Thank you! :-)

You're welcome Felix! :-)

I'm glad it was helpful for you! :-)

You're welcome Amani! :-)

You're welcome! 😀 I'm glad to hear it was helpful.

​@@Trash7Trash7Trash7 hopefully this one helped! 🙂

@@Trash7Trash7Trash7 You're welcome! 😀

You're welcome, I'm glad you enjoy the explanations! :-)

You’re very welcome Zhao, I’m glad you enjoyed it! :-)

I’m glad you enjoyed it! :-)

You're welcome Aman! :-)

I'm glad you enjoyed the explanation! 🙂

Thank you! :-D

You're welcome Kishor! :-)

I'm glad you enjoyed the explanation! :-)

Thanks so much for sharing this, that’s awesome to hear you enjoy the video! :-)

You're very welcome Azarel! :-)

I'm glad you enjoyed it Pasan! :-)

Thank you Muhammad! :-) I’m glad to hear the explanation was helpful!

@@PortfolioCourses This video is really amazing!

I’m glad you enjoyed the video Dimka! :-)

You're very welcome Sasindu! :-)

You’re welcome! :-)

Thank you Norman! And it sounds like that could be done using a while loop, which would be useful if you don’t know how many numbers there are in the string. But I think either approach could work ok too!

if you want to assign into an int then you still need to convert the string: char str[]="12"; int val = atoi(str);

Thank you very much for the positive feedback! :-)

I'm glad you enjoyed it! :-)

@@PortfolioCourses I'm glad you made it

Thank you! :-D

You’re welcome! :-)

If you call it again using S, it will start over from the beginning

You're welcome! :-)

Strings in C *can* be modified, so that's essentially how it's working, strtok() *is* modifying the string. 🙂

@@PortfolioCourses Thanks a lot sir.. Let me show you a code I've been having issues with lately.. Code 1: works well..' a' is modified to 'k' int main(void) { char str[] = "abcd"; str[0] = 'k'; printf("%c ", str[0]); return 0 } Code 2: segmentation fault int main(void) { char *str = "abcd"; str[0] = 'k'; printf("%c ", str[0]); return 0 }

@@PortfolioCourses Not really sure, why the second isn't working..

@@jess-inspired Oh that's a tricky one, basically in the 1st example a char array is created to store the string. In the second example, s becomes a pointer to a 'string literal' stored in a read-only part of memory where modifying them is not allowed by most compilers (the C language definition leaves the exact behaviour as 'undefined'). So if you want to create and initialize a string that you want to be able to modify, you need to do it the first way. The second way does create a string that is a sequence of chars ending with a null terminator '\0', BUT it will be 'read-only' in that case. And you know what? This is a FANTASTIC idea for a video haha... I think I might make this video soon explaining this difference because it's definitely confusing! 😀

@@PortfolioCourses Wow! That would be great. Encountered this issue while trying to write my own strtok function.. Thanks a lot sir, it's an honour..

Great question Dimitrious! You could use atoi() to convert the string into an integer: cplusplus.com/reference/cstdlib/atoi/. I have a video on that one: kzfaq.info/get/bejne/i7d_n7eVptingqM.html. :-)

@@PortfolioCourses I think I also can do that with strtok function in order to keep the 2 digits and after that I can use sscanf to convert it into an intiger. What do you think? Thanks for responding!

@@dimitriossomarakis3946 Yes, I suspect sscanf may work as well. You may even be able to just use sscanf from the start and not even use strtok() at all. Maybe try a format string like "%d-%d-%d-%d-%d-%d" to read in 6 ints separated by - chars? 🙂

@@PortfolioCourses yeah I will try , thanks man

I'm glad to hear you enjoy the channel! :-D So the strtok() function is a bit special, because we call it multiple times for each "portion" of the string, and we call it differently the first time compared to the subsequent calls (for the same string). So the FIRST time we call strtok() above the loop we *do* give it the string s as an argument (and delimiters are the 2nd argument d): char *portion = strtok(s, d); And then inside the loop, in the subsequent calls, instead of s we call it with NULL as the first argument: portion = strtok(NULL, d); This is a signal that tells strtok() to "keep using the same string that we previously passed in". So even though we are passing in NULL, strtok() will continue to use the string s from the previous call. And it will try to find the *next* delimiter in the string from it's previous position (where d is the string of delimiters). "On a first call, the function expects a C string as argument for str, whose first character is used as the starting location to scan for tokens. In subsequent calls, the function expects a null pointer and uses the position right after the end of the last token as the new starting location for scanning." ^ that is from this documentation of the function here: www.cplusplus.com/reference/cstring/strtok/

@@PortfolioCourses Thanks a lot Sir, now I understand it well. Really appreciate it.

You’re welcome! :-)

You're welcome! :-D

@@PortfolioCourses can you print all the delimited strings in a new matrix and then sort them aphabetically

@@dwadwadw8730 With some dynamic memory allocation, string copying, and a sorting algorithm, that's definitely possible. :-)

Thank you Abdur! :-)

I don't know if this is a question or not. :-)

Thank you for sharing this! :-)