Using Benford's Law to Reveal Journal Entry Anomalies

  Рет қаралды 1,812

Mark Nigrini

Mark Nigrini

Жыл бұрын

This companion video to my Journal of Accountancy (September 2022) article reviews Benford's Law, the HealthSouth fraud, the use of the Runs test to detect below-the-testing threshold frauds, caveats to using that test, the use of Benford to reveal unusual duplications, the threshold line, and the suggestion to investigate four spikes. Running the tests on both examples in the article with commentary is also demonstrated.
Links:
Journal of Accountancy
www.journalofaccountancy.com/
www.aicpa.org/resources/landi... (September 2022 issue pp. 12-19)
Benford's Law Excel template
www.dropbox.com/scl/fi/3fwzst...
Accounts payable data
www.dropbox.com/scl/fi/wxy207...
Forensic Analytics
www.wiley.com/en-us/Forensic+...
Benford's Law
www.wiley.com/en-us/Benford%2...
Nigrini.com (data and other free information)
nigrini.com/

Пікірлер: 12
@hartdean101
@hartdean101 Жыл бұрын
Very good video. Thanks for posting
@harumih.3727
@harumih.3727 5 ай бұрын
Can we use just LEFT in stead of VALUE(LEFT(D2*10000,1)), or VALUE(LEFT(D2*1000,1), inside the First Digit formula? I am wondering why you have to use (D2*10000,1) or (D2*1000,1) for the first (left) digit.
@ForensicAnalytics
@ForensicAnalytics 5 ай бұрын
You can use LEFT if you like. I've always used VALUE with LEFT since many years ago when I was programming in SAS. As for the *10000 or *1000, ... If we have an amount of 0.08 then the first digit is an 8 because zero is inadmissible as a first digit. The first digit is the leftmost nonzero digit. So programming LEFT of 0.08 in Excel will give you a 0 and not the correct answer of 8. However if we multiply 0.08 by 1000 then the first digit will be correct as 8 (0.08 * 1000 = 80.00) and the first-two digits will be correct as 80 (because 0.08 can be written as 0.080). If we have a large amount such as $180,583 then after multiplying by 1,000 we'll still get the correct first digit using LEFT. If you want to be top notch then you can use IF and only multiply numbers less than 10 by 1,000. This will avoid LEFT(A1,2) where A1 is 2.34 giving you "2." as the first-two digits.
@harumih.3727
@harumih.3727 5 ай бұрын
@@ForensicAnalytics Thank you for clarification and explanation of using VALUE and a multiplication by 1000. Totally makes sense! Thank you again!
@jimberence
@jimberence Жыл бұрын
Hello sir, assumes that there were 100 articles in a newspaper. I find & count the word 'the' at every articles. I found that there were 80 articles that occurs the word 'the'. I listed all that 80 frequencies & apply to benford's law. My question is, does those 80 sets or data of numbers will obey the benford's law? Thanks in advance.
@ForensicAnalytics
@ForensicAnalytics Жыл бұрын
That data will probably not conform to Benford's Law. First, Benford's Law assumes "long" numbers with about four or more digits on average. It should be okay for three digit numbers. For data sets with small numbers (all numbers under 100) the formula is different and is more biased towards the low digits. Second, Benford's Law works well with accounting, finance, and earth science data. What you have is text data. I think that you would be better off reading up on Zipf's law and other related topics such as term frequencies and word frequencies. Finally, it goes without saying that your "the" distribution is heavily dependent on the language used and the type of article. Business-related research articles are sometimes 20,000 words long whereas articles in regional or local newspapers might all be under 1,000 words.
@jimberence
@jimberence Жыл бұрын
Thanks sir.
@jimberence
@jimberence Жыл бұрын
Hello sir, I got the data from a book. There were 217 data or times The first digits frequencies were as follow: 1 - 19 times 2- 10 times 3 - 15 times 4 - 5 times 5 - 8 times 6 - 3 times 7 - 4 times 8 - 0 times (none) 9 - 2 times Is it obey the Benford's Law predictions Sir? Thanks in advance
@ForensicAnalytics
@ForensicAnalytics Жыл бұрын
@@jimberence No, that data does not conform to Benford's Law. Chapter 4 of my book Forensic Analytics Second Edition discusses measuring conformity in depth.
@jimberence
@jimberence Жыл бұрын
@@ForensicAnalytics tq very much sir.
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