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@sayantansarbadhikary69173 ай бұрын
Very well explained sir.. The way you explain things ans then give the solution actually prepares our way to think logically about the problems Thanks a lot. Please come up with more learnings
@ashishranjan43875 ай бұрын
For a non IT data analyst aspirant like me, this was a wonderful session. Each and every thing explained concept is clear
@arunsundar37394 ай бұрын
learnt new concepts : isNull & offset, also how to approach a problem in multiple ways, thank you very much sir :)
@rawatbobby88832 ай бұрын
Thank you thank you so much, i understand from you rvideo from one go, really amazing sir you are, thanks a lot, and keep moving in this era 😎❤
@MAYANKKUMAR-kg5kc2 жыл бұрын
Hello sir, Can you please share tips to solve this problem statement ? There's a grocery store sales transaction table with columns Tnx ID, customer ID, product ID, Date of Tnx, quantity, price. Every sales transaction that happens at the store, gets stored in this table. The store also has a customers table with columns Customer ID, Customer Name, Age, Gender, and Locality. Write an SQL query to find the name and locality of the customer who purchased the highest number of items in the month of Oct’21.
@pranutabedru43952 жыл бұрын
Thank you Sir for clearing the concept
@mallikarjunpatil75532 жыл бұрын
Thanks for explaining multiple approaches. it seems IFNULL() not working in oracle
@Anonymous_it_is2 жыл бұрын
you can use 'NVL' for oracle DB, it works exactly same
@pratiksawalkar1531 Жыл бұрын
My Solution: select case when max(rn) = 1 then null else salary end as SecondHighestSalary from (select salary, rank() over( order by salary desc) as rn from Employe)a where rn = 2
@ashitosh5012 жыл бұрын
Make video on MySQL performance tuning
@arunavabiswas91772 жыл бұрын
Thanks for your videos.They are quite good. I just feel I the offset solution will not work. As you don't know beforehand the number of distinct values that will return and dependending on that you have to provide the offset count.
@mallikarjunpatil75532 жыл бұрын
Waiting for next Video
@sumibits2 жыл бұрын
I am looking for SQL guidance… Do you have SQL live course ?
@sumitmittal072 жыл бұрын
Hi, You can checkout my SQL playlist where I cover important topics of SQL.
@ayushsen2932 жыл бұрын
Thanks sir.. approaches are really interesting... but i think oracle dont have IFNULL feature .. not sure how to get null with 3rd approach
@Anonymous_it_is2 жыл бұрын
you can use 'NVL' for oracle
@messi_codes2 жыл бұрын
thanks
@ashishranjan43876 ай бұрын
Instead of limit 1 offset 1, can not we do limit 1,1
@arunprasadhsj2 жыл бұрын
Thank you :)
@mohammedasif43492 жыл бұрын
In LC Ques no-177 where we've to write solution for Nth highest salary, if we use limit and offset concept then we've to use offset (N-1) but it shows syntax error when we use minus operator. What to do in this case??
@ooyessabhi Жыл бұрын
Before Return Statement declare and set another variable as N-1 and use that in query. See the below query for reference: CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT BEGIN DECLARE M INT; SET M=N-1; RETURN ( # Write your MySQL query statement below. SELECT DISTINCT Salary FROM Employee ORDER BY Salary DESC LIMIT M, 1 ); END
@sukanyaiyer26712 жыл бұрын
Can you give your solution. ..sql query txt file as well.. Or can post it on your Github and share the link
@SahilGupta-gy5ey2 жыл бұрын
Advance Version - Find n ( eg 10 ) highest salary without order by clause..
@AbhishekKumar-eh1ed Жыл бұрын
The solutions are good sir but if there is a question where we have to find second highest salary from each departments then these solutions would not work I guess.
@nandinisugandhi748 Жыл бұрын
you can use partition by clause then
@sakshijain35345 ай бұрын
WITH cte AS ( SELECT salary, DENSE_RANK() OVER (ORDER BY salary DESC) AS rown FROM employee ) SELECT CASE WHEN rown = 2 THEN salary ELSE NULL END AS SecondHighestSalary FROM cte;
@abimanyur7765Ай бұрын
i think you have missed using DISTINCT function, isn't it? without that...rown=2 wont give exact results. pls correct me if wrong.