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This Math Problem Baffled Everyone | One of the Trickiest Mathematics Questions

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Higher Mathematics

Higher Mathematics

2 ай бұрын

What is a correct answer? What do you think about this problem?
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Пікірлер: 26
@nevillerichardson-ko8le
@nevillerichardson-ko8le 2 ай бұрын
Isn’t it simpler to give the answer as 3 ^9^9
@rickymort135
@rickymort135 Ай бұрын
Yes but thats simpler and better but it's not on there. You need to recognise that d is the same as this
@Felix_Duesenburg
@Felix_Duesenburg 5 күн бұрын
One should probably add a note that there exists a convention about the order of execution when there are stacked symbols, namely that they are to be worked top-down. Someone who isn't aware of this will stumble over the non-commutative property of exponentiation, i.e. (9^9)^9 != 9^(9^9). The operation under the square root in this example is also known as tetration.
@billj5645
@billj5645 Ай бұрын
I think it would be easier to write 9 to the 9th to the 4.5th. If you are going to divide the exponent by the base of the radical then you divide the upper 9 by 2, the other two 9s are unaffected. You could even write it as 9 to the 9th in parentheses and put the last 9 on the outside of the parentheses.
@cosumel
@cosumel Ай бұрын
9^9^9^(0.5)=9^9^3. Power towers are evaluated from the top down.
@rickymort135
@rickymort135 Ай бұрын
You're right and wrong: Yes the stack is evaluated 9^(9^9), but what you're evaluating is the square root of the whole thing, i.e.: (9^(9^9))^0.5 = 9^(0.5*(9^9)) = 9^(0.5*9*(9^8)) = 9^(4.5*(9^8)) Also 3^(9^9) would work but that's not on there
@BlueYammer
@BlueYammer 13 күн бұрын
Wolfram Alpha 9^(4.5*9^8)-sqrt(9^9^9) =
@satiremuch2643
@satiremuch2643 2 ай бұрын
What does the power of a fraction even mean? like, 10^2 is 10 times 10. But 10^(1/2) is the root and 2^(0.3333...)? What are those notation describing? How can it be multiplied with itself partially?
@DanDart
@DanDart 2 ай бұрын
It's a weird concept but partially you can think about rational powers as taking the integer power of the numerator and taking the denominator'th root. A little weirder when the power is irrational but there are continuations you can do
@DanDart
@DanDart 2 ай бұрын
Specifically to your question 2^0.3333... means the principal cube root of 2
@satiremuch2643
@satiremuch2643 2 ай бұрын
@@DanDartI think that this might be a very good way of conceptualizing it. Thank you for the answer !
@Patrik6920
@Patrik6920 2 ай бұрын
2^(.333...) = 2^(1/3) -> What number mutiplied 3 times is equal to 2 ex 9^(1/2) -> what nuber mutiplied 2 times makes nine, aka root of ... A^(1/N) -> what number multiplied B times makes A, aka N:th root of ex 81^(1/4) = 3 * 3 * 3 * 3 , 3 multiplied 4 times... Thers a relationship with Logarithmic functions... Log base ten (on most calculors), ask the question how many times must the number 10 be multiplied to make the value, in a more general term log can have any base (even fractions) ..by using log base rules we can write for example Log base 3(81) as Log(81)/Log(3) and the answer is 4 ... we need to multiply 3 four times to get 81 Log base rule: LogA(B) = LogX(B)/LogX(A); X is an arbitrary log base ex: 3^B = 81-> B = Log(81)/Log(3) = 4 (4:th root of 81 is 3, or 81^(1/4) = 3) ps. on most caculators it just say 'Log' wich is Log base 10, Log base 2 is also quite common as it relates to binary (two digits 1 and 0)...
@fatroberto3012
@fatroberto3012 2 күн бұрын
I would refuse to answer the question on the grounds that the questioner should have used parenthesis to clarify whether they meant 9^(9^9) or (9^9)^9. It's not good enough to assume that any student should know that the first interpretation is correct. Math tests should not be memory tests. There are plenty of other subjects for that.
@patriciaceli1536
@patriciaceli1536 Ай бұрын
Nice!!! Gravias!!!
@Carl_Gustav_Häyhä
@Carl_Gustav_Häyhä 25 күн бұрын
4,43426^38 (15 sec) 😀
@MitzvosGolem1
@MitzvosGolem1 25 күн бұрын
Your 9 looks like a g.. Excellent channel Thank you
@ZeroGravityDog
@ZeroGravityDog Ай бұрын
Why write 'g' if you mean '9'?
@thomasg5554
@thomasg5554 10 сағат бұрын
3⁸¹
@user-lu9gh5em4n
@user-lu9gh5em4n Ай бұрын
@Higher Matematics The result is inaccurate, 3^81 is correct. I did the test and it is correct!!!!!
@ZeroGravityDog
@ZeroGravityDog Ай бұрын
No it isn't!!!!!. If you square 3 ^ 81 you get 9 ^ 81 which is 9 ^ ( 9 * 9 ) which is a tiny tiny splinter compared to 9 ^ ( 9 ^ 9 ). What was the test by the way?
@tambourineman17
@tambourineman17 Ай бұрын
I get the same answer. 9^(81/2) = 3^81
@ZeroGravityDog
@ZeroGravityDog Ай бұрын
@@tambourineman17 Where does the 81 come from? 9^9 is a lot bigger than 9x9
@nazneenakhtar2322
@nazneenakhtar2322 4 күн бұрын
You multiplied 9 with 9 but that is actually 9 to the power 9
@johnpaullogan1365
@johnpaullogan1365 Ай бұрын
obviously it is 9^((9^9)/2). simple enoug. the answers are also obviously in ascending order. 9^3 is obviously less than (9^9)/2. answer is d
@robertveith6383
@robertveith6383 19 күн бұрын
Write sentences.
@vanshkansal73
@vanshkansal73 Ай бұрын
This question is nothing compared to what i have solved, i have solved much much more difficult questions in my regular 12th standard class while preparing for JEE ADVANCED
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