Razavi Electronics 1, Lec 2. Doping, Drift

Рет қаралды 193,006

Behzad Razavi (Long Kong)

9 жыл бұрын

Doping, Drift
(for next series, search for Razavi Electronics 2 or longkong)

Пікірлер: 108

@amalseddiki503 2 жыл бұрын

I've been studyin microelectronics and semi conductors for 3 years ,and no prof could explain things the way professor Razavi did. We're very grateful professor

@yaswanthvasu877 5 жыл бұрын

Thank you professor for giving these valuable lectures without expecting anything

@sahiba421 3 ай бұрын

Extremely kind of you to have uploaded these lectures here, now it can be easily accessed by many students and learners across the world irrespective of any boundaries, to learn the basics the right way from the best person

@kanaditchetpattananondh800 7 жыл бұрын

Thank you for your kindness in giving a valuable lecture class of fundamental microelectronics.

@smartchip 7 жыл бұрын

So happy to have the privilege to have access to such lectures, This Man is a great person for taking the time to help so many, Thank you sir

@Clearprocess 7 жыл бұрын

Thank you very much for all the videos professor. As a recently enrolled masters student after a gap of 9 years from my bachelors degree, these videos is helping me to brush up all the basics required for the Masters study. Thank you very much and please continue. :)

@codenameweeb6233 2 жыл бұрын

"Parachute opens, hopefully". Sarcasm at it's finest, best teacher i've ever seen. 11/10, kudos!

@kavikrishnakant4200 Ай бұрын

I am an electrical engineering student studying basic electronics for the first year course, I hope I find a teacher like you who teaches electrical subjects so effieciently.. Learning from you I regret why did not I choose electronics. Well thank you very much sir from India

@wagsman9999 9 ай бұрын

These are fantastic, very clear explanations. Thank you, professor.

@geez6666 5 жыл бұрын

This is how you lecture undergrads when you know your stuff. Ie. You did not come out of a formula sheet based curriculum. When I was thought this class, my prof. just went on and on,"mu sub mu sub m prime k mu mu....", it was exhausting. Thanks Razavi

@kousalyaindravath4397 5 жыл бұрын

your lectures are golden lecuters for me sir.thank you so much sir.

@svensmets8264 7 жыл бұрын

Thank you professor for these great lectures

@MrTarq1981 6 жыл бұрын

professor rvazi is absolutely genius! many thanks

@shivaniits 6 жыл бұрын

Superb lecture , very well explained ..thank you so much Prof. Razavi and uploader :)

@mnada72 3 жыл бұрын

Superb ... No words can express my thanks

@richardgray8593 7 жыл бұрын

Who needs mediocre professors and TAs anymore wiith superb teachers like this on KZfaq?

@tanmoydutta5846 2 жыл бұрын

Same ❤️❤️❤️

@SohamChakraborty42069 2 жыл бұрын

@@tanmoydutta5846 bhai

@tanmoydutta5846 2 жыл бұрын

@@SohamChakraborty42069 mil gaya saathi ❤️❤️

@SohamChakraborty42069 2 жыл бұрын

@@tanmoydutta5846 ditching mediocre profs and TAs together! issa date uwu

@tanmoydutta5846 2 жыл бұрын

@@SohamChakraborty42069🎉🎉🎉

@mattiford8607 8 ай бұрын

Dr. Razavi is an incredible teacher.

@someone195h Ай бұрын

Great explanation 💯

@krish2nasa 7 жыл бұрын

Many thanks to Prof. Razavi!

@bahrampaivar5178 7 жыл бұрын

Prof. Razavi is alumnus of Sharif University of Technology in Iran.

@series5662 6 жыл бұрын

thank you very much the lecture is so beautifull

@mr.ANIMAT0N 2 жыл бұрын

Yes, it is

@janeap9981 5 жыл бұрын

Many thanks prof. Razavi!! Could you upload lectures on RF design?

@sumitasahu329 6 жыл бұрын

Thank you so much Sir!

@zedlepplin9450 7 жыл бұрын

Thank you sir!!!! very clear

@zedlepplin9450 7 жыл бұрын

May God bless you and the uploader

@sumitasahu329 6 жыл бұрын

Thank you so much Sir.

@Amitkumar-xw1bp 7 жыл бұрын

awsmmm lectures sir.can you also give more lectures for more electronics subjects

@user-fz2ro6th3y 9 жыл бұрын

Thanks to Razavi prof. also provider !

@rohiths5987 4 жыл бұрын

Thank you sir ♥️👍

@mohamedeusa9138 3 жыл бұрын

شكرا جدا لك Thank you very much.

@momenmibo4816 7 жыл бұрын

30:45 first we approximately said N is constant , while we didn't do the same thing for ni which is in the origin N*P or N*N ... so whether both changes or both r constant ... what am i missing here ?

@manishkumar-cn6ip 5 жыл бұрын

Hi Razavi Sir, I want to know what if exceed the doping concentration beyond 10 to power of 18. What is Max limit of doping.

@androidemulation5952 5 жыл бұрын

thanks a lot very helpful. and would you kindly upload lectures about digital uses of transistors? I mean things like how to make an AND gate or Invertors using MOS and BJT i really need it as fast as possible

@abdallahsayegh7731 3 жыл бұрын

Do u know what is the book that I have to study with these lectures or I have to note everything?

@pathikritsyam3687 2 жыл бұрын

@@abdallahsayegh7731Dr. Razavi's own book on microelectronics

@jagadeeshimmadi103 5 жыл бұрын

19:16 So as per mass action low, the maximum number of electrons/cm^3 that we can ever have in Si is 10^20 (at room temperature)

@khan1234536 3 жыл бұрын

No it is 10^10

@KEESAHAJJITSINGH 2 жыл бұрын

THANKA A LOT SIR

@yihou6433 2 жыл бұрын

I'm wondering where I can find video-related problems to practice. Can anyone help?

@williamsimpson4670 4 жыл бұрын

Si in diagram can be doped or undoped (35:20) and 10 E 15 electrons/cm^3 to 10 E 17 electrons/cm^3 (41:08) is for doped Si; for undoped Si we would have 10 E 10 electrons/cm^3.

@sakthivelmurugan6299 4 жыл бұрын

at 51.05, why the velocity is coming into the equation while that "v" is said as a dimension in the silicon picture?

@kolabharath2500 4 жыл бұрын

Suppose a man is walking with a speed or velocity of 3 meters per second. What will you say if you are asked. How much distance he covers in one second? The answer is he covers 3 meters. Suddenly the speed is changed to distance. We are representing it by ignoring per second.

@mangapathiraju7198 4 жыл бұрын

Just divide both sides by 1 sec .on one side it will become current on another side it will become velocity

@seinfan9 7 жыл бұрын

Circuits 2 lectures, please!

@Ben-sx5xb 2 жыл бұрын

The bandgap equation is not working for me. e^(-Eg/2KT) gives me zero.

@Peter_1986 3 жыл бұрын

Try playing the opening track at 1.25 speed; it's really fun to headbang to that track at that speed.

@rahulkapoor9300 3 жыл бұрын

1.5 even better

@marielabarrantes9756 4 жыл бұрын

Thank you a lot! You are really great. I just wanted to know where to find the 90-second quiz. If someone knows where is it or If I havent seen it in the video, I would be grateful to be informed. Thank you!

@jesusocampo5148 4 жыл бұрын

At 26:53 begins the 90 sec quiz

@daredevil6145 4 жыл бұрын

11:25 Isn't the free atoms already the ones that are orphaned and not broken free from a bond at the first place to have a hole?

@gopalkrishna9130 4 жыл бұрын

i think the free electrons are broken free from the bond due to rise in temperature, so when an electron breaks free it leaves a hole behind. so ni = n = p .

@user-bo8hx3jw3m 5 ай бұрын

thankyou sir

@AhmedFathy-tv5zg 9 жыл бұрын

please,can you add closed captions to this course.

@rakeshkumarkeshari6378 4 жыл бұрын

where can i get quizes links?

@pushkarnailwal7237 6 жыл бұрын

Sir I have a question that can carbon be used as a semiconductor material

@mdkalimullah4207 6 жыл бұрын

Pushkar Nailwal no because bandgap energy is very large (5eV)

@abhijitha8867 4 жыл бұрын

49:31 how can we equate the "v" taken to the velocity,that v must be a length representing the volume.

@amoonyolculuk5860 4 жыл бұрын

same question i also haven't got it

@GiorgiAptsiauriX 4 жыл бұрын

v is the length charge goes per second. He is looking for amount of charge that goes through per second. What is the problem of using v as the length that is covered by charge? If you rephrase your question, I might be able to give you a better answer.

@amoonyolculuk5860 4 жыл бұрын

@@GiorgiAptsiauriX great answer thanxx❤❤

4 жыл бұрын

bro v is basically velocity ie In Metres/second so he just took that like its V metres / second ie the distance V metres in 1 second so now he equated it to velocity !!

@mangapathiraju7198 4 жыл бұрын

@@amoonyolculuk5860 just divide both sides by 1 sec.on one side it becomes current on other side if we divide with respect to v then it becomes velocity.

@rahulbharadwaj7923 4 жыл бұрын

Why the velocity becomes constant? Can you please explain it in detail sir.

@GauravKumar-oy3rj 3 ай бұрын

just like in parachute gravity and air resistance balanace each other so it remains constant velocity...in the same way due to electric field its drifting but the atoms which are in greater number as compared to electrons so they are expereincing opposite force hence a time will come when it will reach terminal velocity...ie velocity now is constant

@deepanshuchittora6855 4 жыл бұрын

Can anyone tell me that is there any change in no. of atom of silicone after dropping

@sriharshaml1173 4 жыл бұрын

I think no, as in the intrinsic case we have 5e22 silicon and in case of doping we are adding 1e15 which is very less as compared to no of Si atoms so the density approximately remains same

@anjleenatufail 3 жыл бұрын

@@sriharshaml1173 where you got that we have 5e22 silicon atoms ?? Plz tell me 🤔

@w7shal3dan 5 жыл бұрын

why n is not increasing like p ?, is it because in high temperature ni will still be small compared to n but p will be considered ?.

@harshitpatnaik6381 5 жыл бұрын

yes even at higher temperatures ni will still stay at lower levels as compared to Nd and hence any increase in the number is insignificant...but in case of p which was already lesser in number (density) increases meaning to say you now have considerably more holes than you had earlier

@sakthivelmurugan6299 4 жыл бұрын

@@harshitpatnaik6381 when n*p=ni^2, saying ni^2 is always constant. how p can increase when the temp. increases? dont it affect the ni^2 which is constant?

@vishalmanchanda4213 3 жыл бұрын

@@sakthivelmurugan6299 ni is constant at a constant temperature so if temp. increases ni also increases and p is propotional to ni^2 it increases significantly.

@rakeshkumarkeshari6378 4 жыл бұрын

how to participate in quizes?

@HuyPham-li8gk Жыл бұрын

for the short quiz at 30:01, wouldn't alot of valence electrons become free electrons as temperature rises? why is he saying n is constant? and how is the hole density increasing so much if the free electron denisty is remaining constant (wouldn't the holes be a result of an increase in free electrons)?

@at0977 Жыл бұрын

He asks for a N-type material. For a N-type material majority carriers are the electrons you get from the dopant (Nd). Nd will not change much with temperature

@HuyPham-li8gk Жыл бұрын

@@at0977 thanks alot for the reply

@user-uk4ml2hk8m 22 күн бұрын

@@at0977 did you know the answer of second part ?

@cooltier6174 4 жыл бұрын

At @18:07 where did this 10^20 come from ?

@hpvide 3 жыл бұрын

Previous lecture, 1cm^3 of si atom having n=10

@williamsimpson4670 5 жыл бұрын

59:50 Si Hole Mobility 0.048 Metres squared per Volt per Second

@yajashgoplani345 2 жыл бұрын

why holes decreases when we increase n type doping??

@GauravKumar-oy3rj 3 ай бұрын

ni remains constant in doped or pure ...and nd increase so p ie holes decreases

@siddheshraut9827 6 жыл бұрын

Is this series micro electronic based for gate study in INDIA

@mdkalimullah4207 6 жыл бұрын

Siddhesh Raut yes bro.

@tharun541 4 жыл бұрын

@@mdkalimullah4207 Should we watch all the 45 lectures for GATE ECE?

@williamsimpson4670 5 жыл бұрын

Slip of the tongue at 00:52:40. ${\mu_nnq}$ is the conductivity, $\sigma$, not the resisitivity, $ ho$. Resistivity is $\frac{1}{\mu_nnq}$

@thodiadaknong 9 жыл бұрын

please can you add sub to this course .

@user-hp9ut5mi1v 7 жыл бұрын

18:49 ni (=300K) then 10 to the 10??

@philipecoelho1 6 жыл бұрын

이준영 that's correct. As he found out in the previous video, ni is 10ˆ10. So it becomes 10ˆ20 after applying the square exponent

@krishnareddykrishnareddy3076 3 жыл бұрын

50:10 v is nothing but velocity and second v is nothing but volatage ...then how is it possible to equate them ????

@skfuny 3 жыл бұрын

velocity = mu* E; E = Vb/L; therefore, Velocity = mu*Vb/L;

@williamsimpson4670 4 жыл бұрын

41:00 5 E 22 Si atoms/cm^3 (See Lecture 1 at 43:30)

@prasanthyoungstarscreation9048 7 ай бұрын

51:06 here v is distance/length right then how we can use v = mobility * E? .. the V we are talking is not Velocity right? (because we used it as length in volume formule)

@GauravKumar-oy3rj 3 ай бұрын

v is meter per sec ..in one second charges are travelling v meters......so to find current we have to do q/t.....ie total charges travelling cross sectional area in 1 second....and as we know v meter is travelled in 1 second so we calculated the charges that are accumalated in v meters....and sir wrote mod current ....ie values are same of total charge in v meters and current..quantitavely

@mohamedeusa9138 3 жыл бұрын

I need to get solved problem to study it I hope eny on to help me get some solved problem.

@ayshabdul9329 3 жыл бұрын

Lemme know . Insha Allah, I can help.