Thank you again sir for clarifying this industry wide misconception, I have seen this in many electronic books, even from the University.
@sambenyaakov3 ай бұрын
Indeed, Thanks for comment.
@icesnk3 ай бұрын
Hello Professor, thank you for sharing your knowledge, wish you the best from Romania!
@sambenyaakov3 ай бұрын
Thanks
@Zetex20003 ай бұрын
Great video!! Maybe do a video about negative resistance devices and uses?😊
@sambenyaakov3 ай бұрын
Great suggestion! Will try. Thanks.
@gonzalomeabe52563 ай бұрын
Hello, professor. Thank you so much for your videos! Very well explained and very informative. Greetings from Argentina!
@sambenyaakov3 ай бұрын
Thank you for your kind note.
@vaks2l3 ай бұрын
Well, it is not related to filtering, but low output impedance is a fairly important aspect of any power supply and this circuit enables it due to the common-collector configuration of the BJT. Nevertheless, no doubt that there is a huge misconception about the statements given in the Cadence presentation. Suggestion to all electrical engineers - please use relevant references to learn electronics (Sedra-Smith, Gray-Meyer, etc). Thanks for a nice video lecture!
@sambenyaakov3 ай бұрын
👍🙏
@foobarablesАй бұрын
Companies like Cadence and Altium should stay away from this kind of presentations on subjects they don't fully understand. It would be better if they would both concentrate on delivering quality software. Cadence used to be good. But not so for the latest versions they released. Altium is an other story.
@sambenyaakovАй бұрын
@@foobarables 👍
@anuragmahajan59193 ай бұрын
Thank you for the explanation and analysis! It has been very helpful!
@sambenyaakov3 ай бұрын
Thank you.
@binong73663 ай бұрын
wonderful clarification, thank you
@sambenyaakov3 ай бұрын
Thanks
@Cydget3 ай бұрын
If i'm understanding this correctly, you only consider a miller capacitance to be a capacitor multiplier circuit( capacitor across input to output). The bjt filters merely let you design for lower currents, and thus you can make r smaller without making the capacitor larger. Essentially you can move your pole into higher frequencies without needed a larger capacitor. The misconception being this effect does not actually increase capacitance in any way.
@sambenyaakov3 ай бұрын
Thanks for your comments. There are other cap multiplier circuits that entail current amplification rather than voltage amplification (like base to emitter in BJT).
@HAHA-ho1zz3 ай бұрын
Professor Hello ,Thanks a lot for this clarfication, God bless you .
@sambenyaakov3 ай бұрын
Thanks for warm words.
@hardrocklobsterroll3953 ай бұрын
Do you have a suggestion for alternative circuits that filter that noise? I feel that it is especially important for suppressing 60hz ripple without having massive capacitors to charge
@sambenyaakov3 ай бұрын
I will try to touch on it in a forthcoming video. Thanks for your comment.
@jacksmith-se8lo3 ай бұрын
Thank you for the great informations can you please makes a lecture about capacitor control circuit with dual mosfet for resonance maintaining circuits
@sambenyaakov3 ай бұрын
Will try
@thephantompsychic3 ай бұрын
Thanks Professor!
@sambenyaakov3 ай бұрын
Thanks
@BenjiShock3 ай бұрын
Ive used this circuit to remove a very small ripple on a 200V DC Supply. I needed to have a very clean output voltage and the load was minimal because it was for a supply for a sensor. What would you recommend instead in this case? I have to say it was a really good solution because it was easy, small and power used was minimal because of low current.
@sambenyaakov3 ай бұрын
Thanks for sharing.
@cmuller14413 ай бұрын
13:21 I guess a solution is to combine a normal RC filter with small R to cut high frequencies with the RC+BJT (with higher R) to deal with lower ones (so you don't need a huge C)
@sambenyaakov3 ай бұрын
But in the 'nirmal' RC filer the current will pass via the R?
@cmuller14413 ай бұрын
@@sambenyaakov unfortunately yes. That's why you have to use a small R and can't filter low frequencies unless you have a ridiculously big capacitor. But that's OK if that tasks is done by the BJT+RC.
@vicentematricardi35963 ай бұрын
Gracias !!!!❤
@sambenyaakov3 ай бұрын
👍🙏
@tamaseduard51453 ай бұрын
👍🙏❤️
@sambenyaakov3 ай бұрын
😊👍🙏
@cmuller14413 ай бұрын
7:21 I wonder if we could add a diode in series with Rf to increase the voltage drop.
@sambenyaakov3 ай бұрын
Thanks for your input. Indeed you can, but better to add resistance to Rf to get a lower frequency break point. On the other hand , if the current drops you may still not have a sufficient voltage drop with the Rf.
@k7iq3 ай бұрын
Awesome !
@sambenyaakov3 ай бұрын
👍🙏
@k7iq3 ай бұрын
@@sambenyaakov I hope you and your family is safe over there ! Thinking of you
@sambenyaakov3 ай бұрын
@@k7iq thnks. Thanks for concern. We are personally OK but under a lot of tension. Hoping for a resolution soon
@k7iq3 ай бұрын
@@sambenyaakov Glad you are OK. It has to be hard. Things will be fine, I'm sure.
@user-ui6xt4fd1f3 ай бұрын
Very interesting, thank You! and some bla-bla-bla in order to make this content rated as it should
@sambenyaakov3 ай бұрын
Some content is missing?
@user-ui6xt4fd1f3 ай бұрын
@@sambenyaakov Why? I meant adding some extra words for youtube algorithms to advance this