Turns out that what looks like just a single gap is actually 512 tiny gaps.
Пікірлер: 230
@WeAreShowboat10 жыл бұрын
Your enthusiasm is contagious. Keep enjoying life. Nicely done!
@peanutz2310 жыл бұрын
I LOVE YOUR EVIL LAUGH, thank you so much for this video. I do HL IB Physics so this is great!
@DocSchuster10 жыл бұрын
What? That's my HAPPY laugh. You should hear my evil laugh, though...
@kolaparadise2609 жыл бұрын
you are an incredible teacher voice color explanation and most importantly, fluency, it amazes me that u did that in one single take
@DocSchuster9 жыл бұрын
Peruvian drummer That's really nice of you. I got pretty lucky on that one!
@gregorykarimian38132 жыл бұрын
You mean in one single “phase” haha, sorry, sorry, ill stop, ill stop
@MysticMD9 жыл бұрын
The popcorn was good
@princessrad1119 жыл бұрын
7:44 golden moment
@jak58697 жыл бұрын
Wow your videos are unbelievably better than the crap videos they give me at my university. Thank you so much
@absurdu5t9 жыл бұрын
Thank you so very freaking much. All of your videos are epic.
@azazahamed10 жыл бұрын
Love the enthusiasm. He puts fun in Physics more than Sheldon Cooper. :D
@potatoria9 жыл бұрын
I love your enthusiasm!
@yashen1234511 жыл бұрын
"thats a dark fringe yo!" I LOVE THIS PLZ DONT STAHHHHHPPP EVER
@blazebluebass10 жыл бұрын
This was perfect! The explanations were totally clear, absolutely nothing I did not understand. And the excitement was fantastic, too. I feel very well prepared for tomorrows period - thank you! = )
@Dr.Isaacs3012 жыл бұрын
Mr. Schuster: Are you taking notes? Me: 👀 Also me skipping back to take notes: 😕 🤔
@rehabaljahwari698810 жыл бұрын
You are great .... You make physics very very interesting . ThanX Keep going
@DocSchuster10 жыл бұрын
Thanks! Happy to help.
@LukeR17599 жыл бұрын
Well, my brain is now non existent!
@jaydeezy1237 жыл бұрын
Excellent video. Really helped me a lot. Thanks so much!
@777teiubesc11 жыл бұрын
Thanks for deriving the equations- I've found that to be key for understanding physics!
@050328857419 жыл бұрын
REALLLYYYYY HELPFULLLL , THANK YOU !!
@misssweethearted9 жыл бұрын
awww I like the cute little Newton doll at the beginning I want it. hah
@tomasdanco27798 жыл бұрын
"It's like you're in a conversation with yourself, and get interfered by a text that you sent your self" Love it! Thanks for bringing the humor to physics =)
@Aa-fk8jg3 жыл бұрын
Thank you so much Doc!! You’re amazing
@myprettygirl916 жыл бұрын
this is hilarious, thanks for the laughs :))
@aaryanoberoi229 жыл бұрын
You are amazing!:D
@sweet77creepy10 жыл бұрын
doc, this is the first video of yours that im watchin, and man , i'll tell ya. this video needs more views. your teaching is a reflection of the passion i have for physics. when the teacher is as excited as the kid, then ...well, its a party :D cheers.
@DocSchuster10 жыл бұрын
Yay! Parties! I'm thrilled to hear that you're exited, too.
@marutinandan93599 жыл бұрын
u r a beaut teacher doc!!
@harryburiram10 жыл бұрын
love your videos!
@jamesvlasis38172 жыл бұрын
I can't believe Benson went back to school to get a physics degree
@sapphireblue92093 жыл бұрын
6:30 the example made me laugh, thank you. I was not having a good day but this has brightened me :))
@shresthabijay267 жыл бұрын
i like your funny style.. Nice work
@grethnueva34133 жыл бұрын
I loved this lecture.
@jnxmaster10 жыл бұрын
Great vid! Keep it up!
@captainaddy95912 жыл бұрын
The way he said “goodbye”
@sachinrath1236 жыл бұрын
seems when there is destructive interference we l get a dark spot and in constructive one bright spots with less intensity,so bright fringes,how are dark fringes ? are they having less darkness or less brightness.
@UH60_PILOT8 жыл бұрын
Thank you so much! even though Im not good at English, I can understand from your drawings. really good and easy explanation.
@kamilahkent646 жыл бұрын
thank you for this!
@_Nitrous_3 ай бұрын
It's too chaotic for me.. i feel more confused then i was before 😅
@pikan_golman4 жыл бұрын
im here sipping my lemonade and getting hyped as hell
@jokerhhhify10 жыл бұрын
i have some question when we divide the split into 4 split the wavelength should be h/4 not h/2 ???????? and my sequond question how a sigle wave is interfer with it self i can't imagine that ? do you have some video where i cant watch it ? i saw your Huygen's Principle but i don't get it 3) when do we have the case of 2 split and when we do have 4 split i just cant get it if the first wave interfere with the wave at W/2 and at the same moment it interfere with The wave at w/4 and give us 2 second dark postion ?
@massivejester10 жыл бұрын
Thank you for this video! :) Subscribing
@DocSchuster10 жыл бұрын
Welcome, friend.
@anagr938 жыл бұрын
OH MY GOD THANK YOU SO MUCH SIR!
@longvu59377 жыл бұрын
thank you so muchhhhh !
@danwilloughby7287 жыл бұрын
Do you still get interference when the wavelength is exactly the same length as the slit (W)? Huygens explanation states each source will produce wavelets that interact, but if there is only room for one 'wavelet' then how does interference occur? Seems to work with the maths also as if Wsinx=landa then sinX=1 when W=landa, which puts the first dark fringe at 90 degrees which is saying there wont be a dark fringe, just a light fringe gradually decreasing? Thanks for any help and for the video
@cram97807 жыл бұрын
single slit diffraction made me want to to cry
@DocSchuster11 жыл бұрын
Thanks! I should really look these things up before I start, right?!?
@cram97807 жыл бұрын
if we assume that maxima are found at odd half integers of lambda, for example ø = 3Lambda/2a you can create that maxima by splitting a slit into three slits, slits 1, 2, and 3. so all the waves from 1 interfere destructively with the waves in 2, and only 3 contributes to the maxima at that point. if you have 5 slits, 1 kills 3, 2 kills 4, and only 5 contributes to the maxima, thus ø =5lambda/2a. does that make any sense?
@MysticMD9 жыл бұрын
When you "separate" the slit into 4, do the rays converge to a single point on the screen?!? And it represents a single dark spot?
@gurulinggbiradar69823 жыл бұрын
i have a question .if the wavelength of light is very small,then even a very small distance matters right.then how can we assume parallel rays when we know there will be some extra path difference right and it could be comparable to lights wavelength.
@gentleben59011 жыл бұрын
I see what you're doing and I like it.
@ayadimishra7 жыл бұрын
I wish my class were this fun...Thank youfor this!!
@mgallegoballester10 жыл бұрын
Hi Doctor, I have another question for you I suppose that you're dividing the slit into any number of slits, as many as you want, because of Huygens' principle. But you're only taking rays that are at a distance equal to the width divided by a natural number (w/n) to calculate dark fringes in their intersections (interference), at infinite. So you take two rays separated w/2 to calculate the first dark fringe; two rays separated w/4 to calculate the second dark fringe; and so on. The problem I find is: if you just move a little closer one ray to the other after having calculated the first dark fringe, then these two new rays will interfere destructivly just a little higher in the screen, producing a new dark fringe a little higher (the angle theta will not be very much increased). That would produce a totally dark screen, or maybe totally bright. Where is my mistake? It's hard to explain without a picture, and I know it may be hard for you to understand it too, but I hope you will. Thank you very much
@DocSchuster11 жыл бұрын
Wow, thanks! I like you, too!
@jukainn8 жыл бұрын
I am eating popcorn right now
@ilovecartoonslol8 жыл бұрын
Same!
@DocSchuster11 жыл бұрын
Well, if one slit is two, then each slit is W/2 wide. Also, those two slits are W/2 apart from each other. So, yes, width is also separation, but neither is equal to the width of the real, physical slit width.
@mattheoswho10106 жыл бұрын
But what about the interference of rays from all the other positions on the two halves of the slit, that are not at a distance of W/2? I don't get it. You can form infinite pairs of rays from the two halves, but we just consider the ones who are at a distance of exactly W/2 (which are also an infinite number of pairs don't get me wrong). What is going on here? What am I getting wrong?
@zar18026 жыл бұрын
Geez... but I seriously am sitting here eating popcorn and not taking notes!
@zahraabdi66768 жыл бұрын
I love your enthusiasm when teaching. Really kept me listening with having to struggle to concentrate. I just have a question though, what's the point of treating the single slit as multiple slits? Is it just to get a better equation to use when calculating bright fringe width?
@emadrio11 жыл бұрын
you are now my most favorite person
@Shumayal10 жыл бұрын
Please come and teach at my college. I love you, wished my professors had the same enthusiasm like you.
@DocSchuster10 жыл бұрын
I'd love to, but I probably shouldn't. Thanks for the invitation, though!
@refilwesenosha446810 жыл бұрын
love how you put fun into your teaching.....i like the "fix you bow tie newton" line.....killed me
@JH-qk8tj7 жыл бұрын
How do rays of light moving parallel to each other, and starting at different origins, ever meet on a screen and interfere? 8:05
@Zerpentile9310 жыл бұрын
Thanks for the help. I wish I was as interested as you in physics. I never do this when I study 12:12.
@dhananjaypatel406510 жыл бұрын
i was asking about condition and theory proof of bright fringes.........like u hv shown for dark fringes in this video.......................please reply
@Matixcubix10 жыл бұрын
How are the bright fringes defined in the single slit diffraction?
@johnpincamera296710 жыл бұрын
how do you know that the second ray that is interfering is in the middle of the hole?
@amansinghal24317 жыл бұрын
thanks sir it really really helped
@ramanaathuraisingam817010 жыл бұрын
If you said that any natural number of wavelengths can equal wsin theta. How did you get -1 wavelengths
@apurupamargapuri41926 жыл бұрын
Why divide the slit into powers of two? Why can't we split in into 3 parts or nine parts etc?
@weiv62293 жыл бұрын
i love the title
@AbhishekKumar-rn3dq7 жыл бұрын
great dude .........great explanation.😋😊😇
@kajaldahiya87757 жыл бұрын
I never enjoyed physics that much that I did today
@Chirag149610 жыл бұрын
double slit exp gives different intensities at different points??? (the initial part of the video)
@m.hamzaramay65998 жыл бұрын
Diffraction is prominent when wavelength of light is large as compared to the object (small ball for example).In the slit experiment we say that if slit is small then there will be more prominent diffraction ,isn't the distance between the slits acts as a object here ?
@GauravGupta-by1ml4 жыл бұрын
Awesome another tutorial..
@nathanzhao49036 жыл бұрын
Why is when the distance between two rays w/4, the difference in wavelength is still 1/2? Shouldn't it be 1/4?
@waddles92827 жыл бұрын
How do the rays interfere when they're parallel to each other? (At 8:04) I'm probably just being stupid but I just don't get it :)
@ethann-n30074 жыл бұрын
What causes the bright fringes in between the integers of m
@samreynolds242511 жыл бұрын
great vid
@pokerater44638 жыл бұрын
amazing.......thnks u really are my teacher.......:) love from me
@sarahbiebah8 жыл бұрын
Why couldn't we have done the same calculations for the bright spot? Or, let me guess, there are different ranges of bright rather than the one completely dead spot (dark) so we need more complex calculations to calculate it's position?
@Blooby12348 жыл бұрын
Why does is split in half and not in another quantity, such as 3 or 5?
@DocSchuster8 жыл бұрын
+Julia Zorthian Try the maff of that split and see what it looks like. I think it would work!
@Kelvo9809088 жыл бұрын
+not anyone I've been wondering why the whole night! still no answer...
@babhishek47357 жыл бұрын
very nice lecture
@Jcozzer7 жыл бұрын
Where do the dots come from though?
@saurabh19953011 жыл бұрын
wooh...its like studing from a frnd..! thanks doc
@MrArteriole10 жыл бұрын
Hey man! Incredible video, first one of yours I've watched as I've been desperately searching for solid info on single and double slit light wave experiments. Tis people such as your self who have inspired me to go on to want to do much the same thing and teach physics at high school or university. The only things I don't seem to understand with all of this is; 1. If Huygen's principle says there's infinite points along a wave front from which 'secondary wave-lets' can exist, then why isn't there simply infinite interference? I don't see how the interference pattern can exist from this viewpoint. (I think someone asked this earlier, but I thought you may know now?). 2. At about point 8.20 in the video where by you talk about these two points from which light rays come out from, you say they're both projected with the same angle theta, but then interfere with each other a relatively large distance away. How would this work if they're projected on the same angle, and are therefore parallel? Unless by them being half a phase out means they're pathways change and meet later on? Cheers :)
@DocSchuster10 жыл бұрын
1) Very puzzling concept! Unless there is some impediment (a wall or slit, perhaps), there IS infinite interference. The slit allows only some of the new wavelets to exist, which is the whole reason that light is seen at all above and below our slit. You'll have to also agree that the slit is a very large number of very small slits all sitting on top of each other. That allows me the treatment I've made. 2) The rays are of course not perfectly parallel, but are VERY NEARLY parallel since the screen is, as you say, a long way away. That distance allows them to be [almost] parallel and finally to meet. Of course, parallel rays would only meet if the screen were infinitely far from the slit, but it would take too long to put it there. (and then, how would you get it back?!?)
@MrArteriole10 жыл бұрын
Doc Schuster I see. I guess trying to fully understand how things such as this work is pretty difficult as were only working with models, not reality. Although with Huygen's principle, if spherical waves propagate from all points along the wavefront etc etc, then wouldn't an interference pattern be able to exist on the LHS of the slit, as well as the RHS? It would make sense that there would be to much disturbance behind the slit with incoming waves, but if just one wave were to be sent, then once the wave hits the slit, the wavelets would propagate in all directions from all points along the wave, and so create an interference pattern on both sides of the slit? I understand its a 'forward' moving wave and all, but its almost as though semi-spherical waves propagate from each point, just on the RHS of the point of origin. This could then be seen to make more sense for an interference pattern only occurring on the RHS of the slit? Its all pretty nuts
@Chirag149610 жыл бұрын
Very good. btw, whole no. include zero @15:16
@lamudri11 жыл бұрын
Why does the slit have to be divided into powers of 2? Don't any multiples of 2 work as well?
@AdityaPratapSingh-ss8wg6 жыл бұрын
Mistake - whole no. Starts with 0,1,3.... Not 1,2,3.....
@sunke8811 жыл бұрын
is this how cinema theaters work?
@nikemaul10 жыл бұрын
Great !!!!!!!!! you gave me many details
@goodboi76654 жыл бұрын
ARE YOU NINJA
@Koolki5 жыл бұрын
You remind me of Jake Peralta from Brooklyn 99, fun listening to this
@Emzo999 жыл бұрын
But he did stick needles in his eyes, so that's cool hahaha
@raouf318 жыл бұрын
Doc Schuster Damn ur lucky
@10Anindita1010 жыл бұрын
Hi, I read somewhere that bigger satellite dishes diffract waves less, which causes the waves to be reflected onto a smaller focus. I'm not really sure what diffraction has to do with satellite dishes - does the dish behave like a single slit?
@DocSchuster10 жыл бұрын
Great question. Watch on, 'cuz my video is called Doc Physics - Psst...Hey kids...There's a bright spot in the middle of circular shadows. Really.
@pinkybananas17 жыл бұрын
oh my gooooooddd single slit diffraction T_____T
@ALFPAJARITO8 жыл бұрын
Dear Doc: The doublé slit system has its own interference pattern, but each slit also has it´s own interference pattern. So, in the doublé slit experiment we have 3 interferences mixed right? (that is, slit 1 interefence + slit 2 interference + slits 1 and 2 interference). What is the final interference pattern for the doublé slit takeing in count the 3 interferences mixed together?
@DocSchuster8 жыл бұрын
+Alfpajarito Wow, yes. I have spent some time looking at these patterns and forming them on my retinas, so I can assure you that the double-slit pattern strongly dominates when there are two slits. However, as the two slits each get narrower, the single-slit behavior becomes noticeable. Ultimately, the single-slit diffraction pattern is what causes diffraction-limited optics.
@ALFPAJARITO8 жыл бұрын
+Doc Schuster Thank you very much for your fast reply. I´m ahppy and surpised you was able to understoond my question because my poor english. Regarding your answer: I was trying to get interference patterns with a green laser I own, both single and doublé slit and I wasn´t able to notice the diference between them. Both patterns seems to be the same intensity, don´t konow may be I´m doing something wrong... But if both kind of patterns has the same intensity why one will dominate over the other?... What I´m missing???
@DocSchuster8 жыл бұрын
+Alfpajarito Focus on the central peak - is it twice as broad as every other peak or not. The broadening of the central peak is the only distinction between the two.
@accio_biryani8 жыл бұрын
Thank you so much sir really u r incredible. I would have been more fortunate if you were my physics lecturer. Well here r few topics pls let me know if u can help me in these.....diffraction intensity equationdiffraction at circular aperture (Newton rings)absent spectra in diffraction
@DocSchuster8 жыл бұрын
+md ajaaz Check my video on Poisson! The other topics appear to various degrees in my diffraction videos, but they don't have their own videos. Thanks for watching and learning. Be sure to work problems.
@aayushnahata9211 жыл бұрын
You make me love PHYSICSS...ur'e the COOOOLEST!!
@zungnguyen53005 жыл бұрын
why W/2 but not W or W/3 or whatever it is?
@donegal794 жыл бұрын
w or w/3 or w/5 are all fine......take w/3.....divide slit into thirds....call points between slits s1 and s2 A B and C.....if path difference between s1 and A is lamda/2 then all points between s1 and B destructively interfere (s1 cancels A, points between s1 and A destroy successive points between A and B....leaving one -third of points, those between B and C to all more or less combine to give a subsidiary maximum at that angle. Geometry says that w/3(Sin theta) = lambda/2...so first subsidiary max occurs at w Sin theta = 3lambda/2. Similar arguments work for w/5 etc etc