Understanding Bremsstrahlung Radiation - X ray Production

  Рет қаралды 68,187

Clover Learning

Clover Learning

Жыл бұрын

➡️ LEARN MORE: This video lesson was taken from our X-Ray Production and Safety course. Use this link to view course details and additional lessons. cloverlearning.com/courses/xr...
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➡️ LESSON DESCRIPTION: This lesson’s objectives are to define Bremsstrahlung radiation and to identify the three essential requirements for creating x-ray photons. This lesson also briefly explains how different components and processes in the x-ray tube control the requirements for creating x-ray photons. This lesson also describes the process of creating Bremsstrahlung radiation and explains the factors that control the energy of Bremsstrahlung radiation as well as describes how Bremsstrahlung radiation can be visualized on a graph. Lesson Objectives: *Define Bremsstrahlung radiation *Identify the three essential requirements for creating x-ray photons *Briefly explain how different components and processes in the x-ray tube control the requirements for creating x-ray photons *Describe the process of creating Bremsstrahlung radiation *Explain the factors that control the energy of Bremsstrahlung radiation *Describe how Bremsstrahlung radiation can be visualized on a graph
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Пікірлер: 43
@MrWilly-mm5rv
@MrWilly-mm5rv 10 ай бұрын
The best explanation I found on KZfaq. Thanks a lot❤.
@farxeennn_n
@farxeennn_n 3 ай бұрын
im an Alevels student, it is so difficult to understand phys for A2. but you made it so easy.. Thankyou!!
@ScarlethAngeline25
@ScarlethAngeline25 7 ай бұрын
Thanks, it helps me alot. The best explanation i saw in youtube.😊
@SCCDentalAssisting
@SCCDentalAssisting 4 ай бұрын
Excellent explanation!
@mohamedamr_1
@mohamedamr_1 7 ай бұрын
Thanks a lot . It was so helpful❤
@zeph7691
@zeph7691 2 ай бұрын
great video, very clear and the animations helped a lot! x
@Dentalwali
@Dentalwali Жыл бұрын
Thank-you so muchhhhh❤
@mbohhonorine8470
@mbohhonorine8470 11 ай бұрын
This was so helpful. Thanks a lot
@CloverLearning
@CloverLearning 11 ай бұрын
Glad it was helpful!
@user-xl7xm6vm4f
@user-xl7xm6vm4f 7 ай бұрын
شكرا جزيلا لك كان هذا مفيد جدا الكلية الطبية في سوريا ❤️❤️
@chamasuksansirikul9376
@chamasuksansirikul9376 7 ай бұрын
keep up the good work!
@pavanajsridhar939
@pavanajsridhar939 7 ай бұрын
superb! thanx a lot! best possible explanation !
@alyssamaeamolopido1612
@alyssamaeamolopido1612 9 ай бұрын
Thank youuu ❤
@user-sk3ig6yq5n
@user-sk3ig6yq5n 11 ай бұрын
Thank you for this ❤
@nawlifepeacefullife
@nawlifepeacefullife Ай бұрын
nice lecture
@JavanKibet-lv7kw
@JavanKibet-lv7kw 3 ай бұрын
THANK U MONSIEUR
@ch_arbaz_yt
@ch_arbaz_yt 9 ай бұрын
Salam very good concept
@ohanwenwachiamaka3078
@ohanwenwachiamaka3078 11 ай бұрын
Thank you so much 💖
@user-lb7mg3xc5v
@user-lb7mg3xc5v 16 күн бұрын
greattt
@mreatboom1314
@mreatboom1314 6 ай бұрын
Why this energy is not transfered to the nucleus by moving it ?
@blackalgae370
@blackalgae370 2 ай бұрын
I will preface this by saying i am not an expert, but; I think, it because atom generaly have a neutral charge. it has positvly charged protons and neutral neutrons in the nucleous and negativly charged eletrons in the electron shell. If an electron hits a neutraly charged atom and interacts with it then it will become negativly charged, and a negative charge will push away negatively charged particles. The same way a magnet will be atracted the metal and the negative end of a magnet will attract the positive side of another magnet but push the negative end away. On the atomic scale this would mean that if an electron shot into an atom and it locked into the electron shell it would knock another electron out of the shell and the too would produce an electromagnetic wave. If however it was the nucleus that recieved a transfer of energy and it recieved the impacting energy then the excited atom would release the energy by throwing out an electon or by altering the configuration of its electron shell also releasing a tiny busrt of energy in the form of heat or light. At least thats how i think it works.
@rahafalsultan4999
@rahafalsultan4999 9 ай бұрын
Thank you ❤
@lilianemccallin1143
@lilianemccallin1143 8 ай бұрын
how can electron have an energy of 0 keV, as its rest mass is 500keV? Does this mean the electron has disappeared completely ?
@miaehatamm8936
@miaehatamm8936 8 ай бұрын
i think it is only referring to the kinetic energy that is imparted by the voltage! the electron would still have rest energy
@AliFarhan-hm4ls
@AliFarhan-hm4ls 6 ай бұрын
It is the kinetic energy
@irwo
@irwo 7 ай бұрын
Thx from medical college of iraq
@AliFarhan-hm4ls
@AliFarhan-hm4ls 6 ай бұрын
عراقي ابو الغيرة
@irwo
@irwo 6 ай бұрын
@@AliFarhan-hm4ls 😂😂😂
@AliFarhan-hm4ls
@AliFarhan-hm4ls 6 ай бұрын
@@irwo يا كلية؟
@irwo
@irwo 6 ай бұрын
@@AliFarhan-hm4ls كوفة
@AliFarhan-hm4ls
@AliFarhan-hm4ls 6 ай бұрын
@@irwo موفق ان شاء الله
@emilmohan1000
@emilmohan1000 6 ай бұрын
any other way of x ray production?
@cucciafr68
@cucciafr68 4 ай бұрын
You can get characteristic xrays from when the incoming electron knocks out an electron from one of the shells of the atom. To stabilize itself, an electron from a higher shell moves to that vacancy. To balance the energy difference the atom can release an xray of specific energy. If you look back at the graph it shows of the bell curve it has a large spike. That would be from the characteristic xray.
@LinusFeynstein
@LinusFeynstein 4 ай бұрын
Sehr schöne Erklärung. However, please pronounce Bremsstrahlung as in „BRAMMS-STROAAA-LOONG“. The stress is on the second syllable.
@cucciafr68
@cucciafr68 4 ай бұрын
I cringed trying to pronounce this in front of my German colleagues.
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