Thank you very much, glad to hear the explanations are good 👍 Best wishes with your studies!

No doubt you said the bitter truth.

Thank you very much :)

Really glad to hear that :) Thank you for your kind comment! Best wishes with your studies.

exactly! we need more educators like you

I am glad this helped you. Best wishes with your studies :)

That's awesome to hear! Keep up the great work and best wishes with your studies.

Really happy to hear that. Keep up the awesome work and best wishes with your exams! :)

Thanks! I hope it was helpful.

Thank you very much for your kind comment! :)

Thank you very much! Glad to hear you understood the concept for a short video, keep up the great work. Best wishes with your studies. 🔥

Thank you and I am really happy this is what you were looking for. Keep up the great work and best wishes with your studies.

Thank you, glad to hear it helps :) I also wish you much success in everything you do!

Glad it was helpful! Keep up the good work.

Well, I hope you get many good sleeps in your future! And thank you, glad this video was helpful :)

I hope you did well on your exam and everything went smoothly!

Thank you very much, really glad to hear these videos helped you out. I have the topics you mentioned on my to do list, though I don't know when I will get to them. I'll do my best!

I think this depends on the curriculum. Some courses cover friction as a first year course, others cover it more in dynamics, and some in second year courses. I didn't cover it because I was going to make more videos in the future, just not yet for statics.

I am really glad to hear this video helped you out. Keep up the great work and I hope you do amazingly on your courses.

I am glad these videos help you out :) ❤❤

I am just gonna let you know that if you made it into an engineering course at a university, you're definitely not stupid. Statics will get easier, I promise, as long as you get the fundamentals right. Do as many practice problems as possible, try to solve the problems I solve in these videos without seeing the solution first, and if you get stuck, go through how I solve it. Don't beat yourself up, keep up the hard work and it'll get easier for you. I believe in you! You got this, and I wish you the absolute best with your studies :)

Thank you for your kind words, I really needed it right now. I will definitely remember your advice and this channel. I hope I can help you too someday when I become successful, although I don’t know how. Thank you again. Keep safe.

@@fruitpunch7361 Do your best, you got this! Thank you also for your kind words and let me know if you need clarifications on any part of the videos. I'll do my best to help.

Hello! I just want to thank you again. I’ve just received my second statics assessment results and I got 100%. I really can’t imagine how I’d be able to get that without your videos. Thank you!

@@fruitpunch7361 AWESOME!!! You did really well and I am very happy for you :) Keep up the great work and let me know if you need any clarifications on the videos.

You're very welcome. I wish you the best with your studies!

Thank you very much, for the kind comment and the recommendations on topics to cover. :)

I am really glad to hear this video is helpful to you. Keep up the great work!

I am really glad to hear that. Keep up the awesome work! :)

You are very welcome!

Thank you very much ❤❤

I'm really happy to hear everything you needed was said in the video. Thank you taking the time to write your comment, I appreciate it. I wish you the best with your studies!

👍

You're very welcome! Best of luck on your final 👍

You're very welcome! Thank you for the really nice comment. :)

You're very welcome and thank you for your kind compliment :)

😅 Glad to hear these videos are helping.

Thank you very much! I wish you the best with your studies.

Glad to hear that! Best wishes with your studies :)

Glad it was helpful! :)

Moments aren't positive or negative, they are either "clockwise", or "counter-clockwise" in 2D space, and in 3D space, you would use the right hand rule to determine the direction of the vector. Even in 2D space, the moment vector is still determined using the right hand rule. If it's a counterclockwise moment, then the moment vector would be straight of the screen towards you, and vice versa. This is why people usually pick counterclockwise to be positive. I don't like counterclockwise being positive, it's just a personal preference. It makes no difference to the answer. In fact, I encourage you to try it both ways, you will still get the same answer. This is what is important: -If you pick counterclockwise to be positive, and your answer is positive, then your moment is counterclockwise. -If you pick counterclockwise to be positive and your answer is negative, then your moment is clockwise. -If you pick clockwise to be positive and your answer is positive, then your moment is clockwise. -If you pick clockwise to be positive and your answer is negative, then your moment is counterclockwise. You can pick whatever side you want to be positive, like when you pick up to be positive, or down to be positive. It's just an assumption. As a convention, people generally consider positive moments as counterclockwise since they are directed along the positive z axis (out of the screen/page). It's completely up to you.

Thank you very much, I appreciate it.

You're welcome!

Glad to hear that and you are very welcome! :)

Glad to hear that :) Thank you!

That's on my list of things to do. I will do my best to do a series on that subject as well! :)

You are most welcome!

:) Many thanks!

Thank you for the feedback! I will add that topic to my list of things to do in the future. I can't say when I can get around to it, but I will do my best :)

@@QuestionSolutions

You're very welcome! Keep up the good work and best wishes with your studies.

Thank you very much :)

Glad to hear that :)

You're very welcome :)

I am happy to hear that! Keep up the good work.

Really glad to hear these videos are helping. As per your question, I am assuming something is wrong with how you formulated the moment equation for B. It's hard for me to say where you went wrong without seeing your steps. Also, it's very common for structures to carry forces with varying differences in force values, so you can't assume it's wrong simply because they are very different.

You're very welcome!

Thank you and you're very welcome!

You're very welcome! :)

Any books used are listed in the description 👍👍

Thank you Great effort BTW

@@amirmohsen8772 You're very welcome

I am glad to hear that :)

Thank you very much, really glad to hear!

You can find the x-coordinate using b/2a. The maximum bending moment occurs at the location where the shear force is 0. See 9:40.

Thank you very much :)

Please watch this video first, and then if you still have the same concern, send me a comment, thanks! kzfaq.info/get/bejne/graUZ9mIncydcZc.html

😅 Well, I'm really glad to hear that!

You can pick whatever direction you want to be positive. Depending on the number of negative signs you deal with, you should pick a clockwise or counter-clockwise direction that gives you the least amount of negative signs. That makes your life easier, but if it doesn't, you can always just keep clockwise or counter-clockwise to be positive, it's really up to you. It makes no difference to the answer, because moments aren't positive or negative, they just have directions. So I change the positive side based on what makes the math more simple. It's the same as when you deal with forces. Imagine you have 10 forces down and 2 forces up. It's easier to make down positive and up negative, then you deal with less negative signs. That's why we always establish a coordinate system first, saying which sides will be up or down. In the end, our answer will indicate whether the resultant force is up or down, not whether it's positive or negative. I hope that makes sense.

Thank you! Best wishes with your studies :)

for both pieces *

If it's just 2 pieces, or easy to figure out in your mind, you only need to solve for one half, since you can figure out what comes next, they all have to come back to their return points on the graph. If you do enough questions, you can see what comes next without going through the steps. If you're new to this though, I think its better to solve for all the pieces :)

@@QuestionSolutions Thank you for the explanation! :)

The diagrams were drawn on illustrator.

You're very welcome. I do have plans on creating videos about strengths of materials, but probably not for some time. Best wishes with your studies!

@@QuestionSolutions Looking forward into that. Thank you!

Please see this video first: kzfaq.info/get/bejne/graUZ9mIncydcZc.html

I use illustrator to draw these diagrams.

I am not entirely sure of your question. Is there an example you can give me so I can take a look to see what type of problem you're talking about? Many thanks!

@@QuestionSolutions I mean I'm not sure if you use this book or not but for example 7-9 in the engineering mechanics statics by hibbeler in SI units

@@arthurbosch9041 I don't know which question that is, but is it something like the length represented as a variable instead of a fixed length? If so, the process is the same, you'd just have your graphs as a function of x.

Glad to hear :)

Thank you very much :)

What does your professor want?

You're very welcome! Keep up the great work and best wishes with your studies.

we don't consider x = 2, we consider 0 =< x < 2, and 2 < x = 2, we have a shear force of -10. The difference between the two parts, so 20 - (-10) = 30 kN, that is the applied force of the beam. The diagram will look the same for every student, there shouldn't be any difference. There are no assumptions when drawing these diagrams.

Glad you liked it!⭐

You're very welcome!

So the 1200 N•m is an external moment applied to the beam. It's like someone randomly trying to turn it about that point. That needs to be accounted for in our graph. Clockwise means it needs to be added, counter-clockwise means it needs to be subtracted.

So we want these equations in terms of length. We don't want fixed values. A fixed value would only give us the shear force at a specific length, but if we write it with respect to "x" then we get it as a function of length.

Thank you very much! Keep up the good work :)

Yes, I agree, I will probably cover a example like that in the future, but the general idea is the same, your textbook/ course material should have an example with a triangular distributed load.

That's the first request of this type :) Unfortunately, that's not really something I teach, you should have counselors and career center administrators that teach those sorts of things. Even if I were to make a video on it, I probably wouldn't do that great of a job 😅 Sorry!

Question Solutions no worries! Thank you for the solid mechanics’ videos though! I have shared with Mechanical Engineering students. Have you considered Fluid Mechanics, Thermodynamics, Heat Transfer, etc courses?

@@rehanrashid9296 I have gotten a lot of requests for thermodynamics, which could be what I cover next. These days have been busy, but I hope to start that series soon as well. If you don't mind me asking, what books do you use for those subjects? I am asking this question from a lot of people to get a rough idea of what is being used 👍

Question Solutions For Thermodynamics 1,2 we use: Thermodynamics: An Engineering Approach (9th Edition) Yunus A. Cengel and Michael A Boles For Fluid Mechanics/Fluid Dynamics: Fluid Mechanics by Frank M. White, 8th Edition, McGraw Hill For Heat & Mass Transfer: Heat and Mass Transfer, Fundamentals and Applications by Yunus Cengel and Afshin Ghajar, 5th edition, McGraw Hill these are the books for those courses used at YorkU, and no worries, take your time :)

@@rehanrashid9296 Wow, thanks for taking the time to write this reply. Really appreciate it! I will look through all of them. :)

Yes, that's right. If you look at the equations we write, you can see that by plugging in the full length, it ends up at 0. The beam is in equilibrium, so it starts at 0 and ends at 0.

Many thanks!

For the first question, there are no x-forces acting upon the beam, so there isn't anything for us to consider. For the 2nd question, it depends on the direction you chose the moment to be positive. So for the 2nd example, we chose clockwise as positive. So looking at 6:16, look at the 320 kN force. It's pointing down, and imagine the beam is free to rotate about point A, which way would the beam rotate? If you push down at the location where the 320kN force is applied, it will turn clockwise about point A, so it's a positive moment. The same is true for 20 kN force. But look at the BY force. If you imagine using your finger to push up at that location, which way would the beam rotate? It would rotate counter clockwise, so it's a negative moment.

@@QuestionSolutions okay, thank you very much! your answer made everything clear for me. btw thanks for all your videos, i always watch them before any test!

Glad it was helpful! Keep up the great work.

You're very welcome!

👍 Many thanks!

The timestamp you gave is incorrect, so I think you're talking about 9:06 because that's where I see the 206.25. If yes, then the difference is 20-(-186.25) = 206.25. So you're subtracting the bottom value from the top to figure out the difference between them.

Awesome! Keep up the great work and best wishes with your studies.

Please see: kzfaq.infoP029mqnp4XY

So when you're doing the segments, you're looking at it from the perspective of the cut (where the cut was made). So here, the 133.75 kN force pushes up, causing it to rotate clockwise but the 40x force pushes down, causing a counter-clockwise moment.

Hmm, I guess you can sort of say that, but simply put, shear force and moment diagrams are there to help us understand the effects happening on an object at any given point.

Best wishes with your finals!!

If you're referring to the 2 methods I show in this video, then you can do either one to get the same answer. Its faster to not split the beam and use method 2, especially when you become comfortable with the relationships between shear and moment diagrams.

@@QuestionSolutions Thanks for the quick response!

@@bagaboiebailey You're very welcome!

I'm not sure but maybe this video is what you're looking for? kzfaq.info/get/bejne/graUZ9mIncydcZc.html

See: kzfaq.infoP029mqnp4XY

You're very welcome!

You're very welcome!

Glad it helped :)

Thank you!