoahn4810 3 жыл бұрын

At 10:22, is it the work done should be positive? because the final volume is greater than the initial volume..

@ShannTsaikf 4 жыл бұрын

If it's an isobar compression, then shouldn't the work done be negative? And vice versa? Since for the isobar compression graph the change in vol would be negative.

@foxeverett8164 3 жыл бұрын

you probably dont give a shit but if you are stoned like me atm you can watch pretty much all of the latest movies and series on InstaFlixxer. I've been binge watching with my girlfriend during the lockdown :)

@drakecurtis8025 3 жыл бұрын

@Fox Everett yup, I've been watching on instaflixxer for since december myself =)

@vihaanmenon7175 2 жыл бұрын

No, because positive work is work being done on the system. So a compression is net positive, because you add energy to the system. While expansion is negative, since the system does work and thus loses internal energy. I think so, atleast. Learning this subject myself right now. Thought this might help someone else with the same question.

@parkmin-su4793 2 жыл бұрын

@@vihaanmenon7175 I'm sorry but aren't the conventions for work different in physics and chem? Like if work is done by the system=+W If work is done on the system= -W ? I'm confused about this part :")

@carultch 2 жыл бұрын

@@parkmin-su4793 Sign conventions are arbitrary, and set for the convenience of the context in which you are using them. You need to learn follow the sign convention given to you in your class. Ultimately, it's better to know how to state your answer with words, to explain the meaning of the sign you get, so that your answer is objective, regardless of what sign convention you are using. Not all physics and not all chemistry classes/books, are guaranteed to use the same sign convention as a standard. I'm accustomed to the heat engine sign convention, such that heat added to a system is positive, and work done by a system is positive, for thermodynamics problems. For the original definition of work, work done on an object is positive, and work done by an object is negative, so it is opposite.

@leahevelee 11 ай бұрын

thank you!

@nthumara6288 7 ай бұрын

the world is runing on above 4 prosses approsimately

@haroldgaring8468 7 жыл бұрын

please make TS diagram about these processes

@suryatejayalla3502 6 жыл бұрын

Super

@rabiazafar5982 3 жыл бұрын

Awesome....👌👌👌

@abhinabasaikia6377 6 жыл бұрын

liked it

@bleuemoone8710 6 жыл бұрын

excellent!

@itsasecret2132 3 жыл бұрын

Delta Q = Delta U + Delta W right???

@Incrue 8 жыл бұрын

@11:30 you mean: because if its not equal the piston will move AND MAKE IT EQUAL AGAIN, right?

@mshahzadaslam7357 8 жыл бұрын

thats it

@zubaer73 7 жыл бұрын

if the temperature in isobaric process increases then why the internal energy reduces? i found some maths refering the decrease of internal energy in isobaric process.

@gtrslayer1 5 жыл бұрын

Zubaer Ahmed because the gas inside the piston has to use energy to push all of that area upwards, like he explained in the video, a force is exerted through a distance.

@gtrslayer1 5 жыл бұрын

The examples of the isobaric processes you saw must have been ones where you remove some pressure from your piston and the gas inside pushed it up a distance without the need of heating it up. Thus decreasing the internal energy (U) of the system.

@ParveenKumar-pg3ps 6 жыл бұрын

nys

@Incrue 8 жыл бұрын

@10:43 you make them be at equilibrium but just in the initial state, right?

@merkov8715 7 жыл бұрын

I need help. So what formula should I use? A=F/A(hA) or A=F/A(vf-vi)?

@pulkitraju7034 6 жыл бұрын

merkov ∆hA = Vf - Vi

@joslyns6671 7 жыл бұрын

Isn't work done on the system + and work done by the system -?

@TMPChem 7 жыл бұрын

Unfortunately this convention tends to vary among various scientific disciplines and even individual lecturers, so often it is necessary to carefully observe and note the sign convention being used in each particular case.

@anon_ninja 4 жыл бұрын

Sorry but if it moves to the left it’s positive work?? But isn’t change in volume negative? (Decrease in volume) and vice versa

@bjhu9031 4 жыл бұрын

What software/app are you using for your presentation?

@FeynmanAcademics 4 жыл бұрын

When you know let me know too

@KA1blow 8 жыл бұрын

06:12 if h changes, doesnt that mean the area does too

@Mobimobipopo 8 жыл бұрын

It's the area of the piston ( the lid, the circle part of the cylinder) not the area of the cylinder itself so it won't change when the h changes.

@arthikalexander316 8 жыл бұрын

is it u=q+w or is it u=q-w?

@AnirbanDas7 8 жыл бұрын

+Arthik Alexander It can be both. Consider the expression: U= Q+W. 1. When work is done "ON" the system (e.g. External pressure applied to a gas in a piston-cylinder configuration to compress the gas), W= +W. Therefore, U= Q+ (+W)= Q+W. 2. When work is done "BY" the system ( e.g In a piston-cylinder configuration, when the gas exerts pressure on the piston, the piston moves upward), W= -W. Therefore, U= Q+ (-W)= Q-W. In short. Work done ON the system is always positive in nature (+W) and Work done BY the system is always negative (-W).

@usamaqamar5562 8 жыл бұрын

+Anirban Das Hey! does temperature increase in isobaric expansion?

@AnirbanDas7 8 жыл бұрын

Yes, it does.