Thank u so much make God bless u abundantly , I have watched several videos on stoichiometry, but I only ended up getting confused, this very video made me fully understand everything about stoichiometry and not to be confused when faced with a question relating to it thank u. Subscribed

First question based on calculating number of moles is 0.1mol nd second question is 200g Nd case 2 question is 0.0075mole Case 4 question volume at stp is 0.013mol

Nurse bright is an hero🥰🤸 I so much enjoy this lesson...it has really help to conquer my fears I just read textbook and have no one explaining deeper...you just did ....Thank you so much🥰🤗

Case 1 : 0.1mol Case 2: 0.075g/mol

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Thank you sir, you have made this topic easy for me. May God continue to bless you

For question dealing with formula relationship, the answer is 7.42grams

Wow Nurse Bright you are best teacher, I love your lessons😋

Sir please, I like your explanation but can you teach us with harder examples the examples you used are the basics

Thank you so much sir Case1:0.1mole Case1:200g Case3:0.013mole Case6:7.43g Case7:1.5mole

I love u sir 💋 saving more confused souls😩 more wins to ur career

Thank you so much you've made it easy for me God bless you

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Am so glad I come across ur page here its really helpful. Thanks so much N/Bright

Mass=7.423g

You are doing well sir

The answer to the first question based on calculating number of moles(n) 0.1mol and the second is 200g

thank you sooo much sir God bless you sir

So helpful nurse bright thanks

Thank you.. keep it up 👏👏

Thanks so much sir I'm just getting to understand stoichiometry

Thank you so much sir You just transform me nw Now I can solve any question under stoichiometry What a wonderful teacher❤☺️

To find the mass of calcium. n=mass/molar mass. Ca=40, n=5moles. Mass= 40×5 =200g

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More power to your elbow sir ♥️♥️

Case 6 question dealing with formulae relationship the answer is 7.43g

Case 7: practice question 3 mole of oxygen gas

for general calculations in stoichiometry, the answer is 1.5moles of oxygen gas.

Of a truth it is not difficult 😊thank you sir

Case6:7.42

Case 1 =0.1mol Case 2= 200g, Case dealing with no of mole ,conc,and volume= 0.825mol Case dealing with no of mole,volume at s.t.p 0.0134mole Case 6 : relationship formulas 7.43g

1.5moles of oxygen gas

For the at s.t.p the answer is 0.013 moles

I can't thank you enough Nurse This video was so much helpful 😊😊 Do you run a tutorial class? I would love to get more of your teaching for my JAMB preparation

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Thank you so much Sir

Case 4. Question 5. Answer is. 13.39

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Thank you sir

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Formala relationship= 7.43 approximately

Formular relationship (7.42g)

Please do a video on solubility and nuclear chemistry.

Thank you so much for this comprehensible video lesson on stoichiometry. More strength sir IJN 🙏 Sir, in your first question for PV/RT. The answer I got is 841.196 and not 0.0094moles. Please sir, help me throw more light on it🥺

Nice one sir

1)o.1g 2)200g

Case 6: practice question Mass number=7.428g

What do you understand by the term standard temperature and pressure (s.t.p.)? Calculate the volume of hydrogen produced at s.t.p. when 25 g of zinc are added to excess dilute hydrochloric acid at 31°C and 778 mm Hg pressure. (H = 1, Zn = 65, Cl = 35.5, molar volume of a gas at s.t.p. = 22.4 dm³). Please solve am confused

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Mass of calcium is 200g

Sir thanks so much for your teachings You are really good in your explanation But here again how do go about calculating the MASS where in equation are given in the calculation Calculating the MOLES in your last examples in this VIDEO I have understood, what if I am ask to calculate the MASS Please sir I need your help

Please help us talk about the limiting agent part under stoichiometry

The seventh answer is 3moles

You are the best ❤

Case 4 i got 13.39 mol /dm is it correct sir pls reply

Case 1 1 is 0.lmoles 2 is 200g

Sir I got 0.1...in case 1

Case 7: It requires 0.6 mol of oxygen. Thanks a lot for the lessons sir 😅

Sir please talk more on deriving chemical formula

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U re absolutely brilliant

Mass= 7.4g in case 6

Case 7 answer is 1.5mol

Case 4 : 0.0134

Case 6: mass=7.4g

God bless you sir

The answer is mass = 5.57g

For case 7 is 1.5 right?

Case 2: question 6 answer is 0.075mol Case 6 is 5.571g Case 7 answer is 1.5 mol.

Sir can you please do for physics pleeeeeease🙏🙏🙏

Please make a video on gas laws

Case 7 =1.5 am i correct?

What is the answer foe the mn=mass /molasses

For case 4 the answer is 0.015

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The seventh answers is 3moles

You are good

The answer to the Question 3 of the relationship is 7.43g

Kudos bro

Thanks

Case1 0.1mol Case3 0.013mol Case6 0.742g

7.42g

3mols of oxygen gas

Case 6 answer 7.4g

Case 7 answer 7.4g

1.5 mole of oxygen gas

For case 6 the answer is 7.43

Case 2 0.075moles

Sigh few hours left and i am here

Thanks alot 🫡

My main challenge is to name big compounds

200g

It is 7.429g

0.2mol

0.46

Case 4:0.0134mol

Sir I don't know what is going on I can't download this video 😢

0.1mol