#improving_power_factor#compensation#principle ofcompensation#
Improving power factor and how to calculate capacitors Improving power factor.
How do capacitors improve power factor and how is it calculated?
How to determine the capacitor value of the motor.
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Improving the power factor of a 3-phase engine from 0.6 to 0.9 in the easiest way.
How to calculate the total power factor of loads.
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The simplest explanation for improving the power factor of capacitors.
Power factor explained.
Calculate the value of the capacitors required to improve the power factor.
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The best information in improving the power factor
La compensation d'énergie réactive.
Factor de puissance
Calculate the capacitance of 3 phase capacitors, improve the cosf power factor and conduction method.
_ Power factor improvement:
The power factor is the ratio between the active power and the apparent power. The value of the power factor ranges between 0 to 1 expressing the angle between the voltage phase and the current phase in electrical loads, the closer the number is to one, the better.
The power factor is equal to COS angle, so if the angle between the current phase and the voltage phase is 0, then COS 0 = 1, then the power factor is equal to one (impedance load).
The apparent power is the total power required to operate the equipment and it consists of the active power and the reactive power. The active power is the one that is used mainly in the electrical network and its unit is kilowatts KW, and the reactive power is required to generate the electromagnetic fields necessary to operate Engines and their unit KVAR.
Example.
Let's calculate the capacitance of the capacitor for a 15KW three-phase motor and we want to improve its power factor from 0.6 to 0.9
data:
U=400v voltage
F=50Hz Frequency
P=15 kw Power for the motor
The old power factor is cosf1=0,6
new power factor cosf2=0.9
Let's count.
cos-1(0,6)= 53°,13
That is 1, 333 = ( 31, 53 ° ) tan
cos-1(0,9)=25°,84
i.e. 0.484=( 84,°25)tan
Capacitor capacitance in KVAR
Q(kvar)=P(tanf1_tanf2)
=15(1,333_0.484)
Q = 12,735kvar then
Calculate the capacitance of the capacitor in individuals.
C=Q/2×π×F×U×U
C=12,735×1000/2×π×50×400×400
C=0.000253483F
So %5+- C=253,5 uF
C=3×84.5 uF
So to raise the value of the power factor from 0.6 to 0.9, the capacitor must be connected to a value of 84.5 x 3 mer
Farad.
How to connect a three-pole capacitor
It is connected in parallel with the 3 phases in which the motor operates, or it is placed in a special cabinet for capacitors, and it is connected in parallel with the 3 phases coming from the electrical transformer.
@Youssef Technicien
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