Zeven is even Dutch for Seven!

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Күн бұрын

Here's where you can play Zeven by James Kopp: app.crackingthecryptic.com/v8...
Normal sudoku rules apply. Adjacent digits along an orange line have a difference of at least four. The small numbers in each cage show the sum of the digits in the cage and digits cannot repeat in a cage.
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▶ Contents ◀
0:00 Theme Music & News around the channel
2:38 Rules of today’s puzzle
3:30 Start Of Solve - Let's Get Cracking!

Пікірлер: 71

@Oscarefraim Ай бұрын

Groetjes uit Nederland we houden van jullie!❤

@chocolateboy300 Ай бұрын

I finished in 42 minutes. I'm so used to German Whispers that this puzzle kept messing with me about 5s and 46s. Once I stopped myself from doing that, this puzzle was quite enjoyable. Great Puzzle!

@jdyerjdyer 28 күн бұрын

About the same for me, too, in time and the brain twisting. I definitely prefer German Whispers to Dutch, but that said, Dutch gives a chance to learn more about these difference lines. Luckily I only made one slip, having to back out of my solution about 12 steps. I instantly knew where I'd made a false assumption (and yes it was on the line in column 9) dealing with the placement of the 5 due to ruling out a few possibilities erroneously because I had slipped into thinking about German Whispers differences regarding the 6. (I had said, this can't be a 1, so 6 can't go here or here, but there was a perfectly good 2 in those cells, which in this case does allow a 6 where I had ruled it out.) C'est la vie.

@RecreationalCynic Ай бұрын

Solved it in 38:22. Looking forward to Acht next year!

@smartass4758 Ай бұрын

An easier way to exclude only 2 5s on the long orange line is: 5 in r1c1 would need a 1 either in column 1 or column 2. And suddenly there are three 1s in columns 1 and 2.

@bobh6728 Ай бұрын

Excellent deduction. Almost as easy was to check the blue digit in column 1, r4c1, and go to the blue digit in row 1, r1c8. If you alternate they end up in the same group, so there can’t be just 1 change. So the 5 in box 1 is not in the corner.

@tomgalli1188 28 күн бұрын

I had to let Mark give me a push, just to the point of realizing there had to be four 5s in the outline. After that, what fun!

@davidh.4944 Ай бұрын

1:13:48@#1758. Even though my solve time is long, this is the first one in a while where I didn't feel like I was tricked by the video time. I recognized that it would take me a good amount of time going in. It has been ages since I've tackled a Dutch whispers puzzle, and I had to re-work the logic of them. There was also not too much going in to distinguish them, either, and I had to piece out the polarity by trial and error, and of course coloring.

@cjbarthvdm Ай бұрын

Congratulations / gefeliciteerd. Thanks for the puzzle and video. I started immediately with 6159 in the bottom row, because there is no other way to place the 159 sequence in row 9.

@RichSmith77 Ай бұрын

Did you consider the possibility of no 1-5-9 in row 9? Possible, in theory, with 9-5(-1) around the corner in box 9, no? Mark had to rule this option out first.

@geezerama 28 күн бұрын

Great puzzle. I'm well chuffed with 32:42.

@benjaminrealy5661 29 күн бұрын

17:59. Quickly learned the 159 had to be in order on each outer line. By placing candidates in the cages and realizing the 2 cell had to be 16 but 1 couldn't be corner was the break in I needed

@piarittersporn Ай бұрын

Very beautiful and relaxing puzzle. Still tired this morning I could solve it in 24 minutes while enjoying my coffee. I loved it. 🙂

@Paolo_De_Leva Ай бұрын

Yes, the perimeter is fascinating. Quite easily cracked if you know the *1-5-9* trick, but nice. All the cages are very restricted. I would say this is a great introduction to *Dutch whisper lines* for unexperienced solvers. Almost genuinely approachable. Great and insightful meta-logic by Mark to disambiguate the cage containing *1-6.* 👏👏👏 I used a less elegant approach, but I did it more quickly. I immediately ruled out *r9c1 = 1* because it would require *5* and *9* above it, and a second *1-5-9* sequence in *row 1,* which would be incompatible with the high digit in the opposite corner of the grid (r1c9). In short, I concluded there could be no *5* in the upper left corner of the grid (r1c1). I did not need to generalize to the opposite corner, as Mark brilliantly did.

@emilywilliams3237 Ай бұрын

I did this without watching first in 21 minutes- entirely credited to your excellent teaching about Dutch whispers in many videos, Mark. Thanks for this excellent video and happy birthday, Isaac!

@Kirbyfan87827 Ай бұрын

Finished in 40:24 on my own. Not too proud of my time, but I'm not really ashamed, either. Fine puzzle.

@David_K_Booth Ай бұрын

My time was very close to yours, and I agree. That sums it up nicely. It's not one for a complete novice, but in my opinion a good confidence-builder for anyone who has a few successful solves under their belt.

@poslfit 29 күн бұрын

At 03:38, you can then write in 6 in the top right, because the Dutch whisper lines would force the top and right sides to start with the same 72..., 84..., or 94... if the top right were 7, 8 or 9.

@EelcoWind Ай бұрын

Zayven would be the pronunciation, I think.

@never7848 Ай бұрын

more like Zayve with a silent n i think

@Dido01 29 күн бұрын

@@never7848 And now I wonder who is going to try and explain the also extant pronunciation of Dutch "zeuven" for that number 😂

@johnbell9074 Ай бұрын

24 mins for me. Thanks.

@darthrainbows 29 күн бұрын

Oooh nice, I beat Mark's time! Solved in 17:20.

@Rach881101 Ай бұрын

36:17 for me. Nice puzzle!

@anaayoung9142 Ай бұрын

Nice! Your idea about 5's (2 or 4 of them), helped to understand the puzzle better and I was able to do it! 😁

@Gonzalo_Garcia_ Ай бұрын

10:35 for me. Great puzzle!

@titusadduxas Ай бұрын

53:49 - I really struggled with the break in even though I knew the 159 trick!

@psiphiorg 2 күн бұрын

Very interesting puzzle! My time today was 25:49, solver number 5852.

@MattYDdraig Ай бұрын

14:21 Really nicely themed and perfectly constructed. Not too taxing but enjoyable.

@jdyerjdyer 28 күн бұрын

Thanks for the quick and easy one. I should have followed suit and colored high/low like you did. I would have shaved a good twenty minutes off my time, probably. Still hovering around twice your and Simon's times on most puzzles, so I haven't gotten any worse. I, too almost made a ribbon, but like you, I quickly realized that it could and indeed would have to swap out in places. To get my break, I used the 16 cage and asked if there was a problem with one of the orientations. Sure enough, one quickly lead to an impossibility along row 9 with the 6789s and 2345s (1 being in the box meant that 5 either lived there or in the opposite corner) making 4 cells from 234 in the row. From there, because I didn't have the aid of high/low, I did more pencil marking the possibilities. I also didn't think about the 5 being the only place for a polarity switch for this reason, but it falls out from the logic anyway. I sort of did do high/low, just without the colors. Silly me. I hope you and Simon get a laugh out of my follies, sometimes. As frustrating as they can be for me, I do learn from them (albeit, slowly). Cheers!

@jinkela7295 28 күн бұрын

@12:10, 5 is actually placed in the highlighted cell

@srwapo Ай бұрын

25:00 even. Super fun solve! I broke it at one point, but managed to figure it out (on an orange line, 3 can be next to 7 in addition to 8 and 9!).

@sunflower499 29 күн бұрын

I realized that the only way to place a 5 on any of the outside lines is to have 1 and 9 on both sides: 159 or 951. This is surprisingly restrictive in column 1 and got me my first digits.

@SarahLivne Ай бұрын

Nice one!

@mudscuffer Ай бұрын

30:43 for me. Quite nice.

@ayakoa2096 Ай бұрын

8:53 for me, nice approachable puzzle

@tonybrooms Ай бұрын

00:46:12

@raysouth1952 Ай бұрын

Very enjoyable. Took me an age to determine the number of 5s around the perimeter because I kept trying to fit three of them. Duh!! Very smooth from there.

@robertcousins2274 Ай бұрын

22:51 for me

@dwdei8815 Ай бұрын

But two is their cutest number by far. It is very twee.

@leickrobinson5186 Ай бұрын

Fun puzzle! And quite approachable! :-D

@awilliams1701 29 күн бұрын

I think the 2 digit cage is 1/6 by means of sums AND dutch whispers.

@awilliams1701 29 күн бұрын

lol yup mark got it. LMAO

@bait6652 Ай бұрын

So close to a dualsolve on the outer ring...only breaks at.one point in B2.... And if u change the top left 7sum to 8sum(4.to 5 in B4)...8 of the 9 boxes create a valid solution...unfortunately B2 is invalid and alot of chaos... It's why there are setters...nice rules.

@rhoadeshouse 29 күн бұрын

Is it normal for the puzzle in the android app to not include the solution, when the puzzle does so in the desktop-app? Didn't notice till today.😂

@Orenotter Ай бұрын

Egregious mistakes I was I was making. My poor otter heart they were breaking. My sixes did clash And my sevens did crash Too bad I can't get by with faking.

@erikbakker6974 29 күн бұрын

At 17:46 why can’t the 2 cells contain a low number and a 5?

@erikbakker6974 29 күн бұрын

Because 5 was already pencil marked in box 3

@rhoadeshouse Ай бұрын

I might just be making fun of myself with this confusion, but i did not understand at all, why there couldn't be 3 5s, instead of eighter 2 or 4. And that i thought would be by having 1 of them in a corner and also 2 more not in a corner.

@stangerrits6712 Ай бұрын

Good question. There is an even number of digits on the perimeter. If there weren’t any 5’s, the alternation between high and low would work. Say you start in R1C1 with a low digit and follow clockwise going low-high-low-high-etc, you’ll end up in R2C1 with a high digit, which you need in order to close the loop with R1C1. When introducing a single five, the alternation would change, skip a step, and if you again follow the perimeter, R2C1 would end up being low, which breaks the puzzle because it can’t connect to R1C1 being low as well. If you would add a second 5, the alternation changes twice, so R2C1 would again be high and your error is fixed. So, because there is an even number of digits on the perimeter, and the perimeter is a closed loop, you’ll need an even number (or zero) 5’s to make it work.

@RichSmith77 Ай бұрын

It's also relevant that there's nowhere you could have 1-5-1 or 9-5-9 around the perimeter, so every 5 forces a change of polarity alternation. And there has to be an even number of them for the reasons above.

@rhoadeshouse Ай бұрын

@@RichSmith77 Thanks to Both of you, i think i now understand the work of thinking, Mark must've gone through too but it was so elementary for him (and probably most people on the channel), he didn't think someone would need it to be explained. Thanks a lot.

@rhoadeshouse Ай бұрын

@@stangerrits6712Thank you for explaining this so detailed to me, i assume i finally get it.

@_-_-Sipita-_-_ 29 күн бұрын

15:00 for me.

@highpath4776 Ай бұрын

No 5s on the 7s but three 7s makes me think of fruit machine

@craigroberts7013 Ай бұрын

11m 05s

@poslfit 29 күн бұрын

At 07:00, why does it have to be 16 and not say 26 or 15?

@erikbakker6974 29 күн бұрын

Because it is in a 7 cage. Needs to sum to 7.

@poslfit 29 күн бұрын

@@erikbakker6974 Lol, thanks!

@Leo-ct9pm Ай бұрын

Why it can't be 3 5s around the perimeter?

@felipeguimaraesvasconcelos3772 29 күн бұрын

There are 32 cells around the perimeter, which can be low, high, or 5. Except for where there's a 5, they'll alternate in high-low polarity. A five can only be adjacent to 1 or a 9, and because of the geometry of the loop it must be adjacent to both. Note that this breaks the polarity alternation: you have a low digit, 5, and a high digit. Note also that if there are 3 fives on the loop, then the line will switch polarity exactly 3 times. That can't happen, because the loop has an even number of cells, so it must have an even number of polarity-switching 5's.

@Leo-ct9pm 29 күн бұрын

@@felipeguimaraesvasconcelos3772 Thanks for the explanation, I get it now.

@laurv8370 Ай бұрын

Nitpicking: "almost always when 5 appears on the line it changes the alternation, the only way it doesn't is when it appears between the same digit", well, as 5 can only appear close to 1 or 9, it does NOT change the alternation in 67% of the cases :D (i.e. 1-5-1 and 9-5-9) and it only changes it in 33% (i.e. 1-5-9) 😝

@RichSmith77 Ай бұрын

I think you would need to factor in the proportion of times the two ends digits on a three cell line see each other. In those instances, you couldn't have 1-5-1 or 9-5-9, but could have 1-5-9. Also, surely 1-5-9 and 9-5-1 each occur as frequently as either 1-5-1 or 9-5-9. That immediately doubles the probability, no? "Almost always" no doubt over sells it, but I could see polarity switching more times than not, when a 5 appears on a Dutch whisper. 😉