Torque can’t exist for rigid objects

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Physics Videos by Eugene Khutoryansky

Physics Videos by Eugene Khutoryansky

Күн бұрын

Torque understood in terms of Newton’s Three Laws of Motion.

Пікірлер: 278
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
I have received a number of comments questioning whether we really need non-rigid objects. This is discussed in much more detail, with mathematics, in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=https%3A%2F%2Fwww.google.com%2F&httpsredir=1&article=1494&context=physics_facpubs
@jjs9473
@jjs9473 Ай бұрын
I am a physicist and have dealt a lot with misconceptions in mechanics, especially on the subject of rotational movements of rigid bodies. The paper makes some incorrect assumptions: In section III you assume tangential forces T and -T on the masses m_1 and m_2, but these are not the internal forces between the masses, I don't even know where they come from. You have to be careful here: As soon as you connect the two masses collinearly with a spatially fixed pivot, external bearing forces act on the masses m_1 and m_2 for rigidity, which are exerted by the pivot itself! So the external forces don't have to fulfill Newton's third law, because they are external, not internal. You can show, that the (tangential part of the) external force F_R exerted by the pivot on mass m_1 equals m_1 r_1/(m_2 r_2)F, where F is the tangential part of the external force applied to m_2. Fruthermore your torque equation is indeed wrong, because you have not taken all external forces into account. If you take the external force F_R on the mass 1 into account (F_R = m_1 a_1 = m_1 r_1 alpha), the the total torque is r_1 F_R + r_2 F = m_1 r_1^2 alpha + m_2 r_2^2 alpha = (m_1 r_1^2 + m_2 r_2^2)alpha = J alpha, still the correct result. The total torque consists of multiple torques with different radii. In Section I you find that the multiplication with an radius r is indeed arbitrary. But that does not make the definition of torque incomplete. On the contrary: torque can be defined as a quantity that depends on the choice of reference point, which means that torque forms a vector field. Depending on the choice of reference point, a different relationship is obtained between torque, moment of inertia and angular acceleration. Search for the term phantom torque, for example (here is a paper about the phantom torque: pubs.aip.org/aapt/ajp/article-abstract/78/9/905/1056868/Asymmetric-rolling-bodies-and-the-phantom-torque?redirectedFrom=fulltext) Your paper fails to pay proper attention to constraining forces. For example, as soon as you consider a perfect rigid body that is not subject to any other constraints, but some external forces are applied to it, the internal forces still fulfill Newton's strong third law (i.e. the internal forces lie on the line connecting two masses). This also applies under constraint conditions, but further external forces act to fulfill the constraint conditions.
@FredNort
@FredNort Ай бұрын
​​@@jjs9473The paper is not making a mistake in this regard. The mass further away from the pivot is not directly connected to the pivot, and therefore it only feels the internal forces generated between the two masses.
@maximusideal1525
@maximusideal1525 Ай бұрын
I've been interested in this specific question myself. I've gone through the same reasoning as the video laid out, but I'm not fully convinced one way or the other regarding rigid bodies. There are several reply papers you can find as well. One is *Comment on “The physical origin of torque and of the rotational second law”,* a counter-reply is *Reply to “Comment on ‘The physical origin of torque and of the rotational second law’”,* and another one is *Another comment on “The physical origin of torque and of the rotational second law”.* I wonder what you think about them.
@jjs9473
@jjs9473 Ай бұрын
@@maximusideal1525 I did not know, there are comments on this paper. Randall D. Knight's first comment makes the point I have already made: The assumed pair of forces T and -T is an incorrect application of Newton's laws. A basic concept of mechanics is that as soon as a body is forced into a certain motion, e.g. by bearings, external forces act on that body. In some cases, these external forces don't cancel out (as statet in the comment from Randall D. Knight's) and can even cause energy and angular momentum not to be conserved because systems can pump energy and angular momentum into or out of a bearing: A bearing always interacts with two systems! A great example that shows the importance of this concept can be found in a slipping coupling of two discs. There are several videos on this by Walter Lewin: kzfaq.info/get/bejne/hLWWqbtm18e6Yas.html In this example, the conservation of angular momentum and energy is violated, as the bearing forces perform work and generate torque. There is a simple argument to show, that Daniel J. Cross's Model is wrong: The net force F_net always equals M a_s, where a_s is the acceleration of the center of mass and M is the total mass. Because the center of mass performs an accelerated rotation about the pivot, the center of mass experiences a force that is made up of a radial and tangential force. The radial force is the centripetal force pointing in the direction of the pivot and the tangential force causes angular acceleration. According to Daniel J. Cross's's model, however, there is no centripetal force, only a total tangential force through F, while T and -T cancel each other out. His model does not account for all external forces! So his model not only violates Newton's strong third law, but also the second law, from which one can derive F_net = M a_s.
@jjs9473
@jjs9473 Ай бұрын
@@maximusideal1525 For some reason, i can't see my second comment anymore. To keep it short: I didn't realise there were comments on this article. The article by ‘Randall D. Knight’ already shows what I have claimed: The forces assumed in the original paper are not correct. Regarding the comment on the comment (by Daniel J. Cross himself): I understand the points being made, but the maths is definitely missing here. An important concept that Daniel J. Cross ignores is that bearings can cause external forces and torques, so in some cases even the energy and angular momentum are not conserved.
@VideographerExperience
@VideographerExperience Ай бұрын
"Bring me a *lever* long enough, and a *fulcrum* large enough, and I shall bend that lever"
@CMHE
@CMHE 19 күн бұрын
You shall?
@matthewsalmon2013
@matthewsalmon2013 15 күн бұрын
Misquoting Aristotle
@MrBeiragua
@MrBeiragua Ай бұрын
The animations were fun, but I thought they were going to demonstrate that torque doesn't work on perfectly rigid bodies, not just repeat it doesn't many times.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
This is discussed in detail, with mathematics, in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=https%3A%2F%2Fwww.google.com%2F&httpsredir=1&article=1494&context=physics_facpubs
@sirnikkel6746
@sirnikkel6746 Ай бұрын
​@@EugeneKhutoryansky But I do not want mathematics! I am too dumb for that! Me wants easy to digest video! 😭😭😭
@Nahue1474
@Nahue1474 Ай бұрын
@@EugeneKhutoryansky be patient, friend.
@MrBeiragua
@MrBeiragua Ай бұрын
@@EugeneKhutoryansky Thanks for the reply! That was a very interesting reading. So the author showed (very convincingly) that a rigid two body model cannot reproduce the laws of rotation, while a non-rigid two body can. That's very interesting, but I understand that he didn't show that you need non-rigid bodies to get correct rotation in any model, especially more complicated models, with more masses and 2d geometry. You could model a 2 dimensional 4-masses rigid body in a square shape, with a tension in one of the diagonals, and arrive at the correct torque law for the system using only Newton's laws. So I guess the paper shows a fundamental flaw in 1-d rigid bodies as a model for deriving torque and the equations of rotation, not a fundamental need for non-rigidity for this.
@darth_dan8886
@darth_dan8886 23 күн бұрын
To be honest, I'm not convinced either. The whole thing seems to be based on the assumption that in a perfectly rigid body, no equal and opposite force would be produced along the lines between the masses. I believe that is a false assumption, and the only difference here would be that the force would be transmitted with 100% efficiency (through the fully rigid connections) rather than be partially spent on compression and dissipated along other directions in the object.
@splat752
@splat752 Ай бұрын
Nice not to have loud music at the same time as narration. So much easier to listen to.
@user-gr9nz4xw2k
@user-gr9nz4xw2k Ай бұрын
I really missed the piano
@JohnVKaravitis
@JohnVKaravitis Ай бұрын
Your post == Post of the Century.
@splat752
@splat752 Ай бұрын
@@user-gr9nz4xw2k You can download your own music and play it at the same time as the video if you want.
@nmobrien4ify
@nmobrien4ify Ай бұрын
Years ago, when I was just getting serious about studying math and physics, I spent countless hours over the course of (probably) weeks trying to derive some torque laws for rigid bodies, only assuming Newton’s Laws. I learned it was pretty straightforward for non-rigid objects, but the rigid case literally kept me up at night. I had forgotten all about it until I saw the title of this video. Great work as always ❤
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks!
@nnelg8139
@nnelg8139 22 күн бұрын
For me, the answer is pretty straightforwards. That is: your assumption that rigid bonds can only carry tensile force is incorrect. Or rather, if it were true, then you don't really have a rigid body... you have a matrix that can easily deform along shear lines, because there's no force keeping the angle between bonds constant. If you counteract this with a non-cubic lattice, you find that torque actually arises quite naturally!
@robertengland8769
@robertengland8769 Ай бұрын
As a Diesel mechanic, I routinely twist the maximum allowable torquage.
@kolavithonduraski5031
@kolavithonduraski5031 Ай бұрын
😅
@reefsroost696
@reefsroost696 Ай бұрын
As a mobile crane operator I can tell you ain't nothing ridgid.
@hikolanikola8775
@hikolanikola8775 Ай бұрын
@@reefsroost696 as a Machinist, i can confirm that nothing is rigid.
@willytheriot8439
@willytheriot8439 Ай бұрын
😂
@anatolesokol
@anatolesokol 20 күн бұрын
Some fixed minded are made from 100% ridge materials.
@robinbell1063
@robinbell1063 Ай бұрын
I can't believe she stopped that train car all by herself
@friguspersona
@friguspersona Ай бұрын
I just like how the attractions and repulsions of particles can be simplified as springs.
@drakesmith471
@drakesmith471 Ай бұрын
Springs? Always have been.
@JuliettKilo
@JuliettKilo Ай бұрын
Intuitively, parabola is a good approximation to coulomb interaction if the displacement is small. The potential energy of spring is kx²/2, which is also a parabola. Thus, spring is not only a analogy to the molecular forces among atoms in a solid, but also a rather accurate approximation.
@friguspersona
@friguspersona Ай бұрын
@@JuliettKilo Thank you! I needed that cool explanation
@TheHongKonger
@TheHongKonger Ай бұрын
@@JuliettKiloin fact, most (well-behaved) potential wells behave like a spring under small displacements. We can understand this by considering the Taylor expansion for the potential. If the potential as a function of position is smooth, then we can Taylor expand it. At a minimum, the term in x is zero, hence for small displacements it behaves like a quadratic potential (if the term in x^2 is not also zero).
@BlueSkiesTruthRadio
@BlueSkiesTruthRadio Ай бұрын
This channel is invaluable
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks for the compliment.
@olhoTron
@olhoTron Ай бұрын
Universe: "that is my secret: there are no rigid objects"
@travail-rk4vl
@travail-rk4vl Ай бұрын
Which software for the animation ?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
I use the software "Poser." I explain how I make my 3D animations in my video at kzfaq.info/get/bejne/bK6caMenpp6chaM.html
@GeoffryGifari
@GeoffryGifari Ай бұрын
wait... why does in a perfectly rigid object the strong version of Newton's 3rd law get violated? what is the effect of no elastic deformation?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
This is discussed in detail in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=www.google.com/&httpsredir=1&article=1494&context=physics_facpubs
@GeoffryGifari
@GeoffryGifari Ай бұрын
@@EugeneKhutoryansky thank you for the reference
@leexiong2128
@leexiong2128 Ай бұрын
Well I'm terrible at physics but let me explain intuitively how I understand it. Imagine there is a metal log from the earth to the sun. If you rotate it, it will bend from where it's pushed first. If it was perfectly rigid, the opposite side where pushed would move instantly when rotated. That would violate the speed of light, which all information is bound to.
@drdca8263
@drdca8263 Ай бұрын
@@leexiong2128Special relativity isn’t part of Newtonian mechanics though?
@maynardtrendle820
@maynardtrendle820 Ай бұрын
​@@drdca8263A special case.
@momchi98
@momchi98 Ай бұрын
Wow, this is very interesting! I never even thought about this concept, but it makes alot of sense.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
I am glad you found it interesting.
@johningham1880
@johningham1880 Ай бұрын
As the spring constants are reduced further, not only is torque possible, but also twerk.
@mikkel715
@mikkel715 Ай бұрын
Seriously, this is seriously awesome physics videos! Thanks for the new video Eugene.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks for the compliments.
@mikkel715
@mikkel715 Ай бұрын
@@EugeneKhutoryansky Where is your video about electric charged particles in motion combined with relativity, or similar. Dialect is again claiming to be better than Einstein in relativity. Soon Dialect is also a better quantum mechanics visionary than Bohr.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
That is my video titled "Gravito-electromagnetism" at kzfaq.info/get/bejne/qLF2rblp2Lyoo3U.html
@cript3232
@cript3232 Ай бұрын
Amazing as always the animation helps so much.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks!
@hexium_
@hexium_ 17 күн бұрын
These animations are consistently brilliant and convey novel ideas in a tangible way, thank you!
@EugeneKhutoryansky
@EugeneKhutoryansky 17 күн бұрын
Thanks for the compliments.
@Grateful92
@Grateful92 Ай бұрын
I got A+ in physics and its mostly due to your videos. Thanks for helping students like me. Physics and Mathematics are now ny favorite subjects.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
I am glad that my videos have been helpful. Thanks!
@Grateful92
@Grateful92 Ай бұрын
🥹🥺
@Grateful92
@Grateful92 Ай бұрын
I wish physics could be solely used for helping people instead of making missiles to kill others.
@davidrr8741
@davidrr8741 Ай бұрын
It would be better explained if you included a diagram like the one you have at 2:41, but actually two compared diagrams, one with a rigid joint and another with an ellastic (springy) joint. Instead of a momentum, imagine a force applied to one of the particles. In the rigid joint model, that would act as if it were only one body, but if we analyze the forces, the action and reaction force wouldn't be in the same line joining both bodies. That was the most important missing diagram for understanding, the other is more obvious, as the ellastic joint doesn't require to move the second body instantly as the first body where we applied the force, but that is determined by the spring whose force is depending only in the relative position of particles along it's axis.
@eusebioptolomeu5830
@eusebioptolomeu5830 Ай бұрын
I would love to know how this “distance to axis of rotation” effect works. I know such distance is directly proportional to torque; I just don’t know why that is the case. If the same force is applied to both sides of the object, how come one wins the battle just by virtue of being placed further away?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
You saw why it works in the animation. The force further away from the axis causes a greater deformation in the object, causing an upward force on the other side of the axis as the springs try to straighten the object out. If you want a mathematical analysis deriving the torque equation, this is available in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=www.google.com/&httpsredir=1&article=1494&context=physics_facpubs
@darikdatta
@darikdatta Ай бұрын
I'm having a difficult time accepting this. To fully understand it I think I need to see a visualization of how the force is distributed when applied to the theoretical rigid body.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
You may want to read the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=www.google.com/&httpsredir=1&article=1494&context=physics_facpubs
@darikdatta
@darikdatta Ай бұрын
@@EugeneKhutoryansky I think the problem is that the rigid body is not fully modeled. There has to be some other force present to maintain all the right angles, a repulsive force between the masses that aren't directly connected by a spring. Along the diagonals, if you will. Otherwise all the cubes could fold over and collapse, without ever changing the length of the "springs" between the masses. The force that is preventing that from happening needs to be accounted for.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Even with the rigid diagonals present, I believe we would still violate the strong version of Newton's Third Law, and get the wrong torque equation.
@chrimony
@chrimony Ай бұрын
@@EugeneKhutoryansky You have the software. What happens when you make the model more and more rigid? What is it the limit?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
If I make the spring constants too large, the software crashes.
@ammarkhalid6275
@ammarkhalid6275 Ай бұрын
what a underrated channel, i hope you get the recognition you deserve sir/mam. you are an amazing physicist and teacher, who can actually explicate and make others understand even the most complicated and abstract topics with great analogy, great definitions, and simulations, a lot of things are now clear and i can visualise it happening, my love for physics has immensely increased, thanks to your lucid explanations. also, what do you exactly do professionally apart from youtube?are you physics professor or researcher under some institution?or an independent researcher?i would like to know that, as im interested in that field as well.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks for the compliments. I am glad my videos have been helpful. In reply to your question about me personally, see the link at the end of the video. Thanks.
@alejrandom6592
@alejrandom6592 27 күн бұрын
This is beautiful. The fact that physics can break into smaller pieces, even the simplest phenomenon that we think we comprehend.
@EugeneKhutoryansky
@EugeneKhutoryansky 27 күн бұрын
I am glad you liked my video.
@carultch
@carultch Ай бұрын
One issue I see with these simulations, is the assumption of a simple cubic crystal structure. This crystal structure is uncommon among most solids, and is known to create weak shear strength in materials and weaknesses of non-axial loads, due to the weak diagonal bonds between atoms. Much more common crystal structures are face centered cubic (FCC), body centered cubic (BCC), and hexagonal close-pack (HCP). These crystal structures have higher packing factors than simple cubic, and are much better at supporting shear and moment loads, due to diagonal bonds between atoms, creating "cross-bracing" in the crystal structure.
@kanucks9
@kanucks9 27 күн бұрын
That's an interesting point. Given the axioms, a perfectly rigid cubic structure would have to shear under any load that would have caused torque. After all, the bonds cannot apply perpendicular forces, nor can they rotate.
@marfmarfalot5193
@marfmarfalot5193 24 күн бұрын
They all have shear planes so its just a generalization to consider FCC and BCC - they effectively behave the same regardless of geometry. I used to think about it in this way: think about how they behave as the load goes to 0 or infinity
@3dplanet100
@3dplanet100 Ай бұрын
I think I got it. The analogy of the springs helped me to understand why a hypothetical perfectly rigid body can't have torque. If I understanded correctly, is because when you applied a downward force to a tool, the other end of the tool must have an upward force, just like when you stretch a spring outward, there's an inward force because of the flexibility. Likewise, when you use lug nuts wrench and use a pipe to have more torque, the flexibility of the material gives an opposite force: you move the pipe downward, and the other end of the pipe moves upward. I can imagine if it were possible a perfectly rigid tool, you can apply whichever big force to the tool that it move give any torque, just like when you use a really tiny wrench, but just imagine an infinite small wrench, it won't have torque at all. Well, this is my first time learning this, so I might be wrong, but I think I got it.
@hrig
@hrig Ай бұрын
very enlightning. What is the simulation software? is it Gromacs?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
"Poser Physics." I explain this in more detail in my video "How I make 3D animations" at kzfaq.info/get/bejne/bK6caMenpp6chaM.html
@SpaceFrogFromOuterSpace
@SpaceFrogFromOuterSpace 7 күн бұрын
Conservation of angular momentum can definitely be programmed accurately into rigid body physics simulations, but it requires quite a bit of calculus.
@andrewhunter6536
@andrewhunter6536 24 күн бұрын
Shear forces from friction don’t act along the line connecting surfaces unless you are zooming in and looking at none opposite sections of the surface?
@frogfan449
@frogfan449 Ай бұрын
I have one minor complaint which is that there is sometimes a really high pitched whistling with /s/ sounds, which I think could be EQd away
@nickdiamond7595
@nickdiamond7595 Ай бұрын
Thank you. Now I'll watch it.
@marfmarfalot5193
@marfmarfalot5193 24 күн бұрын
This entirely makes intuitive sense. If you think about a metal bar as a lever, why would it physically get more force with distance? I mean the atoms move the same distance and so on, but it works because each interaction is very strong
@matthewsalmon2013
@matthewsalmon2013 15 күн бұрын
Einstein would say the limit of rigidity is that which creates a speed of sound approaching the speed of light/information
@lolerishype
@lolerishype Ай бұрын
In your paper, you state that "because the internal forces in the rigid-body model do not obey the strong third law, they form a couple that generates a self-torque and thus angular momentum." However, it is not very clear in your paper why they violate. Would you mind explaining? Thanks.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
It is not "my" paper, as I am not the one who wrote it. One of my other viewers initially had criticisms of the paper, thinking it was mistaken about this issue. However, after we talked about it, he then posted the following: "Ok, I think I know what you mean now. I think your point becomes clear with an extreme example: Take three mass points with equal mass that lie equidistantly on a straight line and are rigidly connected to each other. If you exert an external force on the middle mass point, which is also the center of mass, perpendicular to the line connecting the mass points, the result is a translation. Due to the rigid connection, the other two masses must experience the same acceleration, i.e. they experience a force parallel to the external force. However, this force cannot be applied by the internal forces, as they would have to be parallel to the connecting line according to Newton's strong interaction principle. This is where I see the contradiction proclaimed in the paper. Now I understand why perfectly rigid bodies are not realizable with the strong version of the third law."
@keepitsimple7720
@keepitsimple7720 Ай бұрын
Simply awesome
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks.
@SoylentGamer
@SoylentGamer Ай бұрын
I wonder if this is why ATG's Engine Sim always has really strange numbers
@nervous08
@nervous08 Ай бұрын
So , If a force is applied on a perfectly rigid object (not along the centre of mass), then it'll act same as if the force is applied along centre of mass?
@creativenametxt2960
@creativenametxt2960 Ай бұрын
I am fairly certain deformation is not, in fact, required for torque to exist in rigid objects under Newtonian mechanics. Here is a concrete example with all forces laid out that demonstrate how an uowards force is applied to leftmost point of the object while the external force is applied on the right: suppose we have 3 points that do not lie on the same axis with the same mass: O, A, B O is our fixed axis, A is the leftmost point, B is the rightmost point. Suppose A has coordinates (-1, 1) O has coordinates (0, 0), B has coordinates (1, 0) Suppose there is a flrce Fa between O and B, Fb between O and A, Fo between A and B (those forces have a positive sign if they repell points), as well as an external force acting on B downwards: F and the force of the axis of rotation: T that acts in an unknown direction knowing that O is fixed in place we get: T+Fa+Fb=0 in vector form knowing that A and B stay the same distance away from the origin, we get that their acceleration is perpendicular to the lines OA and OB respectively so we get that projection of total force on those axes is 0, specifically: A: Fb+Fo/sqrt(2)=0; B: Fa+Fo/sqrt(2)-F/sqrt(2)=0 we also know that since distance between A and B is unchanging that the tangential component of the acceleration must be the same: Fo/sqrt(2)=-Fo/sqrt(2)-F/sqrt(2) so, we get that Fo=-F/2 Fb=F/(2sqrt(2)) Fa=3F/(2sqrt(2)) T=-Fa-Fb in vector form This way, everything is fine. Point A moves up because force Fb pushes it outwards while force Fo pulls it to the right. The total torque on the system is generated by T and F No contradiction is reached. As others already pointed out, the paper appears to have several mistakes. I don't see any mistake in this concrete 3 point argument that works under Newton's mechanics, has external forces be applied along the lines between 2 objects and describes rotation of a rigid body consisting of 3 same mass points. Obviously that model doesn't work when special relativity is taken into account and is technically not correct as real life objects aren't truly rigid, but it is internally consistent. If anyone finds an error in my comment or finds some fact non-trivial and needing explanation, please let me know. But as of right now, I am convinced that the claim of the video is incorrect or presented in a misleading manner.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
I didn't follow your entire argument, but based on the rigid model you propose, suppose there is a connection between O and A, a connection between O and B, but no direct connection between A and B. If there is an external force only acting on B, then the only force acting on A is from the rigid connection between O and A. But, this force between O and A can only act along the line connecting O and A. Therefore, there is no way that A can initially start moving in a rotation around O. As for the so call "mistake" in the paper, the person who was making the claim that there is a mistake (by posting comments under many other people's comment's), later conceded the point and said that he now agrees with me.
@creativenametxt2960
@creativenametxt2960 Ай бұрын
@@EugeneKhutoryansky I see. I will take a closer look at the paper later. As for the claim, that is correct. If there is no connection between A and B there is no way to make a rigid body and that would be a bad model. In a more general case, if we take the model used in the video with a few dozen points that is why we would need diagonal springs or connections. I will elaborate in more detail later.
@creativenametxt2960
@creativenametxt2960 Ай бұрын
​@@EugeneKhutoryansky Thank you for taking your time to read through the comments. I have looked through the paper and it considers a model with 3 points in figure 2: pivot, m1, m2 It is true that such a model cannot explain rigid body behavior, but the problem seems to be with such a model itself rather than with Newtonian approach, (as the lever cannot be infinitely thin in reality). It is also true that adding in springs does lead to correct behavior once the body bends a tiny bit, but that is only one possible solution. If we wish to more rigorously construct our model we may consider that the lever is, in fact, not infinitely thin, adding in 2 middle points instead of just one in place of m1, located just above and below the center, would solve this issue as the bottom and top points could exert different forces, leading to the total force acting on the middle be directed not along the line pivot-m2 In general if we want to approximate a tiny patch of material as one point, we find that 2 such "point approximations" may transfer torque between each other (as they are not perfectly on the same line), which means when we apply such models the strong version of Newton's 3rd law will not apply in the limit case when all points are completely merged. My problem with the paper is considering such a limit case without realizing that the statements about laws might not behave well in the limit case (to elaborate, some force may behave as "F=1/r" for r being the thickness of the lever and the torque may behave as "F * r = 1", which would mean that in the limit case of r=0 F=inf and everything breaks, making the model incapable of describing the phenomenon we are interested in, the statements about total torque on the system, however, do work in the limit case) In general, real physical bodies have at least 4 points that do not lie on a single plane, let us call some such points A, B, C, D If we consider a model which states that for each point "P" there exists a force between A and P, B and P, C and P, D and P, then we can always solve for internal forces knowing external ones as we know accelerations of every point "P" and the fact that ABCD don't lie on the same plane means that there will never be a "degenerate case" when all the force lines lie in the same plane, the forces between ABC and D would also work out for similar reasons (I do not have concrete concise proof of it, unfortunately) Such a model is not perfect either, but it is capable of describing torque. The model presented in the video with diagonal springs will also work once we replace springs with incompressible rods, but if we remove the diagonal connections (no matter if they are springs or rods), the shape will be free to fold in on itself (consider each point in the upmost layer rotate at the same speed around the axis parallel to the fixed axis, but lowered down by one connection, the upper layer would simply slide, all connections act basically as hinges) The conclusion I draw is that we should be very cautious with making approximations in models and the paper has not made a good approximation of a real life scenario it is trying to describe. If a system of points behaves as a rigid body the torque equations do work. But not all systems of points can form a rigid body, example of which is provided in the paper. Thank you again for reading through the comments, I do hope my long rants are at least somewhat comprehensible to whomever may decide to read it.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
I haven’t actually done the calculations, but I suspect that even if we add the diagonals to the rigid model, we still might not get the correct torque equation when we analyze all the internal forces. But even if we do get the correct torque equation in this case, the claim about rigid objects can then be rephrased to just say that toque can’t exist for "some" rigid objects (such as the scenario described in the paper).
@creativenametxt2960
@creativenametxt2960 Ай бұрын
@@EugeneKhutoryansky I can see your point, however I might rephrase it to be "not all collections of points can form a rigid body, especially if we limit which points can interact with each other" since the way each connection behaves is basically like a ball hinge. (or maybe I am just being overly pedantic, hard to tell) since by definition a rigid body is a collection of points such that the distance between any 2 of them does not change over time I am absolutely certain torque does exist for your object if we add a connection between each two points, since we can select to look at only connections involving some preselected points A B C and D and solve the equations from there, the other connections giving more leeway to what forces might actually be present (it's not always possible to tell each internal force in such a model, as far as I know) If we do not add such overwhelming number of connections I do not have concrete proof that it's enough, but I strongly suspect that any shape constructed of gluing triangular piramids together so that faces allign perfectly and the whole shape is connected by the end will be rigid. If we remove some of the connections your shape does actually get decomposed into a collection of such piramids since each individual cube does. Unfortunately I can't seem to find a proof that that's enough. (and I'm almost sure it's not strictly necessary to form a rigid body, so it's not a "good" critetia either, but it's best I could come up with) I am glad to have cleared some confusion up, at least for myself. Thanks again for considering what your viewers say.
@VCLegos
@VCLegos Ай бұрын
Do you guys have a video explaining why hot gasses are less dense?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Not yet.
@cmyk8964
@cmyk8964 Ай бұрын
I was waiting for a simulation of a theoretically perfectly rigid object, demonstrating it breaking torque
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
This is discussed in detail, with mathematics, in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=https%3A%2F%2Fwww.google.com%2F&httpsredir=1&article=1494&context=physics_facpubs
@liambohl
@liambohl Ай бұрын
I'm still not convinced that an object must deform for torque to make sense.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
This is discussed in much more detail, with mathematics, in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=https%3A%2F%2Fwww.google.com%2F&httpsredir=1&article=1494&context=physics_facpubs
@anatolesokol
@anatolesokol 20 күн бұрын
Congratulations, your flexible thinking is enabling you to steer in right direction.
@EugeneKhutoryansky
@EugeneKhutoryansky 19 күн бұрын
Thanks.
@Jim-tv2tk
@Jim-tv2tk Ай бұрын
But if you are going to assume that an object that can't exist does exist, then wouldn't you expect new physics along with it? If I understand the problem, the object can't stop or start rotation. Wouldn't acceleration in any direction run on to the same issue?
@hariohm1415
@hariohm1415 Ай бұрын
Please make more videos on electronics
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
I plan on making more videos on electronics. Thanks.
@rogerbartlet5720
@rogerbartlet5720 Ай бұрын
Thanks for making these videos
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
You are welcome and thanks.
@pexfmezccle
@pexfmezccle Ай бұрын
what if the spring constant approaches infinity, won't that be a perfectly rigid body?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Spring constants of infinity would be a perfectly rigid object.
@pexfmezccle
@pexfmezccle Ай бұрын
@@EugeneKhutoryansky correct, so you can start with a finite spring constant, and then keep increasing it, tending towards infinity, which will also tend towards the behavior of a perfectly rigid object
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
But you never actually get a perfectly rigid object until you actually reach spring constants of infinity.
@Mandragara
@Mandragara Ай бұрын
​@@pexfmezccleYou extend the spring equation past where it is physically meaningful. Relativity exists, so you'd need to modify the law in a way that makes k a function of spring velocity. Otherwise you have a spring that can snap back faster than the speed of light
@pexfmezccle
@pexfmezccle Ай бұрын
@@EugeneKhutoryansky but i think that there's a mathematically and logically viable model of torque physics at the limit of infinity, though the speed of sound through it would be infinite
@ts4gv
@ts4gv 8 күн бұрын
what does a rigid object "not working properly" look like exactly?
@EugeneKhutoryansky
@EugeneKhutoryansky 8 күн бұрын
This is discussed in detail, with mathematics, in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=https%3A%2F%2Fwww.google.com%2F&httpsredir=1&article=1494&context=physics_facpubs
@nieval
@nieval Ай бұрын
I guess it makes sense, what does infinite rigidity even mean when thinking of multiple particles instead of a single object? What if there were only 2 atoms connected in a line? If the bonds were infinitely strong, the distance between them would never change. If the distance never changes, then why would the second atom ever exert a force on the first object? If the bond doesn't exert any force, is it there at all?
@Splarkszter
@Splarkszter Ай бұрын
WOOOHOOOO SUPER HIGH QUALITY EDUCATIONAL VIDEO LET'S GOOOO
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks!
@hexane360
@hexane360 Ай бұрын
Why should the strong third law apply? For instance, it doesn't seem to apply given Maxwell's equations. It's obvious in the case of masses connected by springs, but not clear how it can be generalized. In the absence of that, this seems more like "Torque on rigid bodies cannot be modeled by a collection of point masses connected by infinitely rigid springs"
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
It does apply to Maxwell's Equations. If you haven't already seen it, I have a detailed video on Maxwell's Equations at kzfaq.info/get/bejne/b7qdZcZns7CsZI0.html
@takek9215
@takek9215 Ай бұрын
winnyの金子さんが20年前にこの理論を拡張して物理演算だけの仮想世界を作ってたなぁ。 設定してないのに回転衝突、変形する画期的な技術だった。
@chabotaorlando5104
@chabotaorlando5104 25 күн бұрын
Thank you Eugene ✌🏿
@EugeneKhutoryansky
@EugeneKhutoryansky 25 күн бұрын
Thanks.
@proteusaugustus
@proteusaugustus Ай бұрын
only when applied to an object that has mass.
@jonathan3372
@jonathan3372 Ай бұрын
I have a question: What is the difference between the weak & strong form of Newton's third law, and why don't we just use the strong form everywhere, since it includes the weak form (which is the one I've always heard of). My guess is that the difference between them is one is a statement about the conservation of linear momentum, and the other of angular momentum, both of which can be derived from first principles (Noether's theorem).
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
The strong form of Newton's Third Law applies everywhere. I guess the reason we typically just use the weak form is because in most cases, it is sufficient to analyze the situation. By the way, the conservation of linear and angular momentum are both a consequence of Newton's Three Laws of motion.
@jjs9473
@jjs9473 Ай бұрын
Newton's laws are often formulated for two bodies, but it is neither mentioned, that those bodies could be mass points, nor which direction interaction forces should have. For systems of mass points the conversation of angular momentum only follows for the strong version of Newton's third law. Some textbooks state this assumption, to derive the conversation of angular momentum mathematically. If the interaction forces don't lie in the line connecting two interacting mass points, they would form a force couple with a torque, independent of the choice of reference. Thus inner interaction forces could produce torque, even when no external forces are acting on the whole mass point system.
@carultch
@carultch Ай бұрын
@@EugeneKhutoryansky There is a Newton's third law paradox, that I'd recommend for a future video topic. Consider the Lorentz force between two identical charges that approach each other, initially along two perpendicular and intersecting axes. Calculating the Lorentz force, we'll see forces that are equal, but not opposite, as an apparent contradiction of N's 3rd law. The topic to show, is how this situation ultimately is consistent with conservation of momentum, since the EM waves that result ultimately are a third agent involved.
@Soloohara
@Soloohara Ай бұрын
Can you make longer video to watch at night before sleep?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
I have lots of long videos.
@Soloohara
@Soloohara Ай бұрын
@@EugeneKhutoryansky ok
@Soloohara
@Soloohara Ай бұрын
@@EugeneKhutoryansky not really
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
My original video on electromagnetism is about 1 hour long.
@lewis7515
@lewis7515 Ай бұрын
Yes, this is excellent.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks for the compliment. I am glad you liked my video.
@HelmutNevermore
@HelmutNevermore Ай бұрын
The moose looks really puzzled.
@SuLokify
@SuLokify 27 күн бұрын
Now that the video title has me thinking about it, can we really call any object with size "rigid" considering the causal speed limit?
@SuLokify
@SuLokify 27 күн бұрын
Ok now I'm watching the video lol
@EugeneKhutoryansky
@EugeneKhutoryansky 27 күн бұрын
As I said in the video: all objects are non-rigid, since the speed of sound through a perfectly rigid object would be infinite, thereby violating Einstein’s Theory of Relativity.
@SuLokify
@SuLokify 27 күн бұрын
@@EugeneKhutoryansky Indeed, I made the comment before pressing play.
@HuRuStav
@HuRuStav Ай бұрын
Amazing! Thank you!
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks.
@MrEmrald123
@MrEmrald123 Ай бұрын
That's Kira vincent-davis.
@realcygnus
@realcygnus Ай бұрын
Nifty as usual
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks.
@drdca8263
@drdca8263 Ай бұрын
2:38 : huh? But what about like, the force applied on a particle moving in a magnetic field (with said magnetic field being a result of a number of other moving electric charges) ? Surely this also conserves angular momentum? If I have two electric charges moving around, shouldn’t there be a part of the force between them which isn’t along the line between them?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
The forces are still along the line between them. I cover this in my original video on electromagnetism at kzfaq.info/get/bejne/b7qdZcZns7CsZI0.html
@drdca8263
@drdca8263 Ай бұрын
@@EugeneKhutoryansky thanks, I’ll check that out
@drdca8263
@drdca8263 Ай бұрын
@@EugeneKhutoryansky I don’t think I quite caught that point in that video. Let particle 1 follow the path x_1(t) = x_1(0) + t v_1 And particle 2 follow the path x_2(t) = x_2(0) + t v_2 Let q_1 be the charge of the first particle. The contribution to the electric field from the first particle at time t is given by E_1(r,t) = k_e q_1 (r - x_1(0) - v_1 t) * ||(r - x_1(0) - v_1 t)||^(-3) (Right?) and so, uh, if we differentiate this with respect to t, then, this should give us the change in the part of the electric field attributable to the first particle. And this should give us the magnetic fiend induced by particle 1, as a function of position and time. (Here I am supposing that the two particles have whatever additional forces are necessary applied to them to make them move along these straight paths) If we consider different values of v_2 , pointing in different directions, then it seems like at time t=0, that the cross product of magnetic field at time t=0 at the position x_2(0) , with v_2 , will be in different directions, but, changing v_2 does not change the line between the particles at time t=0, which is the line through x_1(0) and x_2(0) . So, how can the force between the particles in this case be along the line between the two particles? Maybe having the external forces that force them to follow these linear paths (being arranged beforehand to exactly counteract whatever electromagnetic interaction there will be between the two particles) somehow breaks conservation of angular momentum for us, but, I wouldn’t think so?? Where have I gone wrong?
@DuchAmagi
@DuchAmagi Ай бұрын
Where's the music?!
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
The music will be back for future videos.
@Gelatinocyte2
@Gelatinocyte2 Ай бұрын
Imagine Patreon was a thing that existed in the 90s/early 00s
@zdeneksolnicka6815
@zdeneksolnicka6815 Ай бұрын
Great - no music, thank you
@juhotuho10
@juhotuho10 26 күн бұрын
With enough force, everything is a spring
@logangrimnar3800
@logangrimnar3800 Ай бұрын
Is there such a thing as a perfectly rigid object there isn't I didn't finish the video before making this comment thank-you for answering I have learned two lessons today.
@MrX-gg4gr
@MrX-gg4gr Ай бұрын
as a civil engineer, I had ended to the same conclusion when thought of "load bath" throw a structure. that is, without a deformation, we can't imaging how loads on a floor reach columns (transfering of loads from floor to colums).
@jhonbus
@jhonbus Ай бұрын
Thanks, I actually understood the argument better from this comment than I did from watching the video!
@ericericson9282
@ericericson9282 Ай бұрын
Thank you!!
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
You're welcome and thanks.
@numbers93
@numbers93 Ай бұрын
hot damn so without deformation, we can't even use a basic lever!
@ksp6091
@ksp6091 14 күн бұрын
Hey that's what Vsauce was talking about in the safety third interview !
@quill444
@quill444 Ай бұрын
_Even for individual electrons, isn't it still a mystery how electro-magnetism (can) exert a force at right angles and do so at a distance?_ - j q t -
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
This is explained in Quantum Electrodynamics, where electric and magnetic fields don't actually exist, and all the forces attributed to them are really the result of photon exchanges between charged particles.
@spaffyjimble2317
@spaffyjimble2317 Ай бұрын
The algorithm brought me here
@PiAreSquare
@PiAreSquare Ай бұрын
thanks ❤
@funwithtommyandmore
@funwithtommyandmore 20 күн бұрын
Double the points agai- NAUR PLEASE NA-
@Falcon_9un_anahtari
@Falcon_9un_anahtari Ай бұрын
Nice channel👍
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks.
@yunpeng1991
@yunpeng1991 Ай бұрын
Hello, I like your physics video very much, it is very intuitive and deep. I've watched every video over and over. I saw this one, too. Can you use a video to make clear how to put the role of the lever, the force is amplified, this concept is not intuitive!! Counterintuitive!
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
I am glad to hear that you have watched all my videos and that you enjoy them. Here are two different ways to look at the force amplification. 1. Work = Force * Distance. Since work is the energy transfer, and energy is conserved, this means that the force is amplified for the object that moves a shorter distance. 2. If you want to think about in terms of animations in this video, as the force on the right pushes down on the lever, this initially deforms the lever and adds potential energy to many of the springs. As all these springs release their potential energy to straighten out the lever, this creates an upward force on the opposite side of the lever that is larger than the initial downward force.
@MrGustavier
@MrGustavier Ай бұрын
I think it's the first time I simply don't understand a video from Eugene... 😭
@MrGustavier
@MrGustavier Ай бұрын
I don't understand why you say that the "strong version of Newton's third law" is broken. Maybe you should have represented the object(s) that provides the two forces. Why wouldn't it receive an equal and opposite force ?
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
This is discussed in detail in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=www.google.com/&httpsredir=1&article=1494&context=physics_facpubs
@marfmarfalot5193
@marfmarfalot5193 24 күн бұрын
The music was nice but understandable some people didnt like it. Science should have personality and I believe you have lots of personality in your videos
@stephenmancuso3314
@stephenmancuso3314 Ай бұрын
Not convinced… i watched all your videos. This one does not adequately explain anything in order to arrive at your conclusion. Pretty sure that even if things were perfectly rigid things would still rotate on a fulcrum I’m pretty sure the rotation is caused by the lack of reactionary moment force within the beam, which as nothing to do with rigidity. I know in I am using torque to describe torque here. But you need the same kind of analysis for structural members. You don’t need an elastic material to have a reactionary force upward when a book sits in a shelf .
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
This is discussed in much more detail, with mathematics, in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=https%3A%2F%2Fwww.google.com%2F&httpsredir=1&article=1494&context=physics_facpubs
@가시
@가시 Ай бұрын
Then how will a perfectly rigid object behave? I think without that explanation, this video's argument will be incomplete
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
This is discussed in detail, with mathematics, in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=https%3A%2F%2Fwww.google.com%2F&httpsredir=1&article=1494&context=physics_facpubs
@artemZinn
@artemZinn Ай бұрын
So… Eugene, are we considering Black Holes and Neutron Stars rigid? We do say BH rotate, but what we mean is that space-time is being dragged by inertia of what has fallen into BH (honestly would be great to dive deep into this topic). For Neutron Stars however we do consider them actually rotational and I guess we can speed them up or slow down by applying torque… Crazy interesting, would love you cover these topics! Thank you both as usual.
@Deeeeeeeeeeeeeeeeeeeeeeeeez
@Deeeeeeeeeeeeeeeeeeeeeeeeez Ай бұрын
Crank until it cracks than half a turn back. That's how dad did it, that's how Mmerica does it 😂
@user-qp2ps1bk3b
@user-qp2ps1bk3b Ай бұрын
nice!
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Thanks.
@redandblue1013
@redandblue1013 Ай бұрын
I only realised recently that the voiceover isn’t AI
@MrGustavier
@MrGustavier Ай бұрын
me too !
@laupoke
@laupoke Ай бұрын
wdym, she has been voicing videos for 12 years
@carultch
@carultch Ай бұрын
Eugene is friends with his voice actress. He wouldn't betray her with a pangram and a voice clone engine.
@aniimii4651
@aniimii4651 5 күн бұрын
Eugene I want your permission to recreate your videos in Hindi language. I want your videos to reach more indian students. As I know they are not very familiar with English. And your videos have very much potential for knowledge which they can easily grab upon. Your animation is very approachable to the concept at very basic and easy to understand. And our students really need this. Thanks for all of your contributions towards students who lack resources and connectivity.
@EugeneKhutoryansky
@EugeneKhutoryansky 5 күн бұрын
I am sorry, but I do not give permission for people to make copies of my videos. Many of my videos already have subtitles available in Hindi and in many other languages. To see the subtitles, click on the gear symbol under the video, then click on "subtitles." Then select the language. For the videos that do not yet have Hindi subtitles, if you would like to help me add Hindi subtitles that will appear on my channel, please send me an email indicating which video, and I will email you the subtitle file in English (which includes the timings). You will then be able to edit the file to replace the English with the translation, and then email the file back to me.
@aniimii4651
@aniimii4651 5 күн бұрын
@@EugeneKhutoryansky is there any possibility you can dub them in Hindi. I can help you with that. Treat me as a volunteer to do so. And the reason to add audio is to make it more understandable and easy to grab. Sometimes they don't have smartphones or access to your videos and so on. Well it's okay if it is not possible still I will refer them to this channel here. Meanwhile back in time I shared your videos with some people who wanted to understand the concept of Sanatan dharma (Hinduism) which is obviously the Advanced quantum Physics with no science background. And they were amazed to learn the basics through your videos and i felt the need to make it more clear with Hindi audio translation. Anyway Great Job.
@EugeneKhutoryansky
@EugeneKhutoryansky 4 күн бұрын
Sorry, dubbing is not an option. Though, the subtitles are always available regardless of what type of device they are watching it on (PC, phone, etc.) Thanks for the compliments about my videos.
@anywallsocket
@anywallsocket Ай бұрын
I thought you only needed F=ma anyway
@Verrisin
@Verrisin Ай бұрын
I mean ... nothing can exist for perfectly rigid objects ...as they cannot.
@Djei3747ejd
@Djei3747ejd Ай бұрын
All game engines have rigid bodies with torque 🙃
@HJ28_398
@HJ28_398 20 күн бұрын
I still don't see why it's impossible for rigid objects. I know they can't exist, but if you could somehow force their existance, I don't see why they wouldn't follow Newton's equations.
@HJ28_398
@HJ28_398 20 күн бұрын
in the video it says that solid objects are just softbodies with high rigidity. So you make it more rigid and it still follows the laws, so you make it more rigid, and it still follows. I get that the object can't have a soundspeed faster than light, or some other maximum, certainly not infinite speed, but forcing it to have it and ignoring Einstein's laws doesn't seem to nullify Newton's laws.
@EugeneKhutoryansky
@EugeneKhutoryansky 20 күн бұрын
This is explained in detail, with mathematics, in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=https%3A%2F%2Fwww.google.com%2F&httpsredir=1&article=1494&context=physics_facpubs
@user-rp6yq5rw3r
@user-rp6yq5rw3r Ай бұрын
Just op
@donaldhobson8873
@donaldhobson8873 Ай бұрын
When dealing with springs, you use diagonals. When dealing with "perfectly rigid bodies", you don't include the diagonals. Add enough diagonals to your perfect rigidity stuff, torque will transmit just fine. Sure, no real thing is perfectly rigid. But the maths of perfect rigidity torque make sense.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
You may want to read the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=www.google.com/&httpsredir=1&article=1494&context=physics_facpubs
@donaldhobson8873
@donaldhobson8873 Ай бұрын
@@EugeneKhutoryansky Well their "rigid body" is made of 2 atoms. So of course there aren't diagonals. (Well actually, they are using 2 atoms and a pivot, arranged collinearly, in a double pendulum structure that swings freely. ) Then when they allow non-rigidity, the 3 points in a line flex to form a triangle. You now have a properly rigid triangulated structure (non-degenerate case) and so angular momentum works properly.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
Even with rigid diagonals present in the model of the rectangle, I believe we would still get the wrong torque equation.
@matthewsalmon2013
@matthewsalmon2013 15 күн бұрын
I don't think your conclusion is correct because it doesn't account for the diagonal forces
@EugeneKhutoryansky
@EugeneKhutoryansky 14 күн бұрын
This is discussed in much more detail, with mathematics, in the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=https%3A%2F%2Fwww.google.com%2F&httpsredir=1&article=1494&context=physics_facpubs
@mateuszpraseek6733
@mateuszpraseek6733 16 күн бұрын
Maybe some more philosophical video relating to the existence of God? or any deity/higher power?
@EugeneKhutoryansky
@EugeneKhutoryansky 14 күн бұрын
If you haven't already seen it, I have a video titled "Meta-Physics explained by Maxwell’s Demon" at kzfaq.info/get/bejne/qLqajdaF2L2-iY0.html
@mateuszpraseek6733
@mateuszpraseek6733 14 күн бұрын
@@EugeneKhutoryansky Right, I rewatched it, well-made. Love watching Your videos a few times, they are really that good. Also I can't wait for new ones!
@EugeneKhutoryansky
@EugeneKhutoryansky 14 күн бұрын
Thanks!
@huailiulin
@huailiulin Ай бұрын
19h
@jjs9473
@jjs9473 Ай бұрын
"How can the left part of the body experience an upward force?" Your Video misses a whole point: the fixed axis exerts an upward force, because the net force of the rotating rigid body shown in this video must be zero under the assumption, that the center of mass lies in the fixed axis. Both, the external downward force and the reaction force due to the fixed axis create a force pair generating a torque without an acceleration of the center of mass. Without the fixed axis, the rigid body would experience an angular AND linear acceleration, causing each particle moving downward and to the left/right due rotation and internal forces, but no particle would go upwards.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
The fixed axis generates an upward force but it doesn't generate any torque, because R=0.
@jjs9473
@jjs9473 Ай бұрын
@@EugeneKhutoryansky Torque is dependent on the choice of reference point. You could also take any reference point, that lies not in the axis of rotation. The interesting fact is, that the net torque of two parallel forces is independent of the choice of reference point. Thus, parallel forces are called "force couples" with a uniquely determined torque. So the upward force due to the fixed axis forms a force couple with the impressed downward force generating a net torque, that is independent from the choice of reference point.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
@jjs9473 You and I have been continuing this conversation underneath comments from several different people. For everyone else reading this, I would like to copy your last statement from under a different comment, where you now agree with me. In this statement, you wrote: "Ok, I think I know what you mean now. I think your point becomes clear with an extreme example: Take three mass points with equal mass that lie equidistantly on a straight line and are rigidly connected to each other. If you exert an external force on the middle mass point, which is also the center of mass, perpendicular to the line connecting the mass points, the result is a translation. Due to the rigid connection, the other two masses must experience the same acceleration, i.e. they experience a force parallel to the external force. However, this force cannot be applied by the internal forces, as they would have to be parallel to the connecting line according to Newton's strong interaction principle. This is where I see the contradiction proclaimed in the paper. Now I understand why perfectly rigid bodies are not realizable with the strong version of the third law."
@danielsieker9927
@danielsieker9927 Ай бұрын
This was a nice demonstration, but the argument is incorrect. We can assume a perfectly rigid object as, instead of just saying "stiff connections", a bunch of masses connected by springs (as in your example), but with infinite spring stiffness. All the consequences of a deformable object approach still apply, the forces get transferred correctly, and torque works. Rigidity isn't incompatible with Newton's motion equations.
@EugeneKhutoryansky
@EugeneKhutoryansky 29 күн бұрын
If we set the spring stiffness to infinity, then this leads to precisely the problems discussed in the video. This is explained in detail, with mathematics, in the paper at the following link. scholarship.haverford.edu/cgi/viewcontent.cgi?referer=www.google.com/&httpsredir=1&article=1494&context=physics_facpubs
@FaikFatihKorkmaz
@FaikFatihKorkmaz Ай бұрын
Not meaningful. Moment equilibrium can be obtained using newton laws and vector calculus. No other one is required. There is an enginnering concept, machine theory, to analyze the motion of 'rigit' bodies. Also in finite element analysis, there are many rigit element types to transfer the moment
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
You may want to read the paper at scholarship.haverford.edu/cgi/viewcontent.cgi?referer=www.google.com/&httpsredir=1&article=1494&context=physics_facpubs
@timothy8426
@timothy8426 Ай бұрын
Liquidity infinity to illusionary solidity of liquidity infinity. External heat energy is within mass as internal magnetic fields grounding currents into itself and surrounding mass through its nucleus or core. Heat has to ground or burn as decaying internal magnetic fields. External magnetic fields don't ground energy and circulation around the sphere of absolute zero heat energy within its core or nucleus as a monopole of complete repulsion to heat propulsion energy from surrounding space and mass disolving its internal magnetic fields grounding currents by disrupted normal space filled with dark heat energy outside of entanglement of mass as potential renewable heat energy when entanglement with mass occurs. Space is a weak external magnetic field filled with dark heat energy outside of entanglement. Distance is always equal to force. Hydrogen has the strongest internal magnetic field of force. Hydrogen under extreme pressure expands into helium. Helium occupies more occupational space within mass, and more occupational space itself has more force of pressure from repulsion within mass and distance traveling cycling circulation patterns of internal magnetic field increases in equalization to force of pressure decreases. As mass moves away from the core of earth's internal magnetic field grounding currents through its nucleus or core where force is stronger and distance traveling is minimal, it increases in distance traveling and decreases in force of pressure currents grounding through all masses in its path. Currents are the force of pressure known as weight. As mass moves away from the central point of earth's internal magnetic field, grounding currents weaken as distance traveling increases and force of pressure from current grounding decreases. Equalization to force of pressure and distance traveling cycling circulation patterns as mass. The more currents grounding as weight, the more repulsion to the mass and distance traveling cycling circulation decreases. Force of pressure is always equalization to distance traveling, and weight is currents grounding through mass as weight. Table of elements proves hypothesis. Hydrogen has more force of pressure currents grounding than helium. And has the least distance traveling cycling circulation patterns. As mass expands, its internal magnetic field grounding currents weaken. Equalization without gravity. Magnetism. Theoretically factual probability that works with quantum physics without gravity. Friction causes sparks of striking resistance of mass as potential renewable heat energy passing through all masses in its path until resistance is overcome by open space itself and returns to dark heat energy outside of entanglement of mass as potential renewable heat energy when entanglement with mass occurs again. Liquidity infinity to illusionary solidity of liquidity infinity. Alpha and Omega. Cold repulsion of space to heat energy singularities. Cold and heat coexist as space itself as a weak external magnetic field. External heat energy within mass in quantum internal magnetic fields grounding currents through all masses in its path. Space has a weak external heat energy field as maximum distance traveling through space and least amount of heat energy force of pressure to and from cold repulsion of space itself as perpetual motion. Force is when the accumulation of heat energy singularities is unified of unidirectional flow repulsion back onto itself as internal magnetic fields grounding heat currents as force fields of pressure holding mass together as the weakest point of repulsion back onto itself as internal magnetic fields grounding currents into the weakest point of repulsion. Mass neutralizes repulsion as outward pressure exerted within mass and without mass equalization. Mass is always the weakest point of repulsion. In a greater internal magnetic field, grounding currents synchronization as directional force of pressure grounding currents as weight. Outside of a greater internal magnetic field, grounding currents into itself is weightless. Outward pressure is weightless without a greater internal magnetic field directional pressure of force. Magnets show the bonding force of pressure known as weight when you try to pull them apart. No negative force of flow. Unification of unidirectional flow. One flow redirected trajectories by repulsion of cold space. Alpha and Omega. Clockwise and counterclockwise. Same flow cycling circulation patterns of magnetism grounding currents as force of pressure known as weight. Quantum Internal magnetic fields grounding currents. Hydrogen and oxygen sharing currents are grounding as water. Cold repulsion unification of hydrogen and oxygen. Ice in a glass of liquid condensate oxygen and hydrogen sharing internal magnetism grounding currents as water. Atmospheres grounding currents as water molecules sharing internal magnetism grounding currents into each other as friction. Heat exchanging singularities point to point chain reactions through all masses in its path. Equalization is lightning strikes burning through atmospheres, gasses releasing heat singularities as friction of spark lighting up atmospheres. Sparks (electrons) light up atmospheres. Grinding friction causes sparks lighting up. Heat transference lighting up atmospheres as daylight magnetism exchanging singularities point to point chain reactions through all masses in its path. Heat waves traveling through space and atmospheres piggyback light as heat waves, magnifying light throughout space and atmospheres. Light is only present in resistance. Lightning proves hypothesis. Fire is the decay of internal magnetic fields releasing heat singularities outside of entanglement of mass as potential renewable energy absorbed by surrounding masses. Liquidity infinity to illusionary solidity of liquidity infinity. Heat is always present in exchanging singularities point to point chain reactions through all masses. It's not the waste product. Electricity is rapid heat exchanging through mass. Heat has to ground or mass burns. Lightning burns through atmospheres. Electricity is sparks of electrons lighting up as friction. Heat currents grounding themselves through all masses or mass burns or decay of internal magnetic fields. Engines ground heat energy to anti freeze and radiators ground to atmospheres and atmospheres grounding currents into surrounding atmospheres or earth's internal magnetic field. Grounding currents of heat is equalization of internal magnetic fields temperature control. If internal magnetic fields grounding currents fails it decays as heat releasing e external energy flow as fire or molten masses. Refrigerators and air conditioning remove heat and leave behind cold repulsion of space. As usual, water is found condensate. Unification of internal magnetic fields grounding currents into surrounding mass sharing heat energy. Magnetism is a force of pressure known as space itself filled with dark heat energy outside of entanglement of mass. Mass is the expansion of space. Monopoles of pure fabric of cold space repulsion are external magnetic fields that don't ground energy. Galaxies and planets prove the hypothesis of cold repulsion within entanglement of mass and without mass. Theoretically factual probability that works with quantum physics without gravity.
@drdca8263
@drdca8263 Ай бұрын
Clanging disorder?
@antoniolewis1016
@antoniolewis1016 Ай бұрын
I am not sure this conclusion is correct. For example, there is torque applied in Euler equations for rigid body rotation of a spinning rigid top.
@EugeneKhutoryansky
@EugeneKhutoryansky Ай бұрын
There are many equations that discuss torque for rigid objects. These equations correctly predict the object’s behavior, from the perspective of the outside world. However, if we assume that this is a rigid object, then we get into trouble when we start thinking of the object as a collection point masses connected to each other, and we try to calculate the behavior of these point masses in terms of Newton’s Three Laws of Motion.
@ytt8370
@ytt8370 28 күн бұрын
Newton's third law talks about inertial forces, you're talking about mechanical constraints. Of course the solution does not work if you change the problem. Rigidity changes how much a body deforms when a force is applied, not the force transmitted by the body
@EugeneKhutoryansky
@EugeneKhutoryansky 28 күн бұрын
If two masses are constrained to each other, then this means that there is a force holding them together. Newton's Third Law applies to all forces.
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