Worked example: Integral test | Series | AP Calculus BC | Khan Academy

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Khan Academy

10 жыл бұрын

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See how the integral test is put to use in determining whether a sequence converges or diverges.
AP Calculus BC on Khan Academy: Learn AP Calculus BC - everything from AP Calculus AB plus a few extra goodies, such as Taylor series, to prepare you for the AP Test
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Пікірлер: 18
@bdgrey
@bdgrey 8 жыл бұрын
This is where mathematics shows you the future. In other words, from here on out, logic, theorems, and justification.
@koleth1
@koleth1 9 жыл бұрын
Why is there no practice problems for integral test and the root test on khan academy?
@guledaaydemir
@guledaaydemir 8 жыл бұрын
Thanks from Turkey Mr!
@stunninglad1
@stunninglad1 10 жыл бұрын
Clearly put and a very good lesson.
@NYKYADU
@NYKYADU 7 жыл бұрын
What if i decide to draw the rectangle leftwards for 1/x will that be now not conclusive that 1/x is convergent or divergent
@Alive4Metal
@Alive4Metal 9 жыл бұрын
I still don't understand why for the example for convergence we used the right endpoint of the intervals to determine the area of the squares, and for the example for divergence we used the left end point of the interval to determine the area of the block... it seems to arbitrary... if I had made squares using the right end points for the example with divergence, then the sum of the area of all the squares would be less than the area under the curve 1/x... can someone please clarify this?
@indraotsutsuki9080
@indraotsutsuki9080 8 жыл бұрын
+Alive4Metal If you choose the left end point, then the integral will be less than the area of the rectangles, and you can use this to prove that sum diverges by showing that the integral(which is smaller) diverges(meaning the integral is infinite. If you think that the series converges, than you use the right end point, and the integral will be greater the sum of the series. If the integral is not infinite, than the sum of the series must also converge,since it is smaller than the integral. Why does this work? This is a test for positive infinite series, so you can factor out the negative if they're negative numbers. Remember, the numbers being added must end up being zero eventually(even at infinity), therefore the rectangles must be getting smaller and smaller.
@davidmetz9499
@davidmetz9499 6 жыл бұрын
When you're applying the Integral Test, you really don't need to worry about that, because if you add or subtract a finite number of terms in any series, that won't influence whether the series converges or diverges.
@jaieeke
@jaieeke 10 жыл бұрын
good
@multipledone7501
@multipledone7501 4 жыл бұрын
What are Integral test applications of iur daily Life...anyone?
@yadpreetcheema4806
@yadpreetcheema4806 6 жыл бұрын
You're a God
@Riiisuu
@Riiisuu 7 жыл бұрын
But isn't 1/x convergent? How could it = infinity
@Oussama-uo1gf
@Oussama-uo1gf 6 жыл бұрын
1/x is convergent but the integral of 1/x which is ln(x) is not convergent.
@tyrannism5648
@tyrannism5648 6 жыл бұрын
It approaches infinity too slowly.
@OverLordGoldDragon
@OverLordGoldDragon 10 жыл бұрын
No graphical explanation? Useless.
@saffakhalid3510
@saffakhalid3510 9 жыл бұрын
Did you even watch the whole thing
@randomwindowsstuffz
@randomwindowsstuffz 9 жыл бұрын
The graphical part is provided at 6:40
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