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Yes , But I want modules, Unittest Threading, Logging, Paramiko, For these models videos

You are learning python for marks wow

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Yes same feelings

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Amuls Academy mam can u make practice programs in dictionary also ...it's a quit important topic . They ask in exam

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@@AmulsAcademy a

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will you plz explain once

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@@AmulsAcademy what if the lower value starts from 2

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@@AmulsAcademy have u uploaded prime number using while loop because its way too confusing in while loop

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We took range form 2 to num. {for i in range(2,num)} when num is 2 range will become range(2,2) so it won't execute for loop body so it will execute else part and it will print 2 as prime number.

It will print nothing. In this case, if your "num" is two(2), it means you would have given your upper limit as two(2).In range, it will take only (n-1) values. So that would print nothing. As it would be like (2,1), I suppose.

@@harikrishnants8545 then how she get 2 in the second example

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Mam is there machine learning and artificial intelligence in your academy

If it is there, please send me the link .If it is not there please make a tutorial on it🙏🙏🙏🙏

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Yes i think this will work :)

@@AmulsAcademy pls explain this

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In the for loop use range as lower to upper+1 😊

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Same doubt

When i know there is a number which divides entered number then i know that number is not prime , so when for i in range(2,num): if num%i==0: This condition becomes true then i will print number is not prime and i don't want to execute anything else, so i used break statement there. for example if i take number as 16, first i will check whether 16 is divisible by 2 if yes then i won't check further , i know 16 is not prime so i will print that and stop execution. in your case you are not using break statement, so when i take number as 9, it will check 9%2==0 no so it will check 9%3==0 yes , so it will print 9 is not prime number, but again continue with the for loop, so it will check 9%4==0.... till i =8 ok. here if any other number divides 9 then again the massage "9 is not prime number" will be printed. After that control comes out of the loop , and it will execute else part because , The else block just after for/while is executed only when the loop is NOT terminated by a break statement. Ok so you will get 9 is prime number message also :)

@@AmulsAcademy thank you so much

hey 9 is not a prime number

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Ⓛⓞⓞⓢⓤ

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We can use else with loops, for and while loop. And here we can't use else part with if . If i use that i won't get proper output. for i in range(2,num): if (num % i) == 0: print(num,"is not a prime number") print(i,"times",num//i,"is",num) break else: print(num,"is a prime number") for example: take number 21 control goes to if condition and it will check, if 21%2==0 No so it come out of the if body and execute else part, that is it will print message 21 is prime number, but it is not. i need to check all divisors right. So we can't write like this. We are using for - else because it will check whole for loop body, it will divide the number with every other number starting from 2 and if that number is not divisible then we will print the message that is "not prime number". :)

@@AmulsAcademy Thank you so much. I have the same question. it really makes sense to me now.

@@AmulsAcademy I was having the same question thnx for answering , actually no one explains this for-else loop nor I find it on any website so it's a bit confusing

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Thank you :) It's better you ask your queries here :) mail: AmulsAcademy@gmail.com

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Break the statement after one loop

I understood. This reply is for those who didn't understand for 2. If your Lower limit is 2. It's 2 > 1 but when 2 will go to the (2, num) loop. It will become (2,1) because num will be excluded. So it will directly go to the print(num) function.

To check entered number is prime or not: kzfaq.info/get/bejne/oMtpecapzLKmlmg.html 1 is not a prime number. :)

else is for, for loop :)

We can use else with loops also, and here we need else with while loop 😀

In range function, end is exclusive. syntax of rang function is, range(start,end,step) if you want to print 1 to 10 numbers then you need to take range as, range(1,11) try this: for i in range(1,11): print(i) :)

Amuls Academy I understood. Thank you 🤗

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yeah this is what my question also,,

for i in range(2,num): if (num % i) == 0: when num =2, for i in range(2,2) : so it won't execute for loop body, control goes to else part directly. so it won't execute if condition. If you have still confusion, execute this piece of code for i in range(2,2): print("h") else: print("a") in range() start and end value is same it won't execute the for loop. :)

@@AmulsAcademy thanks sister

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Thank you 😊 What type of videos ?

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