Riemann hypothesis

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discovermaths

discovermaths

4 жыл бұрын

The Riemann hypothesis is widely regarded as the greatest unsolved problem in mathematics.
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Пікірлер: 175
@RSLT
@RSLT Жыл бұрын
A Brilliant and wonderful explanation. This makes me love math and R.H. even more. There is so much beauty and mystery in the Riemann hypothesis and prime numbers patterns.
@asbarker31
@asbarker31 4 жыл бұрын
A wonderful summary of this intriguing hypothesis. I like the apparent connection to real world physical systems.
@MOHNAKHAN
@MOHNAKHAN 4 жыл бұрын
Hello Professor, Would Quantum Computers and Quantum A.I. will solve these types of problems like Riemann Hypothesis or Navier Stroke Equations...?
@strangerdanger7616
@strangerdanger7616 3 жыл бұрын
@@MOHNAKHAN How do you know he Is a professor lmao. Just because he has a good grasp on English.
@MOHNAKHAN
@MOHNAKHAN 3 жыл бұрын
@@strangerdanger7616 that's what you say and think... He is connected with me on Social Media that's the reason I know 🥴🥴🥴🥴🥴
@reggyreptinall9598
@reggyreptinall9598 2 жыл бұрын
I solved and proved the Reimann zeta function, check it out. I posted it yesterday!
@Quotesandfacts1
@Quotesandfacts1 2 жыл бұрын
@@reggyreptinall9598 send link
@manhsy9039
@manhsy9039 3 жыл бұрын
literally couldn't understand what Riemann hypothesis was from all the other videos on youtube, thank you for this video !!!!!
@reubenemmanuel3287
@reubenemmanuel3287 Жыл бұрын
Your videos on mathematicians are amazing. Please continue this work.
@Oscar-gx2yf
@Oscar-gx2yf 4 жыл бұрын
I've watched many videos on this subject, but i really feel like yours gives me the best picture of what this all means.
@ManishKumar-mv1zh
@ManishKumar-mv1zh 4 жыл бұрын
That's very fascinating.
@steaminglobster
@steaminglobster Жыл бұрын
I love your video, full of wisdom as the topic itself.
@jorn-michaelbartels9386
@jorn-michaelbartels9386 3 жыл бұрын
I watched many talks regarding the Riemann Hypothesis, but this one is one of the two best ones I ever watched. Thank-you very much. I will subscribe your channel.
@discovermaths
@discovermaths 3 жыл бұрын
Thank you.
@stevearmstrong7023
@stevearmstrong7023 4 жыл бұрын
Absolutey great content, thank you for this Sir
@discovermaths
@discovermaths 4 жыл бұрын
Thank you, Steve.
@Quantum_in_Java
@Quantum_in_Java Жыл бұрын
Fantastic explanation!
@RiadhBoukratem
@RiadhBoukratem 4 жыл бұрын
Good conclusion of the Riemann hypothesis, I'd like to ask you about to make a video about, how can the man calculate the first non trivial zero 1/2+i14... by hand, Thank you!
@prosimulate
@prosimulate 3 жыл бұрын
Primes arranged in a particular way do show a pattern and indeed display this order amongst all the randomness. Trouble is the pattern is beautiful to see but not repetitive. Maybe we haven't put the numbers into a coordinate system where a repeated pattern is possible, yet.
@s_edu2295
@s_edu2295 4 жыл бұрын
Thank you sir ,for such an outstanding lucid lecture ....about the intriguing hypothesis
@discovermaths
@discovermaths 4 жыл бұрын
Thanks for your kind words, Sivaditya.
@MarkusDarkess
@MarkusDarkess 4 жыл бұрын
@@discovermaths All twin primes lie at multiples of 15. Odd numbers will be where 1,3 and 7,9 Even numbers will be twins 9,1. Euler Euclid PNT Q= P1,P2,P3.... P24 First three primes 2,3,5= 30. So you will only find primes 9,1. I have the full proof written down and I will upload the video in the next 23 hours. Fastest way to confirm this is find know twins. And divide the number ending in 5 after the twins 1,3. And dividing numbers ending in 5 before twins 7,9 And the number in between twins 9,1 which will end in 0. This is partial proof of the riemann hypothesis. I have the full proof
@pudy2487
@pudy2487 Жыл бұрын
@@MarkusDarkess Least insane riemann hypothesis "prover"
@amraouza4937
@amraouza4937 3 жыл бұрын
the best lay introduction to the Riemann-Hypothesis i have ever seen , great job sir , you deserve many more views
@discovermaths
@discovermaths 3 жыл бұрын
Thank you for your kind comment.
@evalsoftserver
@evalsoftserver 3 жыл бұрын
A Solution for the RIEMANN ZETA FUNCTION is extremely valuable because It also point to Solutions for enhancing the HAMILTON GEOMETRZATION Poincare conjecture, Hodge Invariance conjecture as it relates to PRIME NUMBERS, TAYLOR INFINITE SERIES ,MACULIN SERIES and Doing Arithmetic past ZERO or Singularity as it is called in Analytic Geometry , and Algebraic Geometry, and it Directly points to the Prime factorization Algorithm , the Division algorithm, and the QUADRIATIC FORMULA This Solves many DIMENSIONS and RANK IN THE COMPLEX FUNCTION PLANE for MANIFOLD like The Kahler MANIFOLD ,CALIBU YAU MANIFOLD simeoustanesly and Points to Soulutions to the entire Millennium Prize Problems proposed by The Early 20th Century Philospher and Mathematician David HILBERT , Including the YANG-MILL Mass GAP , and the NP COMPUTATION time space COMPLEXITY problem also know as the Traveling Salesman problem
@randyzeitman1354
@randyzeitman1354 10 ай бұрын
Fantastic.
@Troinik
@Troinik 2 ай бұрын
You’re very eloquent. I would really like to hear from you what a mathematical proof is and maybe give a couple examples. Thank you for the video.
@xyzct
@xyzct 3 жыл бұрын
I'll get on it as soon as I'm done proving the solvability of the Generalized Navier-Stokes Equation.
@zanecreed
@zanecreed Жыл бұрын
The Riemann hypothesis is named after the German mathematician Bernhard Riemann, who proposed it in 1859, and it has to do with the distribution of prime numbers. A prime number is a number that can be divided only by itself and one without leaving a remainder. Prime numbers are fascinating, not only because they are of fundamental importance in math, but also because although we can't predict where the next one will turn up on the number line, they don't occur completely at random. There are rules governing their overall distribution. The most important of these rules has been proved today, and it is called "the prime number theorem." It states that for any number
@evalsoftserver
@evalsoftserver 3 жыл бұрын
A Solution for the RIEMANN ZETA FUNCTION is extremely valuable because It also point to Solutions for enhancing the HAMILTON GEOMETRZATION Poincare conjecture, Hodge Invariance conjecture as it relates to PRIME NUMBERS, TAYLOR INFINITE SERIES ,MACULIN SERIES and Doing Arithmetic past ZERO or Singularity as it is called in Analytic Geometry , and Algebraic Geometry, and it Directly points to the Prime factorization Algorithm , the Division algorithm, and the QUADRIATIC FORMULA This Solves many DIMENSIONS and RANK IN THE COMPLEX FUNCTION PLANE for MANIFOLD like The Kahler MANIFOLD ,CALIBU YAU MANIFOLD simeoustanesly and Points to Soulutions to the entire Millennium Prize Problems proposed by The Early 20th Century Philospher and Mathematician David HILBERT , Including the YANG-MILL Mass GAP , and the NP COMPUTATION time space COMPLEXITY problem also know as the Traveling Salesman problem
@azzteke
@azzteke Жыл бұрын
There is no such thing as the MACULIN SERIES!
@evalsoftserver
@evalsoftserver Жыл бұрын
@@azzteke Funny Can't you Say Something More Constructive !Than pointing out a Simple Spelling Error??
@HowardARoark
@HowardARoark Жыл бұрын
Good presentation, and fascinating topic. This $1Million prize though has fairly declined in value since first instituted - could they perhaps inflation adjust it ? What with the sky-rocketing prices of fuel and energy especially it is not going to go too far !
@chevasit
@chevasit 2 жыл бұрын
Very good!
@discovermaths
@discovermaths 2 жыл бұрын
Thanks!
@abiddiba
@abiddiba 3 жыл бұрын
I’ve always wanted a video on how the zeta function actually revealed the secrets of prime numbers - and your video delivered! Thank you. I’ve subscribed :)
@blableu4519
@blableu4519 Жыл бұрын
hi i hope i can help answer your question by directing you to the zetamath channel their last video about integrals in the complex world shows why this is the case at a certain point in the video
@TadGallion
@TadGallion 4 жыл бұрын
Thanks for the video. I notice you have a diagram at 5:07 that shows a pole at 1; surprisingly you also have a pole at 0. Unless I'm mistaken, 0 has a value of -1/2.
@glumbortango7182
@glumbortango7182 Жыл бұрын
No, you're completely correct. Most representations of the function that use the right half to reflect onto the left have a hole there, so in this case while the function isn't continuous there the limit of the function for x-->0 tends towards -1/2. Most definitions of the zeta function patch up this hole though, so I'm guessing it was left in for the symmetry of the diagram and mislabelled.
@tommyrjensen
@tommyrjensen 10 ай бұрын
@@glumbortango7182 That is not correct.The ζ-function is continuous at s = 0, where its value is ζ(0) = -½.
@miloszforman6270
@miloszforman6270 4 ай бұрын
@@tommyrjensen Frequently the functional equation is used for continuation. ζ(s) = 2ˢ * πˢ⁻¹ * sin(πs/2) * Γ(1- s) * ζ(1- s) Plugging in zero for s gives 2ˢ = 1, πˢ⁻¹ = 1/π, sin(πs/2) = 0, Γ(1- s) = 1, ζ(1- s) = ∞ Now sin(πs/2) ≈ πs/2 for small values of s, and ζ(1- s) ≈ 1/-s due to the residue 1 of the zeta-Funktion at s=1. So we have ζ(0) = 1 * 1/π * π/2 * lim[s->0] (s * 1/-s) = -1/2. So the pole of ζ(s) at s=1 and the zero of sin(πs/2) cancel each other perfectly. The pole at s=1 might tempt someone to believe that there is a discontinuity at s=0 but there is none.
@GameMaster-pz9pw
@GameMaster-pz9pw 4 жыл бұрын
So underrated
@RickyCespedes
@RickyCespedes 4 жыл бұрын
Best explaination of the Riemann hypothesis. Simple and straight forward.
@discovermaths
@discovermaths 4 жыл бұрын
Thank you!
@MarkusDarkess
@MarkusDarkess 3 жыл бұрын
@@discovermaths I solved the riemann hypothesis. There are 7 lines of proof. And I know the true fibonacci ratio. It's on my channel
@venkatbabu186
@venkatbabu186 3 жыл бұрын
Multiplicative primes for mass and addition primes for time. Spin quantum is ratio. And when ratios match quantum entangled. 7 2×7-1 3×7-2. Numbers of Doppler effects.
@alexandertownsend3291
@alexandertownsend3291 2 жыл бұрын
That word salad is delicious. Have any more?
@orenkrimchansky
@orenkrimchansky 3 жыл бұрын
Great video. Thanks! What is the smallest imaginary number on the 1/2 real number strip ever found?
@scp3178
@scp3178 3 жыл бұрын
14.134725: z=1/2 + 14.134725 i is the "smallest" non-trivial zero of the zeta function Here are the first 6 zeros (with Re = 1/2, numerically found many years ago) 1 1/2+14.134725 i (* "smallest") 2 1/2+21.022040 i 3 1/2+25.010858 i 4 1/2+30.424876 i 5 1/2+32.935062 i 6 1/2+37.586178 i One can easily show for all non-trivial zeros (in { 00 (real) The functional equation of the zeta function shows a symmetry of the zeta function at the axis Re(z) = 1/2 => If z is a zero, then 1-z is also a zero. together with the above mentioned (conjugated complex) we have: Let be z=1/2+delta + it with zeta(z)= 0. Then there are always 4 different "related" zeros forming a rectangle (z1,z2,z3,z4) with z1= 1/2+ delta + it z2= 1/2+ delta - it z3= 1/2 - delta - it z4= 1/2 - delta +it zeta(z1)=zeta(z2)=zeta(z3)=zeta(z4) = 0 If the RH is true, then this delta is always equal to 0 (delta=0, no pure rectangle)
@orenkrimchansky
@orenkrimchansky 3 жыл бұрын
@@scp3178 wow. Thank you. It is moving that's a stranger dedicate his time for me.... Thanks again 😍
@user-is5vu2rz5p
@user-is5vu2rz5p Жыл бұрын
How to find next primes? 2x=3,x=1.5 2x*3x =5,x=5/6x 2x*3x*5x =7,x=7/30x 2x*3x*5x7x=11,x=11/210x If these x value have a rule, we can find next primes? For example when 2 3 5 7 11 13 17 19 primes what is next prime?
@hipotesisderiemannderivada5763
@hipotesisderiemannderivada5763 3 жыл бұрын
You can find it zeta of function (1/2 + 14.13 ... i) = 0
@liviu445
@liviu445 2 жыл бұрын
C'mon man, how will you not show the proof to the solution, you're really keeping me on the edge of my seat.
@mathapplication
@mathapplication 3 жыл бұрын
Do you have a podcast?
@kenichimori8533
@kenichimori8533 3 жыл бұрын
ζ/12 is Riemann hypothesis zeta twelve.thanks.
@michaelkoch6863
@michaelkoch6863 2 жыл бұрын
Dear Professor. Is there perhaps a website or book listing the failed evidence of the Riemann-hypothesis ?
@wertherquartett
@wertherquartett 3 жыл бұрын
One thing I don’t get as an amateur mathematician, viz., the concept of the first so-many zeros of the function (about 8 minutes in). I presume the implied ordering relates to progression in one direction along the critical line starting at the real axis (say going up), BUT ... if there was an accumulation point of such zeros when approached from above then it wouldn’t make sense to refer to the first n zeros for a sufficiently large n (like it doesn’t make sense to refer to the first n rational numbers bigger than 0). I presume there isn’t and can’t be any such accumulation point of zeros of the Riemann zeta function but is that obvious, or is it a deep result on its own?
@lock_ray
@lock_ray Жыл бұрын
Good observation! By a well known result any analytic function can have only isolated zeros (unless it's the constant function 0). The Zeta function is analytic (i.e. it can be described locally by a power series). Thus this is not a concern. Proof sketch: Suppose f is analytic and has an accumulation of zeros at z=0 (without loss of generality, otherwise we just apply the argument to a translation of f). By analyticity we can expand f(z) = c0 + c1z + c2z² + ... in an open neighborhood of 0. By taking limits along a sequence of zeros we immediately see that c0 = f(0) = 0. It then follows that f(z)/z is also analytic. f(z)/z = c1 + c2z + c3z² + ... We can apply the exact same argument again to show that c1 = 0. And continuing inductively we in fact get all coefficients equal to 0. You can convince yourself that this means f is identically 0.
@freddyminchala8134
@freddyminchala8134 2 жыл бұрын
Can you review to Beimar Lopez, he's a Bolivian and he found a new formula to understand and solve more fast.
@Skiddla
@Skiddla 4 жыл бұрын
does that mean each non trivial zero corresponds to a prime number?
@michaelkoch6863
@michaelkoch6863 2 жыл бұрын
Where can one look at the evidence of the statements of 1915, 1989 and 1995? Could you please write an answer-Thank you.
@juvenalibarra6335
@juvenalibarra6335 Жыл бұрын
Its a way to get a me measurement to calculated a place in space
@josephdays07
@josephdays07 Жыл бұрын
I have developed a new theory, I have called Partitions Trigonometric and I have discovered something amazing. I can do X Rays with these equations applied to Z Riemann Equation.
@patrickjackman8688
@patrickjackman8688 2 жыл бұрын
Surely a disproof would be more interesting as so much work "assumes" the Riemann Hypothesis
@musicsubicandcebu1774
@musicsubicandcebu1774 3 жыл бұрын
"'Sblood, there is something in this more than natural, if philosophy could find it out."
@saidtagimouti3575
@saidtagimouti3575 3 жыл бұрын
I've seen several claims from people that supposedly solved it. There are many here in KZfaq, what's your take on that? Is there a possibility that the actual level of knowledge in mathematics prevents us from either confirming or rejecting certain solutions?
@discovermaths
@discovermaths 3 жыл бұрын
As you'll know, most claims by people who aren't professional mathematicians of having solved long-standing problems don't stand up to close scrutiny. Some problems - and the Riemann hypothesis may be one of them - probably require further advances in maths to make them tractable. On the other hand, as we saw with Fermat's Last Theorem, unexpected solutions can suddenly come to light.
@saidtagimouti3575
@saidtagimouti3575 3 жыл бұрын
@@discovermaths Thank you!
@BritishBeachcomber
@BritishBeachcomber Жыл бұрын
The are just attention seekers who don't understand the math and don't provide any proof.
@AdityaKumar-vb9jh
@AdityaKumar-vb9jh 11 ай бұрын
Please one और video lacture on riamann hypothisis
@berrybanana1267
@berrybanana1267 Жыл бұрын
What if I have found a method to exactly calculate all Pseudoprimes chronologicaly and can therefore tell you were all prime numbers are standing up...Would that be the long awaited solution?
@user-sb7mh3or4c
@user-sb7mh3or4c Ай бұрын
there is a very simple solution to this issue and a way to predict all prime numbers, prime numbers in sequence and all twin prime numbers also, it also accounts for the gaps between primes to, would like to chat more about this if anyone wishes to see some proof of this concept but so far it can count the primes in only the prime sequence e.g: 30000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000223 is a direct result of 223 and also there are 97 0's in the above and 97 is the 25th prime the opposite to that wave function is 223 or more so 3 being the opposite to 7 were 5 is the mid point or decimal or 0 so 22 = 0 0 .5 variation in that wave function so also this long number tells me that 31223 is also prime but this can be done in sequence also so from 31223 (3364th prime) the next prime is 31231 (3365th prime) the next would be 31237 (3366th prime) the next is 31247 (3367th prime) next = 31249 (3368th prime) etc counting in sequence with the right base functions, there are wave functions within the whole number as a single wave function, anyways if anyone is open to talking about how this is achieved then let me know because i'm eager to work with someone that wants to figure this math problem out as much as I do.
@prakharverma1671
@prakharverma1671 4 жыл бұрын
Sir, please analyze PRMO question paper and please make a series to help us prepare for it. (PRMO - Pre regional Mathematic Olympiad)
@geertdejonge4194
@geertdejonge4194 3 жыл бұрын
Great video! Only at 1:20 Riemann picture, he was born in 1826, not 1822. Died when he was 39 in 1866.
@c.h-btpsarl8562
@c.h-btpsarl8562 2 жыл бұрын
TRUE
@gordonis179577
@gordonis179577 Жыл бұрын
If I said I understood more than the first minute of this, I would be lying.
@leonelmateus
@leonelmateus 4 жыл бұрын
Saddened to hear that Mr Dyson of Dyson Sphere fame (and Im sure other ideas) has passed not too long ago. We need more great minds like him..
@discovermaths
@discovermaths 4 жыл бұрын
Indeed. He was one of the great intellects of the 20th century.
@MgtowRubicon
@MgtowRubicon Жыл бұрын
I watched the entire video and I only have one question: what?
@nigelanicette9243
@nigelanicette9243 3 жыл бұрын
Oh, I get it. So basically the Riemann hypothesis is a mathematical hypothesis created by a mathematician named Bernhard Riemann. According to what your saying. He created it the 1800s. Roughly 200 years later it's still unsolved. There's a million dollar prize for the one who solves it. The equation dealt with prime numbers and complex analysis. Along with complex functions. Thank you for the video. I hope the Riemann hypothesis gets solved soon.
@KingHim00
@KingHim00 3 жыл бұрын
I solved Riemann's hypothesis that every zero does end up on the line and I have proof to show you in a way for you to check and see if every zero ends up on a critical line
@josephcote6120
@josephcote6120 Жыл бұрын
There's an interesting idea that this may fall into the Godel cracks in provable theorems. (That is, there are true statements that cannot be proven.) If THAT can be proven then we would know that Riemann is true, but we can't prove it directly.
@user-vf2fl4ei8k
@user-vf2fl4ei8k Жыл бұрын
Welcome The explanation is beautiful and clear, but I have a lot of questions about the topic. Can I send you a private message to answer them.... You are my only hope
@ProfessorDBehrman
@ProfessorDBehrman Жыл бұрын
The birth year given in the graphic is incorrect. Riemann was born in 1826, not 1822.
@RSLT
@RSLT Жыл бұрын
Good Catch!
@ramesh.pikkili6886
@ramesh.pikkili6886 2 жыл бұрын
It is solved by telugu man ..andhra in india ..
@malikfahad2161
@malikfahad2161 2 жыл бұрын
Sir can you explain that function theory and Function we want to understand that Function and want to reached on it
@monoman4083
@monoman4083 Жыл бұрын
good
@itsME-dc4vm
@itsME-dc4vm 3 жыл бұрын
Nice ;D
@jinkazamaaa
@jinkazamaaa 2 жыл бұрын
This problem was solved recently by indian mathematician Dr Kumar Eswaran.
@krunalrudani
@krunalrudani 2 жыл бұрын
Not fack, it is open to challenge world top mathamacian to debate with him. Last words, only Bharat know very well "Ghanit"
@miloszforman6270
@miloszforman6270 4 ай бұрын
He _claimed_ that he proved it, and so did some nincompoop Indian journalists. Nevertheless, his "proof" was never accepted by the international experts, and the prize from the Clay Mathematics Institute has not been awarded to him.
@khabourys.2373
@khabourys.2373 3 жыл бұрын
The solution is quadrature of the circle
@1yolowe459
@1yolowe459 4 жыл бұрын
-_- No words
@sushilbalami
@sushilbalami 2 жыл бұрын
Anyone after solving it? 😅
@anglosaxondlzar9093
@anglosaxondlzar9093 2 жыл бұрын
I know the answer and i can make any number less than one a critical line
@meenadeshpande637
@meenadeshpande637 2 жыл бұрын
Hi This is Abhijeet Deshpande and.... This is how to understand the theorem.... Points: 1.) From 1 to 100, calculate the number of odds and evens 2.) Now for every single of the odd and even numbers, measure and write down the number of steps, for both to go to the number 4. 3.) For both the odd and even numbers, calculate individually as below, a.) Add the number of steps to get a total of both odd and even b.) Get a total of odd / even numbers by addition i.e. a.) How many numbers are odd and even b.) And what the the sum total of odd and even by addition c.) What is the sum total of odd and even by division d.) What is the sum total of odd and even numbers by substraction 4.) Divide the number of steps with the number of odd / even numbers wiithin 1 to 100 5.) Now upon fiding the value of the division of both odd and even numbers, Use the above results of calculations to calculate with the results to determine the base structure or the point of average c divisions or calculations, where both the calculations of odd and even align, And Voila, you have a symmetry of calculative set of equations that would determine the results of any similar supposedly unsolvable equations. These equative calculations of mine can also solve the problems of Rieman hypothesis of prime numbers as well. As such I am eligible to win the seed of Clay Institute for of and towards the same. 3x+1, Rieman Hypothesis © Abhijeet Deshpande, 2021
@user-sb7mh3or4c
@user-sb7mh3or4c Ай бұрын
30001500000000000000590009500000000000093 just noticed also this is a sequence of Pi π (also a prime number)
@user-di9xb3jz2c
@user-di9xb3jz2c 2 жыл бұрын
الترجمه
@99bits46
@99bits46 3 жыл бұрын
Prove by induction.
@rayubinger9780
@rayubinger9780 Жыл бұрын
Is the hypothesis maybe unprovable? Has its decidability been established? Has anyone proved that it is not unprovable?
@miloszforman6270
@miloszforman6270 4 ай бұрын
Nobody knows. Some years ago, many people conjectured that the Fermat conjecture might be _unprovable and unrefutable._ That was before Andrew Wiles found his sensational proof in 1993, unfortunately removing all what had been mystical about it.
@bhpkgaming5036
@bhpkgaming5036 2 жыл бұрын
It was solved
@davidwilkie9551
@davidwilkie9551 4 жыл бұрын
Interesting stories. By a bit of a random path around math-physics and a lot of Feynman type guesses, the congruence of approaches, "top down" math-experiment discrimination of proof/disproof "wave-package" superimposed on a "bottom up" reciprocal physics measurement analysis, is not so surprising as a comparison of reciprocals in the naturally occurring e-Pi-i interference, temporal positioning resonance Principle, derived format. But this is Amateur Observation, about as relevant as reading about someone else's hard work.
@GRONOPRIO
@GRONOPRIO 3 жыл бұрын
i can proof riemann hypothesis. where do i began?
@sunkhirous
@sunkhirous 3 жыл бұрын
Amazing , I solved in 2010 and mathematicians are using it to come up with alternative explanations and their new conjectures < Peter Sarnak , Barry Mazur , Michael Atiyah . Anyway all zeros have real part Zero and roots are in form of S= i (pi+- 2kpi )/lnp^2^n . Pere Sarnak had it because I send it to Annals of Mathematics and they had my manuscript for 9 months !!!
@natalyawoop4263
@natalyawoop4263 3 жыл бұрын
Send it in and get millions dollars, bruh
@jbond193
@jbond193 3 жыл бұрын
Does anyone think Leonhard Euler could have solved the Riemann Hypothesis?
@scp3178
@scp3178 2 жыл бұрын
Probably not, because Euler had not enough complex analysis skills. He worked on zeta(x in R) = Sum (1/n^x) (n=1.. inf) with x R (real numbers), specially gave very smart proofs of zeta(2k) = constant(k) * pi^(2k) (constant(k) is rational, k natural number, with real analysis tools) (solution of Basel Problem: zeta(2) = pi^2/6) We therefore know: zeta(2k) is irrational, and even more: zeta(2k) is transcendental (bc. pi=> pi^m, is!) The analytic continuation of the zeta function to the whole complex plain (without the simple pole at s=1) and the residue theorem (complex analysis, Euler didn't know) gives an expression related to the "weighted prime number counting" function, where the non-trival zeroes of the zeta function appear. That's the key point of the relation of the "Riemann Hypothesis" and the "prime number theory" (best possible approximation of the "number of primes
@marcosainte6114
@marcosainte6114 2 жыл бұрын
KRISHNA.
@reneticona385
@reneticona385 2 жыл бұрын
Lo siento pero parece que un boliviano Beimar López encontró una fórmula para dicho problema del milenio. Saludos 🖖 desde Bolivia 🇧🇴.
@elaprendiz7649
@elaprendiz7649 2 жыл бұрын
the greatest experts in this area must evaluate the work rigorously, nothing is said yet, we must be responsible
@Amandadiana22
@Amandadiana22 2 жыл бұрын
I’ve figured it out, wrote a paper on it and have no idea where to submit my paper.
@mohammedamer3527
@mohammedamer3527 2 жыл бұрын
Problem solved by hyderabad India this is so easy😎 problem
@shivabollam4081
@shivabollam4081 2 жыл бұрын
😂
@mohammedamer3527
@mohammedamer3527 2 жыл бұрын
@@shivabollam4081 🤣
@boozakid5531
@boozakid5531 2 жыл бұрын
Huh?
@stable8692
@stable8692 2 жыл бұрын
Indian person has solved it, what's your opinion on his solution??? Do you agree with him ,if not then why???
@vocnus
@vocnus 3 жыл бұрын
P.S.P. in my humble opinion (Professional Science Popularization), however the Riemann-zeta function has only one pole at 1, so there is no pole at 0 where its value is -1/2.
@williejohnson5172
@williejohnson5172 3 жыл бұрын
Tibor Banjai: (-1/2) is equal to the square root of negative 1 which is i. The entire critical line is equal to i which is equal to zero.
@vocnus
@vocnus 3 жыл бұрын
@@williejohnson5172, good joke! So, i is equal to zero, and i is square root of negativ 1, so the negative 1 must be equal to zero, because only zero is the number of which square root is zero... Good to know that (I'm joking as well). :)
@williejohnson5172
@williejohnson5172 3 жыл бұрын
@@vocnus : Take a deep breath, and think a bit. 1. I hope we both agree that Zeta(0)=(-1/2). 2. Now in the unit circle starting at zero degrees it takes two 90 degrees rotations of i to generate -1. Therefore i=-1/2. 3. In the unit circle the diameter of the unit circle along the entire y axis is 2i. The midpoint of that diameter is i which is exactly the origin of the circle which is zero. Therefore i=0. 4. Therefore i is equivalent to negative one half which is generated by Zeta(0). 5. You cannot refute these first 4 steps mathematically. Period. 6. Try logic instead of sarcasm. It works so much better when solving math problems.
@vocnus
@vocnus 3 жыл бұрын
@@williejohnson5172, I'm too low to this to catch up with these squared circles... though maybe I'm reaching 1/2 i high already, so I totally agree with myself that I need just once more this amount to grow to reach the fullness of that one crazy big I which You talking about my friend. Bytheway, if I will reach fully full I, will I forget the real numbers at all... a bit confused about that, because I fear no one would take some newly crypted i dollars at shop when I want to buy something... They are so small, aren't they, don't want to grow to higher math and to hyper truths of nature... LoOoL
@williejohnson5172
@williejohnson5172 3 жыл бұрын
@@vocnus : Yep. Just as I thought. You have a good day.
@kenichimori8533
@kenichimori8533 2 жыл бұрын
all is prime numbers. P^all
@Mac2point1
@Mac2point1 4 жыл бұрын
I solved the RH. But there's not enough space in the comment section for me to write it.
@vikassoni1760
@vikassoni1760 4 жыл бұрын
Why not to tell everyone
@MarkusDarkess
@MarkusDarkess 3 жыл бұрын
I solved it and it's on my channel.
@capnrob97
@capnrob97 2 жыл бұрын
Nice Fermat reference
@volkanturkbay6184
@volkanturkbay6184 3 жыл бұрын
You misspelled Riemann's date of birth.
@universal4334
@universal4334 2 жыл бұрын
It was solved by a telugu state professor, who live is Hyderabad, india and he has been awarded 7crores by Cambridge
@Jopie65
@Jopie65 3 жыл бұрын
The 1000000001st zero sits on 0.4
@user-sb7mh3or4c
@user-sb7mh3or4c Ай бұрын
1000000021 this would be the next prime for 1000000001, not sure if that helps but that's a result of the prime 127 remove the 0's for example the next prime is 127 and the opposite to that 7 is 3 were 5 is the mid point of that wave function, again not sure if that helps with anything
@gonelavinay2141
@gonelavinay2141 2 жыл бұрын
This problem solved by Doctor kumar ishwaran From India
@ShivamKumar-ks3tb
@ShivamKumar-ks3tb 4 жыл бұрын
I = √-1=-1^1/2×4×1/4=-1^2×1/4=-(-1^1/2)^1/4=1^1/4="+1" or "-1". Hence there is no imaginary number
@BritishBeachcomber
@BritishBeachcomber Жыл бұрын
The solution to the Riemann Hypothesis will almost certainly be found by a lone genius, like Andrew Wiles (Fermat's Last Theorem), working in secret, bringing together several seemingly unrelated branches of math. That's the beauty of it.
@RSLT
@RSLT Жыл бұрын
I agree. and should I say Good luck ?
@user-mg1hz2qm8k
@user-mg1hz2qm8k 2 жыл бұрын
SADNESS OF MATH YET TO PROVE IT'S ALL IN RETURNING OF JESUS
@merchpublicschool9331
@merchpublicschool9331 4 жыл бұрын
I believe I have solved it. And yes the proof is as beautiful and mystifying as the problem.
@discovermaths
@discovermaths 4 жыл бұрын
Send your proposed solution to the Clay Mathematics Institute. There's a million-dollar prize on offer! www.claymath.org/millennium-problems/riemann-hypothesis
@merchpublicschool9331
@merchpublicschool9331 4 жыл бұрын
@@discovermaths the CLAY said not to send proposed solutions to them, but rather publish it in a renowned mathematical paper. I know I it has to be formated a certain way, So I have to get familiar with that process first.
@merchpublicschool9331
@merchpublicschool9331 3 жыл бұрын
@@2piee I haven't sent yet, the proof itself is just a by-product of another research I'm working on. Hopefully I'll get it finished soon.
@miloszforman6270
@miloszforman6270 4 ай бұрын
I found a really wonderful proof already 30 years ago, when I was sitting in an inn. I wanted to write it down immediately. Unfortunately this beer mat was too small.
@md.salman122
@md.salman122 2 жыл бұрын
This is proved
@artificialresearching4437
@artificialresearching4437 2 жыл бұрын
I might be wrong, but this could work: kzfaq.info/get/bejne/htyFpcWh2L6-fIk.html P.S. A piece of advice: make video 1.5 faster, I speak very slowly)
@human8454
@human8454 2 жыл бұрын
It is solved by an indian 4 days ago
@alexanderealley9992
@alexanderealley9992 2 жыл бұрын
The answer to the Riemann Hypothesis is Infinity. Infinity times infinity equals infinity to the power of infinity. Infinity squared equals infinity to the power of infinity. If 2 is a prime then so is infinity. You are all welcome.
@learnedsoul7248
@learnedsoul7248 Жыл бұрын
I solved it already. -2x+iy+ai+c=0 Quadratic function of Decimal will never give you the imaginary integral Value of ZERO(0). A summation of something can mathematically NEVER Equal (=) equal... Trust me I failed Alegebra 1 &2...25 zeros will lower the average but the 25th primordial number in the first 100 of the Number Matrix is 97... So I technically got an A+ not a 37% ( another prime number) but we live in a Matriarchy full of bitchness and emotions. So fuck em
@lock_ray
@lock_ray Жыл бұрын
Nonsense with a side of misogyny. Lovely.
@markmckenna3491
@markmckenna3491 Жыл бұрын
I like the show but there were many too commercials so I turned it off and unsubscribed.
@MuddahFukkah
@MuddahFukkah 3 жыл бұрын
I think I solved it... The line x=1/2 is not x=1/2 in reality... It is an optical illusion and mistake on Riemann's part imho. Why? You have to imagine that line as frontier between two worlds: world of existing numbers and world of non-existing (imaginary) numbers. You have to change your mindset and stop looking at imaginary numbers as numbers but as something that does not exist at all. As for complex numbers, they are something like hypercube = picture/shadow of two totally different worlds meeting each other. From existing numbers' point of view, the line is x=0 because everything that equals to 0 and less does not exist!!! From non-existing numbers point of view, the line is x>0 because everything bigger than 0 exists!!!.... In reality, negative numbers do NOT exist. You cannot draw -1m2 in 2D plane, for example. That is why root of -1 does not exist either. The frontier is exactly x=1/2 because [(any x>0)+0]/2 = 1/2x => It is average/mean/equilibrium of those two worlds, let's say. Equilibrium that does not exist in reality and is relative to each world. Anyway, back to my reasoning before you are too confused: Every number lying to the right of this line (depicted as x=1/2 in the video) does exist and can be divided and is NOT a prime number... All numbers lying to the left of this line do NOT exist and therefore cannot be divided. They are imaginary numbers. The numbers lying exactly on the X=0 (which is called x=1/2 in the video) are prime numbers BECAUSE the X-axis (from existing numbers' POV) represents a total sum of possible numbers by which a certain (natural) number can be divided by and which are not equal to 1 or the original number... That is why the circles are growing bigger and bigger over time when you are increasing the input constant... It is increasing in volume/diameter over time because the total number of numbers that can be used for division of certain real numbers is increasing, too. And that is why all negative numbers will return trivial zeroes. Those trivial zeroes for negative input constants say: hi, you can divide me exactly 0 times because I do not exist. Conclusion: only prime numbers can be positioned on the line x=1/2 because all other numbers would be either placed to the right or to the left from this line. Non-prime numbers CANNOT be positioned on X=1/2 line. That is impossible... And why X is equal exactly to 1/2 according to Riemann?? Because exactly one half of the equation he uses represents existing numbers while the other half represents non-existing (imaginary) numbers. One could say it is one half because there are either existing states in our universe (1s) or non-existing states (0s). And (1 + 0)/2 = 1/2. That is why. Previously, I said x=1/2 is an optical illusion. I said that because there are only two states of existence in the universe, not three (0,1,1/2). I personally believe my theory can be used in quantum physics too, I guess... Why? Because according to quantum physics some subatomic particles can exist in two states simultaneously. Not always though! And this is why prime numbers are important!! I would bet my left nut that mathematical probability or time these particles spend in both states simultaneously is (in %) equal to ratio of prime numbers vs. other natural numbers. BAM!! And that is why prime numbers are fundamental to our universe and need to exist. lol Here you go, take this proof to some university and buy something nice for the million bucks. I will be happy for you. :) Radovan Hrubý, Brno, Czech Republic
@user-sb7mh3or4c
@user-sb7mh3or4c Ай бұрын
I agree and from what I can tell each new prime is a new sequence of a 0.5 wave function and each new twin prime is a total of 2 for yet another new sequence, would like to chat about this some more, sounds like a similar way that I used to calculate all the primes in sequence so far and the twin primes matches also to the periodic table to with the elements H for example is a 3 (3 things in total 1 thing never changes and 2 possible variations of a wave function and 1 possible observation at any one point at a time) of a prime sequence E.g: H, He (3), 6, Li, Be (7), 9, 12, B, C (13), 15, 18, N, O (19), 21, 24, F, Ne (25), 27, 30, Na, Mg (31), 33, 36, Al, Si (37), 39, 42, P, S (43), 45, 48, Cl, Ar (49), 51, 54, etc... the original table for this was: (this sequence has many different variations and the - and + are just differences or a wave function not addition and subtraction so for say carbon C that tells me that 18 can also be +12 or - 18 for binding aka anything that meets that set either or will bind, still working on this table but a by-product of it was understanding the prime numbers though) H = 3 -2 +1 He = 6 -4 +2 Li = 9 -6 +3 Be = 12 -8 +4 B = 15 -10 +5 C = 18 -12 +6 N = 21 -14 +7 O = 24 -16 +8 F = 27 -18 +9 Ne = 30 -20 +10 Na = 33 -22 +11 Mg = 36 -24 +12 Al = 39 -26 +13 Si = 42 -28 +14 P = 45 -30 +15 S = 48 -32 +16 Cl = 51 -34 +17 Ar = 54 -36 +18 etc...
@Shubham-bh1ph
@Shubham-bh1ph 3 жыл бұрын
Indian aryabhatta is invent all infinity sum problems and also trigonometry value of pi mathematical rules and other this all stolen by arebians and other countries
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