Test Review of XL6009 DC to DC 1.2V to 32V 5A Buck Boost converter module
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Күн бұрынIn this video you will see Test Review of XL6009 DC to DC Buck Boost converter module
Watch 5A 50V Converter with WiFi App Control WZ5005 : bit.ly/wz5005
XYS3590 35V 5A Buck Converter with Color LCD Display: • Review of XYS3580 5A S...
We have tested this module under different load, input and output voltage condition and result is presented.
View Section of this video:
00:00 Introduction
1:25 Data sheet
02:44 Voltage regulation stability
Boost conversion tests
-Input 12V, Output 30V, 4A at 06:48
-Input 12V, Output 30V, 3A at 07:20
-Input 12V, Output 24V, 4A at 07:43
-Input 12V, Output 24V, 3A at 08:05
-Input 12V, Output 24V, 2A at 08:18
-Input 12V, Output 24V, 1.5A at 08:43
-Input 12V, Output 24V, 1A at 09:11
Buck conversion tests
-Input 12V, Output 9V, 4A at 10:28
-Input 12V, Output 9V, 3A at 10:57
-Input 12V, Output 9V, 2A at 11:09
-Input 12V, Output 9V, 1.5A at 11:39
-Input 12V, Output 5V, 3A at 12:00
-Input 12V, Output 5V, 2A at 12:42
-Input 12V, Output 3.3V, 2A at 13:15
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Tutorial by Ahmad Shamshiri form Canada
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@Lann91 4 жыл бұрын
That FAILED message scared the shit out of me, man
@robojax 4 жыл бұрын
LOL 😊😊😊😊😊
@kamalkant381 3 жыл бұрын
same here
@barriegordon1108 3 жыл бұрын
Same here on earphones!
@manlot_ 2 жыл бұрын
The XL series are actually quite successful when used for their own purposes. For example, in my tests on the buck converter, the efficiency is around % 75-80 for the LM2596, while it is around 90-95% for the XL4005. XL6009 is for boost converter only. I see that this circuit design including the Buck converter is actually a failed topology. You did a very nice and professional job. It was useful for me, thanks a lot!
@richgoza1956 3 жыл бұрын
These DC-DC converters with the XL6019E1 semiconductor in the TO263-5L package performs rather poorly, given the datasheet specifications. However, the KeeYees DC-DC Boost Mini step-up converter with a micro USB input on the PCB which has the SDB628 6-pin SOT23 semiconductor package really outperforms the larger aforementioned units surprisingly well. The entire KeeYees circuit board is less than 1/3 the size of the XL6019E1 type modules. The SDB628 6-pin SOT23 component is a fraction of the size and it really outperforms the XL6019E1 by a landslide. This seems very counterintuitive to say the least. Thank you for this video and all of your research. Keep up the excellent work.
@danydepp8487 2 жыл бұрын
Thankyou 11:11 this is what i needed. I have 12v 2A wall charger and want to convert it to 8v 2A. Going from 12 to 8. The aplication is for replacing 2 18650 Batteries with wall adapter.
@timbrown9961 2 жыл бұрын
If you read the data sheet for this buck boost converter it is rated at about 1 amp output continuous with about 10v differential so example 10volts in at 2 amps = 20volts out 1 amp = 22.5w input with losses about 2.5 watts 5a is its Max rating for milliseconds which includes input or output amperage
@spylake 4 жыл бұрын
The reviewer has misread the spec sheet. The 4 amp rating is for the switching MOSFET and essentially defines the Maximum INPUT current NOT the Maximum OUTPUT current. Consider that in the video's first load test he is trying to draw 4 amps at 30 volts from a 12 volt source. This is a 120 watt load. If we assume 92% efficiency that means we must draw 130 watts from the 12 volt source. This translates into aprox. 11 Amps. This is well beyond the 4 Amp specification for the device. Because this is a buck-boost up converter the output current limit is derived from the input and output voltage. In the reviewer's example 12 Vin 30 Vout we can calculate the maximum current from this formula. Iout = (4 Amps * Vin * 0.85%) / Vout Note: I used 85% efficiency because the datasheet only gives a rating for one case and depending of the voltages it can range between 85% and 96%. Hence 85% is a safe maximum. In your specific use case, you may be able to exceed this slightly. Simplifying our equation and inserting the values used in the video we get Amps out = 3.4amps * Vin / Vout 3.4 *12/30 = 1.35 amps Maximum output at 30 Volts with and input source of 12 volts. Note this formula is for any case where Vin < Vout.
@robojax 4 жыл бұрын
I have been victim of stores. So I am trying to test with whatever label they have on eBay, AliExpress or Amazon. so people are not fooled by the fake labels. Thanks for the comment.
@puriap250 3 жыл бұрын
Great review, very detailed and methodical. However I wish you also tested the efficiency of these things. They claim 94% efficiency in the datasheet. But with my actual test they had about 50% efficiency!! I was trying to run a 9v@1A load from a 5v supply and I realized it draws about 3.5A of current from the input.
@robojax 3 жыл бұрын
this was one of early videos. I've added so many features to the tests. here is a converter video on my other channel which focuses only on Power, charger, solar and battery kzfaq.info/get/bejne/Z7x-pLWiu5bPlZ8.html
@Lord5oth 8 ай бұрын
thanks for the thorough testing
@robojax 8 ай бұрын
Our pleasure!
@aladino10100 6 жыл бұрын
Nice and simple video, thank you for sharing. BY THE WAY, did you measure the A you can get @ 12V output? I'm running a project where the load (an aquarium pump) needs 2A @12VDC, and the small step up can't cope with such need. Any advice? Thx
@robojax 6 жыл бұрын
Thank you. You are right. At the time, I did not have power supply with 30V and 5A. now I have got it and make sure to do another test with 30 or 35V
@sculpturekris3548 3 жыл бұрын
The stability test at 4.14 to 4.19 shows a nasty problem. If the input voltage drops below the minimum threshold - the output voltage jumps from the desired 8v up to 13.6v. My testing of an input supply drop-out - with a small LED load - has produced an over-voltage up to 25v when set for a 4v output. I would have expected the output to degrade safely when the input drops below the minimum.
@generalawareness101 3 жыл бұрын
I purchased four of these and the slow boat from China just arrived. If I wanted to drive a white LED from a 1.2v cell how would I do it since this is not a CC driver?
@neilparker2310 2 жыл бұрын
Seems to have two inductors. Is it an isolated buck / boost converter ?
@bwtharp 6 жыл бұрын
What is the make and model of your test equipment? I need to test converters at 12v/12A input boosted to 15v/8A output. I’ve been hunting for a way to do it. That unit would help me.
@robojax 6 жыл бұрын
it is called 150W electronic load. sold on eBay. I have a video on it here : kzfaq.info/get/bejne/Y9F5arKlua7IYWw.html
@anthonysanico1045 3 жыл бұрын
Good review sir very specific Hope for further videos
@robojax 3 жыл бұрын
I will try my best
@altamiradorable 5 жыл бұрын
Question: Should you not adjust output voltage WHILE on the load instead ? Any 12v car battery will register 14.4-15v by itself and drop to 11-12v on load.
@robojax 5 жыл бұрын
You can adjust but if the output is connected to sensitive device you might burn that device if voltage increases
@pietdepad4103 Жыл бұрын
I appreciate your work and demonstration. What a pity that you didn't measure the currents at 10V and 14V input and 12V output. I what to use this module to stabilize a battery. If you have that data, please let me know. Anyway thanks for the video.
@johnf3326 5 жыл бұрын
What is the equipment you use to create the test load? I could do with one!
@robojax 5 жыл бұрын
I should have mentioned in the video as "Electronic load" and I have a video on that: kzfaq.info/get/bejne/Y9F5arKlua7IYWw.html
@acdcjavier22 4 жыл бұрын
Thanks so much for your video! In the university, when I learned about boost converter I remember that Boost only is used for low current operation, boost isn't good for hight current. Anyone can recommend a good boost/buck converter?
@robojax 4 жыл бұрын
You're very welcome! I can't suggest. But have tones of videos. kzfaq.infovideos search here
@MrChrono777 6 жыл бұрын
Greetings friend!! Considering the use of XL6009, what is the minimum voltage that I need to input to obtain an output of 19V 2A?
@robojax 4 жыл бұрын
Hi, KZfaq made new tools so I can check which comments I have not replied and here I found you. Sorry I missed your comment.
@TheKetsa 6 жыл бұрын
12V input and 30V - 4A output... How many Amps are you pulling from the INPUT ? 10 A ? ratings are given for the input, no ?
@robojax 6 жыл бұрын
it doesn't work and failed shown at 07:19 . But generally if it works, the total power P = V x I, I is current so if output is 30V at 3A, P = 30X3= 90W and the input should be 90W + losses (if 10%) = 100W. and you see at 12V, you can get I = P÷V, I= 100÷12= 8.33A
@luisgalviz9188 3 жыл бұрын
Good video, with a power bank 5V 3A, can you opt for the 9v and 2A output? Thank you
@robojax 3 жыл бұрын
P=IV, I=3, V=5, so P=3(5)=15W and for output you wan to make P=2(9)=18W. so you wan to get 3W more than input. The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. you can't do it.
@hemantakakati1103 4 жыл бұрын
I need 5v to 9v 2a converter. Im confused which one to get this one or step up converter ? I need this for a guitar amp it needs dc 9v 2a. So i was thinking to use my powerbank it outputs 5v and upto 2.4a so possible to draw 9v 2a using any of this booster or converter ? What would you suggest ?
@kaikart123 3 жыл бұрын
9v 2A is 18W and your supply could only give 5v 2.4A which is 10.8W, so it's not possible.
@abdullahnaggar Жыл бұрын
Thank you very much good job
@billydemulder8413 3 жыл бұрын
Hi, I am working on a project that uses a hand crank generator that I built to charge an 18650 Li-ion cell. I have a charge protection circuit for the 18650 cell which requires a 5V input. The issue that I have is that due to the nature of hand cranks the voltages they produce are quite variable. I have added a 4700uF capacitor to the output of the generator to try to help with this but I need a buck/boost converter which will take the voltage from the hand crank, about 8V (which varies by about +/- 1V) and provide a 5V output which is stable to supply the Charging circuit. The other issue is that the current draw from the battery decreases as it gets more charged so I’m worried this will further affect the stability of the buck/boosted 5V. Can you suggest a buck/boost module for this? Thanks
@robojax 3 жыл бұрын
Yes you can use just a boost converter so it always output like 12V. then you need buck converter that brings it down to your need level. of course if you get buck boost will do that for you.
@alemansrao 2 жыл бұрын
Thank you for this video
@AlvimBR 4 жыл бұрын
Hi Robojax! The "4A" current limit specified on this module is IN or OUT current? Whichever is bigger?
@robojax 4 жыл бұрын
Hi, it is OUT. See my test.
@RexxSchneider 3 жыл бұрын
@@robojax Nonsense - the 4A current limit is the limit of the current flowing through the internal MOSFET. If it's in boost mode, the 4A will be the limit for the INPUT current. That's why you get the so-called "FAILED" when you try to take 4A out at 30V - with only 12V input, you're trying to draw over 10A input current. Of course it shuts down.
@vanhoanguyen9331 Жыл бұрын
@@RexxSchneider yes. You're right. Power is limited
@JithinJose2 3 жыл бұрын
V.good video, you definitely need to get a FLIR cam.
@robojax 3 жыл бұрын
thanks. see my latest review of converter kzfaq.info/get/bejne/ntF8dpl2yLnPnH0.html
@astayandablinkisastink9980 3 жыл бұрын
i don't know if i sound stupid, i have no background info about this but...does the output current of XL6009 depend on the load? or it depends on something else?
@robojax 3 жыл бұрын
No question via stupid. The current depends on the load but if load draws mor than the board can supply, then either the voltage will be reduced or the board dies.
@blueskyy40 5 жыл бұрын
Can i use xl6009 for 12v modem using power bank???
@robojax 5 жыл бұрын
Check for your output voltage, see how much current (ampere) is needed and if your modem power bank has that much power or current, yes you can use it. It must be DC.
@yankovalsky7696 7 ай бұрын
Thanks. Good test.
@robojax 7 ай бұрын
Thank you too!
@TaylorSoloaiJR 4 жыл бұрын
Hi there, I ahve two questions. 1. Will adding heat sink to the IC help? 2. What buck/boost converter have you tested so far that you recommend. Thank you in advance.
@robojax 4 жыл бұрын
1-yes it can reach up to 5A 2-Can't recommend but you can see them here kzfaq.infosearch?query=review
@jazasleman5475 4 жыл бұрын
hello bro i have one question please ..can i use it for regulate turbine voltage.?
@robojax 4 жыл бұрын
Yes this is exactly does that. For example your turbine is 12V to 18V and you want always 9V, this will always give you 9V.
@alejoramirez5846 4 жыл бұрын
Hello, with this module is it possible to supply a 3.7V 18650 2600 mAh battery with a 9V output? and how much ampere will be obtained with the output, the question is how much this module consumes, I will connect it with arduino due with 3 peripheral modules, thanks for your help
@robojax 4 жыл бұрын
Hi, I did this test to answer all question you might have. Please watch it without skipping the video. watch it fully and you will find the answer.
@anthonysanico1045 3 жыл бұрын
Hellow sir i have another question Can i put 20a max current on this module? Ty for the response
@robojax 3 жыл бұрын
Hello, current does not matter at input. you can put 1000A battery. this module takes current only for the load that it needs.
@sulaimankhan5681 Жыл бұрын
Sir can i run a 9volt 0.06amp wifi router with this module.use as a buck module from 12to 9volt?
@robojax Жыл бұрын
Hi, I am not sure if you paid attention. I have tested different input and output voltages and tested it with load. Load is like your WiFi router. I don't remember the numbers so watch and see which value is closer to what you need and see if it work. but 12V to 9V conversion at 60mA is like nothing to this module.
@FaisalAhmed-ng8hx 5 жыл бұрын
I want input 5v from power bank and i want run my router and onu 12v 0.5A 2device??
@AbhishekKumar1902 4 жыл бұрын
yes u can power it
@Ziplock9000 4 жыл бұрын
@@AbhishekKumar1902 You don't know that, it depends how much current can be drawn from the power bank which will be more than 0.5A as it's boosting the voltage which lowers the current.
@Techknowledgevva. 2 жыл бұрын
Subscribed.
@JeffsTravels 5 жыл бұрын
This board works better with a heat sink on the diode. There is a well known heat problem with this board which can be solved by using a heat sink or adding another diode in parallel. (there is a video on youtube from a British guy that covers it).
@robojax 5 жыл бұрын
this product is very cheap. buying diode would cost the same as the board. People should simply avoid this a select something else.
@muflatu 5 жыл бұрын
Help me to find him please.
@englishrupe01 4 жыл бұрын
@@muflatu He probably means Antony Cartwright.
@imperialrecker7111 3 жыл бұрын
I watched your video without skipping :) but I am still unsure of how I could use xl6009 to step down my power source from 24V 10A to 12V 2A. over here I am not worrying about the output voltage but the input current from my supply is 10A. Any ideas of stepping the current down? I was thing of using resistors in parallel configuration .
@robojax 3 жыл бұрын
if you connect 24V 1A or 24V 1000A it doesn't make any difference when you connecting it. Only when you consume or use higher current, if the convert can't handle it, either it disconnects the output or the module burns. in your case the module will simply reduce the voltage and and allow up to 5V to pass. the 5V depends on the load. if the load needs 2A, then 2A will pass.
@imperialrecker7111 3 жыл бұрын
@@robojax OK thanks. As you can see from my electrical knowledge I am a hobbyist
@MattTogli 2 жыл бұрын
@@robojaxRobojax I get confused, guess you mean 5A not 5V.
@lawalmohammed83 2 жыл бұрын
Please Sir will it work with input of 4.2v from lithium ion battery? And why if yes?
@robojax 2 жыл бұрын
I have mentioned they minimum and maximum input voltage and shown datasheet. Please watch the video.
@kirkguille 6 жыл бұрын
Hello, i need 3mA at 24V, my supply is 5V, 1A, can this module do this?
@robojax 6 жыл бұрын
yes. you supply 5V x 1A= 5W that is total power. You need 24V x 0.003 =0.0072 or 7.2mA. this is about 60 time of this device can supply and it should work fine.
@gavinwilkinson3722 4 жыл бұрын
The boost tests were particularly bad. I just ordered one if these before i seen your videos. I got it to go from 12.3v to 14v and my load is 500ma.
@samanthiliyanapathirana4305 4 жыл бұрын
What will happen if I connect 10A to the Input ???? Plz Reply to me!
@robojax 4 жыл бұрын
it is if you can carry on your back 50kg and walk easily up to 1000m. if they put 100kg, then your back will perhaps bent and after 200m you will stop and say "can't do it". exactly the same will happen. first the output voltage will drop and it will and then will stop working.See this datasheet www.xlsemi.com/datasheet/XL6019%20datasheet-English.pdf on page one you see very important features .
@Rdsw-techBlogspot Жыл бұрын
Thanks I need this
@niky7197 Жыл бұрын
Problem is with the charging capacitors, inductors and line path ampherage. Not with the topology...
@imrannazir5585 Жыл бұрын
I want to get 12V 2.1 or 2.2 amp from this module as output voltage. Will it drop when the load is putted?
@robojax Жыл бұрын
this test was exactly for that purpose so you can get to see it. Please watch and come to conclusions
@imrannazir5585 Жыл бұрын
@@robojax do you have any videos with XL 6019 board?
@yubinator7455 Ай бұрын
Does heatsink on the IC help on the temperature?
@robojax Ай бұрын
of course it does help.
@Rcrdo072 4 жыл бұрын
would 2pcs of XL009 in parallel connection would double the ampere capacity?
@robojax 4 жыл бұрын
Yes BUT you have to set exactly output voltage.
@Rcrdo072 4 жыл бұрын
@@robojax thank you sir, i think this solves my problem👍👍
@davaadorjd9370 2 жыл бұрын
Hello, xl6009e1 can i use it to run an electric bike motor
@robojax 2 жыл бұрын
Hello, if your bike motor has two wires which is called DC motor then yes.
@ayaaca8500 4 жыл бұрын
what happens if you use an input voltage less than the recommended voltage? maybe a voltage less than 5 volts
@robojax 4 жыл бұрын
I had to watch the video to see if I have answer to your question and indeed I have. You have skipped the video. I have spend almost full day testing, recording and editing. Please watch without skipping and you will get the answer to your question.
@ayaaca8500 4 жыл бұрын
@@robojax yes sorry, that was my fault I can conclude if the input voltage is below 3volt, the output voltage seems to rise above the desired voltage. Is it true? Is that the character? if yes, I think this module is very dangerous for a beginner thank you
@Ziplock9000 4 жыл бұрын
@@ayaaca8500 It seem so, but the testing below 3.6v was so brief it's not conclusive.
@user-zj8vm4tl5f 2 жыл бұрын
thank you sir you are so good Im Ali from Iraq 💖😊
@bosstronix4970 Жыл бұрын
why you removed the diode from the input sir?
@robojax Жыл бұрын
I have not modified anything. Where ? please mention the time like 3:45 so I look at it
@interestingnews5296 3 жыл бұрын
Can i input 12 v battery 20 ah And could get 24 v 5 amp?
@robojax 3 жыл бұрын
Hello, that is exactly I made the video so you watch and get the answer. I don't know unless I watch it. so you watch.
@ducthangphamngoc5971 3 жыл бұрын
Could you please try with INPUT 5V , OUTPUT 12V , load 1.5A?
@robojax 3 жыл бұрын
you can do it easily.
@svem1972 3 жыл бұрын
Sir, recently I bought xl6009e1 dc-dc module when I connect from battery of 5v I get desired output, however when I connect to any device immediately vtage drops and my router or modem or setup box do not turn on which consist of 12v. Your inputs is highly appreciated
@robojax 3 жыл бұрын
I've demonstrated the maximum current (ampere). if the output power exceeds, the voltage is reduced. so check your load or router's current before connecting making sure this module is capable of powering it up. calculate input and output power and input must be 15% higher than output. your 5V must be able to have AT LEAST 15% higher power than output. Power is IV where I=current in ampere and V is voltage for both input and output calculate this. good luck.
@svem1972 3 жыл бұрын
@@robojax Sir Thanks for your valuable inputs, I have power bank with 5v 2.1a as on output. which is connected to step up module and getting output as 12v. I cannot increase input 15% as higher than output, coz i am drawing voltage and load from a mobile powerbank and boosting up to 12v. i am hobbyist and beginner not expert, so thought to do own circuit and see if works.
@robojax 3 жыл бұрын
15% is the losses, if you can't increase the input by 15%, then subtract 15% at output. I have to make a video so anyone had question, just send them the link. when input is 12W the output can never be 12W it will always be less than the input by the amount of losses. good luck.
@svem1972 3 жыл бұрын
@@robojax sure sir I will, just all want is 5v with 2amp and step up to 12v with load of 2amp in this regard I have used mc34063 IC however it has only capacity of 1.5amp current drawn for the components have used in my circuit. Just wanted 2amp at the max, please do one video it's a request
@MattTogli 2 жыл бұрын
Nice and clear. Have you tested booster XL6009?
@robojax 2 жыл бұрын
Here is how to find a video in a channel kzfaq.info/get/bejne/hc6biMaWp73HeKc.html
@ryancastro1262 3 жыл бұрын
Can i use it for input 5 volts 2 amp (power bank) to boost up 15 volts 1 amp to power a modem router? Thanks..
@robojax 3 жыл бұрын
Unless I watch the video, I won't know. So please watch and see the tests and you will know.
@blackaplha 3 жыл бұрын
@@robojax lol
@timbrown9961 2 жыл бұрын
No just multiply volts and amps 5v x 2 amp = 10watts 15v x 1amp = 15 watts so from a 2 amp supply it is not possible even if it was 100% efficient
@japnanang4132 5 жыл бұрын
Low input amp?
@robojax 4 жыл бұрын
sorry missed your comment. what do you mean by "low input amp" ?
@AbhishekKumar1902 4 жыл бұрын
please also use a thermal camera to monitor the chip temperature
@robojax 4 жыл бұрын
I did use it when I had the camera. But some videos are done before I got a thermal camera.
@AbhishekKumar1902 4 жыл бұрын
@@robojax ok, keep up the good work 👍
@robojax 4 жыл бұрын
Thanks. Will do .
@baogiangsongque5507 6 жыл бұрын
if you take off the trim pot 103=10kΩ then fb=0v; it turns out Vout=48v. if you piggy back xl6009 ic and diode ss34(max 3A instants) on the top with thermal pad then you doable double amperes from 2A to 4A. the module has no voltage protect feature but you can use for lab or cheap project not for expensive device. avg load =12w max then you need to change cap of out put=100u200v and inductor filter=8uh.
@robojax 6 жыл бұрын
Your suggestion might work. then why use the module at all? Make your own PCB and circuit.
@panchagnulamanasa5324 4 жыл бұрын
Can I use this for 3.7 to 5v
@robojax 4 жыл бұрын
I believe I made this video to answer these type of questions. Please watch it without skipping. you will get the answer.
@rishigondiya689 5 жыл бұрын
Which thing is used to increase current ma to A
@robojax 5 жыл бұрын
The maximum current is fixed in this module Your load determines if you want to draw high current or low current. connecting smaller resister at output will draw higher current . (i) is current in Amper I = V/R
@rishigondiya689 5 жыл бұрын
@@robojax i had a current 30ma and i need a cuurent 2A what can i doo
@robojax 5 жыл бұрын
you had 30ma and need 2A? sorry didn't get it. you had 20mA where?
@imperialrecker7111 3 жыл бұрын
hey robojax I accidently cranked up or down the pot in the circuit. How do I fix it?
@robojax 3 жыл бұрын
Hello, if it is broken, then you gotta replace it. The value is on the pot as 204 or 105 or any other 3 digit. if not broken, turn it about 10 to 20 turns to bring it back.
@imperialrecker7111 3 жыл бұрын
@@robojax value on mine now is about 260 ohms
@imperialrecker7111 3 жыл бұрын
is it broken ?
@sudiptade2104 3 жыл бұрын
Which is better , xl6009 or lm2529 ???
@robojax 3 жыл бұрын
two different things XL6009 is 5A www.xlsemi.com/datasheet/XL6019%20datasheet-English.pdf and LM2596 is 4A converter www.ti.com/lit/ds/symlink/lm2596.pdf?ts=1607320532696&ref_url=https%253A%252F%252Fwww.google.com%252F we can't compare them. it is like a sedan and SUV.
@adamelkoumy5141 6 жыл бұрын
Thank you so much for the video. Would you please make a video on the ( CJMCU-758 ACS758LCB-050B-PFF-T Linear Current Sensor Current Module ) ????
@robojax 6 жыл бұрын
You are welcome. Sure I will. I just put it on my list.
@vanhoanguyen9331 Жыл бұрын
Some shops do not provide information about output power. But I researched and found out it's only ~20W (and 25W with heatsink) in theory. Yeah, pretty low but don't ask too much at 2$. (Sorry if my English makes you uncomfortable)
@imperialrecker7111 3 жыл бұрын
Can I use this for steping down 24V 10A to 12V 2A?
@robojax 3 жыл бұрын
I believe I made this video to answer questions like this. please watch it to get the answer. I have spent over 10 hours to make this video. You can will watch it for 20 minuets and get all experience and usage of equipment and knowledge.
@imperialrecker7111 3 жыл бұрын
@@robojax ok thx. I will re watch it again
@robojax 3 жыл бұрын
you are welcome.
@Dansk55 4 жыл бұрын
I noticed that adding a slice of tin foil over the heat sink helps improve these numbers
@robojax 4 жыл бұрын
thank you for tip.
@SaffroelJamal 3 жыл бұрын
Can we add heatsink on its board?
@robojax 3 жыл бұрын
people use smart ways to attached heatsink. Sure if you can attach it to the chip, it will help greatly.
@kaikart123 3 жыл бұрын
Just put a grain of thermal plaster or a piece of thermal adhesive tape.
@21thTek 2 ай бұрын
Great !! ⭐⭐⭐⭐⭐
@amargupta.8847 4 жыл бұрын
Hii I'm using the same module, but it's overheating. Even the solder melting. Plz help me..
@robojax 4 жыл бұрын
Either reduce load. Or reduce input voltage. If it does this without load, then the module is bad.
@amargupta.8847 4 жыл бұрын
@@robojax yes its with no load. And multiple modules burned. All those boards are faulty?
@englishrupe01 4 жыл бұрын
@@amargupta.8847 Obviously not, as his is not. No, they are generally very reliable in my experience. Are you connecting it correctly?
@amargupta.8847 4 жыл бұрын
@@englishrupe01 yes . I checked the polarity and limited my current to .5 amps at input. And no load is connected except multi meter... . And I agree with the circuits that I buy from chaina. I ordered many boards and never happened like that. Maybe the batch I ordered might be flawed ( may be used different valued caps or inductors). I will check in detail and update soon. Tq sm for the response ,🤗
@heartbeat1812 3 жыл бұрын
Mt 3608 is better than xl6009????
@robojax 3 жыл бұрын
watch MT3608 review here kzfaq.info/get/bejne/grN7nLN2xJi5pWg.html and decide which one is better. The word "better" is relative. So you watch and decide if it is better 'for you' or not.
@sabbirahamed3183 3 жыл бұрын
Hello bro i am from india please make a video on Dc to dc buck boost converter i need the current over 2amp so please make video on better buck boost converter cause i need 12v and 3amp constant
@panchagnulamanasa5324 4 жыл бұрын
Xl6009 vs mt3608 which is best
@robojax 4 жыл бұрын
here is the video on that kzfaq.info/get/bejne/grN7nLN2xJi5pWg.html watch and compare
@faizmomin9658 3 жыл бұрын
Nice
@sanketwani1391 4 жыл бұрын
Can i give 3.3 v and get 5v 2amps output
@robojax 4 жыл бұрын
this is Buck converter or step down converter. You need boost converter. So my videos on boost converters kzfaq.info/love/kcBSig_Iu4ZnAIeCeG1TVgsearch?query=boost
@englishrupe01 4 жыл бұрын
@@robojax Umm....i think you are confused with all your videos Robojax, lol. This one is a buck boost.
@englishrupe01 4 жыл бұрын
Yes, that should be OK
@ourchannel8215 11 ай бұрын
when input 3.2v - 3.3v module get something is go boost to up 28v😅
@rishigondiya689 5 жыл бұрын
What is input current
@robojax 5 жыл бұрын
I did not provide it but I have noticed that these converters have about 90% efficiency which is 10% loss. So they need 10% extra power at input. for 9V and 3A output 9V x3A=27W, add 10% to it would be 1.1x27 =29.7W. Now if you need to get this power from 12V input, then 29.7W÷12V =2.48A at input.
@repcomk 5 жыл бұрын
Input current depends of the output, but in video you can’t see variations in the input it means that power is enough for the tests, the regulator is what fails
@xxycom8963 5 жыл бұрын
I will bet you the problem is heat not being dissipated, and the device protecting itself. Wonder if a heatsink will help
@robojax 5 жыл бұрын
the chip is already soldered on the PCB so you can't put it on heat sink. Even if you left it, up, there is no enough room to put heat sink as the inductor is on the way. So this module is how it is used.
@rktronic3651 3 жыл бұрын
Thanksss.
@robojax 3 жыл бұрын
You're welcome
@anton000 4 жыл бұрын
how many amp your input source?
@robojax 4 жыл бұрын
Poutput=Iout X Vout and Pin=Iin X Vin to find the current subtract add 15% power to the input so Pin + 15%Pin = Pout. the 15% is losses of the module.
@anton000 4 жыл бұрын
@@robojax yes but are you using battery? if battery C-rate might be a factor it's failing. I've used this successfully with 18650 in 2s2p w/ 15W LED COB LED.
@anton000 4 жыл бұрын
like your example, 30v 4a. Can your 12v supply do 11.5a ? Also 12a draw is already over specification thus will fail.
@shuhaib-kottakkal 3 жыл бұрын
Input ampere???
@robojax 3 жыл бұрын
I believe I made the to actually show exactly the input current (input ampere as you call it). have you watched the video?
@maximilienjenius1389 3 жыл бұрын
Source Input 12V > ?A if Source Power lower amp .... A. Boots Step < A. Source Power . 12V 1A = 12W if you boot to 24V Max A= 0.5A = 12W I want to know how many amps of the 12V power source. Because if you put 12V 1 A it will not boost you. The output is directly proportional to the source power supply, so if you supply lower current than what the destination load uses. It dropped. The test source is invalid, the result of this test is invalid. --------------------- อยากทราบว่า แหล่งไฟฟาต้นทาง 12V กี่แอม เพราะถ้าคุณใส่ 12V 1 A ยังไงมันก็ บูสเพิ่มให้คุณไม่ได้หรอก เอาท์พุท จะแปรผันตรงกับแหล่งจ่ายไฟต้นทาง ดังนั้น ถ้าคุณจ่ายกระแสไฟ ต่ำกว่า ที่โหลดปลายทางใช้ มันก็ดรอปนะสิ ต้นทางที่ทดสอบ ไม่ถูกต้อง ผลลัพท์ การทดสอบนี้ จึงไม่ถูกต้อง
@electron-1979 5 жыл бұрын
I like anti-clockwise to increase output voltage, just like a water tap!
@robojax 5 жыл бұрын
Yes but some people like it like volume control on Car to increase the volume.
@electron-1979 5 жыл бұрын
@@robojax Oh yes, I can see that
@gordonrichs3357 3 жыл бұрын
19v 2a 34v 👍👍
@daveton3895 4 жыл бұрын
All these xl 6009/6019 converters are a great way to blow up your electronic circuits. These boosts wildly swing output voltages at low input voltage . Most test review do not even mention this or warn you. Good luck using this crap. For more see the comment from richardnanis
@robojax 4 жыл бұрын
you are right.
@shadowhunterxxx5891 4 жыл бұрын
This madule is max 15 watt with heatsink
@robojax 4 жыл бұрын
It had 5A rating at all 1.2V to 32V output voltage. See it on datasheet: www.xlsemi.com/datasheet/XL6019%20datasheet-English.pdf
@chamunu123 2 жыл бұрын
No sound ..
@robojax 2 жыл бұрын
Turn the volume Up. 1000s of people have watched it. It has sound
@stibis5713 2 жыл бұрын
its rated with 25 watt max and 20watt with no cooler...
@robojax 2 жыл бұрын
the chip manufacturer rating is misleading. When you buy this module, you don't expect to attach anything. just input power and the load. That's why I am doing the test so user knows what to expect from the item they purchase.
@stibis5713 2 жыл бұрын
@@robojax when chinese rated something... expect you can only get half of it but not bad for the price lol...
@user-rp9ok6so9z 3 жыл бұрын
I need 3 pcs, this items...
@robojax 3 жыл бұрын
they are very cheap on eBay and aliExpress.
@user-rp9ok6so9z 3 жыл бұрын
I can't find this item, link please, please
@tanishqbhaiji103 2 жыл бұрын
These are not safe to use they will blow your load because most of the safety features don't even work.
@muhammadsoleh693 9 ай бұрын
If battery drop (input), your device output will be burn 🔥🔥🔥
@givenfirstnamefamilyfirstn3935 7 ай бұрын
Ridiculous ‘testing’ in boost mode. Milliamps would have been sensible.
@navidmafi 4 жыл бұрын
what a bull$h!t thanks for you great video , now i'm knowing i cant run even a fan using this!
@robojax 4 жыл бұрын
Glad I could help
@weerobot 4 жыл бұрын
Failed Failed Failed Failed Failed....lol
@robojax 4 жыл бұрын
Yes. They put misleading title for modules. LOL
@tanishqbhaiji103 2 жыл бұрын
All these xl chips are god awful, just get a classic uc384x based converter instead or a monolithic power systems sycnronous one.
@sabbirahamed3183 3 жыл бұрын
Hello bro i am from india please make a video on Dc to dc buck boost converter i need the current over 2amp so please make video on better buck boost converter cause i need 12v and 3amp constant
@robojax 3 жыл бұрын
Hello, please search my channel. I've tones of reviews on other modules including the boost converters.
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