Spiral Traversing A Matrix Solution ( LeetCode #54 ) | FREE DSA Course in JAVA

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Spiral Traversing A Matrix Solution ( LeetCode #54 ) | FREE DSA Course in JAVA | Lecture 85

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Күн бұрын

It is an interesting question where we have to traverse a matrix in a spiral format.
So the question is, we have to write a program to print the elements of a given 2D array/matrix of size m*n in spiral order.
So for the matrix,
1,2,3,
4,5,6
7,8,9
The output will be 1,2,3,6,9,8,7,4,5.
Let's see how we can come up with an approach to deal with this program and solve it.
Hint - We are again and again moving in a pattern as left to right, top to bottom, right to left, and bottom to top. You have to use this pattern to approach the program.
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Пікірлер: 11

@user-hx1kp8kr4m 2 ай бұрын

Excellent Explanation Sir

@KRajesh-ej7dy Жыл бұрын

Sir Excellent Explination

@paisastocks8363 11 ай бұрын

Perfect 💯

@hari7110 6 ай бұрын

great explanation bro

@kethavatharyan3255 11 ай бұрын

Great

@akarshgupta4981 11 ай бұрын

Great explanation! Thank you soo much.

@user-bu4rv9od7b Жыл бұрын

superb explanation sir.

@Arjunsingh-cf7nf Жыл бұрын

owsome question

@Raubritterr222 3 ай бұрын

sir, I am saying, this is the best explanation of spiral matrix! ...I hope its clear 😉

@manoranjankumarjha3776 10 ай бұрын

class Solution { public List spiralOrder(int[][] matrix) { ArrayListres = new ArrayList(); int top = 0, bottom = matrix.length-1; int left = 0,right = matrix[0].length-1; while(left>> right top are constant for(int i=left;ibottom for(int i = top;i>>left for(int i=right;i>=left;i--) { res.add(matrix[bottom][i]); } bottom--; // bottom---->>>top for(int i = bottom;i>=top;i--) { res.add(matrix[i][left]); } left++; } return res; } }

@saurabhdwivedi7699 8 ай бұрын

Can anyone please explain me my whole code is same but when i write :- ( result.add(arr[i][right] ); It is showing me error that the type java.util.AbstractList cannot be resolved